I have the following table
id num sub_id
1 3 1
1 5 2
1 1 1
1 4 2
2 1 5
2 2 5
I want to get this result
id num sub_id number
1 3 1 1
1 5 2 2
1 1 1 1
1 4 2 2
2 1 5 1
2 2 5 1
I tried to do this row_number() over (partition by id order by num,sub_id DESC) but th result is obviosly differs
I don't understand your business because you don't explain your logic and information about that, but maybe this query helps you?
Result and info: dbfiddle
with recursive
cte_r as (
select id,
num,
sub_id,
row_number() over () as rn
from test),
cte as (
select id,
num,
sub_id,
rn,
rn as grp
from cte_r
where rn = 1
union all
select cr.id,
cr.num,
cr.sub_id,
cr.rn,
case
when cr.id != c.id then 1
when cr.id = c.id and cr.sub_id = c.sub_id then c.grp
when cr.id = c.id and cr.sub_id > c.sub_id then c.grp + 1
when cr.id = c.id and cr.sub_id < c.sub_id then 1
end
from cte c,
cte_r cr
where c.rn = cr.rn - 1)
select id,
num,
sub_id,
grp
from cte
order by id
It looks like you actually want to ignore the num column and then use DENSE_RANK on sub_id:
SELECT *, dense_rank() AS number OVER (PARTITION BY id ORDER BY sub_id) FROM …;
I have a table with the following entries in them
id price quantity
1. 10 75
2. 10 75
3. 10 -150
4. 10 75
5. 10 -75
What I need to do is to update each row with a number that is the number of times the running total has been 0. In the above example, the cumulative totals would be
id. cum_total
1. 750
2. 1500
3. 0
4. 750
5. 0
Desired result
id price quantity seq
1. 10 75 1
2. 10 75 1
3. 10 -150 1
4. 10 75 2
5. 10 -75 2
I'm now lost in a spiral of CTEs and window functions and figured I'd ask the experts.
Thanks in advance :-)
Here is one option using analytic functions:
WITH cte AS (
SELECT *, CASE WHEN SUM(price*quantity) OVER (ORDER BY id) = 0 THEN 1 ELSE 0 END AS price_sum
FROM yourTable
),
cte2 AS (
SELECT *, LAG(price_sum, 1, 0) OVER (ORDER BY id) price_sum_lag
FROM cte
)
SELECT id, price, quantity, 1 + SUM(price_sum_lag) OVER (ORDER BY id) cumulative_total
FROM cte2
ORDER BY id;
Demo
You may try running each CTE in succession to see how the logic is working.
With window functions:
SELECT id, price, quantity,
coalesce(
sum(CASE WHEN iszero THEN 1 ELSE 0 END)
OVER (ORDER BY id
ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING),
0
) + 1 AS batch
FROM (SELECT id, price, quantity,
sum(price * quantity) OVER (ORDER BY id) = 0 AS iszero
FROM mytable) AS subq;
I have a table:
id market
1 mkt1
2 mkt2
3 mkt1
4 special
5 mkt2
6 mkt2
7 special
How can I select all columns from the table while also adding a sequential counter column, which starts counting once a condition has been triggered? In this example, when market=="special":
id market count
1 mkt1 0
2 mkt2 0
3 mkt1 0
4 special 1
5 mkt2 2
6 mkt2 3
7 special 4
Here's one option using row_number with union all:
with cte as (
select min(id) as id from t where market = 'special'
)
select t.id, t.market, 0 rn
from t join cte on t.id < cte.id
union all
select t.id, t.market, row_number() over (order by t.id) rn
from t join cte on t.id >= cte.id
Online Demo
Edited to use min after your edits...
I have a table customer_history which log customer_id and modification_date.
When customer_id is not modified there is no entry in the table
I can find when customer_id haven't been modified (=last_date_with_no_modification). I look for when the date is missing (= Gaps and Islands problem).
But in the same query if no date is missing the value last_date_with_no_modification should
be DATEADD(DAY,-1,min(modification_date)) for the customer_id.
I don't know how to add this last condition in my SQL query?
I use following tables:
"Customer_history" table:
customer_id modification_date
1 2017-12-20
1 2017-12-19
1 2017-12-17
2 2017-12-20
2 2017-12-18
2 2017-12-17
2 2017-12-15
3 2017-12-20
3 2017-12-19
"#tmp_calendar" table:
date
2017-12-15
2017-12-16
2017-12-17
2017-12-18
2017-12-19
2017-12-20
Query used to qet gap date:
WITH CTE_GAP AS
(SELECT ch.customer_id,
LAG(ch.modification_date) OVER(PARTITION BY ch.customer_id ORDER BY ch.modification_date) as GapStart,
ch.modification_date as GapEnd,
(DATEDIFF(DAY,LAG(ch.modification_date) OVER(PARTITION BY ch.customer_id ORDER BY ch.modification_date), ch.modification_date)-1) GapDays
FROM customer_history ch )
SELECT cg.customer_id,
DATEADD(DAY,1,MAX(cg.GapStart)) as last_date_with_no_modification
FROM CTE_GAP cg
CROSS JOIN #tmp_calendar c
WHERE cg.GapDays >0
AND c.date BETWEEN DATEADD(DAY,1,cg.GapStart) AND DATEADD(DAY,-1,cg.GapEnd)
GROUP BY cg.customer_id
Result:
customer_id last_date_with_no_modification
1 2017-12-18
2 2017-12-19
3 2017-12-19 (Row missing)
How to get customer_id 3?
Something this should work:
WITH CTE_GAP
AS
(
SELECT
ch.customer_id,
LAG(ch.modification_date) OVER(PARTITION BY ch.customer_id ORDER BY ch.modification_date) as GapStart,
ch.modification_date as GapEnd,
(DATEDIFF(DAY,LAG(ch.modification_date) OVER(PARTITION BY ch.customer_id ORDER BY ch.modification_date), ch.modification_date)-1) GapDays
FROM #customer_history ch
)
SELECT DISTINCT
C.customer_id
, ISNULL(LD.last_date_with_no_modification, LD_NO_GAP.last_date_with_no_modification) last_date_with_no_modification
FROM
customer_history C
LEFT JOIN
(
SELECT
cg.customer_id,
DATEADD(DAY, 1, MAX(cg.GapStart)) last_date_with_no_modification
FROM
CTE_GAP cg
CROSS JOIN #tmp_calendar c
WHERE
cg.GapDays >0
AND c.date BETWEEN DATEADD(DAY, 1, cg.GapStart) AND DATEADD(DAY, -1, cg.GapEnd)
GROUP BY cg.customer_id
) LD
ON C.customer_id = LD.customer_id
LEFT JOIN
(
SELECT
customer_id
, DATEADD(DAY, -1, MIN(modification_date)) last_date_with_no_modification
FROM customer_history
GROUP BY customer_id
) LD_NO_GAP
ON C.customer_id = LD_NO_GAP.customer_id
Can some one please help me with how to create end date from start date.
Products referred to a company for testing while the product with the company they carry out multiple tests on different dates and record the test date to establish the product condition i.e. (outcomeID).
I need to establish the StartDate which is the testDate and EndDate which is the start date of the next row. But if multiple consecutive tests resulted in the same OutcomeID I need to return only one row with the StartDate of the first test and the end date of the last test. In another word if the outcomeID did not change over a few consecutive tests.
Here is my data set
DECLARE #ProductTests TABLE
(
RequestID int not null,
ProductID int not null,
TestID int not null,
TestDate datetime null,
OutcomeID int
)
insert into #ProductTests
(RequestID ,ProductID ,TestID ,TestDate ,OutcomeID )
select 1,2,22,'2005-01-21',10
union all
select 1,2,42,'2007-03-17',10
union all
select 1,2,45,'2010-12-25',10
union all
select 1,2,325,'2011-01-14',13
union all
select 1,2,895,'2011-08-10',15
union all
select 1,2,111,'2011-12-23',15
union all
select 1,2,636,'2012-05-02',10
union all
select 1,2,554,'2012-11-08',17
--select *from #producttests
RequestID ProductID TestID TestDate OutcomeID
1 2 22 2005-01-21 10
1 2 42 2007-03-17 10
1 2 45 2010-12-25 10
1 2 325 2011-01-14 13
1 2 895 2011-08-10 15
1 2 111 2011-12-23 15
1 2 636 2012-05-02 10
1 2 554 2012-11-08 17
And this is what I need to achieve.
RequestID ProductID StartDate EndDate OutcomeID
1 2 2005-01-21 2011-01-14 10
1 2 2011-01-14 2011-08-10 13
1 2 2011-08-10 2012-05-02 15
1 2 2012-05-02 2012-11-08 10
1 2 2012-11-08 NULL 17
As you see from the dataset the first three tests (22, 42, and 45) all resulted in OutcomeID 10 so in my result I only need start date of test 22 and end date of test 45 which is the start date of test 325.As you see in test 636 outcomeID has gone back to 10 from 15 so it needs to be returned too.
--This is what I have managed to achieve at the moment using the following script
select T1.RequestID,T1.ProductID,T1.TestDate AS StartDate
,MIN(T2.TestDate) AS EndDate ,T1.OutcomeID
from #producttests T1
left join #ProductTests T2 ON T1.RequestID=T2.RequestID
and T1.ProductID=T2.ProductID and T2.TestDate>T1.TestDate
group by T1.RequestID,T1.ProductID ,T1.OutcomeID,T1.TestDate
order by T1.TestDate
Result:
RequestID ProductID StartDate EndDate OutcomeID
1 2 2005-01-21 2007-03-17 10
1 2 2007-03-17 2010-12-25 10
1 2 2010-12-25 2011-01-14 10
1 2 2011-01-14 2011-08-10 13
1 2 2011-08-10 2011-12-23 15
1 2 2011-12-23 2012-05-02 15
1 2 2012-05-02 2012-11-08 10
1 2 2012-11-08 NULL 17
nov 7 but still not answered
so here is my solution
not soo pretty but works
my hint is read about windowing , ranking and aggregate functions like row_number, rank , avg, sum etc.
those are essential when you want to write raports , and becoming quite powerfull in sql server 2012
i have also used CTE (common table expression) but it can be written as subquery or temporary table
;with cte ( ida, requestid, productid, testid, testdate, outcomeid) as
(
-- select rows where the outcome id is changing
select b.* from
(select ROW_NUMBER() over( partition by requestid, productid order by testDate) as id, * from #ProductTests)a
right outer join
(select ROW_NUMBER() over(partition by requestid, productid order by testDate) as id, * from #ProductTests) b
on a.requestID = b.requestID and a.productID = b.productID and a.id +1 = b.id
where 1=1
--or a.id = 1
and a.outcomeid <> b.outcomeid or b.outcomeid is null or a.id is null
)
select --*
a.RequestID,a.ProductID,a.TestDate AS StartDate ,MIN(b.TestDate) AS EndDate ,a.OutcomeID
from cte a left join cte b on a.requestid = b.requestid and a.productid = b.productid and a.testdate < b.testdate
group by a.RequestID,a.ProductID ,a.OutcomeID,a.TestDate
order by StartDate
Actually, there seem to be two problems in your question. One is how to group sequential (based on specific criteria) rows containing the same value. The other is the one actually spelled out in your title, i.e. how to use the next row's StartDate as the current row's EndDate.
Personally, I would solve these two problems in the order I mentioned them, so I would first address the grouping problem. One way to group the data properly in this case would be to use double ranking like this:
WITH partitioned AS (
SELECT
*,
grp = ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID ORDER BY TestDate)
- ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID, OutcomeID ORDER BY TestDate)
FROM #ProductTests
)
, grouped AS (
SELECT
RequestID,
ProductID,
StartDate = MIN(TestDate),
OutcomeID
FROM partitioned
GROUP BY
RequestID,
ProductID,
OutcomeID,
grp
)
SELECT *
FROM grouped
;
This should give you the following output for your data sample:
RequestID ProductID StartDate OutcomeID
--------- --------- ---------- ---------
1 2 2005-01-21 10
1 2 2011-01-14 13
1 2 2011-08-10 15
1 2 2012-05-02 10
1 2 2012-11-08 17
Obviously, one thing is still missing, and it's EndDate, and now is the right time to care about it. Use ROW_NUMBER() once again, to rank the result set of the grouped CTE, then use the rankings in the join condition when joining the result set with itself (using an outer join):
WITH partitioned AS (
SELECT
*,
grp = ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID ORDER BY TestDate)
- ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID, OutcomeID ORDER BY TestDate)
FROM #ProductTests
)
, grouped AS (
SELECT
RequestID,
ProductID,
StartDate = MIN(TestDate),
OutcomeID,
rnk = ROW_NUMBER() OVER (PARTITION BY RequestID, ProductID ORDER BY MIN(TestDate))
FROM partitioned
GROUP BY
RequestID,
ProductID,
OutcomeID,
grp
)
SELECT
g1.RequestID,
g1.ProductID,
g1.StartDate,
g2.StartDate AS EndDate,
g1.OutcomeID
FROM grouped g1
LEFT JOIN grouped g2
ON g1.RequestID = g2.RequestID
AND g1.ProductID = g2.ProductID
AND g1.rnk = g2.rnk - 1
;
You can try this query at SQL Fiddle to verify that it returns the output you are after.