Get-ChildItem "\\myfileserver\files\folder\999\*" | Rename-Item -NewName { ($_.Name-replace '(?<=^[^_]+)_.+?(?=\.)').Replace(".vfmpclmadj.", ".va.").Replace(".VFMP.",".va.") }
The above changes the file name
Before
999_837I.84146.VFMP.000000384.20210127.121415
After
999.84146.va.000000384.20210127.121415
Now I need to remove
20210127.121415
and add the current date and time.
I need help accomplishing that last piece. Thanks.
Append another -replace operation:
# Remove the '.20210127.121415' suffix.
PS> '999.84146.va.000000384.20210127.121415' -replace '(\.\d+){2}$'
999.84146.va.000000384
Then re-append a timestamp string suffix in the same format based on the current point in time:
PS> '999.84146.va.000000384' + '.' + (Get-Date -Format yyyyMMdd.HHmmss)
999.84146.va.000000384.20210127.165325 # e.g.
Or, preferably, as part of a single -replace operation:
'999.84146.va.000000384.20210127.121415' -replace '(\.\d+){2}$', ".$(Get-Date -Format yyyyMMdd.HHmmss)"
Related
A general thing that I need to do a lot with files is to create/reference a backup version of a file. e.g. I might want to have a date/time stamp version of a file so that I can reference both the original report and the backup version throughout a script:
$now = $(Get-Date -format "yyyy-MM-dd__HH-mm")
$ReportName = "MyReport-en.csv"
$Backups = "D:\Backups\Reports"
I found that using -join or + always inserted a space before the date/time stamp:
$ReportBackup = "$Backups\$($ReportName -split ".csv")" + "_$now.csv"
$ReportBackup = "$Backups\$($ReportName -split ".csv")" -join "_$now.csv"
I found a way to do this, but it looks feels inefficient with the triple $ and duplication of the .csv
$ReportBackup = "$Backups\$($($ReportName -split ".csv")[0])$_now.csv"
which results in:
$ReportBackup => D:\Backups\Reports\MyReport-en_2022-04-15__07-55.csv
Can you think of simpler/cleaner way to achieve the generic goal of inserting a piece of text before the extension, without the triple $ or duplication of the extension? ("Use a $name = "MyReport-en"" is not so useful because often I am reading a file object and get the name complete with extension.
$now = Get-Date -Format "yyyy-MM-dd__HH-mm"
$reportName = "MyReport-en.csv"
$backups = "D:\Backups\Reports"
$reportBackup = Join-Path $backups $reportName.Replace(".csv","_$now.csv")
$reportBackup
P.S.
There is no risk in using .Replace(), if you know how it works.
This method is case sensitive and replaces all occurrences. In this particular case, we know exactly the name in advance, so we can use this method safely.
The name "My.csvReport-en.csv" is an nonsense, but if the problem explicitly referred to the universal solution "any-name.ext":
$reportName = "My.aSd_Report-en.aSD"
$backups = "D:\Backups\Reports"
$reportBackup = Join-Path $backups ($reportName -replace "(?=\.[^.]+$)", (Get-Date -Format "_yyyy-MM-dd__HH-mm"))
$reportBackup
If you have obtained the report file as FileInfo object by perhaps using Get-Item or Get-ChildItem, you'll find that object has convenient properties you can use to create a new filename with the date included:
# assume $ReportName is a FileInfo object
$Backups = "D:\Backups\Reports"
# I'm creating a new filename using the '-f' Format operator
$NewName = '{0}_{1:yyyy-MM-dd__HH-mm}{2}' -f $ReportName.BaseName, (Get-Date), $ReportName.Extension
$ReportBackup = Join-Path -Path $Backups -ChildPath $NewName
If however $ReportName is just a string that only holds the filename, you can do:
$ReportName = "MyReport-en.csv"
$Backups = "D:\Backups\Reports"
$baseName = [System.IO.Path]::GetFileNameWithoutExtension($ReportName)
$extension = [System.IO.Path]::GetExtension($ReportName)
$NewName = '{0}_{1:yyyy-MM-dd__HH-mm}{2}' -f $baseName, (Get-Date), $extension
$ReportBackup = Join-Path -Path $Backups -ChildPath $NewName
P.S. It is always risky to simply use .Replace() on a filename because that doesn't allow you to anchor the substring to replace, which is needed, because that substring may very well also be part of the name itself.
Also, the string .Replace() method works case-sensitive.
This means that
'My.csvReport-en.csv'.Replace(".csv", "_$(Get-Date -Format 'yyyy-MM-dd__HH-mm').csv")
would fail (returns My_2022-04-15__13-36.csvReport-en_2022-04-15__13-36.csv)
and
'MyReport-en.CSV'.Replace(".csv", "$(Get-Date -Format 'yyyy-MM-dd__HH-mm').csv")
would simply not replace anything because it cannot find the uppercase .CSV
..
If you really want to do this by replacing the extension into a date+extension, go for a more complex case-insensitive regex -replace like:
$ReportName -replace '^(.+)(\.[^.]+)$', "`$1_$(Get-Date -Format 'yyyy-MM-dd__HH-mm')`$2"
Regex details:
^ Assert position at the beginning of the string
( Match the regular expression below and capture its match into backreference number 1
. Match any single character that is not a line break character
+ Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)
( Match the regular expression below and capture its match into backreference number 2
\. Match the character “.” literally
[^.] Match any character that is NOT a “.”
+ Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)
$ Assert position at the end of the string (or before the line break at the end of the string, if any)
I need to format the file name from ...
2639423_3_30_56 PM_9_4_2020.txt
... to ...
2639423-15-30-56-09-04-2020.txt
i.e. Need to change date in Military time format and replace '_' with '-', Also append with “0” for single digit months and single digit days
Please advise I need to perform this in powershell & need to perform this in bulk.
Start by splitting the file name into two parts - the prefix, which remains the same, and the timestamp, which you want to re-format:
$basename = '2639423_3_30_56 PM_9_4_2020'
$prefix,$timestamp = $basename -split '_',2
Next, parse the timestamp according to it's specific format:
$inputFormat = 'h_mm_ss tt_d_M_yyyy'
$parsedDateTime = [datetime]::ParseExact($timestamp,$inputFormat,$null)
Finally convert the parsed [datetime] object back to a string with the desired output format, and then join the prefix and (updated) timestamp together again:
$outputFormat = 'HH-mm-ss-dd-MM-yyyy'
$timestamp = $parsedDateTime.ToString($outputFormat)
# or
$timestamp = Get-Date $parsedDateTime -Format $outputFormat
$newFileName = $prefix,$timestamp -join '-'
# 2639423-15-30-56-09-04-2020
To rename the files in bulk, pipe the files to Rename-Item and use the parameter binder to generate the new name of each file based on the existing name:
Get-ChildItem -Path .\folder\with\files -Filter *.txt |Rename-Item -NewName {
$prefix,$timestamp = $_.BaseName -split '_',2
$parsedDateTime = [datetime]::ParseExact($timestamp, 'h_mm_ss tt_d_M_yyyy', $null)
$timestamp = $parsedDateTime.ToString('HH-mm-ss-dd-MM-yyyy')
$newBaseName = $prefix,$timestamp -join '-'
$newBaseName + $_.Extension
}
I need to replace the time\date stamp that's included in the filename after 2nd underscore (needs to be in the same format yyyyMMddHHmmss)
example file: 123456_123456_20190716163001.xml
sometimes the file in question gets created with an additional character which invalidates the file, in this case I need to replace this with the current timestamp.
example: 123456_123456_current Timestamp here.xml
The file should never exceed 32 characters(including extension)
I found a script but it deletes everything after the 1st underscore not the 2nd and I'm struggling to find a way to replace the text with the current timestamp.
Get-ChildItem c:\test -Filter 123456_123456*.xml | Foreach-Object -Process {
$NewName = [Regex]::Match($_.Name,"^[^_]*").Value + '.xml' $_ | Rename-Item -NewName $NewName
}
timestamp after 2nd underscore to be updated to the current timestamp if original file exceeds 32 characters
123456_123456_current Timestamp here.xml
this takes advantage of the way a [fileinfo] object is structured. the .BaseName is easy to get to & use .Split() on. then one can use -join to put it back into one basename & finally add the extension onto the basename.
# fake reading in a file info object
# in real life, use Get-ChildItem or Get-Item
$FileObject = [System.IO.FileInfo]'123456_123456_current Timestamp here.xml'
$NewName = -join (($FileObject.BaseName.Split('_')[0,1] -join '_'), $FileObject.Extension)
$NewName
output = 123456_123456.xml
Sticking with the regex theme, you can do the following:
$CurrentTime = Get-Date -Format 'yyyyMMddHHmmss'
$RegexReplace = "(.*?_.*?_).*(\..*)"
Get-ChildItem c:\test -Filter 123456_123456*.xml |
Rename-Item -NewName {$_.Name -replace $RegexReplace,"`${1}$CurrentTime`${2}"}
If duplicate file names are a concern, you can build in an increment to $CurrentTime.
$CurrentTime = Get-Date -Format 'yyyyMMddHHmmss'
$RegexReplace = "(.*?_.*?_).*(\..*)"
Get-ChildItem c:\test -Filter 123456_123456*.xml |
Rename-Item -NewName {
$NewName = $_.Name -replace $RegexReplace,"`${1}$CurrentTime`${2}"
if (test-path $NewName) {
$CurrentTime = [double]$CurrentTime + 1
$NewName = $_.Name -replace $RegexReplace,"`${1}$CurrentTime`${2}"
}
$NewName
}
Explanation:
$RegexReplace contains the regex expression that will need to be matched for the ideal rename operation to happen. The regex mechanisms are explained below:
.*?_.*?_: Matches a minimal number of characters (lazy matching) followed by an underscore and then another minimal number of characters followed by an underscore.
.*: Greedily matches any characters
\.: Literally matches the dot character (.).
(): The parentheses here represent capture groups with the first set being 1 and the second set being 2. These are later referenced as ${1} and ${2} in the -replace operation.
Since Rename-Item -NewName supports delayed script binding, we can just pipe Get-ChildItem output directly to it. The current pipeline object is $_.
The -replace operation uses the variable $CurrentTime, which must be expanded in order for a successful outcome. For that reason, we use double quotes around the replacement. Since we do not want capture groups ${1} and ${2} expanded, we backtick escape them.
I am trying to use a regex to find dates in a csv file and change the formatting because there are over 200 columns in this csv; manual column mapping for each date is not possible.
what I had previously was the following
$sf = '\\path\dept\Extracts\Date_Modified.csv'
$regex = "\d{1,2}/\d{1,2}/\d{4}"
(Get-Content $sf) |
Foreach-Object {$_ -replace $regex, (get-date -f "yyyy-MM-dd") } |
Set-Content $sf
that works fine if I want to replace all the dates with the current date, but that wasn't my goal. my goal is to recognize human entry type dates (mm/dd/yyyy) and change them to yyyy-mm-dd that the database table is expecting when I load the csv.
how can I modify this? or is there a better way to recognize date formats and change the format?
The answer: use capture groups. I don't know why you wouldn't be able to assign the regex to a variable before use (as I have done many times):
$sf = '\\path\dept\Extracts\Date_Modified.csv'
$regex = '(\d{1,2})\/(\d{1,2})\/(\d{4})'
#(Get-Content -Path $sf) |
ForEach-Object { $_ -replace $regex, '$3-$1-$2' } |
Set-Content -Path $sf
Of special note, use single-quotes in the replace statement so you don't end up trying to interpolate $1 into a (presumably null) variable.
I've been batch renaming .las files in powershell with a simple script:
cd "C:\Users\User\desktop\Folder"
Dir | Rename-Item -NewName {$_.name-replace "-", "" }
Dir | Rename-Item -NewName {$_.name-replace "_", "" }
Dir | Rename-Item -NewName {$_.BaseName+ "0.las"}
This has been working great, but I need to modify it to account for a different naming convention.
The files start out in this format: 123_45-67-890-12W_0
and get converted to 123456789012W00.las
Occasionally the number after the W will be non zero, and I need to carry that on as the last digit, eg. 123_45-67-890-12W_2 needs to go to 123456789012W02
I'm not sure how to use if statements and to select a specific digit in powershell format, which is how I would approach this problem. Does anyone have some ideas on how to go about this?
Thanks
You can use a regular expression to achieve this:
Get-ChildItem "C:\Users\User\desktop\Folder" | ForEach-Object {
#capture everything we need with regex
$newName = $_.Name -replace "(\d{3})_(\d{2})-(\d{2})-(\d{3})-(\d{2})(\w)_(\d)",'$1$2$3$4$5$6$7'
#insert 0 before last digit and append file extension
$newName = $newName.Insert(($newName.Length - 1), "0") + ".las"
#rename file
Rename-Item $_.FullName -NewName $newName
}
You can use the substring method to get all but the last character in the basename, then concatenate the zero, then use substring again to get the basename's last character, then finish off with the .las extension:
Dir | Rename-Item -NewName {($_.BaseName).substring(0,$_.BaseName.length - 1) + "0" + ($_.BaseName).substring($_.BaseName.length -1,1) + ".las"}
# ^^^^This gets everything but the last charcter^^^ ^^^^^^^^^^This gets the last character^^^^^^^^^^