Access resources inside library - scala

Question

I have a project L which is published as a library.
Inside L, there is a resources folder and a snippet of code that access the content.
I created a second module in L to add a main as a test, and it works.
Now when I include L into my other project, it doesnt find the folder located inside the resources of L.
in all the below path is equal to folder_i_am_looking_for and I generate varieties with /$path, $path/, $path and /$path/. ( I am desperate at this point )
I tried:
getClass.getClassLoader.getResource(path).getPath,
getClass.getClassLoader.getResource(path).toExternalForm,
getClass.getResource(path).getPath,
getClass.getResource(path).toExternalForm,
as well as
val location: URL = this.getClass.getProtectionDomain.getCodeSource.getLocation
Paths
.get(location.toURI)
.resolve("../classes/" + path)
.normalize()
.toFile
.getAbsoluteFile
.toString
from https://stackoverflow.com/a/54142960
and for each generated path, I've tried to :
input ::
input.split('!').last ::
input.split("file:/").last ::
input.split("file:").last ::
Nil
from https://stackoverflow.com/a/5346020
each time , i get path that looks like :
/path/to/projectFolder/jar:file:/path/to/library/lib_2.11-version.jar!/folder
I let you imagine all the variety of different path I get with all the above operations.
None of them find the directory.
I am testing all path simultaneously with ZIO.validateFirstPar so if you have any idea, I can add more to test.
Thank you.