How to make AOSP Module with Specified JDK Version? - android-source

As when I do complete compile ,some modules use jdk1.9 , some use jdk1.8(because the date 0 bug, it can not compile with jdk1.9).
So how can I specify the special JDK when complete compile for some special modules? how to config the special jdk version in Android.mk?

For AOSP 10: it is LOCAL_JAVA_LANGUAGE_VERSION in Android.mk.
Since:
build\soong\androidmk\cmd\androidmk\android.go:
"LOCAL_JAVA_LANGUAGE_VERSION": "java_version",
build\soong\java\java.go:
func (j *Library) GenerateAndroidBuildActions(ctx android.ModuleContext)
calls
func (j *Module) compile(ctx android.ModuleContext, extraSrcJars ...android.Path)
calls
func (j *Module) collectBuilderFlags(ctx android.ModuleContext, deps deps) javaBuilderFlags
calls
func (j *Module) collectBuilderFlags(ctx android.ModuleContext, deps deps) javaBuilderFlags
calls
func getJavaVersion(ctx android.ModuleContext, javaVersion string, sdkContext sdkContext) string
Based on getJavaVersion's source code, if the parameter "javaVersion " is empty (guess when LOCAL_JAVA_LANGUAGE_VERSION is not set), it will return version based on Android version etc, if "javaVersion" is not empty then it is returned and put into the java build command line by its caller collectBuilderFlags.
In collectBuilderFlags, that parameter comes from j.properties.Java_version which should comes from "LOCAL_JAVA_LANGUAGE_VERSION" due to the above information from android.go.
Also per the source code of collectBuilderFlags, you can only use LOCAL_JAVA_LANGUAGE_VERSION to set the "-source" and "-target" parameter of javac. Every javac command invocation in AOSP10 is the javac from JDK9, i.e. prebuilts/jdk/jdk9/linux-x86/bin/javac

Related

How to differentiate between a script and normal class files in Scala?

In the book, Programming in Scala 5th Edition, the author says the following for two classes:
Neither ChecksumAccumulator.scala nor Summer.scala are scripts, because they end in a definition. A script, by contrast, must end in a result expression.
The ChecksumAccumulator.scala is as follows:
import scala.collection.mutable
class CheckSumAccumulator:
private var sum = 0
def add(b: Byte): Unit = sum += b
def checksum(): Int = ~(sum & 0XFF) + 1
object CheckSumAccumulator:
private val cache = mutable.Map.empty[String, Int]
def calculate(s: String): Int =
if cache.contains(s) then
cache(s)
else
val acc = new CheckSumAccumulator
for c<-s do
acc.add((c >> 8).toByte)
acc.add(c.toByte)
val cs = acc.checksum()
cache += (s -> cs)
cs
whereas the Summer.scala is as follows:
import CheckSumAccumulator.calculate
object Summer:
def main(args: Array[String]): Unit =
for arg <- args do
println(arg + ": " + calculate(arg))
But when I run the Summer.scala file, I get a different error than what mentioned by the author:
➜ learning-scala git:(main) ./scala3-3.0.0-RC3/bin/scala Summer.scala
-- [E006] Not Found Error: /Users/avirals/dev/learning-scala/Summer.scala:1:7 --
1 |import CheckSumAccumulator.calculate
| ^^^^^^^^^^^^^^^^^^^
| Not found: CheckSumAccumulator
longer explanation available when compiling with `-explain`
1 error found
Error: Errors encountered during compilation
➜ learning-scala git:(main)
The author mentioned that the error would be around not having a result expression.
I also tried to compile CheckSumAccumulator only and then run Summer.scala as a script without compiling it:
➜ learning-scala git:(main) ./scala3-3.0.0-RC3/bin/scalac CheckSumAccumulator.scala
➜ learning-scala git:(main) ✗ ./scala3-3.0.0-RC3/bin/scala Summer.scala
<No output, given no input>
➜ learning-scala git:(main) ✗ ./scala3-3.0.0-RC3/bin/scala Summer.scala Summer of love
Summer: -121
of: -213
love: -182
It works.
Obviously, when I compile both, and then run Summer.scala, it works as expected. However, the differentiation of Summer.scala as a script vs normal file is unclear to me.
Let's start top-down...
The most regular way to compile Scala is to use a build tool like SBT/Maven/Mill/Gradle/etc. This build tool will help with a few things: downloading dependencies/libraries, downloading Scala compiler (optional), setting up CLASS_PATH and most importantly running scalac compiler and passing all flags to it. Additionally it can package compiled class files into JARs and other formats and do much more. Most relevant part is CP and compilation flags.
If you strip off the build tool you can compile your project by manually invoking scalac with all required arguments and making sure your working directory matches package structure, i.e. you are in the right directory. This can be tedious because you need to download all libraries manually and make sure they are on the class path.
So far build tool and manual compiler invocation are very similar to what you can also do in Java.
If you want to have an ah-hoc way of running some Scala code there are 2 options. scala let's you run scripts or REPL by simply compiling your uncompiled code before it executes it.
However, there are some caveats. Essentially REPL and shell scripts are the same - Scala wraps your code in some anonymous object and then runs it. This way you can write any expression without having to follow convention of using main function or App trait (which provides main). It will compile the script you are trying to run but will have no idea about imported classes. You can either compile them beforehand or make a large script that contains all code. Of course if it starts getting too large it's time to make a proper project.
So in a sense there is no such thing as script vs normal file because they both contain Scala code. The file you are running with scala is a script if it's an uncompiled code XXX.scala and "normal" compiled class XXX.class otherwise. If you ignore object wrapping I've mentioned above the rest is the same just different steps to compile and run them.
Here is the traditional 2.xxx scala runner code snippet with all possible options:
def runTarget(): Option[Throwable] = howToRun match {
case AsObject =>
ObjectRunner.runAndCatch(settings.classpathURLs, thingToRun, command.arguments)
case AsScript if isE =>
ScriptRunner(settings).runScriptText(combinedCode, thingToRun +: command.arguments)
case AsScript =>
ScriptRunner(settings).runScript(thingToRun, command.arguments)
case AsJar =>
JarRunner.runJar(settings, thingToRun, command.arguments)
case Error =>
None
case _ =>
// We start the repl when no arguments are given.
if (settings.Wconf.isDefault && settings.lint.isDefault) {
// If user is agnostic about -Wconf and -Xlint, enable -deprecation and -feature
settings.deprecation.value = true
settings.feature.value = true
}
val config = ShellConfig(settings)
new ILoop(config).run(settings)
None
}
This is what's getting invoked when you run scala.
In Dotty/Scala3 the idea is similar but split into multiple classes and classpath logic might be different: REPL, Script runner. Script runner invokes repl.

Rust `unresolved import` on third party library

I want to compile a simple rust program using a third party library named warp:
[package]
name = "hello-world-warp"
version = "0.1.0"
[dependencies]
warp = "0.1.18"
In src/main.rs:
use warp::{self, path, Filter};
fn main() {
// GET /hello/warp => 200 OK with body "Hello, warp!"
let hello = warp::path!("hello" / String)
.map(|name| format!("Hello, {}!", name));
warp::serve(hello)
.run(([127, 0, 0, 1], 3030));
}
When I run cargo build I see it download warp and lots of transitive dependencies, then I get the errors:
Compiling hello-world-warp v0.1.0 (<path>) error[E0432]: unresolved import `warp`
--> src/main.rs:3:12
|
3 | use warp::{self, path, Filter};
| ^^^^ no `warp` in the root
error: cannot find macro `path!` in this scope
I've gone through various docs on modules and crates. What am I doing wrong in this simple scenario?
The example you copied uses a syntax that works in the most recent edition of Rust, but you've accidentally set your Rust to emulate an old "2015" version of the language.
You must add:
edition = "2018"
to your Cargo.toml's [package] section.
When starting new projects, always use cargo new. It will ensure the latest edition flag is set correctly.

Failing to compile MonoGame on Boo compiler

SharpDevelop compiles fine, but trying to compile through booc doesn't work.
Boo Compiler version 0.9.4.9 (CLR 2.0.50727.8000)
Program.boo(4,8): BCE0021: Namespace 'Microsoft.Xna.Framework' not found, maybe
you forgot to add an assembly reference?
booc -resource:"C:\test\" Program.boo , the command used in Windows cmd tool.
Thank you. Alisa.
Sharpdevelop most likely already references the libraries to the compiler for you. What that means is, when you manually invoke the booc command line compiler, you will have to tell the compiler where exactly the MonoGame library is. I haven't been able to check myself yet, but I did have a quick look at the command lines and the Boo source code, and I think you have to do the following:
-lib:C:/Path/To/MonoGame/Libraries
This will tell the compiler where to look for additional libraries.
The next thing you should then do is add the libraries you want, eg:
-r:Microsoft.Xna.Framework.dll,Microsoft.Xna.Framework.Game.dll
Add these two additional compiler options to your command line and I think it should work.
I haven't compiled this myself really, because I found it rather tedious. Instead, I decided to create my own build script in Boo itself in order to compile my Boo programs. That way I still had to add the library path and reference the libraries, as in the following snippet:
def CompileEngine() as bool:
"""Compiles the engine and puts it in ./lib/SpectralEngine.dll"""
compiler = BooCompiler()
compiler.Parameters.Pipeline = CompileToFile()
compiler.Parameters.OutputType = CompilerOutputType.Library
compiler.Parameters.Ducky = true
compiler.Parameters.LibPaths.Add("./lib")
compiler.Parameters.OutputAssembly = "./lib/SpectralEngine.dll"
# Add libraries.
compiler.Parameters.References.Add(compiler.Parameters.LoadAssembly("OpenTK.dll"))
compiler.Parameters.References.Add(compiler.Parameters.LoadAssembly("NAudio.dll"))
compiler.Parameters.References.Add(compiler.Parameters.LoadAssembly("Boo.Lang.dll"))
compiler.Parameters.References.Add(compiler.Parameters.LoadAssembly("Boo.Lang.Parser.dll"))
compiler.Parameters.References.Add(compiler.Parameters.LoadAssembly("Boo.Lang.Compiler.dll"))
# Take all boo files from the Engine source directory.
files = (Directory.GetFiles(Directory.GetCurrentDirectory() + """/src/Engine""", "*.boo", SearchOption.AllDirectories)
.Where({file as string | return not file.Contains("Gwen")})) # Filter out old GWEN files.
for file in files:
print "Adding file: " + file
compiler.Parameters.Input.Add(FileInput(file))
print "Compiling to ./lib/SpectralEngine.dll"
context = compiler.Run()
if context.GeneratedAssembly is null:
print "Failed to compile:\n" + join(e for e in context.Errors, "\n")
return false
else:
return true
I've put two of these build scripts at here and here. It's perhaps a bit overkill for you, though.

How to execute Scala script from Gradle?

I have a Scala script that looks something like:
#!/bin/sh
PATH=${SCALA_HOME}:${PATH}
exec scala "$0" "$#"
!#
Console.println("Hello, world!")
Is there some way in Gradle to set the version of Scala to be used, have it implicitly set SCALA_HOME, and execute the script?
There is no built-in feature for this. The way to tackle this is to declare two tasks: A Copy task that downloads the Scala distribution and unpacks it to a local directory, and an Exec task that sets the SCALA_HOME environment variable to the copy task's output directory and executes your script.
Here is an example of executing Scala from Gradle. It is a nascent attempt to build a plugin using Scalafmt. Of note is how nasty it is to use static values.
buildscript {
repositories {
mavenCentral()
}
dependencies {
classpath 'com.geirsson:scalafmt-core_2.11:0.4.2'
}
}
task scalafmt << {
String target = "object FormatMe { List(Split(Space, 0).withPolicy(SingleLineBlock(close)), Split(Newline, 1).withPolicy{ case Decision(t#FormatToken(_, `close`, _), s) => Decision(t, List(Split(Newline, 0)))}.withIndent(2, close, Right)) }"
def config = org.scalafmt.config.ScalafmtConfig$.MODULE$.default
def range = scala.collection.immutable.Set$EmptySet$.MODULE$
println org.scalafmt.Scalafmt.format(target, config, range).formattedCode()
}
I know this is not quite on topic but I couldn't find anywhere else to put this and I hope it is of some value to people who ended up here for the same reason I did.
Gradle has an Exec task in which you can set the environment to be passed to the new process. You could pass SCALA_HOME through that.

How to start a Scala method from command line?

This question may sound a bit stupid, but I couldn't figure out, how to start a Scala method from the command line.
I compiled the following file Test.scala :
package example
object Test {
def print() {
println("Hello World")
}
}
with scalac Test.scala.
Then, I can run the method print with scala in two steps:
C:\Users\John\Scala\Examples>scala
Welcome to Scala version 2.9.2 (Java HotSpot(TM) Client VM, Java 1.6.0_32).
Type in expressions to have them evaluated.
Type :help for more information.
scala> example.Test.print
Hello World
But what I really like to do is, to run the method directly from the command line with one command like scala example.Test.print.
How can I achieve this goal ?
UPDATE:
Suggested solution by ArikG does not work for me - What I am missing ?
C:\Users\John\Scala\Examples>scala -e 'example.Test.print'
C:\Users\John\AppData\Local\Temp\scalacmd1874056752498579477.scala:1: error: u
nclosed character literal
'example.Test.print'
^
one error found
C:\Users\John\Scala\Examples>scala -e "example.Test.print"
C:\Users\John\AppData\Local\Temp\scalacmd1889443681948722298.scala:1: error: o
bject Test in package example cannot be accessed in package example
example.Test.print
^
one error found
where
C:\Users\John\Scala\Examples>dir example
Volume in drive C has no label.
Volume Serial Number is 4C49-8C7F
Directory of C:\Users\John\Scala\Examples\example
14.08.2012 12:14 <DIR> .
14.08.2012 12:14 <DIR> ..
14.08.2012 12:14 493 Test$.class
14.08.2012 12:14 530 Test.class
2 File(s) 1.023 bytes
2 Dir(s) 107.935.760.384 bytes free
UPDATE 2 - Possible SOLUTIONs:
As ArikG correctly suggested, with scala -e "import example.Test._; print" works well with Windows 7.
See answer of Daniel to get it work without the import statement
Let me expand on this solution a bit:
scala -e 'example.Test.print'
Instead, try:
scala -cp path-to-the-target-directory -e 'example.Test.print'
Where the target directory is the directory where scala used as destination for whatever it compiled. In your example, it is not C:\Users\John\Scala\Examples\example, but C:\Users\John\Scala\Examples. The directory example is where Scala will look for classes belonging to the package example.
This is why things did not work: it expected to find the package example under a directory example, but there were no such directory under the current directory in which you ran scala, and the classfiles that were present on the current directory were expected to be on the default package.
The best way to do this is to extend App which is a slightly special class (or at least DelayedInit which underlies it is):
package example
object Test extends App {
println("Hello World")
}
It's still possible to add methods to this as well, the body of the object is executed on startup.
Here you go:
scala -e 'example.Test.print'