How to combine two objects in a List by summing a member - scala

Question

Given this case class:
case class Categories(fruit: String, amount: Double, mappedTo: String)
I have a list containing the following:
List(
Categories("Others",22.38394964594807,"Others"),
Categories("Others",77.6160503540519,"Others")
)
I want to combine two elements in the list by summing up their amount if they are in the same category, so that the end result in this case would be:
List(Categories("Others",99.99999999999997,"Others"))
How can I do that?

Answer 1

Since groupMapReduce was introduced in Scala 2.13, I'll try to provide another approch to Martinjn's great answer.
Assuming we have:
case class Categories(Fruit: String, amount: Double, mappedTo: String)
val categories = List(
Categories("Apple",22.38394964594807,"Others"),
Categories("Apple",77.6160503540519,"Others")
)
If you want to aggregate by both mappedTo and Fruit
val result = categories.groupBy(c => (c.Fruit, c.mappedTo)).map {
case ((fruit, mappedTo), categories) => Categories(fruit, categories.map(_.amount).sum, mappedTo)
}
Code run can be found at Scastie.
If you want to aggregate only by mappedTo, and choose a random Fruit, you can do:
val result = categories.groupBy(c => c.mappedTo).map {
case (mappedTo, categories) => Categories(categories.head.Fruit, categories.map(_.amount).sum, mappedTo)
}
Code run can be found at Scastie

Answer 2

You want to group your list entries by category, and reduce them to a single value. There is groupMapReduce for that, which groups entries, and then maps the group (you don't need this) and reduces the group to a single value.
given
case class Category(category: String, amount: Double)
if you have a val myList: List[Category], then you want to group on Category#category, and reduce them by merging the members, summing up the amount.
that gives
myList.groupMapReduce(_.category) //group
(identity) //map. We don't need to map, so we use the identity mapping
{
case (Category(name, amount1), Category(_, amount2)) =>
Category(name, amount1 + amount2) }
} //reduce, combine each elements by taking the name, and summing the amojunts
In theory just a groupReduce would have been enough, but that doesn't exist, so we're stuck with the identity here.