Google OR-Tools Set Fixed Start Location and Allow Arbitrary End Location - or-tools

For a VRP in or-tools, is there a way to have vehicles start at some fixed locations, but allow for arbitrary end locations?
The documentation https://developers.google.com/optimization/routing/routing_tasks#setting-start-and-end-locations-for-routes and https://developers.google.com/optimization/routing/routing_tasks#allowing-arbitrary-start-and-end-locations show present how to set custom or arbitrary start/end locations respectively.
My question is can we combine them both? i.e. custom start location and arbitrary end location(and vice-versa)?
Thank you

You just need to tweak your distance matrix to have a zero length from any normal node to the end nodes, and ignore this last arc when reading the solution.

Related

breadth-first search in coordinate based system

I am not an experienced programmer (programming language MATLAB) and hence have barely any knowledge of advanced algorithms. One of these is the breadth-first search. The concept I understand but implementing it into my problem is difficult for me.
My problem:
I place disks, of equal sizes, randomly in a square and will place the coordinates of the disks into separate matrices when they are one connected network. I colorized them for clarity (see image). Now, I have to find the shortest path from left to right of the network which spans from left to right and want to do this based on the coordinates. The disks have to touch in order to be connected to each other. They cannot form a path if they are not touching.
So this is what I currently have:
I have a matrix with coordinates x and coordinates y in columns 1 and 2, every row representing one of the disks (for ease, let's just take the coordinates of all the connecting disks, excluding those which are not spanning from left to right when connected).
The diameter of the disks is known (0.2).
We can easily identify which disks are on the left boundary of the square and which disks are on the right boundary of the square. These represent the possible starting coordinates and the possible goal coordinates.
% Coordinates of group of disks, where the group connects from left to right.
0.0159 0.1385
0.0172 0.2194
0.0179 0.4246
0.0231 0.0486
0.0488 0.1392
0.0709 0.2109
0.0813 0.0595
0.0856 0.3530
0.1119 0.3756
0.1275 0.2530
0.1585 0.4751
0.1702 0.2926
0.1908 0.3828
0.1961 0.3277
0.2427 0.4001
0.2492 0.4799
0.2734 0.4788
0.3232 0.3547
0.3399 0.3275
0.3789 0.3716
0.4117 0.3474
0.4579 0.3961
0.4670 0.3394
0.4797 0.3279
0.4853 0.4786
0.3495 0.4455
0.4796 0.2736
0.0693 0.0746
0.1288 0.4204
0.1271 0.4071
0.1218 0.4646
0.1255 0.3080
0.4154 0.2926
Positions of disks and colored the connecting disks. Image is very schematic and many more disks should be expected in a much larger area (keeping same size disks).
My strategy was to set up a breadth-first search, taking the starting coordinates as one of the disks (can be any) on the left side of the square. The goal will be to find the shortest path to the right side of the square.
To my understanding, I want to pick a starting coordinate and check all disks if they are within a diameter distance (middle point to middle point of the disks) of my starting coordinate. If they are within range of my starting coordinate I want to place them in a 'queue' (natively not supported by MATLAB? but let's set one up ourselves). Then, the next step is to take the first disk which was close enough and do the same for this one. I can do this but once I have to do the second disk which was within my first disk, I am lost in how and/or what data structure I should take and how to save the 'path' which it is finding. This means I can find a path but not all paths and hence also not the shortest path.
I appreciate any help! Maybe some documentation which I have not seen yet or maybe an example which is very comparable.
Best regards,
If they are within range of my starting coordinate I want to place
them in a 'queue'
Before you add it to the queue you want to make sure this disk was not processed (put in the queue) before. Each disk should be processed only once, so you make sure the "neighbor" disk has not been processed before, then mark it as processed and add it to the queue.
the next step is to take the first disk which was close enough and do
the same for this one.
Actually the next disc to process is simply the one at the head of the queue.
Continue to do so until you hit the target / stop criteria.
how to save the 'path' which it is finding
There are several techniques to do so. An easy one would be to maintain a "come from" value to each disk. This value points to the "parent" of the disk.
Since each disk is processed once (at most) it will have one "come from" value or none.
When the target is reached the path can be reconstructed starting from the "come from" value of the target.
This question has now been solved!
The way I have solved this was close to what was already suggested in my question but also with help from some of the comments.
The distance between coordinates can be put into a matrix. Let us look at coordinate (disk) 1 and coordinate (disk 3). This means that we will be at elements (1,3) and (3,1). If the disks are within touching distance, these two elements will indicate a 1 and otherwise a 0. This is done for all disks and this creates the adjacency matrix.
I created a 'graph' with the built-in function G = Graph(adjacency matrix) we can create an undirected graph. Then with the built in function [path, distance of path] = shortestpath(G,s,t) where G is the graph and s and t are the starting disks (in this case, indicated by integers), the shortest path can be found from disk s to t.
There is however one thing that we must pay attention to and that is representing the actual distance between disks. If we look at G, we can actually see that it contains two objects. One representing the nodes and the other representing the edges. The edges is crucial for the coordinate based distances as we can set the 'weight' of the edge as the distance between two disks. This can simply be done by looping over the nodes and calculating the distance between the neighbouring nodes and inserting them into the weight (G.Edges.Weight(i) = distance between the respective nodes).
How do I find the optimal path from left to right? I loop over all starting disks (defined as touching the left side of the square) and find the shortest path to all disks that touch the right side of the square. Saving the distances of the paths the actual shortest path can be found.
To give you an example of what can be achieved, the following video shows what paths from every starting disk can be found and the final frame shows the shortest path. Video of path finding. The shortest path I have also attached here:
Shortest path left to right.
If there are any questions you would like to ask me about specifics, let me know.

Matlab - Flag points using nearest neighbour search

I have the following problem and I am a bit clueless how to tackle it as my programming skills are very elementary ( I am an engineer, so please dont bite my head off).
Problem
I have a point cloud, the picture above displaying one level off it. Every point is a centroid off a block (x =5, y=1, z=5) and is specefied by carteisian coordinates.
The centroids further have two values: one called "access" and one "product". If the product value is positive and pays for the access to the point I want to include it in my outcome. The red marker in the picture represents a possible starting point.
Starting Idea
As a start I am trying to set up an algorithm, that starts at the red marker, runs through the blocks left and right (along the x-axis), checks until where it would be feasible to access (so sum "product" > sum "access") and then goes to the next point (in y direction from marker) and does the same until the end of the level.
Final Goal
My final goal is that I can Flag points as accessed and the algorithm connects profitable "products" (so products that would pay for their access) on the shortest way to the access point (by setting blocks/points on the way to accessed).
I know this is a very open question and I apologize for that. I am just lacking a good starting point programming wise. I was thinking of knnsearch, but I am not sure if this is the right way to go as the blocks have different sizes and i technically want the nearest neighbour in every direction but also only one per direction.
Another idea I had was using shortestpath or creating a travel salesman problem out of it, but I am not sure how to properly implement it.
If you have any ideas or you could offer any help I would very much appreciate it. If any more information is needed I gladly provide it.

How does routing services for OSM determine the distance between two points

I am going to design an Android application and I will be needing the distances of the pathways inside our university(pathways between buildings)
I read about OSM(OpenStreetMap) and tried it. It is a map which is editable which means anyone can contribute to that map(like a wikipedia map version).
It has many routing services that give routes and directions between two point(start and end).
There is a routing service named GraphHopper and it is very easy to use. I can just drag and drop the start and end pt and it gives the distance(km) between the two pts.
What I want to know is how did they come up with the distance?
Is the distance reliable and accurate?
Any help is greatly appreciated because I want to use the distances for my Android app and I need to know if these distances have basis.
The distance is 'accurate' in the sense that it correctly processes the existing information from OpenStreetMap and correctly adds road segments for the final route. You can just try for your local area and compare to your own knowledge.
There could be mapping errors, where a road is incorrectly mapped. And there could be also roads missing and so the router uses a detour making the path unnecessarily longer. Also there are different modes like for cars or bikes or fastest and shortest where you get a different distance between two coordinates.

How do I optimize point-to-circle matching?

I have a table that contains a bunch of Earth coordinates (latitude/longitude) and associated radii. I also have a table containing a bunch of points that I want to match with those circles, and vice versa. Both are dynamic; that is, a new circle or a new point can be added or deleted at any time. When either is added, I want to be able to match the new circle or point with all applicable points or circles, respectively.
I currently have a PostgreSQL module containing a C function to find the distance between two points on earth given their coordinates, and it seems to work. The problem is scalability. In order for it to do its thing, the function currently has to scan the whole table and do some trigonometric calculations against each row. Both tables are indexed by latitude and longitude, but the function can't use them. It has to do its thing before we know whether the two things match. New information may be posted as often as several times a second, and checking every point every time is starting to become quite unwieldy.
I've looked at PostgreSQL's geometric types, but they seem more suited to rectangular coordinates than to points on a sphere.
How can I arrange/optimize/filter/precalculate this data to make the matching faster and lighten the load?
You haven't mentioned PostGIS - why have you ruled that out as a possibility?
http://postgis.refractions.net/documentation/manual-2.0/PostGIS_Special_Functions_Index.html#PostGIS_GeographyFunctions
Thinking out loud a bit here... you have a point (lat/long) and a radius, and you want to find all extisting point-radii combinations that may overlap? (or some thing like that...)
Seems you might be able to store a few more bits of information Along with those numbers that could help you rule out others that are nowhere close during your query... This might avoid a lot of trig operations.
Example, with point x,y and radius r, you could easily calculate a range a feasible lat/long (squarish area) that could be used to help rule it out if needless calculations against another point.
You could then store the max and min lat and long along with that point in the database. Then, before running your trig on every row, you could Filter your results to eliminate points obviously out of bounds.
If I undestand you correctly then my first idea would be to cache some data and eliminate most of the checking.
Like imagine your circle is actually a box and it has 4 sides
you could store the base coordinates of those lines much like you have lines (a mesh) on a real map. So you store east, west, north, south edge of each circle
If you get your coordinate and its outside of that box you can be sure it won't be inside the circle either since the box is bigger than the circle.
If it isn't then you have to check like you do now. But I guess you can eliminate most of the steps already.

Calculate nearest point of KML polygon for iPhone app

I have a series of nature reserves that need to be plotted, as polygon overlays, on a map using the coordinates contained within KML data. I’ve found a tutorial on the Apple website for displaying KML overlays on map instances.
The problem is that the reserves vary in size greatly - from a small pond right up to several hundred kilometers in size. As a result I can’t use the coordinates of the center point to find the nearest reserves. Instead I need to calculate the nearest point of the reserves polygon to find the nearest one. With the data in KML - how would I go about trying to achieve this?
I've only managed to find one other person ask this and no one had replied :(
Well, there are a couple different solutions depending on your needs. The higher the accuracy required, the more work required. I like Phil's meanRadius parameter idea. That would give you a rough idea of which polygon is closest and would be pretty easy to calculate. This idea works best if the polygons are "circlish". If the polygon are very irregular in shape, this idea loses it's accuracy.
From a math standpoint, here is what you want to do. Loop through all points of all polygons. Calculate the distance from those points to your current coordinate. Then just keep track of which one is closest. There is one final wrinkle. Imagine a two points making a line segment that is very long. You are located one meter away from the midpoint of the line. Well, the distance to these two points is very large, while, in fact you are very close to the polygon. You will need to calculate the distance from your coordinate to every possible line segment which you can do in a variety of manners which are outlined here:
http://www.worsleyschool.net/science/files/linepoint/distance.html
Finally, you need to ask yourself, am I in any polygons? If you're 10 meters away from a point on a polygon, but are, in fact, inside the polygon, obviously, you need to consider that. The best way to do that is to use a ray casting algorithm:
http://en.wikipedia.org/wiki/Point_in_polygon#Ray_casting_algorithm