kdb: getting one row from HDB - kdb

For a normal table, we can select one row using select[1] from t. How can I do this for HDB?
I tried select[1] from t where date=2021.02.25 but it gives error
Not yet implemented: it probably makes sense, but it’s not defined nor implemented, and needs more thinking about as the language evolves

select[n] syntax works only if table is already loaded in memory.
The easiest way to get 1st row of HDB table is:
1#select from t where date=2021.02.25
select[n] will work if applied on already loaded data, e.g.
select[1] from select from t where date=2021.02.25

I've done this before for ad-hoc queries by using the virtual index i, which should avoid the cost of pulling all data into memory just to select a couple of rows. If your query needs to map constraints in first before pulling a subset, this is a reasonable solution.
It will however pull N rows for each date partition selected due to the way that q queries work under the covers. So YMMV and this might not be the best solution if it was behind an API for example.
/ 5 rows (i[5] is the 6th row)
select from t where date=2021.02.25, sum=`abcd, price=1234.5, i<i[5]

If your table is date partitioned, you can simply run
select col1,col2 from t where date=2021.02.25,i=0
That will get the first record from 2021.02.25's partition, and avoid loading every record into memory.
Per your first request (which is different to above) select[1] from t, you can achieve that with
.Q.ind[t;enlist 0]

Related

How to generate line segments from survey records using PostGIS

I have a table of survey locations as
id,from,to,azimuth,x,y
'L1',0,5,120,508776,7098873
'L1',5,10,141,null,null
'L1',10,24,121,null,null
'L2',0,12,135,507882,8020098
'L2',12,15,121,null,null
'L2',15,25,null,null
Each line "id" can have 2 or more records defining their geometry.
Using a postgis query, how can I create line segments for each of these records, assuming the x and y values for the line starts are in EPSG:3578?
I've tried LAG and LEAD OVER (Partition BY "id" order by "from_m"), but I get lost in the recursion needed. Is what I'm attempting possible?
If you select the whole table the database will run the LAG/LEAD OVER for every selected row. You can return a new column with the result. I think this is already the recursion you need.
I once did this with time based positions and created a line from the temporal latest point to his ancestor. I ordered by time - in your case you need to order by 'from' or 'to'. Sometimes running an independent query for every id is easier than doing the whole thing at once.
Have a look at this thread, they are trying pretty much the opposite of what you want, but maybe it will help you clarify things.

Understanding SQL query complexity

I'm currently having trouble understanding why a seemingly simple query is taking much longer to return results than a much more complicated (looking) query.
I have a view, performance_summary (which in turn selects from another view). Currently, within psql, when I run a query like
SELECT section
FROM performance_summary
LIMIT 1;
it takes a minute or so to return a result, whereas a query like
SELECT section, version, weighted_approval_rate
FROM performance_summary
WHERE version in ('1.3.10', '1.3.11') AND section ~~ '%WEST'
ORDER BY 1,2;
gets results almost instantly. Without knowing how the view is defined, is there any obvious or common reason why this is?
Not really, without knowing how the view is defined. It could be that the "more complex" query uses an index to select just two rows and then perform some trivial grouping sorting on the two. The query without the where clause might see postgres operating on millions of rows, trillions of operations and producing a single row out after discarding 999999999 rows, we just don't know unless you post the view definition and the explain plan output for both queries
You might be falling into the trap of thinking that a View is somehow a cache of info - it isn't. It's a stored query, that is inserted into the larger query when you select from it/include it in another query- this means that the whole thing must be planned and executed from scratch. There isn't a notion that creating a View does any pre planning etc, onto which other further improvement is done. It's more like the definition of the View is pasted into any query that uses it, then the query is run as if it were just written there and then

Data Lake Analytics - Large vertex query

I have a simple query which make a GROUP BY using two fields:
#facturas =
SELECT a.CodFactura,
Convert.ToInt32(a.Fecha.ToString("yyyyMMdd")) AS DateKey,
SUM(a.Consumo) AS Consumo
FROM #table_facturas AS a
GROUP BY a.CodFactura, a.DateKey;
#table_facturas has 4100 rows but query takes several minutes to finish. Seeing the graph explorer I see it uses 2500 vertices because I'm having 2500 CodFactura+DateKey unique rows. I don't know if it normal ADAL behaviour. Is there any way to reduce the vertices number and execute this query faster?
First: I am not sure your query actually will compile. You would need the Convert expression in your GROUP BY or do it in a previous SELECT statement.
Secondly: In order to answer your question, we would need to know how the full query is defined. Where does #table_facturas come from? How was it produced?
Without this information, I can only give some wild speculative guesses:
If #table_facturas is coming from an actual U-SQL Table, your table is over partitioned/fragmented. This could be because:
you inserted a lot of data originally with a distribution on the grouping columns and you either have a predicate that reduces the number of rows per partition and/or you do not have uptodate statistics (run CREATE STATISTICS on the columns).
you did a lot of INSERT statements, each inserting a small number of rows into the table, thus creating a big number of individual files. This will "scale-out" the processing as well. Use ALTER TABLE REBUILD to recompact.
If it is coming from a fileset, you may have too many small files in the input. See if you can merge them into less, larger files.
You can also try to hint a small number of rows in your query that creates #table_facturas if the above does not help by adding OPTION(ROWCOUNT=4000).

kdb+/q optimize union function

To give you a bit of background. I have a process which does this large complex calculation which takes a while to complete. It runs on a timer. After some investigation I realise that what is causing the slowness isn't the actual calculation but the internal q function, union.
I am trying to union two simple tables, table A and table B. A is approximately 5m rows and B is 500. Both tables have only two columns. First column is a symbol. Table A is actually a compound primary key of a table. (Also, how do you copy directly from the console?)
n:5000000
big:([]n?`4;n?100)
small:([]500?`4;500?100)
\ts big union small
I tried keying both columns and upserting, join and then distinct, "big, small where not small in big" but nothing seems to work :(
Any help will be appreciated!
If you want to upsert the big table it has to be keyed and upsert operator should be used. For example
n:5000000
//big ids are unique numbers from 0 to 499999
//table is keyed with 1! operator
big:1!([]id:(neg n)?n;val:n?100)
//big ids are unique numbers. 250 from 0-4999999 and 250 from 500000-1000000 intervals
small:([]id:(-250?n),(n+-250?n);val:500?100)
If big is global variable it is efficient to upsert it as
`big upsert small
if big is local
big: big upsert small
As the result big will have 500250 elements, because there are 250 common keys (id column) in big and small tables
this may not be relevant, but just a quick thought. If your big table has a column which has type `sym and if this column does not really show up that much throughout your program, why not cast it to string or other value? if you are doing this update process every single day then as the data gets packed in your partitioned hdb, whenever the new data is added, kdb+ process has to reassign/rewrite its sym file and i believe this is the part that actually takes a lot of time, not the union calculation itself..
if above is true, i'd suggest either rewriting your schema for the table which minimises # of rehashing(not sure if this is the right term though!) on your symfile. or, as the above person mentioned, try to assign attribute to your table.. this may reduce the time too.

Efficient way of insert millions of rows, convert data and deal with it, on PostgreSQL+PostGIS

I have a big collection of data I want to use for user search later.
Currently I have 200 millions resources (~50GB). For each, I have latitude+longitude. The goal is to create spatial index to be able to do spatial queries on it.
So for that, the plan is to use PostgreSQL + PostGIS.
My data are on CSV file. I tried to use custom function to not insert duplicates, but after days of processing I gave up. I found a way to load it fast in the database: with COPY it takes less than 2 hours.
Then, I need to convert latitude+longitude on Geometry format. For that I just need to do:
ST_SetSRID(ST_MakePoint(longi::double precision,lat::double precision),4326))
After some checking, I saw that for 200 millions, I have 50 millions points. So, I think the best way is to have a table "TABLE_POINTS" that will store all the points, and a table "TABLE_RESOURCES" that will store resources with point_key.
So I need to fill "TABLE_POINTS" and "TABLE_RESOURCES" from temporary table "TABLE_TEMP" and not keeping duplicates.
For "POINTS" I did:
INSERT INTO TABLE_POINTS (point)
SELECT DISTINCT ST_SetSRID(ST_MakePoint(longi::double precision,lat::double precision),4326))
FROM TABLE_RESOURCES
I don't remember how much time it took, but I think it was matter of hours.
Then, to fill "RESOURCES", I tried:
INSERT INTO TABLE_RESOURCES (...,point_key)
SELECT DISTINCT ...,point_key
FROM TABLE_TEMP, TABLE_POINTS
WHERE ST_SetSRID(ST_MakePoint(longi::double precision,lat::double precision),4326) = point;
but again take days, and there is no way to see how far the query is ...
Also something important, the number of resources will continue to grow up, currently should be like 100K added by day, so storage should be optimized to keep fast access to data.
So if you have any idea for the loading or the optimization of the storage you are welcome.
Look into optimizing postgres first (ie google postgres unlogged, wal and fsync options), second do you really need points to be unique? Maybe just have one table with resources and points combined and not worry about duplicate points as it seems your duplicate lookup maybe whats slow.
For DISTINCT to work efficiently, you'll need a database index on those columns for which you want to eliminate duplicates (e.g. on the latitude/longitude columns, or even on the set of all columns).
So first insert all data into your temp table, then CREATE INDEX (this is usually faster that creating the index beforehand, as maintaining it during insertion is costly), and only afterwards do the INSERT INTO ... SELECT DISTINCT.
An EXPLAIN <your query> can tell you whether the SELECT DISTINCT now uses the index.