I have this table
table A(price) and this table B(name)
and i want to get the Avarage price of something from Table A using the name from table B
I tried like this
select AVG(a.price) from a,b where b.name='something' but this returns the Avarage of all the items in table A.
I also tried using join like this
AVG(a.price) from a left join b on b.name='something'
but it returns the same thing as before
You are missing a key in your join. The price in table A for an item must be against a record with a specific key whereby the same key is available in table b with the name. It might be something like below.
Select avg(price) from A
Join B on
A.key=B.key
Where B.name=‘something’
Then again this depends on your table structure.
Related
I am creating 2 tables, one called quizes with:
id, quiz_name, plays
and the second one called quizes taken with:
session_id, quiz_id
and I would like to store count of rows, inside of plays column in table quizes, but I have no clue how to do it.
In more detail, what I am trying to achieve, is that on every update/insert into quizes_taken, in table quizes, the play" column updates with the row count of that quiz's ID from table quizes_taken.
If someone could explain how to achieve it, I'd be grateful!
Thanks in advance!
you could make a view or materialized view for the expected result output,
CREATE OR REPLACE VIEW AS quizes_live_update AS
SELECT a.id , a.quiz_name, COUNT(b.quiz_id) as plays
FROM quizes a
JOIN quizes_taken b ON a.id = b.quiz_id
GROUP BY a.id, a.quiz_name
Postgres: Create view
Although, if you need to proceed with tables approach, you can set up some upsert triggers
on quizes_taken table to perform update and insert on quizes table, plays column.
Is it possible to add a new column to an existing table from another table using insert or update in conjunction with full outer join .
In my main table i am missing some records in one column in the other table i have all those records i want to take the full record set into the maintable table. Something like this;
UPDATE maintable
SET all_records= othertable.records
FROM
FULL JOIN othertable on maintable.col = othertable.records;
Where maintable.col has same id a othertable.records.
I know i could simply join the tables but i have a lot of comments in the maintable i don't want to have to copy paste back in if possible. As i understand using where is equivalent of a left join so won't show me what i'm missing
EDIT:
What i want is effectively a new maintable.col with all the records i can then pare down based on presence of records in other cols from other tables
Try this:
UPDATE maintable
SET all_records = o.records
FROM othertable o
WHERE maintable.col = o.records;
This is the general syntax to use in postgres when updating via a join.
HTH
EDIT
BTW you will need to change this - I used your example, but you are updating the maintable with the column used for the join! Your set needs to be something like SET missingcol = o.extracol
AMENDED GENERALISED ANSWER (following off-line chat)
To take a simplified example, suppose that you have two tables maintable and subtable, each with the same columns, but where the subtable has extra records. For both tables id is the primary key. To fill maintable with the missing records, for pre 9.5 versions of Postgres you must use the following syntax:
INSERT INTO maintable (SELECT * FROM subtable s WHERE NOT EXISTS
(SELECT 1 FROM maintable m WHERE m.id = s.id));
Since 9.5 there is a (preferred) alternative:
INSERT INTO maintable (SELECT * FROM subtable) ON CONFLICT DO NOTHING;
This is preferred because (apart from being simpler) it avoids the situation that has been known to arise in the former, where a race condition is created between the INSERT and the sub-SELECT.
Obviously when the columns are different, you need to specify in the INSERT statement which columns are inserted from which. Something like:
INSERT INTO maintable (id, ColA, ColB)
(SELECT id, ColE, ColG FROM subtable ....)
Similarly the common field might not be id in both tables. However, the simplified example should be enough to point you in the right direction.
Is there a way to tell Talend not to remove the prefix of column names especially when they are specified in the query to retrieve data from data source and keep the names mentioned in the query itself?
Thanks!
Assuming you are using the 'guess schema' feature with a query that joins some tables. Further assuming your tables have columns with the same names you run into trouble with the guessed schema. There is no way to have talend use or even know the names of the tables the colums come from, because they are part of a 'projection' and could result from transformation and/or aggregation. Thus, you'll need to help talend guessing the correct schema, which means a) you cant use the * to select all columns and b) you should assign each column an alias that hints at the table the column comes from.
So instead of select * from employee join department on employee.department_id = department.id you'd have something like select e.id as emp_id, e.name as emp_name, d.id as department_id, d.name as department_name from employee e join department d on e.department_id = d.id. The id from employee will be emp_id in the guessed schema.
I'm trying to build a request to get the data from a table, but some of those columns have foreign keys I would like to replace by the associated keyword in one request.
Basically there's
table A with column 1:PKA-ID and column 2:name.
table B with column 1:PKB-ID, column 2:FKA-ID, column 3:amount.
I want to get all the lines in table B but with all foreign keys replaced by the associated names in table A.
I started building a request with a subrequest + alias to get that, but ofc I have more than one result per subrequest, yet I can't find a way to link that subrequest to the ID of table B [might be exhausted, dumb or both] from the main request. I did something like that:
SELECT (SELECT "NAME" FROM A JOIN B ON ID = FKA-ID) AS name, amount FROM TABLEB;
it feels so simple of a request yet...
You don't need a join in the subselect.
SELECT pkb_id,
(SELECT name FROM a WHERE a.pka_id = b.fka_id),
amount
FROM b;
(See it live in SQL Fiddle).
The subselect query runs for each and every row of its parent select and has the parent row available from the context.
You can also use a simple join.
SELECT b.pkb_id, a.name, b.amount
FROM b, a
WHERE a.pka_id = b.fka_id;
Note that the join version puts less restrictions on the PostgreSQL query optimizer so in some cases the join version might work faster. (For example, in PostgreSQL 9.6 the join might utilize multiple CPU units, cf. Parallel Query).
Let us consider two tables
table1 - name,id,publisher_name,exp_date
table2-book_id,price,discount,last_date
I have to retrieve the name, id,publisher_name from table1 and price, last_date from table2
I wrote a code in active record rails 2
Table1.find(:all,:select=>"table1.name,table1.publisher_name,table1.id,table2.last_date,table2.price",:joins=>"LEFT OUTER JOIN table1s on table1s.id= table2s.book_id")
in this code by selecting multiple column name we need write that table name repeatedly,
need a simple code to avoid this problem
if the selected columns are not present in both tables you don't need to write the tablename as a prefix. You also don't need to name the table2 in front of "book_id". You only need them if the column-names are ambigious.
Table1.find( :all, :select=> "name, publisher_name, id, last_date, price", :joins => "LEFT OUTER JOIN table1s on table1s.id = book_id")