Is realm.write asynchronous - swift

I am trying to add CustomUserData to my MongoDB Realm Database and then refresh the user data.
But as it seems is realm.write asynchronous, whereas I thought it would be synchronous (Swift Realm Write method is Sync or Async Thread). So my question is what's really the case and when its synchronous why does the .refreshCustomData() function is only able to fetch the new data after a short delay.
try! realm.write {
realm.add(member)
}
app.currentUser!.refreshCustomData()
// -> after the refresh the customUserData is still empty
// only if you call it with a short delay the result contains the new written data

No, it is not asynchronous.
Have a look at the implementation (removed everything that is not important to understand).
A write transaction is simply started and committed if no exception has occurred, otherwise the transaction is rolled back.
public func write<Result>(_ block: (() throws -> Result)) throws -> Result {
beginWrite()
var ret: Result!
do {
ret = try block()
} catch let error {
if isInWriteTransaction { cancelWrite() }
throw error
}
if isInWriteTransaction { try commitWrite(withoutNotifying: tokens) }
return ret
}
But: If you query the data just written in another thread, that is another story.
New objects just wont be visible on another thread for some time.
My solutions to this is: stay on the same thread for write and read operations.
See also: Saving data and query it in different threads with Realm

Related

Combine: How to clean up resources while an AnyCancellable is being cancelled?

Overview:
I have a async task to fetch from the database
I have created a Future for the async task (fetching from the database).
Question:
How can execute custom code when the Future is cancelled?
Purpose:
I would like the database connection to be closed when the subscription is cancelled.
For example, I would like to use Combine to rewrite this helper method:
// Similar to https://developer.apple.com/documentation/coredata/nspersistentcontainer/1640564-performbackgroundtask
func withDatabaseFTSContext(block: #escaping (FMDatabase?) -> Void) {
queue.async {
guard let database = self.database else {
block(nil)
return
}
database.open()
let simpleTokenizer = FMSimpleTokenizer(locale: nil)
FMDatabase.registerTokenizer(simpleTokenizer, withKey: "simple")
database.installTokenizerModule()
block(database)
database.close()
}
}
Could I leverage Combine to rewrite this method to return FMDatabase as a parameter of a publisher?
I was attempting to use Combine but it does not work. The database will be closed before cancel()
private func withDatabaseFTSContext() -> AnyPublisher<FMDatabase?, Never> {
return Future<FMDatabase?, Never> { promise in
self.queue.async {
guard let database = self.database else {
promise(.success(nil))
return
}
database.open()
let simpleTokenizer = FMSimpleTokenizer(locale: nil)
FMDatabase.registerTokenizer(simpleTokenizer, withKey: "simple")
database.installTokenizerModule()
promise(.success(database))
database.close() // When to close this database? Currently it will be closed before `cancel()`
}
}.eraseToAnyPublisher()
}
Short answer: there isn't a callback that triggers through to the underlying Future that you can use to clean things up on a subscriber cancel. In the Combine design, these functions are very intentionally separated and don't have reference links back to their publishers.
(In addition, Future is a tricky figure in the Combine world because the closure is invoked immediately upon creation time, rather than when you have a subscription (if you want that, wrap in the Future publisher in a Deferred publisher)).
All that being said, what you likely want to do to solve your underlying problem is reframe how you're treating this to separate the concerns of managing the FMDB instance and publishing data. One pattern that's been reasonably useful in this context is to the make an object that holds the lifetime of the FMDB reference, and handle cleaning up resources on it's deinit(). You can then also have a function which vends a Publisher of whatever you need from that same object, and then the cancellation of the request is changed semantically to only cancelling getting the database, not cancelling and cleaning up the database connection.

How to call every struct method inside write transaction

I created struct Repository for manipulating with objects of Realm database (changing some properties, adding new objects, deleting, etc.). When I want to write to the database, I have to do it inside do-try-catch block, so I created a method with completion which I call every time I need to write something to the database
private func action(_ completion: () -> Void) {
do {
try realm.write {
completion()
}
} catch {
print(error)
}
}
then I call methods for manipulating with objects like this:
func createObject(_ object: MyObject) {
action {
realm.add(object)
}
}
func deleteObject(_ object: MyObject) {
action {
realm.delete(object)
}
}
func setTitleForObject(_ object: MyObject, title: String) {
action {
object.title = title
}
}
...
My question is, is there any way how I can call every method inside this Repository struct inside write transaction in do-try-catch block by default instead of calling it inside completion of action? (or is some better way how to write to the Realm database without do-try-catch block?)
Short answer is no, there is no way to write data to realm without write transaction and without try-catch.
realm.write() is a convenient wrapper of transaction building with beginWrite() and commitWrite() calls.
These two functions build a transaction and commitWrite() is throwable, so you need to wrap to try-catch, anyway.
See https://realm.io/docs/swift/latest#writes
Example of using beginWrite()+commitWrite() https://realm.io/docs/swift/latest#interface-driven-writes
There are a lot of failures could happen during write transactions. So, simply, it is not safe to not to handle it somehow.
Also grouping write transactions by "action" is not a good idea if you going to process big amounts of objects because write transactions are costly. You'd rather group these changes to a single transaction instead of having a lot of small transactions.

All asynchronous calls succeed or none, how to handle

I'm trying to create an online mobile application and can't figure out the best way to handle functions with multiple asynchronous calls. Say I have a function for example that updates a user in some way, but involved multiple asynchronous calls in the single function call. So for example:
// Function caller
update(myUser) { (updatedUser, error) in
if let error = error {
// Present some error UI to the user
}
if let updatedUser = updatedUser {
// Do something with the user
}
}
// Function implementation
public func updateUser(user: User, completion: #escaping (User?, Error?) -> () {
// asynchronous call A
updateUserTable(user: User) { error in
if let error = error {
completion(nil, error)
} else {
// create some new user object
completion(user, nil)
}
}
// asynchronous call B
uploadMediaForUser(user: User) { error in
if let error = error {
completion(nil, error)
}
}
// asynchronous call C
removeOldReferenceForUser(user: User) { error in
if let error = error {
completion(nil, error)
}
}
// Possibly any additional amount of asynchronous calls...
}
In a case like this, where one function call like updating a user involved multiple asynchronous calls, is this an all or nothing situation? Say for example the updateUserTable() call completes, but the user disconnects from the internet as uploadMediaForUser() was running, and that throws an error. Since updateUserTable() completed fine, my function caller thinks this method succeeded when in fact not everything involved in updating the user completed. Now I'm stuck with a user that might have mismatched references or wrong information in my database because the user's connection dropped mid call.
How do I handle this all or nothing case? If EVERY asynchronous call completed without an error, I know updating the user was a success. If only a partial amount of asynchronous calls succeeded and some failed, this is BAD and I need to either undo the changes that succeeded or attempt the failed methods again.
What do I do in this scenario? And also, and how do I use my completion closure to help identify the actions needed depending on the success or failure of the method. Did all them succeed? Good, tell the user. Do some succeed and some failed? Bad, revert changes or try again (i dont know)??
Edit:
Just calling my completion with the error doesn't seem like enough. Sure the user sees that something failed, but that doesn't help with the application knowing the steps needed to fix the damage where partial changes were made.
I would suggest adding helper enums for your tasks and returned result, things like (User?, Error?) have a small ambiguity of the case when for example both are nil? or you have the User and the Error set, is it a success or not?
Regarding the all succeeded or some failed - I would suggest using the DispatchGroup to notify when all tasks finished (and check how they finished in the end).
Also from you current code, when some request fails it's not clear for which user - as you pass nil, so it might bring difficulties in rolling it back after failure.
So in my point of view something like below (not tested the code, but think you should catch the idea from it) could give you control about the issues you described:
public enum UpdateTask {
case userTable
case mediaUpload
// ... any more tasks you need
}
public enum UpdateResult {
case success
case error([UpdateTask: Error])
}
// Function implementation
public func updateUser(user: User, completion: #escaping (User, UpdateResult) -> ()) {
let updateGroup = DispatchGroup()
var tasksErrors = [UpdateTask: Error]()
// asynchronous call A
updateGroup.enter()
updateUserTable(user: User) { error in
if let error = error {
tasksErrors[.userTable] = error
}
updateGroup.leave()
}
// ... any other similar tasks here
updateGroup.notify(queue: DispatchQueue.global()) { // Choose the Queue that suits your needs here by yourself
if tasksErrors.isEmpty {
completion(user, .success)
} else {
completion(user, .error(tasksErrors))
}
}
}
Keep a “previous” version of everything changed, then if something failed revert back to the “previous” versions. Only change UI once all returned without failure, and if one failed, revert to “previous” version.
EX:
var temporary = “userName”
getChanges(fromUser) {
If error {
userName = temporary //This reverts back due to failure.
}
}

Realm notifications registration while in write transaction

I understand that you can not register a Realm .observe block on an object or collection if the Realm is in a write transaction.
This is easier to manage if everything is happening on the main thread however I run into this exception often because I prefer to hand my JSON parsing off to a background thread. This works great because I don't have to bog down the main thread and with Realm's beautiful notification system I can get notified of all modifications if I have already registered to listen for those changes.
Right now, if I am about to add an observation block I check to make sure my Realm is not in a write transaction like this:
guard let realm = try? Realm(), !realm.isInWriteTransaction else {
return
}
self.myToken = myRealmObject.observe({ [weak self] (change) in
//Do what ever
}
This successfully guards against this exception. However I never get a chance to re - register this token unless I get a little creative.
Does the Realm team have any code examples/ suggestions on a better pattern to avoid this exception? Any tricks I'm missing to successfully register the token?
In addition to the standard function, I do use an extension for Results to avoid this in general. This issue popped up, when our data load grew bigger and bigger.
While we do now rewrite our observe functions logic, this extension is an interims solution to avoid the crashes at a first place.
Idea is simple: when currently in a write transaction, try it again.
import Foundation
import RealmSwift
extension Results {
public func safeObserve(on queue: DispatchQueue? = nil,
_ block: #escaping (RealmSwift.RealmCollectionChange<RealmSwift.Results<Element>>) -> Void)
-> RealmSwift.NotificationToken {
// If in Write transaction, call it again
if self.realm?.isInWriteTransaction ?? false {
DispatchQueue.global().sync {
Thread.sleep(forTimeInterval: 0.1) // Better to have some delay than a crash, hm?
}
return safeObserve(on: queue, block)
}
// Aight, we can proceed to call Realms Observe function
else {
return self.observe(on: queue, block)
}
}
}
Then call it like
realmResult.safeObserve({ [weak self] (_: RealmCollectionChange<Results<AbaPOI>>) in
// Do anything
})

Does throwing a asynchronous function make it synchronous in Swift?

This is a code example taken from Perfect Swift PostgresSTORM library.
do{
//Create a user object
let obj = User()
obj.name = "someUser"
//Save it to db
try obj.save({ id in
print(2..)
obj.id = id as! Int
})
print("1..")
}catch{
print("Something went wrong.")
}
//Go to next page
print("3..")
I expected to see the print logs to be
1..
3..
2..
but, The logs looked like this.
2..
1..
3..
It's highly unlikely for "2.." to print before "1..". Is it the "try" that's making it to run as a synchronous function?
It's totally up to PostgresSTORM implementation of save. I'm not familiar with it so I can't say whether it's actually asynchronous or not but I can offer you two dummy implementations, one asynchronous and one synchronous of a method with a similar signature.
Asynchronous:
func save(callback: #escaping (Int) -> Void) throws {
OperationQueue.main.addOperation {
callback(0)
}
}
Synchronous:
func save(callback: (Int) -> Void) throws {
callback(0)
}
(Note that it doesn't throw any exception in this example just for simplicity's sake).
try is required by Swift compiler when you call a function that might throw an exception and has no impact in (a)synchronous execution of the method. In fact try is just required to ensure that when we use the method we are well aware about it possibly throwing an exception.
I might be wrong but if this is SwiftORM's implementation of save method then callback is always synchronously called.