I have made a flutter chat app, using Firebase.
I am listening to the messages using a stream builder. Another feature of my chat app is, when the user long presses his chat message, the message gets deleted.
I want to show a pop animation of the deleted message because right now message gets deletes abruptly.
You can use a show dialog for this.
void _showDialog() {
// flutter defined function
showDialog(
context: context,
builder: (BuildContext context) {
// return object of type Dialog
return AlertDialog(
content: new Text("Are you sure you want to delete?"),
actions: <Widget>[
// usually buttons at the bottom of the dialog
FlatButton(
child: new Text("Delete"),
onPressed: () {
// Your deleteMessage method!
},
),
FlatButton(
child: new Text("Close"),
onPressed: () {
Navigator.of(context).pop();
},
),
],
);
},
);
}
You can read more from the official document.
the thing that you need is animated widget i don't know what kind of animation you need or how you going to use it but the best way to make it is watch or read the animated widget from flutter official doc
Related
What to put inside onPressed to call another page, for example I want to call class_one() after I press the button, what is the solution for it?
Padding(
padding: const EdgeInsets.all(8.0),
child: ElevatedButton(
onPressed: () {
// Respond to button press
},
child: Text('Kehadiran Anggota'),
)),
You can use the pushNamed function like this:
Navigator.of(context).pushNamed('/yourScreen');
In order for it to work you need to register the route inside MaterialApp like this:
MaterialApp(routes: {
'/': (context) => TelaSplashScreen(),
},)
You can use the code below to navigate between pages, with Navigator.push() you will be able to go next page and back and with Navigator.pushReplacement() it will proceed to next page but loses its capability to go back to previous page.
Navigator.push(
context,
MaterialPageRoute(
builder: (context) => const MemberAttendancePage(),
),
);
I'm building an app for fire tv/fire stick using flutter.
My requirement: Show a dialog on press of a button in the fire TV remote and hide the dialog when the user presses the back button on the remote.
What I have accomplished: I'm able to show the dialog on the press of a button on the remote.
I need help in dismissing the dialog when the user presses back button on the remote.
What is happening now: When I press back while the dialog is shown, the entire page gets rerouted to the previous page.
I'm guessing it has something to do with the context, not sure how to fix this issue.
_showInfoModal(context) {
return showDialog(
context: context,
builder: (BuildContext context) {
return AlertDialog(
backgroundColor: Colors.transparent,
content: Container(
child: Center(
child: Text(widget.message, style: TextStyle(color: Colors.white)),
),
)
);
},
);
}
This is the code I'm using to show the dialog.
Navigator.of(context, rootNavigator: true).pop();
This is how I'm trying to pop the alert dialog.
Can someone please help me out here? TIA.
Try below code hope its works because I also build apk for TV and use below Alert Code
showAlert(BuildContext context) {
showDialog(
context: context,
builder: (context) {
return AlertDialog(
title: Text('Top '),
content: Text('Bottom '),
actions: [
TextButton(
onPressed: () => Navigator.of(context).pop(),
child: Text('Ok'),
),
],
);
},
);
}
So I was able to accomplish this using a workaround.
Having a boolean variable and showing either the dialog or a container with 0 height.
Not a good approach but gets the work done.
I am showing a dialogue with Get library and I want to dismiss automatically after a few seconds with Future. But I found no suitable function for that. So how do I dismiss a get dialogue after showing it?
code:
Get.dialog(Center(
child: Material(
color: Colors.blue,
child: Text('Hello'),
),
)); // how to dismiss? Like Get.Dismiss().
for dismiss dialog try using :
Get.back();
or
navigator.pop();
I have not used Get, but if you really want to do that thing, that I can suggest my way of doing it.
So, we will be using Flutter AlerDialog Class, which works the same, that is popping up the dialog, and you can always edit the content.
Now let us do these things:
Creating a dialog
Pop Up when the button is clicked
Auto dismiss the dialog
This will help you organize your solution. And we will be using Future only.
showAlertDialog(BuildContext context) {
// set up the button
Widget okButton = FlatButton(
child: Text("OK"),
onPressed: () { },
);
// set up the AlertDialog
AlertDialog alert = AlertDialog(
title: Text("My title"),
content: Text("This is my message."),
actions: [
okButton,
],
);
// show the dialog
showDialog(
context: context,
builder: (BuildContext context) {
return alert;
},
);
}
This method will pop-up the dialog, and then autodismiss, the dialog:
void _ourAutoDismissDialog(BuildContext context){
//Calling out showdialog method
showAlertDialog(context);
//Auto dismissing after the 2 seconds
// You can set the time as per your requirements in Duration
// This will dismiss the dialog automatically after the time you
// have mentioned
Future.delayed(const Duration(seconds: 2), (){
Navigator.of(context).pop();
});
}
FlatButton(
onPressed: () => _ourAutoDismissDialog(context)
child: Text('Hello')
)
To dismiss the dialog, we need to do back operation, and we do it via Navigator.of(context).pop()
This is the result we get after implementing the above:
I am developing an app that mainly just displays information from a web service to the user (info created by their admin). On the Drawer Menu there are 5 screens to display different information.
After the user has logged in, I use Navigator to move between screens by using pushReplacement. Meaning the current screen is always at the bottom of the screen stack. If the user presses the back button on their device, the app exists immediately.
How can I catch this, so I can ask the user if they want to log out, and then display the login screen?
Thanks for any suggestions.
Cheers,
Paul
You can do this with the WillPopScope widget and changing the onWillPop parameter. The example I posted does something similar to what you want as it shows an alert dialog that can determine what will happen next. The FlatButton onPressed code probably isn't exactly what you're looking for and you'll have to handle that according to your implementation This is the example code is from #AironTark answer to this related question.
#override
Widget build(BuildContext context) {
return WillPopScope(
child: Scaffold(...),
onWillPop: () => showDialog<bool>(
context: context,
builder: (c) => AlertDialog(
title: Text('Warning'),
content: Text('Do you really want to exit'),
actions: [
FlatButton(
child: Text('Yes'),
onPressed: () => Navigator.pop(c, true),
),
FlatButton(
child: Text('No'),
onPressed: () => Navigator.pop(c, false),
),
],
),
),
);
}
I want to create a stateful class which has an alert dialog with content then how can i call it from another class. I am newbie in programming. Could you show with example code
Create a new dart file my_alerts.dart and define it as a library. You can then import the showSampleDialog function from it and use it in any class. Just pass the context from the class that is using it.
For more info about alerts see this article
library my_alerts;
import 'package:flutter/material.dart';
// user defined function
void showSampleDialog(BuildContext context) {
// flutter defined function
showDialog(
context: context,
builder: (BuildContext context) {
// return object of type Dialog
return AlertDialog(
title: new Text("Alert Dialog title"),
content: new Text("Alert Dialog body"),
actions: <Widget>[
// usually buttons at the bottom of the dialog
new FlatButton(
child: new Text("Close"),
onPressed: () {
Navigator.of(context).pop();
},
),
],
);
},
);
}
Tomas answer is the way to go.
Here a running example:
https://dartpad.dartlang.org/638db165becbe88b25bbd9c77f636297