I am using an audio file received through the input type file,
I also create an audio context for this file.
const audio = this.$refs.testAudio; // <audio ref="testAudio" />
this.audioContext = new (window.AudioContext || window.webkitAudioContext) ();
this.srcAudio = this.audioContext.createMediaElementSource (audio);
I need to be able to delete this file and upload a new one.
for this i clear the input, stop the context and disconnect the connections
this.srcAudio.context.close (). then (() => {
this.srcAudio.disconnect ();
this.analyser = null;
this.srcAudio = null;
inputAudio.value = '';
this. $ refs.testAudio.src = null;
});
this.audioContext = null;
But any attempt to use the new file ends with an error:
Blockquote
InvalidStateError: Failed to execute 'createMediaElementSource' on 'AudioContext': HTMLMediaElement already connected previously to a different MediaElementSourceNode. "
Blockquote
help please solve the problem
Related
I am trying to create a Word file and download the created file in clients browser.
The creation part seems to work fine and I can open the file manually from its Folder.
But the downloaded file in browser does not open correctly and produces an error
"The file is corrupt and cannot be opened"
I am using the code from here
Microsoft instructions for downloading a file in Blazor
My code seems like this
private async Task CreateAndDownloadWordFile()
{
var destination = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
var fileName = destination + "\\test12.docx";
//SpreadsheetDocument spreadsheetDocument = SpreadsheetDocument.Create(destination, SpreadsheetDocumentType.Workbook);
using (WordprocessingDocument doc = WordprocessingDocument.Create
(fileName, DocumentFormat.OpenXml.WordprocessingDocumentType.Document))
{
// Add a main document part.
MainDocumentPart mainPart = doc.AddMainDocumentPart();
// Create the document structure and add some text.
mainPart.Document = new Document();
Body body = mainPart.Document.AppendChild(new Body());
Paragraph para = body.AppendChild(new Paragraph());
Run run = para.AppendChild(new Run());
// String msg contains the text, "Hello, Word!"
run.AppendChild(new Text("New text in document"));
}
var fileStream = GetFileStream();
using var streamRef = new DotNetStreamReference(stream: fileStream);
await JS.InvokeVoidAsync("downloadFileFromStream", fileName, streamRef);
}
private Stream GetFileStream()
{
var randomBinaryData = new byte[50 * 1024];
var fileStream = new MemoryStream(randomBinaryData);
return fileStream;
}
And I use this Javascript code
async function downloadFileFromStream(fileName, contentStreamReference) {
const arrayBuffer = await contentStreamReference.arrayBuffer();
const blob = new Blob([arrayBuffer]);
const url = URL.createObjectURL(blob);
triggerFileDownload(fileName, url);
URL.revokeObjectURL(url);
}
function triggerFileDownload(fileName, url) {
const anchorElement = document.createElement('a');
anchorElement.href = url;
anchorElement.download = fileName ?? '';
anchorElement.click();
anchorElement.remove();
}
Any ideas?
But the downloaded file in browser does not open correctly
That is probably because you
First create a Word document
And then download var randomBinaryData = new byte[50 * 1024];
the downloaded file in browser
Check those. Are they exactly 50 * 1024 bytes ?
--
Also, you shouldn't pass the full C:\... path to the download funtion.
var fileStream = File.OpenRead(filename);
using var streamRef = new DotNetStreamReference(stream: fileStream);
//await JS.InvokeVoidAsync("downloadFileFromStream", fileName, streamRef);
await JS.InvokeVoidAsync("downloadFileFromStream", "suggestedName", streamRef);
Where can I find code and instruction on how to allow users to upload files with Google Form without login?
I searched all over here and couldn't find any information.
https://developers.google.com/apps-script/reference
Thanks in advance.
The user will be uploading the files to your drive. So, google needs to verify the user. If there is no verification, someone can fill your drive in no time.
It is for your safety to know who has uploaded, so, login is must.
There's a workaround, I'm in a hurry to write the code now, but if you're interested let me know and I'll edit later.
Basically, you set up a web app with apps script, then you setup a custom HTML form, you'll have to manually collect the file, convert is to base64 then json, then when you catch it in apps script you reverse the process and save it wherever you want in your drive.
Since the user will be executing the script as you, there's no verification required
/*
These functions basically go through a file array and reads the files first as binary string (in second function), then converts the files to base64 string (func 1) before stringifying the files (after putting their base64 content into an object with other metadata attached; mime, name e.t.c);
You pass this stringified object into the body part of fetch(request,{body:"stringified object goes here"})
see next code block for how to read in apps script and save the files to google drive
N.B. The body data will be available under doPost(e){e.postData.contents}
*/
async function bundleFilesForUpload(){
let filesDataObj = [];
let copy = {fileInfo:{"ogname":"","meme":""},fileData:""};
for(let i = 0 ; i < counters.localVar.counters.filesForUploadArr.length ; i++){
let tempObj = JSON.parse(JSON.stringify(copy));
let file = counters.localVar.counters.filesForUploadArr[i];
tempObj.fileInfo.ogname = file.name;
tempObj.fileInfo.meme = file.type;
tempObj.fileData = await readFile(file).then((file)=>{
file = btoa(file);
return file;
}).then((file)=>{
return file;
})
filesDataObj.push(tempObj);
}
return filesDataObj;
}
async function readFile (file){
const toBinaryString = file => new Promise((resolve, reject) => {
const reader = new FileReader();
reader.readAsBinaryString(file);
reader.onload = () => resolve(reader.result);
reader.onerror = error => reject(error);
});
let parsedFile = null;
parsedFile = await toBinaryString(file);
return parsedFile;
}
/*From doPost downward, we read the file Array convert the base64 to blob and make a file in google drive using the blob and metadata we have, you may also see some sheet code, I'm using sheet as db for this */
//in buit function doPost in Code.gs
doPost(e){
const myDataObj = JSON.parse(e.postData.contents);
mainFileFunc(myDataObj.params[0].dataObj.images);
//the actual object structure might look different from yours, console log around
}
function mainFileFunc(fileArr) {
let myArrObj = [{"madeit":"toFileF"}];
let copy = JSON.parse(JSON.stringify(myArrObj[0]));
//sheet.getRange("A1").setValue(JSON.stringify(fileArr.length));
for(let i=0 ; i < fileArr.length ; i++){
myArrObj.push(copy);
let blob = doFileStuff(fileArr[i].data,fileArr[i].info[0].mime,fileArr[i].id);
myArrObj[i] = uploadFileOne(blob,fileArr[i].id);
myArrObj[i].mime = fileArr[i].info[0].mime;
myArrObj[i].realName = fileArr[i].name;
// sheet.getRange("A"+(i+1)).setValue(myArrObj[i].name);
// sheet.getRange("B"+(i+1)).setValue(myArrObj[i].url);
// sheet.getRange("C"+(i+1)).setValue(myArrObj[i].mime);
// sheet.getRange("D"+(i+1)).setValue(myArrObj[i].size);
}
return myArrObj;
}
function doFileStuff(filedata,filetype,filename){
var data = Utilities.base64Decode(filedata, Utilities.Charset.UTF_8);
var blob = Utilities.newBlob(data,filetype,filename);
return blob;
}
function uploadFileOne(data,filename) {
let myObj = {}
myObj["name"] = "";
myObj["realName"] = "Story_Picture";
myObj["url"] = "";
myObj["mime"] = "";
myObj["size"] = "";
myObj["thumb"] = "nonety";
var folders = DriveApp.getFoldersByName("LadhaWeb");
while (folders.hasNext()) {
var folder = folders.next();
folder.createFile(data);
}
var files = DriveApp.getFilesByName(filename);
while (files.hasNext()) {
var file = files.next();
myObj.name = file.getName();
myObj.url = file.getUrl();
myObj.mime = file.getMimeType();
myObj.size = file.getSize();
}
return myObj;
}
You can view the full frontend code for this project here and the backend here.
Hope this helps someone.
The client can preview before uploading but cannot see after uploding as the local language file name.
So I want to rename the filename before upload the image for it can preview before and after uploading.
reference the https://github.com/blueimp/jQuery-File-Upload/wiki/API
How to provide alternative file names:
The name property of File objects is read only, but an alternative name can be provided as uploadName property for each individual file:
$('#fileupload').fileupload({
add: function (e, data) {
var count = data.files.length;
var i;
for (i = 0; i < count; i++) {
data.files[i].uploadName =
Math.floor(Math.random() * 1000) + '_' + data.files[i].name;
}
data.submit();
}
});
When I use above js function the preview is good function when the image add and submit to server immediately~
But when I delete
data.submit();
as I want client to decide if upload or not before uploading.
the preview image function is missing!
and cannot upload any file.
Does any code can rename for the unicode filename (as the local language encoing filename cannot show on the preview function when it uploaded) before submit to the server?
jquery.fileupload.js
....
} else {
$.each(options.files, function (index, file) {
// This check allows the tests to run with
// dummy objects:
if (that._isInstanceOf('File', file) ||
that._isInstanceOf('Blob', file)) {
formData.append(
($.type(options.paramName) === 'array' &&
options.paramName[index]) || paramName,
file,
file.uploadName || file.name
);
}
});
}
}
change the last
file.uploadName || file.name
to
encodeURI(file.uploadName || file.name)
then can see the write decode in the back
fileName = URLDecoder.decode(fileDetail.getFileName(), "UTF-8");
I want to download a file and save it into my app folder. I have to download different files with different formats, but only one each time.
I've read that I have to use HttpUtils, but sample codes are to difficult for me (I'm too noob).
Can anyone upload any sample code?? Thanks!!
This should point you in the right direction:
URL u = new URL(urlString);
HttpURLConnection c = (HttpURLConnection) u.openConnection();
c.setRequestMethod("GET");
c.setDoOutput(true);
c.connect();
File file = new File(outputDirectoryFile, outputFileName);
OutputStream out = new FileOutputStream(file);
InputStream in = c.getInputStream();
byte[] buffer = new byte[4096];
while ( (int len1 = in.read(buffer)) > 0 ) {
out.write(buffer,0, len1);
}
in.close();
out.close();
c.disconnect();
Remember, you should never perform operations like this on the default UI tread. It could prompt the user to force close your app. Read more here:
http://developer.android.com/resources/articles/painless-threading.html
This is how I finally do:
imgurl = "http://dl.dropbox.com/u/25045/file.jpg"
HttpUtils.CallbackActivity = "myactivity" 'Current activity name.
HttpUtils.CallbackJobDoneSub = "JobDone"
HttpUtils.Download("Job1", imgurl)
Dim out As OutputStream
out = File.OpenOutput(File.DirInternal, "file.jpg", True)
File.Copy2(HttpUtils.GetInputStream(imgurl), out)
out.Close
I have spent a couple hours trying to add a simple upload file option to my Zend application. I have double checked all of the necessary permissions and everything works fine. Quite simply, I have it uploading nicely to a temporary folder but once I have it in that temp folder, I can't get it to move to its permanent storage location. Below is the code that keeps failing...
To be precise, the code fails with the $uploaded die statement. I thought it might be an issue since I am sending it to the Model rather than handling it right in the Action but that didn't solve the problem either. Can anyone point me in the right direction? I just can't get the file out of the temprorary directly and into the permenant storage locatoin I want.
Thank you!
//This is the action that is called when form is submitted.
function addImageAction()
{
$imgForm = new Admin_Form_ImageUploadForm();
$imgForm->setAction('/admin/media/add-image');
$imgForm->setMethod('post');
$this->view->form = $imgForm;
if($this->getRequest()->isPost())
{
if(!$imgForm->image->receive())
{
$this->view->message = '<div class="popup-warning">Errors Receiving File.</div>';
$this->_redirect('/admin/media/add-image');
}
if($imgForm->image->isUploaded())
{
$imageModel = new Admin_Model_Image();
$imageId = $imageModel->addImage($imgForm->image->getFileName());
$this->_redirect('/admin/media/view-image/'.$imageId);
}
}
}
Block #2 - The Model
public function addImage($image)
{
// Process the New File
// Check to see if Filename is already in Database
$select = $this->select();
$select->where('filename=?', $image);
$row = $this->fetchRow($select);
if ($row)
{
die("Filename already exists in Database. Please try another file.");
}
// Move file to Storage Directory
// Check/Create Storage Directoy (YYYYMMDD)
// Temporarily set MEDIA_DIR
$mediaDir = APPLICATION_PATH . '/../public/media/uploads/';
$destinationDir = $mediaDir . date('Ymd');
if (!is_dir($destinationDir)){
$storageDir = mkdir($destinationDir);
}
// Save Image
$uploaded = is_uploaded_file($image);
if (!$uploaded) {
die("Image has not been uploaded");
}
$image_saved = move_uploaded_file($image, $destinationDir);
if(!$image_saved)
{
die("Image could not be moved");
}
// Create Alternative Sizes
// Save Data to Database Tables
$dateObject = new Zend_Date();
$row = $this->createRow();
$row->filename = $image;
$row->date_added = $dateObject->get(Zend_Date::TIMESTAMP);
$row->date_modified = $dateObject->get(Zend_Date::TIMESTAMP);
$row->save();
// Fetch the ID of the newly created row
$id = $this->_db->lastInsertId();
// Retrieve IPTC Data
// Retrieve EXIF Data
// Return Image ID
return $id;
}
receive() method moves the file using move_uploaded_file(). So the file you work with is not uploaded anymore, it's normal file. You should use standard copy() function instead.