append an id onto the name of a table - postgresql

I have a select statement
select * from schema.table_id
where ID is a number that is passed into a function
how do I append this ID onto the table I have tried || but that gave a syntax error. I have also tried using concat('schema.table_, id::text) but when that ran a select * from %I, table name that gave an error of relation "schema.tablename" does not exist I assume this is due to it being in quotes

This answer is limited to you problem mentioned in the question. You should write it in this way:
format('select * from %I.%I',schema_name,'table_'||id::text)
or
format('select * from "schema_name".%I','table_'||id::text)

Related

How to declare a variable in select statement in Postgres SQL [duplicate]

How do I declare a variable for use in a PostgreSQL 8.3 query?
In MS SQL Server I can do this:
DECLARE #myvar INT
SET #myvar = 5
SELECT *
FROM somewhere
WHERE something = #myvar
How do I do the same in PostgreSQL? According to the documentation variables are declared simply as "name type;", but this gives me a syntax error:
myvar INTEGER;
Could someone give me an example of the correct syntax?
I accomplished the same goal by using a WITH clause, it's nowhere near as elegant but can do the same thing. Though for this example it's really overkill. I also don't particularly recommend this.
WITH myconstants (var1, var2) as (
values (5, 'foo')
)
SELECT *
FROM somewhere, myconstants
WHERE something = var1
OR something_else = var2;
There is no such feature in PostgreSQL. You can do it only in pl/PgSQL (or other pl/*), but not in plain SQL.
An exception is WITH () query which can work as a variable, or even tuple of variables. It allows you to return a table of temporary values.
WITH master_user AS (
SELECT
login,
registration_date
FROM users
WHERE ...
)
SELECT *
FROM users
WHERE master_login = (SELECT login
FROM master_user)
AND (SELECT registration_date
FROM master_user) > ...;
You could also try this in PLPGSQL:
DO $$
DECLARE myvar integer;
BEGIN
SELECT 5 INTO myvar;
DROP TABLE IF EXISTS tmp_table;
CREATE TABLE tmp_table AS
SELECT * FROM yourtable WHERE id = myvar;
END $$;
SELECT * FROM tmp_table;
The above requires Postgres 9.0 or later.
Dynamic Config Settings
you can "abuse" dynamic config settings for this:
-- choose some prefix that is unlikely to be used by postgres
set session my.vars.id = '1';
select *
from person
where id = current_setting('my.vars.id')::int;
Config settings are always varchar values, so you need to cast them to the correct data type when using them. This works with any SQL client whereas \set only works in psql
The above requires Postgres 9.2 or later.
For previous versions, the variable had to be declared in postgresql.conf prior to being used, so it limited its usability somewhat. Actually not the variable completely, but the config "class" which is essentially the prefix. But once the prefix was defined, any variable could be used without changing postgresql.conf
It depends on your client.
However, if you're using the psql client, then you can use the following:
my_db=> \set myvar 5
my_db=> SELECT :myvar + 1 AS my_var_plus_1;
my_var_plus_1
---------------
6
If you are using text variables you need to quote.
\set myvar 'sometextvalue'
select * from sometable where name = :'myvar';
This solution is based on the one proposed by fei0x but it has the advantages that there is no need to join the value list of constants in the query and constants can be easily listed at the start of the query. It also works in recursive queries.
Basically, every constant is a single-value table declared in a WITH clause which can then be called anywhere in the remaining part of the query.
Basic example with two constants:
WITH
constant_1_str AS (VALUES ('Hello World')),
constant_2_int AS (VALUES (100))
SELECT *
FROM some_table
WHERE table_column = (table constant_1_str)
LIMIT (table constant_2_int)
Alternatively you can use SELECT * FROM constant_name instead of TABLE constant_name which might not be valid for other query languages different to postgresql.
Using a Temp Table outside of pl/PgSQL
Outside of using pl/pgsql or other pl/* language as suggested, this is the only other possibility I could think of.
begin;
select 5::int as var into temp table myvar;
select *
from somewhere s, myvar v
where s.something = v.var;
commit;
I want to propose an improvement to #DarioBarrionuevo's answer, to make it simpler leveraging temporary tables.
DO $$
DECLARE myvar integer = 5;
BEGIN
CREATE TEMP TABLE tmp_table ON COMMIT DROP AS
-- put here your query with variables:
SELECT *
FROM yourtable
WHERE id = myvar;
END $$;
SELECT * FROM tmp_table;
True, there is no vivid and unambiguous way to declare a single-value variable, what you can do is
with myVar as (select "any value really")
then, to get access to the value stored in this construction, you do
(select * from myVar)
for example
with var as (select 123)
... where id = (select * from var)
You may resort to tool special features. Like for DBeaver own proprietary syntax:
#set name = 'me'
SELECT :name;
SELECT ${name};
DELETE FROM book b
WHERE b.author_id IN (SELECT a.id FROM author AS a WHERE a.name = :name);
As you will have gathered from the other answers, PostgreSQL doesn’t have this mechanism in straight SQL, though you can now use an anonymous block. However, you can do something similar with a Common Table Expression (CTE):
WITH vars AS (
SELECT 5 AS myvar
)
SELECT *
FROM somewhere,vars
WHERE something = vars.myvar;
You can, of course, have as many variables as you like, and they can also be derived. For example:
WITH vars AS (
SELECT
'1980-01-01'::date AS start,
'1999-12-31'::date AS end,
(SELECT avg(height) FROM customers) AS avg_height
)
SELECT *
FROM customers,vars
WHERE (dob BETWEEN vars.start AND vars.end) AND height<vars.avg_height;
The process is:
Generate a one-row cte using SELECT without a table (in Oracle you will need to include FROM DUAL).
CROSS JOIN the cte with the other table. Although there is a CROSS JOIN syntax, the older comma syntax is slightly more readable.
Note that I have cast the dates to avoid possible issues in the SELECT clause. I used PostgreSQL’s shorter syntax, but you could have used the more formal CAST('1980-01-01' AS date) for cross-dialect compatibility.
Normally, you want to avoid cross joins, but since you’re only cross joining a single row, this has the effect of simply widening the table with the variable data.
In many cases, you don’t need to include the vars. prefix if the names don’t clash with the names in the other table. I include it here to make the point clear.
Also, you can go on to add more CTEs.
This also works in all current versions of MSSQL and MySQL, which do support variables, as well as SQLite which doesn’t, and Oracle which sort of does and sort of doesn’t.
Here is an example using PREPARE statements. You still can't use ?, but you can use $n notation:
PREPARE foo(integer) AS
SELECT *
FROM somewhere
WHERE something = $1;
EXECUTE foo(5);
DEALLOCATE foo;
In DBeaver you can use parameters in queries just like you can from code, so this will work:
SELECT *
FROM somewhere
WHERE something = :myvar
When you run the query DBeaver will ask you for the value for :myvar and run the query.
Here is a code segment using plain variable in postges terminal. I have used it a few times. But need to figure a better way. Here I am working with string variable. Working with integer variable, you don't need the triple quote. Triple quote becomes single quote at query time; otherwise you got syntax error. There might be a way to eliminate the need of triple quote when working with string variables. Please update if you find a way to improve.
\set strainname '''B.1.1.7'''
select *
from covid19strain
where name = :strainname ;
In psql, you can use these 'variables' as macros. Note that they get "evaluated" every time they are used, rather than at the time that they are "set".
Simple example:
\set my_random '(SELECT random())'
select :my_random; -- gives 0.23330629315990592
select :my_random; -- gives 0.67458399344433542
this gives two different answers each time.
However, you can still use these as a valuable shorthand to avoid repeating lots of subselects.
\set the_id '(SELECT id FROM table_1 WHERE name = ''xxx'' LIMIT 1)'
and then use it in your queries later as
:the_id
e.g.
INSERT INTO table2 (table1_id,x,y,z) VALUES (:the_id, 1,2,3)
Note you have to double-quote the strings in the variables, because the whole thing is then string-interpolated (i.e. macro-expanded) into your query.

PL/PostgreSQL how to convert a variable into a table name

So I have a function in PostgreSQL that dynamically selects columns from a dynamic table. I got this solution from this post and it works great other than one thing.
This is inside of a file that is connected to a Node server, and so the $1 and $2 in the second SELECT * FROM represent values passed from there. The issue right now is that I am getting a syntax error that I don't understand (I am newer to SQL so that may be why).
$2 represents the name of the table to be selected from as a string, so for example it could be 'goals'. The error is syntax error at or near "'goals'". I realize that it cannot be a string with single quotes (I believe) and so I am wondering how to convert that variable to be a table name? using "goals" there as well as goals, for example works as expected, though I'm not sure how to do that outside of a function.
CREATE OR REPLACE FUNCTION get_data(user_id INT, table_name anyelement)
RETURNS SETOF ANYELEMENT AS $$
BEGIN
RETURN QUERY EXECUTE
format('SELECT * FROM %s WHERE user_id = $1', pg_typeof(table_name)) USING user_id;
END;
$$ LANGUAGE plpgsql;
SELECT * FROM get_data($1, NULL::$2);
$1 is 5 and $2 is 'goals' for example
After many hours of trying to figure it out, thanks to Adrian's comment, I found MassiveJS (how I'm connecting to my PostgreSQL server) has inline functions to do queries. In my controller file in my server I was able to create a one line function as such:
const data = await db[tableName].where("user_id=$1", [userId])
Didn't know inline SQL existed in MassiveJS, so that was great to find out!

How to update column based on column name in postgres?

I've narrowed it down to two possibilities - DynamicSQL and using a case statement.
However, I've failed with both of these.
I simply don't understand dynamicSQL, and how I would use it in my case.
This is my attempt using case statements; one of many failed variations.
SELECT column_name,
CASE WHEN column_name = 'address' THEN (**update statement gives syntax error within here**)
END
FROM information_schema.columns
WHERE table_name = 'employees';
As an overview, I'm using Axios to talk to my Node server, which is making calls to my Heroku database using Massivejs.
Maybe this isn't the way to go - so here's my main problem:
I've ran into troubles because the values I'm planning on using as column names are sent to my server as strings. The exact call that I've been trying to use is
update employees
set $1 = $2
where employee_id = $3;
Once again, I'm passing into those using massive.
I get the error back { error: syntax error at or near "'address'"} because my incoming values are strings. My thought process was that the above statement would allow me to use variables because 'address' is encapsulated by quotes.
But alas, my thought process has failed me.
This seems to be close to answering my question, but I can't seem to figure out what to do in my case if using dynamic SQL.
How to use dynamic column names in an UPDATE or SELECT statement in a function?
Thanks in advance.
I will show you a way to do this by using a function.
First we create the employees table :
CREATE TABLE employees(
id BIGSERIAL PRIMARY KEY,
column1 TEXT,
column2 TEXT
);
Next, we create a function that requires three parameters:
columnName - the name of the column that needs to be updated
columnValue - the new value to which the column needs to be updated
employeeId - the id of the employee that will be updated
By using the format function we generate the update query as a string and use the EXECUTE command to execute the query.
Here is the code of the function.
CREATE OR REPLACE FUNCTION update_columns_on_employee(columnName TEXT, columnValue TEXT, employeeId BIGINT)
RETURNS VOID AS
$$
DECLARE update_statement TEXT := format('UPDATE EMPLOYEES SET %s = ''%s'' WHERE id = %L',columnName, columnValue, employeeId);
BEGIN
EXECUTE update_statement;
end;
$$ LANGUAGE plpgsql;
Now, lets insert some data into the employees table
INSERT INTO employees(column1, column2) VALUES ('column1_start_value','column2_start_value');
So now we currently have an employee with an id value of 1 who has 'column1_start_value' value for the column1, and 'column2_start_value' value for column2.
If we want to update the value of column2 from 'column2_start_value' to 'column2_new_value' all we have to do is execute the following call
SELECT * FROM update_columns_on_employee('column2','column2_new_value',1);

postgresql error when attempting to do a select all from table

I am trying to do the postgresql equivalent of mysql select * from table on a postgresql specific database. I can find the name of the table I need within that database when I do:
SELECT table_name FROM information_schema.tables WHERE table_schema = 'public';
But when I try a select all on the table, I get:
SELECT * from Sample;
SELECT * from Sample;
ERROR: relation "sample" does not exist
LINE 1: SELECT * from Sample;
^
Any ideas?
Postgresql is case sensitive.
I usually use all lower char for field, tables and functions.
Anyway, you can double quote them.
To full answer your question and see why and when useing quote, i suggest to read this specific section:
http://www.postgresql.org/docs/current/interactive/sql-syntax-lexical.html#SQL-SYNTAX-IDENTIFIERS
The manes of the tables are stored in information_schema.tables so you have to see your table by using select * from information_schema.tables. IF your table_schema is "public"
try for a table select select * from public.sample, is your table_schema a differed schema chance it to the right one.
this link will help you Psotgresql doc
I tried single-quoting 'Sample' and it didn't work. Fixed by double-quoting "Sample".

dynamic sql query in postgres

I was attempting to use Dynamic SQL to run some queries in postgres.
Example:
EXECUTE format('SELECT * from result_%s_table', quote_ident((select id from ids where condition = some_condition)))
I have to query a table, which is of the form result_%s_table wherein, I need to substitute the correct table name (an id) from an another table.
I get the error ERROR: prepared statement "format" does not exist
Link: string substitution with query result postgresql
EXECUTE ... USING only works in PL/PgSQL - ie within functions or DO blocks written in the PL/PgSQL language. It does not work in plain SQL; the EXECUTE in plain SQL is completely different, for executing prepared statements. You cannot use dynamic SQL directly in PostgreSQL's SQL dialect.
Compare:
PL/PgSQL's EXECUTE ... USING; to
SQL's EXECUTE
See the 2nd last par in my prior answer.
In addition to not running except in PL/PgSQL your SQL statement is wrong, it won't do what you expect. If (select id from ids where condition = some_condition) returns say 42, the statement would fail if id is an integer. If it's cast to text you'd get:
EXECUTE format('SELECT * from result_%s_table', quote_ident('42'));
EXECUTE format('SELECT * from result_%s_table', '"42"');
EXECUTE 'SELECT * from result_"42"_table';
That's invalid. You actually want result_42_table or "result_42_table". You'd have to write something more like:
EXECUTE format('SELECT * from %s', quote_ident('result_'||(select id from ids where condition = some_condition)||'_table'))
... if you must use quote_ident.
CREATE OR REPLACE FUNCTION public.exec(
text)
RETURNS SETOF RECORD
LANGUAGE 'plpgsql'
AS $BODY$
BEGIN
RETURN QUERY EXECUTE $1 ;
END
$BODY$;
usage:
select * from exec('select now()') as t(dt timestamptz)
Try using
RETURN QUERY EXECUTE '<SQL Command>'
This will return data into form of table. You have to use this into stored function of PostgreSQL.
I have already created on full demonstration on custom filter and custom sorting using dynamic query of PostgreSQL.
Please visit this url:
http://www.dbrnd.com/2015/05/postgresql-dynamic-sql/
These all look more complicated than the OP's question. A different formatting should do the trick.. but it could absolutely the case that I don't understand.
From how I read OP's question, I think others in a similar situation may benefit from how I got it.
I am using Postgre on Redshift, and I ran into this issue and found a solution.
I was trying to create a dynamic query, putting in my own date.
date = dt.date(2018, 10, 30)
query = ''' select * from table where date >= ''' + str(my_date) + ''' order by date '''
But, the query entirely ignores the condition when typing it this way.
However, if you use the percent sign (%), you can insert the date correctly.
One correct way to write the above statement is:
query = ''' select * from table where date >= ''' + ''' '%s' ''' % my_date + ''' order by date '''
So, maybe this is helpful, or maybe it is not. I hope it helps at least one person in my situation!
Best wishes.
EXECUTE will work only on pl/pqsql environment.
instead of EXECUTE try with SELECT
SELECT format('SELECT * from result_%s_table', quote_ident((select id from ids where condition = some_condition))
output would be the dynamic query.