How can I toggle two LEDs at difference frequencies using SYSTICK on keil for the ST32 processor - toggle

Question

I want to toggle each LED one aT 4Hz and one at 3Hz, so far i can only toggle 2 at the same frequency.So far i can do them separately only but i dont know how to write to code to combine them so i can run it all at the same time.
// THIS CODE IS FOR BOTH
int main (void){
//Enable clock for GPIO A and Gpio B
RCC->AHB2ENR |= 0x3UL;
//Configure PA_0 and PA_1
GPIOA->MODER &= ~0xFUL ;
GPIOA->MODER |= 0x5UL;
GPIOA-> PUPDR &= ~0XFUL;
GPIOA-> PUPDR |= 0xAUL;
//FOR LED GREEN
SysTick ->LOAD = 1000000-1 ;
SysTick-> VAL = 0;
SysTick->CTRL |= 0x5UL;
while (1)
{
if (SysTick -> CTRL & SysTick_CTRL_COUNTFLAG_Msk)
{
GPIOA->ODR ^= 0x2UL;
}
}
}
//THEN deleting LED GREEN TO WRITE LED orange
SysTick ->LOAD = 666667-1 ;
SysTick-> VAL = 0;
SysTick->CTRL |= 0x5UL;
while (1)
{
if (SysTick -> CTRL & SysTick_CTRL_COUNTFLAG_Msk)
{
GPIOA->ODR ^= 0x1UL;
}
}
}
i just need help to combine them mainly the systick->load for each led.

Answer 1

Do not use systick this way. Set the systick interrupt to be triggered lets say 1000 times per second (standard STM startup files do it this way)
Then toggle LEDs in the interrupt handler
volatile uint32_t count = 0;
void SysTick_Handler(void)
{
count++;
if(!(count % (1000 / 8))) GPIOA -> ODR ^= 1; // 4 blinks per secons
if(!(count % (1000 / 6))) GPIOA -> ODR ^= 2; // 3 blinks per second
}