How to simulate a system output with a sine wave input? - matlab

Question

I wish to simulate the output of a certain gear system I have. How the gear system looks isn't particularly important to the problem, I managed to get the differential equation needed from the mechanical system.
Here is the code I have
% parameters
N2 = 90;
N1 = 36;
Jn1 = 0.5;
Jn2 = 0.8;
J2 = 2;
D = 8;
K = 5;
J = (N2/N1)^2 * Jn1 + Jn2 + J2;
% define the system
sys = ss([0 1; -K/J -D/J], [0; N2/(N1*J)], [1 0], 0);
% initial state: (position, velocity) [rad; rad/s]
x0 = [0; 0];
% define the time span
t = linspace(0, 15, 10000)';
% define the input step
T1 = zeros(length(t), 1);
T1(t>=0) = 1;
% compute the system step response at once
theta1 = lsim(sys, T1, t, x0);
% compute the system response as aggregate of the forced and unforced
% temporal evolutions
theta2 = lsim(sys, T1, t, [0; 0]) + initial(sys, x0, t);
% plot results
figure('color', 'white');
hold on;
yyaxis left;
plot(t, T1, '-.', 'linewidth', 2);
ylabel('[N]');
yyaxis right;
plot(t, theta1, 'linewidth', 3);
plot(t, theta2, 'k--');
xlabel('t [s]');
ylabel('[rad]');
grid minor;
legend({'$T_1$', '$\theta_1$', '$\theta_2$'}, 'Interpreter', 'latex',...
'location', 'southeast');
hold off;
This should work in generating a graph that shows the positions, my outputs, for a Heaviside/step input. My question is, how would I do this for a sine wave input. I figure I should have sin(w*t) instead of (t>=0), where w is my pulse frequency. Still, I can't seem to make this work. Any help would be really appreciated! :)

Answer 1

Here is the solution to my problem :)
function x = integrate(t, u, x0)
% parameters
N2 = 90;
N1 = 36;
Jn1 = 0.5;
Jn2 = 0.8;
J2 = 2;
D = 8;
K = 5;
J = (N2/N1)^2 * Jn1 + Jn2 + J2;
% integrate the differential equation
[t, x] = ode23(#fun, t, x0);
% plot results
figure('color', 'white');
% plot position
yyaxis left;
plot(t, x(:, 1));
ylabel('$x$ [rad]', 'Interpreter', 'latex');
% plot velocity
yyaxis right;
plot(t, x(:, 2));
ylabel('$\dot{x}$ [rad/s]', 'Interpreter', 'latex');
grid minor;
xlabel('$t$ [s]', 'Interpreter', 'latex');
function g = fun(t, x)
g = zeros(2, 1);
g(1) = x(2);
g(2) = (-K/J)*x(1) + (-D/J)*x(2) + (N2/(N1*J)*u(t));
end
end
Now we can use an anonymous function for example:
t = linspace(0, 120, 10000)';
x0 = [0.1; 0];
x = integrate(t, #(t)(sin(1.5*t)), x0);

Answer 2

Test Run
These are the output results I currently get on MATLAB R2019b. As Luis' comment has suggested I have also declared a sinusoid as T1 to serve as the input. Currently not sure if this result is the expected output.
Code Snippet:
t = linspace(0, 15, 10000)';
f = 0.1;
phi = 0;
T1 = sin(2*pi*f*t + phi);
f → Frequency of sinusoidal input (0.1Hz in this example).
phi → Phase offset of sinusoidal input/initial phase (0 in this example).
t → Time vector dictating the samples of the sinusoid.
0 → Start time (0 seconds in this example).
15 → End time (15 seconds in this example).
10000 → Number of samples between the start time (0s) and end time (15s).
Implementation in Script:
% parameters
N2 = 90;
N1 = 36;
Jn1 = 0.5;
Jn2 = 0.8;
J2 = 2;
D = 8;
K = 5;
J = (N2/N1)^2 * Jn1 + Jn2 + J2;
% define the system
sys = ss([0 1; -K/J -D/J], [0; N2/(N1*J)], [1 0], 0);
% initial state: (position, velocity) [rad; rad/s]
x0 = [0; 0];
% define the time span
t = linspace(0, 15, 10000)';
% define the input step
T1 = zeros(length(t), 1);
T1(t>=0) = 1;
f = 0.1; %Sinusoid frequency = 0.1Hz%
phi = 0; %Phase = 0%
T1 = sin(2*pi*f*t + phi);
% compute the system step response at once
theta1 = lsim(sys, T1, t, x0);
% compute the system response as aggregate of the forced and unforced
% temporal evolutions
theta2 = lsim(sys, T1, t, [0; 0]) + initial(sys, x0, t);
% plot results
figure('color', 'white');
hold on;
yyaxis left;
plot(t, T1, '-.', 'linewidth', 2);
ylabel('[N]');
yyaxis right;
plot(t, theta1, 'linewidth', 3);
plot(t, theta2, 'k--');
xlabel('t [s]');
ylabel('[rad]');
grid minor;
legend({'$T_1$', '$\theta_1$', '$\theta_2$'}, 'Interpreter', 'latex',...
'location', 'southeast');
hold off;