How to print a value in loop after some delay in swift - swift

Question

i want to print my values in loop after 5 seconds delay
here is how im trying to do so
let count = 1...10
for calls in count{
let seconds = 5
DispatchQueue.main.asyncAfter(deadline: .now() + .seconds(seconds), execute: {
print(calls)
})
}
But it waits 5 seconds only in the first time and the print all the values at once.
Maybe there is another way to call a function many times after a delay of time please recommened
this is how im trying with timer
var seconds = 10
var timer = Timer()
override func viewDidLoad() {
super.viewDidLoad()
let count = 1...10
for number in count{
timer = Timer.scheduledTimer(timeInterval: 1, target: self, selector: #selector(ViewController.counter), userInfo: nil, repeats: true)
print(number)
}
}
#objc func counter(){
seconds -= 1
if (seconds == 0){
print("User Location")
}
}
}

Answer 1

Two pieces of criticisms. Forst, don't use a loop - it's executed immediately. Second, do use threading, there's no need. Use a Timer instead:
class ViewController: UIViewController {
var timer = Timer()
var iterations = 0
override func viewDidLoad() {
super.viewDidLoad()
timer = Timer.scheduledTimer(timeInterval: 5.0, target: self, selector: #selector(printTime), userInfo: nil, repeats: true)
}
#objc func printTime() {
print(Date())
iterations += 1
if iterations == 5 {
timer.invalidate()
}
}
}
It's output:
2020-08-15 18:08:38 +0000
2020-08-15 18:08:43 +0000
2020-08-15 18:08:48 +0000
2020-08-15 18:08:53 +0000
2020-08-15 18:08:58 +0000
After 5 iterations, you invalidate the time to shut it off.