I have a document model that contains an array of user objects. What I want to do is return the document if that array contains an object with a specific user _id. Is this possible?
Something like
{
_id: 1
name: 'Document with Array of User Ids'
arrayOfUsers: [
{
name: 'John Doe',
_id: 2
},
{
name: 'Michael Scott',
_id: 3
}
]
}
And then returning all documents that have an _id of 3 in arrayOfUsers
Thanks!
You can use dot notation like so:
https://mongoplayground.net/p/iu0f68D1vbL
Model.find({
"arrayOfUsers._id": 2
})
https://docs.mongodb.com/manual/tutorial/query-embedded-documents/#query-on-nested-field
Related
From mongodb collection I want to get only one property like if I had a array of object structure
[
{
_id: 'property1',
name: 'property1',
value: 1
},
{
_id: 'property2',
name: 'property2',
value: 2
}
]
So here I don't want to get whole collection, instead I only just need name from all the documents in the collection
I have the following schema:
var lessonSchema = mongoose.Schema({
_id: mongoose.Schema.Types.ObjectId,
name: String,
students: [{
_id: mongoose.Schema.Types.ObjectId,
attendance: {
type: Boolean,
default: false,
},
}],
});
The students array is an array of students who attended the particular lesson. I want to find a lesson using whether a particular user is present in the students array and then sent only that element of the students array which corresponds to the user making the request, along with all other fields as it is. For example, the query should return:
{
_id: 'objectid',
name: 'lesson-name'
students: [details of just the one student corresponding to req.user._id]
}
I tried using:
Lesson.find({'students._id': String(req.user._id)}, {"students.$": 1})
The query returns the document with just the id and the relevant element from the students array:
{
_id: 'objectid'
students: [details of the one student corresponding to req.user._id]
}
I tried using:
Lesson.find({'students._id': mongoose.Types.ObjectId(req.user._id)})
This returns the document with the details of all the students:
{
_id: 'objectid',
name: 'lesson-name'
students: [array containing details of all the students who attended the lesson]
}
How can I modify the query to return it the way I want?
You can return the name field by adding it to the projection object like this:
Lesson.find({ "students._id": String(req.user._id) }, { "name": 1, "students.$": 1 })
When you add a projection object (2nd parameter to find), the _id field is returned by default, plus whichever fields you set to 1.
Therefore, you were returning just the _id and the desired student but not the name field.
If you want to return all other fields and just limit the array to the matched item then you can make use of $slice in your projection:
Lesson.find({ "students._id": String(req.user._id) }, { "students.$": { $slice: 1 } })
I have the following schema:
{
_id: objectID('593f8c591aa95154cfebe612'),
name: 'test'
businesses: [
{
_id: objectID('5967bd5f1aa9515fd9cdc87f'),
likes: [objectID('595796811aa9514c862033a1'), objectID('593f8c591ba95154cfebe790')]
}
{
_id: objectID('59579ff91aa9514f600cbba6'),
likes: [objectID('693f8c554aa95154cfebe146'), objectID('193f8c591ba95154cfeber790')]
}
]
}
I need to update "businesses.likes" where businesses._id equal to a center value and where businesses.likes contains certain objectID.
If the objectID exists in the array, I want to remove it.
This is what I have tried and didn't work correctly, because $in is searching in all the subdocuments, instead of the only subdocument where businesses._id = with my value:
db.col.update(
{ businesses._id: objectID('5967bd5f1aa9515fd9cdc87f'), 'businesses.likes': {$in: [objectID('193f8c591ba95154cfeber790')]}},
{$pull: {'businesses.$.likes': objectID('193f8c591ba95154cfeber790')}}
)
Any ideas how how I can write the query? Keep in mind that businesses.likes from different businesses can have the same objectID's.
Suppose, I have the following database:
{
_id: 1,
name: 'Alice',
courses: [
{
_id: 'DB103',
credits: 6
},
{
_id: 'ML203',
credits: 4
}
]
},
{
_id: 2,
name: 'Bob',
courses: []
}
I now want to 'upsert' the document with the course id 'DB103' in both documents. Although the _id field should remain the same, the credits field value should change (i.e. to 4). In the first document, the respective field should be changed, in the second one, {_id: 'DB103', credits: 4} should be inserted into the courses array.
Is there any possibility in MongoDB to handle both cases?
Sure, I could search with $elemMatch in courses for 'DB103' and if I haven't found it, insert, otherwise update the value. But these are two steps and I would like to do both in just one.
I'm a new user of mongodb and I have a model like below. For update list data, I have to specify the element in an array. So I think I need to store a unique value for each element. Because list.name and list.price are variable data.
So are there any good ways to create an unique id in mongodb? Or should I create unique ids by myself?
{
name: 'AAA',
list: [
{name: 'HOGE', price: 10, id: 'XXXXXXXXXX'}, // way to add id
{name: 'FUGA', price: 12, id: 'YYYYYYYYYY'} // way to add id
]
}
Mongodb creates unique id only for documents. There is no better way for list or array elements. So, you should create Unique ids yourself.
Add keep in mind that, While updating your list use $addToSet.
For more information of $addToSet follow this documentation
use ObjectId() on your id field, so like..
db.test.update({name: "AAA"}, { $push: { list: {_id : ObjectId(), name: "dingles", price: 21} }});
reference: https://docs.mongodb.org/v3.0/reference/object-id/
whoever is seeing this in 2022, mongodb creates unique ids automatically we just have to provide schema for that particular array.
like,
_id : {
type: String
},
list: {
type: [{
Name : {
type: String
},
price : {
type: String
}
}]
}
this schema will generate auto id for all elements added into array
but below example will not create it.
_id : {
type: String
},
list: {
type: Array
}