Conditional check column value in mongodb - mongodb

I have document like below
[
{
"_id" : ObjectId("601992e354787877866"),
"status" : 1,
"user_id" : 2,
},
{
"_id" : ObjectId("601992e354787877866"),
"status" : 2,
"user_id" : 2,
},
{
"_id" : ObjectId("601992e354787877866"),
"status" : 2,
"user_id" : 3,
},
{
"_id" : ObjectId("601992e354787877866"),
"status" : 3,
"user_id" : 4,
}
]
status column can have value 1, 2 or 3. I want to match user_id only if status column value is 2 and document having status other than 2 will come in result as it is.
I have tried with match query
db.collection.find({"status" : 1});
But it will only match the status
Now if my user id is 2 then output should b
[
{
"_id" : ObjectId("601992e354787877866"),
"status" : 1,
"user_id" : 2,
},
{
"_id" : ObjectId("601992e354787877866"),
"status" : 2,
"user_id" : 2,
},
{
"_id" : ObjectId("601992e354787877866"),
"status" : 3,
"user_id" : 4,
}
]
Here you can see document which status is 2 and user_id is not equal to 2 is not in expected output but for document which status is other than 2 will come is result

You could use the $or operator: https://mongoplayground.net/p/y9vR2PEGYdI
db.collection.find({
$or: [
{
status: 2,
user_id: 2
},
{
status: {
$ne: 2
}
}
]
})

Related

Mongo aggregation - Sorting using a field value from previous pipeline as the sort field

I have produced the below output using mongodb aggregation (including $group pipeline inside levelsCount field) :
{
"_id" : "1",
"name" : "First",
"levelsCount" : [
{ "_id" : "level_One", "levelNum" : 1, "count" : 1 },
{ "_id" : "level_Three", "levelNum" : 3, "count" : 1 },
{ "_id" : "level_Four", "levelNum" : 4, "count" : 8 }
]
}
{
"_id" : "2",
"name" : "Second",
"levelsCount" : [
{ "_id" : "level_One", "levelNum" : 1, "count" : 5 },
{ "_id" : "level_Two", "levelNum" : 2, "count" : 2 },
{ "_id" : "level_Three", "levelNum" : 3, "count" : 1 },
{ "_id" : "level_Four", "levelNum" : 4, "count" : 3 }
]
}
{
"_id" : "3",
"name" : "Third",
"levelsCount" : [
{ "_id" : "level_One", "levelNum" : 1, "count" : 1 },
{ "_id" : "level_Two", "levelNum" : 2, "count" : 3 },
{ "_id" : "level_Three", "levelNum" : 3, "count" : 2 },
{ "_id" : "level_Four", "levelNum" : 4, "count" : 3 }
]
}
Now, I need to sort these documents based on the levelNum and count fields of levelsCount array elements. I.e. If two documents both had the count 5 forlevelNum: 1 (level_One), then the sort goes to compare the count of levelNum: 2 (level_Two) field and so on.
I see how $sort pipeline would work on multiple fields (Something like { $sort : { level_One : 1, level_Two: 1 } }), But the problem is how to access those values of levelNum of each array element and set that value as a field name to do sorting on that. (I couldn't handle it even after $unwinding the levelsCount array).
P.s: The initial order of levelsCount array's elements may differ on each document and is not important.
Edit:
The expected output of the above structure would be:
// Sorted result:
{
"_id" : "2",
"name" : "Second",
"levelsCount" : [
{ "_id" : "level_One", "levelNum" : 1, "count" : 5 }, // "level_One's count: 5" is greater than "level_One's count: 1" in two other documents, regardless of other level_* fields. Therefore this whole document with "name: Second" is ordered first.
{ "_id" : "level_Two", "levelNum" : 2, "count" : 2 },
{ "_id" : "level_Three", "levelNum" : 3, "count" : 1 },
{ "_id" : "level_Four", "levelNum" : 4, "count" : 3 }
]
}
{
"_id" : "3",
"name" : "Third",
"levelsCount" : [
{ "_id" : "level_One", "levelNum" : 1, "count" : 1 },
{ "_id" : "level_Two", "levelNum" : 2, "count" : 3 }, // "level_Two's count" in this document exists with value (3) while the "level_Two" doesn't exist in the below document which mean (0) value for count. So this document with "name: Third" is ordered higher than the below document.
{ "_id" : "level_Three", "levelNum" : 3, "count" : 2 },
{ "_id" : "level_Four", "levelNum" : 4, "count" : 3 }
]
}
{
"_id" : "1",
"name" : "First",
"levelsCount" : [
{ "_id" : "level_One", "levelNum" : 1, "count" : 1 },
{ "_id" : "level_Three", "levelNum" : 3, "count" : 1 },
{ "_id" : "level_Four", "levelNum" : 4, "count" : 8 }
]
}
Of course, I'd prefer to have an output document in the below format, But the first problem is to sort all docs:
{
"_id" : "1",
"name" : "First",
"levelsCount" : [
{ "level_One" : 1 },
{ "level_Three" : 1 },
{ "level_Four" : 8 }
]
}
You can sort by levelNum as descending order and count as ascending order,
db.collection.aggregate([
{
$sort: {
"levelsCount.levelNum": -1,
"levelsCount.count": 1
}
}
])
Playground
For key-value format result of levelsCount array,
$map to iterate loop of levelsCount array
prepare key-value pair array and convert to object using $arrayToObject
{
$addFields: {
levelsCount: {
$map: {
input: "$levelsCount",
in: {
$arrayToObject: [
[{ k: "$$this._id", v: "$$this.levelNum" }]
]
}
}
}
}
}
Playground

mongo multiple count and devide result

I have a mongodb collection as follow :
[
{
"_id" : ObjectId("5ba0e5a99e7537012371855a"),
"user_id" : 2,
"action" : 0,
"source" : 1,
"service" : "FootPlus",
"free" : false,
"source_detail" : {
"source_type" : "landing",
"source_id" : 2,
"promoter_id" : 1
},
"created_at" : ISODate("2018-09-18T11:46:49.000Z")
}
{
"_id" : ObjectId("5ba0e5cc9e7537013d57e37a"),
"user_id" : 2,
"action" : 1,
"service" : "FootPlus",
"source" : 0,
"created_at" : ISODate("2018-09-18T11:47:24.000Z"),
"source_detail" : {
"source_type" : "landing",
"source_id" : 2,
"promoter_id" : 1
}
}
]
I want to group by source_detail.promoter_id and count action = 0 and action = 1
and also divide count of action = 0 to count of action = 1 per promoter
so my result should be :
[
{
"promoter_id": 2
"action_0": 27,
"action_1": 9,
"devide": 3
},
{
"promoter_id": 3
"action_0": 18,
"action_1": 3,
"devide": 6
}
]
how can I achieve this result ?
thanks.
You can use below aggregation.
Something like
db.colname.aggregate([
{"$group":{
"_id":"$source_detail.promoter_id",
"action_0":{"$sum":{"$cond":[{"$eq":["$action",0]},1,0]}},
"action_1":{"$sum":{"$cond":[{"$eq":["$action",1]},1,0]}}
}},
{"$addFields":{"divide":{"$divide":["$action_0","$action_1"]}}}
])

MongoDB - Fast Aggregation with grouping and min to more than 20M records

I have 20 million rows similar to this and the field "type1" has the following values 1,2,3,4 or 5
{
"_id" : ObjectId("59d55b0324934c04a7534d30"),
"name" : "Maria",
"nights" : 3,
"price" : 322,
"type1" : 3,
"type2" : 4,
"type3" : 5,
"type4" : 3,
"departure" : ObjectId("59d540194cb72658a4511665"),
"destination" : ObjectId("59d5401e4cb72658a4511666"),
"refundable" : false,
"active" : true,
"date_start" : ISODate("2017-04-18T18:33:14.871Z"),
"date_end" : ISODate("2017-06-30T12:55:04.164Z"),
"updated_at" : ISODate("2017-10-04T22:04:51.127Z"),
"created_at" : ISODate("2017-10-04T22:04:51.127Z"),
"__v" : 0
}
and I want to find the min price per type1
I run the following aggregation but it is very slow
db.fakers.aggregate(
[
{
$group:
{
_id: "$type1",
minPrice: { $min: "$price" }
}
}
]
)
I have also create the following index
db.fakers.createIndex( { type1: 1, price: -1 } )
Any suggestions? It makes ~20sec to execute

MongoDB MapReduce - How to populate an array in reduce function?

I have a MovieRatings database with columns userId, movieId, movie-categoryId, reviewId, movieRating and reviewDate.
In my mapper I want to extract userId -> (movieId, movieRating)
And then in the reducer I want to group all movieId, movieRating pair by user.
Here is my attempt:
Map function:
var map = function() {
var values={movieId : this.movieId, movieRating : this.movieRating};
emit(this.userId, values);}
Reduce function:
var reduce = function(key,values) {
var ratings = [];
values.forEach(function(V){
var temp = {movieId : V.movieId, movieRating : V.movieRating};
Array.prototype.push.apply(ratings, temp);
});
return {userId : key, ratings : ratings };
}
Run MapReduce:
db.ratings.mapReduce(map, reduce, { out: "map_reduce_step1" })
Output: db.map_reduce_step1.find()
{ "_id" : 1, "value" : { "userId" : 1, "ratings" : [ ] } }
{ "_id" : 2, "value" : { "userId" : 2, "ratings" : [ ] } }
{ "_id" : 3, "value" : { "userId" : 3, "ratings" : [ ] } }
{ "_id" : 4, "value" : { "userId" : 4, "ratings" : [ ] } }
{ "_id" : 5, "value" : { "userId" : 5, "ratings" : [ ] } }
{ "_id" : 6, "value" : { "userId" : 6, "ratings" : [ ] } }
{ "_id" : 7, "value" : { "userId" : 7, "ratings" : [ ] } }
{ "_id" : 8, "value" : { "userId" : 8, "ratings" : [ ] } }
{ "_id" : 9, "value" : { "userId" : 9, "ratings" : [ ] } }
{ "_id" : 10, "value" : { "userId" : 10, "ratings" : [ ] } }
{ "_id" : 11, "value" : { "userId" : 11, "ratings" : [ ] } }
{ "_id" : 12, "value" : { "userId" : 12, "ratings" : [ ] } }
{ "_id" : 13, "value" : { "userId" : 13, "ratings" : [ ] } }
{ "_id" : 14, "value" : { "userId" : 14, "ratings" : [ ] } }
{ "_id" : 15, "value" : { "movieId" : 1, "movieRating" : 3 } }
{ "_id" : 16, "value" : { "userId" : 16, "ratings" : [ ] } }
I am not getting the expected output. In fact, this output makes no sense to me!
Here is the python equivalent of what I am trying to do in the reducer (just in case the purpose of reducer wasn't clear above) :
def reducer_ratings_by_user(self, user_id, itemRatings):
#Group (item, rating) pairs by userID
ratings = []
for movieID, rating in itemRatings:
ratings.append((movieID, rating))
yield user_id, ratings
Edit 1 #chridam
Here is an outline of what I really want to do here :
Movies.csv file looks like :
userId,movieId,movie-categoryId,reviewId,movieRating,reviewDate
1,1,1,1,5,7/12/2000
2,1,1,2,5,7/12/2000
3,1,1,3,5,7/12/2000
4,1,1,4,4,7/12/2000
5,1,1,5,4,7/12/2000
6,1,1,6,5,7/15/2000
1,2,1,7,4,7/25/2000
8,1,1,8,4,7/28/2000
9,1,1,9,3,8/3/2000
...
...
I import this into mongoDB :
mongoimport --db SomeName --collection ratings --type csv --headerline --file Movies.csv
Then I am trying to apply the map-reduce function as define above. After that I will export it back to a csv by doing somethig like :
mongoexport --db SomeName --collection map_reduce_step1 --csv --out movie_ratings_out.csv --fields ...
This movie_ratings_out.csv file should be like :
userId, movieId1, rating1, movieId2, rating2 ,...
1,1,5,2,4
...
...
So each row contains all the (movie,rating) pair for every user.
Edit 2
Sample :
db.ratings.find().pretty()
{
"_id" : ObjectId("57f4a0dd9cb74fc4d344a40f"),
"userId" : 4,
"movieId" : 1,
"movie-categoryId" : 1,
"reviewId" : 4,
"movieRating" : 4,
"reviewDate" : "7/12/2000"
}
{
"_id" : ObjectId("57f4a0dd9cb74fc4d344a410"),
"userId" : 5,
"movieId" : 1,
"movie-categoryId" : 1,
"reviewId" : 5,
"movieRating" : 4,
"reviewDate" : "7/12/2000"
}
{
"_id" : ObjectId("57f4a0dd9cb74fc4d344a411"),
"userId" : 4,
"movieId" : 2,
"movie-categoryId" : 1,
"reviewId" : 6,
"movieRating" : 5,
"reviewDate" : "7/15/2000"
}
{
"_id" : ObjectId("57f4a0dd9cb74fc4d344a412"),
"userId" : 4,
"movieId" : 3,
"movie-categoryId" : 1,
"reviewId" : 2,
"movieRating" : 5,
"reviewDate" : "7/12/2000"
}
...
Then after MapReduce expected output json is :
{
"_id" : ....,
"userId" : 4,
"movieList" : [ {
"movieId" : 2
"movieRating" : 5
},
{
"movieId" : 1
"movieRating" : 4
}
...
]
}
{
"_id" : ....,
"userId" : 5,
"movieList" : ...
}
...
You just need to run an aggregation pipeline which consists of a $group stage that summarize documents. This groups input documents by a specified identifier expression and applies the accumulator expression(s). The $group pipeline operator is similar to the SQL's GROUP BY clause. In SQL, you can't use GROUP BY unless you use any of the aggregation functions. The same way, you have to use an aggregation function in MongoDB as well. You can read more about the aggregation functions here.
The accumulator operator you would need to create the movieList array is $push.
Another pipeline which follows after the $group stage is the $project operator which is used to select or reshape each document in the stream, include, exclude or rename fields, inject computed fields, create sub-document fields, using mathematical expressions, dates, strings and/or logical (comparison, boolean, control) expressions - similar to what you would do with the SQL SELECT clause.
The last step is the $out pipeline which writes the resulting documents of the aggregation pipeline to a collection. It must be the last stage in the pipeline.
So as a result, you can run the following aggregate operation:
db.ratings.aggregate([
{
"$group": {
"_id": "$userId",
"movieList": {
"$push": {
"movieId": "$movieId",
"movieRating": "$movieRating",
}
}
}
},
{
"$project": {
"_id": 0, "userId": "$_id", "movieList": 1
}
},
{ "$out": "movie_ratings_out" }
])
Using the sample 5 documents above, the sample output if you query db.getCollection('movie_ratings_out').find({}) would yield:
/* 1 */
{
"_id" : ObjectId("57f52636b9c3ea346ab1d399"),
"movieList" : [
{
"movieId" : 1.0,
"movieRating" : 4.0
}
],
"userId" : 5.0
}
/* 2 */
{
"_id" : ObjectId("57f52636b9c3ea346ab1d39a"),
"movieList" : [
{
"movieId" : 1.0,
"movieRating" : 4.0
},
{
"movieId" : 2.0,
"movieRating" : 5.0
},
{
"movieId" : 3.0,
"movieRating" : 5.0
}
],
"userId" : 4.0
}

MongoDB: Sort in combination with Aggregation group

I have a collection called transaction with below documents,
/* 0 */
{
"_id" : ObjectId("5603fad216e90d53d6795131"),
"statusId" : "65c719e6727d",
"relatedWith" : "65c719e67267",
"status" : "A",
"userId" : "100",
"createdTs" : ISODate("2015-09-24T13:15:36.609Z")
}
/* 1 */
{
"_id" : ObjectId("5603fad216e90d53d6795134"),
"statusId" : "65c719e6727d",
"relatedWith" : "65c719e6726d",
"status" : "B",
"userId" : "100",
"createdTs" : ISODate("2015-09-24T13:14:31.609Z")
}
/* 2 */
{
"_id" : ObjectId("5603fad216e90d53d679512e"),
"statusId" : "65c719e6727d",
"relatedWith" : "65c719e6726d",
"status" : "C",
"userId" : "100",
"createdTs" : ISODate("2015-09-24T13:13:36.609Z")
}
/* 3 */
{
"_id" : ObjectId("5603fad216e90d53d6795132"),
"statusId" : "65c719e6727d",
"relatedWith" : "65c719e6726d",
"status" : "D",
"userId" : "100",
"createdTs" : ISODate("2015-09-24T13:16:36.609Z")
}
When I run the below Aggregation query without $group,
db.transaction.aggregate([
{
"$match": {
"userId": "100",
"statusId": "65c719e6727d"
}
},
{
"$sort": {
"createdTs": -1
}
}
])
I get the result in expected sorting order. i.e Sort createdTs in descending order (Minimal result)
/* 0 */
{
"result" : [
{
"_id" : ObjectId("5603fad216e90d53d6795132"),
"createdTs" : ISODate("2015-09-24T13:16:36.609Z")
},
{
"_id" : ObjectId("5603fad216e90d53d6795131"),
"createdTs" : ISODate("2015-09-24T13:15:36.609Z")
},
{
"_id" : ObjectId("5603fad216e90d53d6795134"),
"createdTs" : ISODate("2015-09-24T13:14:31.609Z")
},
{
"_id" : ObjectId("5603fad216e90d53d679512e"),
"createdTs" : ISODate("2015-09-24T13:13:36.609Z")
}
],
"ok" : 1
}
If I apply the below aggregation with $group, the resultant is inversely sorted(i.e Ascending sort)
db.transaction.aggregate([
{
"$match": {
"userId": "100",
"statusId": "65c719e6727d"
}
},
{
"$sort": {
"createdTs": -1
}
},
{
$group: {
"_id": {
"statusId": "$statusId",
"relatedWith": "$relatedWith",
"status": "$status"
},
"status": {$first: "$status"},
"statusId": {$first: "$statusId"},
"relatedWith": {$first: "$relatedWith"},
"createdTs": {$first: "$createdTs"}
}
}
]);
I get the result in inverse Order i.e. ** Sort createdTs in Ascending order**
/* 0 */
{
"result" : [
{
"_id" : ObjectId("5603fad216e90d53d679512e"),
"createdTs" : ISODate("2015-09-24T13:13:36.609Z")
},
{
"_id" : ObjectId("5603fad216e90d53d6795134"),
"createdTs" : ISODate("2015-09-24T13:14:31.609Z")
},
{
"_id" : ObjectId("5603fad216e90d53d6795131"),
"createdTs" : ISODate("2015-09-24T13:15:36.609Z")
},
{
"_id" : ObjectId("5603fad216e90d53d6795132"),
"createdTs" : ISODate("2015-09-24T13:16:36.609Z")
}
],
"ok" : 1
}
Where am I wrong ?
The $group stage doesn't insure the ordering of the results. See here the first paragraph.
If you want the results to be sorted after a $group, you need to add a $sort after the $group stage.
In your case, you should move the $sort after the $group and before you ask the question : No, the $sort won't be able to use an index after the $group like it does before the $group :-).
The internal algorithm of $group seems to keep some sort of ordering (reversed apparently), but I would not count on that and add a $sort.
You are not doing anything wrong here, Its a $group behavior in Mongodb
Lets have a look in this example
Suppose you have following doc in collection
{ "_id" : 1, "item" : "abc", "price" : 10, "quantity" : 2, "date" : ISODate("2014-01-01T08:00:00Z") }
{ "_id" : 2, "item" : "jkl", "price" : 20, "quantity" : 1, "date" : ISODate("2014-02-03T09:00:00Z") }
{ "_id" : 3, "item" : "xyz", "price" : 5, "quantity" : 5, "date" : ISODate("2014-02-03T09:05:00Z") }
{ "_id" : 4, "item" : "abc", "price" : 10, "quantity" : 10, "date" : ISODate("2014-02-15T08:00:00Z") }
{ "_id" : 5, "item" : "xyz", "price" : 5, "quantity" : 10, "date" : ISODate("2014-02-15T09:05:00Z") }
{ "_id" : 6, "item" : "xyz", "price" : 5, "quantity" : 5, "date" : ISODate("2014-02-15T12:05:10Z") }
{ "_id" : 7, "item" : "xyz", "price" : 5, "quantity" : 10, "date" : ISODate("2014-02-15T14:12:12Z") }
Now if you run this
db.collection.aggregate([{ $sort: { item: 1,date:1}} ] )
the output will be in ascending order of item and date.
Now if you add group stage in aggregation pipeline it will reverse the order.
db.collection.aggregate([{ $sort: { item: 1,date:1}},{$group:{_id:"$item"}} ] )
Output will be
{ "_id" : "xyz" }
{ "_id" : "jkl" }
{ "_id" : "abc" }
Now the solution for your problem
change "createdTs": -1 to "createdTs": 1 for group