Still learning python, and struggling with dates and na's.. I have a situation as the image below would show
enter image description here
for the NAT values in the column EndDT_New, i would like to fill them with a specific value based on a condition, eg:
if the DATE_ACT_CLOSED = '01/01/2040' then replace just the NAT in EndDT_New with 30/03/2021 else
if the DATE_ACT_CLOSED <> '01/01/2040', then replace just the NAT in EndDT_New with the value in DATE_ACT_CLOSED .
My previous experience is in SAS, so its quite a learning curve and mind shift to python.
Any help is much appreciated.
Kind Regards,
i reckon i figured it out.
df_all_valid.loc[(np.isnat(df_all_valid['EndDT_New'])==True) & (df_all_valid['DATE_ACT_CLOSED'] == '01/01/2040'), 'EndDT_New'] = np.datetime64('2021-03-30')
Related
I want to create a variable called 'flag_artifact' where certain subjects from my dataset (for whom I know have bad quality images) are coded as e.g., 1. My dataset is stored in a table T with a certain number of rows and 'subject' is the 1st column in the table.
I managed to do it by creating a for loop. Surely there is a more efficient way to do this by perhaps directly creating the variable and using less lines of code? Could anyone give some advice?
Thank you very much! Here is what I have:
flag_artifact = {'T_300'}; %flagging subject number 300 for example
for i = 1:size(T,1)
if isequal(table2cell(T(i, 1)), flag_artifact)
T(i, 1) = {'1'};
end
end
However, when creating the variable flag_artifact = {'T_300'}, I would like it to include more than one subject. I tried using flag_artifact = {'T_300'}; {'T_301'}, as well as flag_artifact = {'T_300', 'T_301'} but it doesn't work because these subject identifiers do not get replaced with 1s.
GAMS: I think I have a pretty simple question, however I'm stuck and was wondering if someone could help here.
A simplified version of my model looks like this:
set(i,t) ;
parameter price
D;
variable p(i,t)
e(i,t);
equations
Equation1
obj.. C=sum((i,t), p(i,t)*price);
Model file /all/ ;
Solve file minimizing C using MIP ;
Display C.l;
p(i,t) and e(i,t) are related:
Equation1 .. e(i,t)=e=e(i,t-1)+p(i,t)*D
Now I want to retrieve information from the solution: lets say I want to know at what t e(i,t) has a certain value for example --> e(i,t)= x(i) or otherwise formulated e(i,t=TD)=x(i) find TD, where x(i) thus is depending on i. Does anyone know how I can write this in to my GAMs model? To be clear I do not want to change anything about my solution and the model I have runs; I just want to retrieve this information from the solution given.
So far I tried a couple of thing and nothing worked. I think that this must be simple, can anyone help? Thank you!
Try something like this:
set i /i1*i10/
t /t1*t10/;
variable e(i,t);
*some random dummy "solution"
e.l(i,t) = uniformInt(1,10);
set find5(i,t) 'find all combinations of i and t for which e.l=5';
find5(i,t)$(e.l(i,t)=5) = yes;
display e.l,find5;
Hope that helps,
Lutz
I am using Matlab to read a workbook with a bunch of sheets in it.
I do some calculation and have to update one particular column in one sheet. I tried using xlswrite after xlsread, it does not work.
So, my code looks something like:
[~,~,Data] = xlsread('MyFile.xlsx', 'MySheet');
Data(2:end-1,5) = Data(2:end-1,5) + 1.5; %Random operation for illustration only
ret = xlswrite('MyFile.xlsx',Data,'MySheet');
But ret is 0. So, I am not able to achieve replacement process. Can you please help.
Thanks
Based on my own comment:
Please use the second output argument as well an check what message you get:
[status,message] = xlswrite(filename,A,sheet)
Hopefully that is sufficient to find the cause, please let us know if that's the case.
Apparently it was indeed sufficient for the asker.
I've been looking throught the documentation, but can't seem to find the bit I want.
I have a for loop and I would like to be able to view every value in the for loop.
for example here is a part of my code:
for d = 1 : nb
%for loop performs blade by blade averaging and produces a column vector
for cc = navg : length(atbmat);
atb2 = (sum(atbmat((cc-(navg-1):cc),d)))/navg;
atbvec2(:,cc) = atb2;
end
%assigns column vector 'atbvec2' to the correct column of the matrix 'atbmat2'
atbmat2(d,1:length(atbvec2)) = atbvec2;
end
I would like to view every value of atb2. I'm a python user(new to MATLAB) and would normally use a simple print statement to find this.
I'm sure there is a way to do it, but I can't quite find how.
Thankyou in advance.
you can use disp in Matlab to print to the screen but you might want to use sprintf first to format it nicely. However for debugging you're better off using a break point and then inspect the variable in the workspace browser graphically. To me, this is one of Matlab's best features.
Have a look at the "Examine Values" section of this article
The simplest way to view it everywhere is to change this line:
atb2 = (sum(atbmat((cc-(navg-1):cc),d)))/navg;
Into this, without semicolon:
atb2 = (sum(atbmat((cc-(navg-1):cc),d)))/navg
That being said, given the nature of your calculation, you could get the information you need as well by simply storing every value of abt2 and observing them afterwards. This may be done in atbmat2 already?
If you want to look at each value at the time it happens, consider setting a breakpoint or conditional breakpoint after the line where abt2 is assigned.
I am trying to figure out how to get the position of a selected Range in an Excel(2007)-Worksheet. Is there something similar to $self->{EXCEL}->ActiveCell->Row for Cells (self->{EXCEL} being an Excel-Object)?
I tried ->Selection->Range, ->ActiveSheet->Range, and as a workaround ->Range->Row, ->Range->Rows both with an Excel- and a Worksheet-Object with no success.
The most fancy output being two Cell-Objects, one for the start-address, the other one end-address.
Thanks for any helpful hints!
=== Update ===
I now use successfully the command $self->{EXCEL}->Selection->Address(); to retrieve the address of the selected range. By default I get the address in "A1"-format ($E$1:$G$14). Using ->Address("ToReferenceStyle:=xlR1C1") however does not return the address in "R1C1"-format as I would have expected...
Faulty command? Ignorant Excel? Thanky again on any helpful hint!
How about ->Selection->Address? I'm not sure on the format, but the address property of the selection (range object) will give you the address of the range for example. $A$1:$B$7. You would be able to parse the start and end by splitting the string on the colon.
To address your new questions... I'm not even sure if what you're using, but the third parameter of the address method is ReferenceStyle not ToReferenceStyle. So I would try either ->Address(ReferenceStyle:=xlR1C1) or ->Address(,,xlR1C1)