Accept user input Range - swift

Question

I want to accept user input in a range, but keep on getting error:
Cannot convert value of type Range<Int32> to expected argument type Range<_>
I am learning Swift but I did not understand the different scenarios to convert UITextField to text and maybe integer.
class ViewController: UIViewController {
#IBOutlet weak var Range1: UITextField!
#IBOutlet weak var Range2: UITextField!
#IBOutlet weak var TheNUmber: UITextField!
#IBOutlet weak var OutletLabel: UILabel!
#IBAction func Guess(_ sender: UIButton) {
var R1 = (Range1.text! as NSString).intValue
var R2 = (Range2.text! as NSString).intValue
//print(R1, " ", R2)
var answer = Int.random(in: R1..<R2)
// I tried my best to use custom range from UItext field but did not work.
//I need more help.
print ("Random Number: \(answer)")
var turn = 0;
if(((R1>1)&&(R1<1000))&&((R2>1)&&(R2<1000))){
for i in 1...5{
let guess = (TheNUmber.text! as NSString).intValue
turn = i;
//let guess = (TheNUmber.text! as NSString).intValue
if(guess == answer){
OutletLabel.text = ("Yes, it is \(answer).")
OutletLabel.text = ("It took you \(turn) tries.")
break
}
else if(guess>answer){
OutletLabel.text = ("Lower!")
}
else if (guess<answer){
OutletLabel.text = ("Higher!")
}
else{
continue;
}
}
if (turn > 5){
OutletLabel.text = ("Sorry, it was \(answer).")
}
}
else{
OutletLabel.text = ("Keep the numbers between 1 and 100.")
}
}
#IBAction func Reset(_ sender: Any) {
self.Reset (sender)
}
I am not sure about this error. Please help me with the range.

Answer 1

The problem is that intValue returns an Int32, not an Int. So change
var R1 = (Range1.text! as NSString).intValue
var R2 = (Range2.text! as NSString).intValue
var answer = Int.random(in: R1..<R2)
To
let R1 = Int((Range1.text! as NSString).intValue)
let R2 = Int((Range2.text! as NSString).intValue)
let answer = Int.random(in: R1..<R2)
Even better, don't use NSString or intValue. Use Swift.
let R1 = Int(Range1.text!)!
let R2 = Int(Range1.text!)!
let answer = Int.random(in: R1..<R2)
Be aware that this code can crash — for example, if the user types "howdy" instead of an integer. But you need to deal with that.
Your code has other issues, but at least you will get past this one.