Sort Dictionary [Key: [Key: Value]] by value - Swift - swift

Question

I have a dictonary that looks like this:
var dict = [Int: [String: Any]]()
dict[1] = ["nausea": 23, "other": "hhh"]
dict[2] = ["nausea": 3, "other": "kkk"]
dict[3] = ["nausea": 33, "other" : "yyy"]
I want to sort the dictionary by the value of the dictionary value for key "nausea" from least to greatest.
To look like this:
sortedDict = [2: ["nausea": 3, "other": "kkk"], 1: ["nausea": 23, "other": "hhh"], 3: ["nausea": 33, "other" : "yyy"]]
I tried to play around with it using .sort():
let sortedDict = dict.sort( { ($0["nausea"] as! Int) > ($1["nausea"] as! Int) })
but, obviously It didn't work because "nausea" isn't the key for the dictonary
Can someone show me how they would do this?
Thanks in advance!

Answer 1

A Dictionary is unordered by design, as the documentation clearly states:
Every dictionary is an unordered collection of key-value pairs.
You are probably looking for an ordered type like Array.
var arrayDict = [
["nausea": 23, "other": "hhh"],
["nausea": 3, "other": "kkk"],
["nausea": 33, "other" : "yyy"]
]
let sorted = arrayDict.sorted { $0["nausea"] as! Int < $1["nausea"] as! Int }
print(sorted)
Update: Even better as #LeoDabus suggested in the comment you can use an array of custom objects:
struct MyObject {
var nausea: Int
var other: String
}
var array = [
MyObject(nausea: 23, other: "hhh"),
MyObject(nausea: 3, other: "kkk"),
MyObject(nausea: 33, other: "yyy")
]
let sorted = array.sorted { $0.nausea < $1.nausea }
print(sorted)