Have the function MathChallenge(num) take the num parameter being passed and determine the largest double digit number within the whole number. For example: if num is 4759472 then your program should return 94 because that is the largest double digit number. The input will always contain at least two positive digits.
I am looking for a solution to this problem in dart programming language.
I am using Pentaho-code I am round the queries values as decimal but getting some colums values not decimal
table output:
NORMAL (06:00--17:00) 3 14341.54 43024.62
OFF_PEAK (22:00--06:00) 3 7002.39 21007.170000000002
PEAK (17:00--22:00) 3 9362.95 28088.850000000002
required output
NORMAL (06:00--17:00) 3 14341.54 43024.62
OFF_PEAK (22:00--06:00) 3 7002.39 21007.17
PEAK (17:00--22:00) 3 9362.95 28088.85
Column formats %.2f will definitely work to show 2 decimal point. You just need to be define column formats for every column. For string you need to define %s, for only real digit use %d, and to get 2 decimal you need to define %.2f etc.
You can have a look in my sample image for correct configuration-
I'm having a trouble in concatenating the Negative numbers and Strings. I've successfully display the negative numbers with parenthesis (ex. (3)) but when I add the string to it the format of number becomes -3 again. This is my expression:
=Cint(Fields!UNT_TAKEN.Value) & " UNITS"
It returns me with this value -3 UNITS
But I want to return (3) UNITS
Thank you in advance.
If UNIT_TAKEN is already a number then you can just set the format property of the cell/textbox to
0 Units;(0) Units
If UNIT_TAKEN is a string then set the value expression of the cell/textbox to
=FORMAT(CINT(Fields!UNIT_TAKEN.Value),"0 Units;(0) Units")
Below I created a dataset with both a numeric and string version of seven numbers. The table below shows the actual values and the formatted values as above.
Apparently I am misunderstanding the printf man page. (Or else it's a bug in exiftool 10.55 and 10.77)
I am trying to get GPS coordinates from image files with exiftool. I would like to make them the same width and without unnecessary spaces.
The format string I tried, and one of the results:
-coordFormat "%03d°%02d′%0d%02.5f″"
042°37′280.00000″ N, 002°05′510.00000″ W
(I don't need five decimal places—I just put that in temporarily to see whether any of the cameras wer being dishonest about the precision.) The three unnecessary spaces can't be helped; they are outside the format string’s control, but I did get rid of others that were in the default. The leading zero for latitude isn't needed, but it is there because longitude uses the same format string. One problem is the bogus zero inserted between floor(seconds) and its decimal point. The other problem is the false fractional part. The default format for that file is 42 deg 37' 28.39" N, 2 deg 5' 51.96" W
Someone's "cheat sheet" said that my second digit should be the total width, including the decimal point, so I changed the seconds to "%08.5f" but all that did was add another bogus zero in front of the decimal point, e.g., 510.00000→5100.00000 (width of ten, not eight!).
A few years ago, I did something similar, and got the correct results. But I didn't bother to save the script "for future reference."
(Several other SO answers agree with that "cheat sheet.")
It looks like the issue is with the seconds field, for which you have the format specifier %0d%02.5f. I'm not sure what you intended, but there can be only one % for each value to be rendered
If you're formatting longitude then you are dealing with values between -180 and 180. If you want five decimal points then the total width will be
One character for the sign + or -
Three characters for the integer part
One character for the decimal point .
Five fractional digits
giving a total field width of ten. Your full specifier will be %0+10.5f, giving output between «-180.00000» and «+180.00000»
You may use a space flag instead of the +, as in %0 10.5f, which will use a space instead of a + to indicate a positive number, rendering 180 as « 180.00000». The leading zero is there so that zeroes are use to fill the full ten character field with
When dealing with latitude, you will need a total width one character smaller. %0+9.5f will result in a range of «-90.00000» to «+90.00000». Of course you may use the same format specifier as for longitude, which will produce «-090.00000» to «+090.00000». This way the latitude and longitude seconds will have the same number of characters
The %0d is throwing you off. That part of the template is consuming the "51.0" seconds component of the coordinate, leaving nothing for the %02.5d part of the template.
printf "%0d", 51 ===> "51"
printf "%02.5f"; ===> "0.00000"
printf "%0d%02.5f", 51 ===> "510.00000"
So lose the %0d.
The 2 in %02.5f also doesn't do you any good. The number before the decimal place is the minimum length of the field, and the number after the decimal place is the number of decimal places to use. Since 5 decimal places will be printed, the output will be at least 7 characters, and the 2 value will be ignored.
First number is the width, second number is the number of decimal points so what you have currently (%2.5f) appears to be backwards. %5.2f would give you a number that occupies 5 characters and has 2 decimal places. For a number as big as 510, you probably want to make it %6.2f
I need to replace numbers like 2530.30 with 2599 in PostgreSQL.
I tried using ROUND(2530.30)+0.99 but it only changes the numbers after the decimal point to 99. So it results in 2530.99, which I don't want.
I want to remove fractional digits and replace the last two decimal digits with 99. I know I can just use an integer, but my assignment at school says I need to do this.
There should no be negative numbers, the assignment says that I should have a product that is sold for, let's say, 3500.50 dollars, I then need to make this number go from 3500.50 to 3599. Not 3500.99.
Divide by 100, truncate, multiply by 100 again:
SELECT trunc(2530.30 / 100) * 100 + 99;
This replaces all numbers in the range [2500, 2600) with 2599.
Or, in more general terms, it replaces the last two decimal digits with 99 and discards fractional digits (which also transforms 0 or 12.50 to 99).
Negative numbers cannot occur, as you say, so ignored.