Powershell - "Copy-item" command in scriptblock of Invoke-Command - powershell

Question

I need to copy file from one remote server to other using powershell script.
What I have tried :-
While i use following powershell commands it's work fine.(means file copied from one server to other)
But while i use following script it gives error "cannot find path..." as follows
Actually, file is exist at that path.
I have tried to refer following stack-overflow already question-answer
Error with PowerShell command for copying file to remote server with credential
'Session' Parameter is null or empty in PowerShell script
powershell remote
Invoke-Command with remote session: Cannot validate argument on parameter
Unable to copy a binary to a remote Azure VM
PowerShell Command to Copy File on Remote Machine
I have also tried to get help using
Get-Help Invoke-Command
Question :-
How can i use "Copy-Item" command inside "Invoke-Command(Scriptblock)" in script(2) to copy file?
Is there any better way to achieve this(means best practice)?

Answer 1

Invoke-Command has the parameter -ArgumentList wich can be used to supply the values of local variables in the remote session. The Problem is: it's just the VALUE of the variable. No file!
What you can do:
Use Get-Content -Raw on small files to save the contant in a variable. On the target system create a New-Item with the -Value of that file. However thats not very efficent.
Example:
$txt = Get-Content -Raw -Path "C:\test\oldFile.txt"
$Session = New-PSSession 127.0.0.1
Invoke-Command -Session $Session -ScriptBlock { Param($Txt) New-Item -Path c:\test\newFile.txt -Value $txt } -ArgumentList $txt
#Get-PSSession | Remove-PSSession
Result:
Verzeichnis: C:\test # Sry german OS
Mode LastWriteTime Length Name PSComputerName
---- ------------- ------ ---- --------------
-a---- 03.09.2020 12:23 658033 newFile.txt 127.0.0.1
What you should do:
I think your use of Copy-Item -ToSession $Session is the right way to do it. It's litteraly made just for your purpose. The downside is, that the target directory needs to exist. But you need a PSSession for both cmdlets anyway. So you can use Invoke-Command with the same PSSession. First Create a PSSession. Use Invoke-Command to create you directory. Then use Copy-Item to move your file to the right place. Finally you can use Invoke-Command to do some finishing steps. And don't forget to Remove-PSSession when you are done:
$DestinationPath = "C:\test"
Invoke-Command -Session $Session -ScriptBlock { Param($Destination) New-Item -Path $Destination -ItemType Directory } -ArgumentList $DestinationPath
Copy-Item -Path "C:\test\oldFile.txt" -ToSession $Session -Destination "c:\test\newFile.txt"
Invoke-Command -Session $Session -ScriptBlock { write-host "Do some stuff" }
$Session | Remove-PSSession