I am trying to solve Two sum problem using scala
val list = List(1,2,3,4,5)
val map = collection.mutable.Map.empty[Int, Int]
val sum = 9
for {
i <- 0 until list.size
} yield {
map.get(sum - list(i)) match {
case None => map += (list(i) -> i)
case Some(previousIndex) => println(s" Indexes $previousIndex $i")
}
}
Can anyone suggest an O(n) solution without using mutable map using scala
If you are trying to solve "Two sum problem" - meaning you need from given list find two numbers which gives sum equal to given, can go with:
val list = List(1,2,3,4,5)
val sum = 9
val set = list.toSet
val solution = list.flatMap { item =>
val rest = sum - item
val min = Math.min(item, rest)
val max = Math.max(item, rest)
if (set(rest)) Some(min, max) else None
}.toSet
println(solution)
Print result:
Set((4,5))
ScalaFiddle: https://scalafiddle.io/sf/LA6P3eh/0
UPDATE
The result required to return indices not values:
val list = List(1,2,3,4,5)
val sum = 9
val inputMap = list.zipWithIndex.toMap
val solution = list.zipWithIndex.flatMap { case (item, itemIndex) =>
inputMap.get(sum - item).map { restIndex =>
val minIndex = Math.min(itemIndex, restIndex)
val maxIndex = Math.max(itemIndex, restIndex)
minIndex -> maxIndex
}
}.toSet
println(solution)
Printout: Set((3,4))
ScalaFiddle: https://scalafiddle.io/sf/LA6P3eh/1
You can try something as follows for the first result:
object Solution extends App {
def twoSums(xs: List[Int], target: Int): Option[(Int,Int)] = {
#annotation.tailrec def go(zipped: List[(Int,Int)], map: Map[Int,Int] = Map.empty): Option[(Int,Int)] = {
zipped match {
case Nil => None
case (ele, idx) :: tail =>
map.get(target - ele) match {
case Some(prevIdx) => Some((prevIdx, idx))
case None => go(tail, map + (ele -> idx))
}
}
}
go(xs.zipWithIndex)
}
val res = twoSums(List(1,2,3,4,5), 9)
println(res)
}
Or via foldLeft for all results:
object Solution extends App {
def twoSums(xs: List[Int], target: Int): List[(Int, Int)] = {
xs.zipWithIndex.foldLeft((Map.empty[Int,Int], List.empty[(Int,Int)])) {
case ((map, results), (ele, idx)) =>
map.get(target - ele) match {
case Some(prevIdx) =>(map, (prevIdx, idx) :: results)
case None => (map + (ele -> idx), results)
}
}
}._2
val res = twoSums(List(1,2,3,4,5), 9)
println(res)
}
Related
I have a Scala list below :
val numList = List(1,2,3,4,5,1,2)
I want to get index of the same element pair in the list. The output should look like (0,5),(1,6)
How can I achieve using map?
def catchDuplicates(num : List[Int]) : (Int , Int) = {
val count = 0;
val emptyMap: HashMap[Int, Int] = HashMap.empty[Int, Int]
for (i <- num)
if (emptyMap.contains(i)) {
emptyMap.put(i, (emptyMap.get(i)) + 1) }
else {
emptyMap.put(i, 1)
}
}
Let's make the challenge a little more interesting.
val numList = List(1,2,3,4,5,1,2,1)
Now the result should be something like (0, 5, 7),(1, 6), which makes it pretty clear that returning one or more tuples is not going to be feasible. Returning a List of List[Int] would make much more sense.
def catchDuplicates(nums: List[Int]): List[List[Int]] =
nums.zipWithIndex //List[(Int,Int)]
.groupMap(_._1)(_._2) //Map[Int,List[Int]]
.values //Iterable[List[Int]]
.filter(_.lengthIs > 1)
.toList //List[List[Int]]
You might also add a .view in order to minimize the number of traversals and intermediate collections created.
def catchDuplicates(nums: List[Int]): List[List[Int]] =
nums.view
.zipWithIndex
.groupMap(_._1)(_._2)
.collect{case (_,vs) if vs.sizeIs > 1 => vs.toList}
.toList
How can I achieve using map?
You can't.
Because you only want to return the indexes of the elements that appear twice; which is a very different kind of transformation than the one that map expects.
You can use foldLeft thought.
object catchDuplicates {
final case class Result[A](elem: A, firstIdx: Int, secondIdx: Int)
private final case class State[A](seenElements: Map[A, Int], duplicates: List[Result[A]]) {
def next(elem: A, idx: Int): State[A] =
seenElements.get(key = elem).fold(
ifEmpty = this.copy(seenElements = this.seenElements + (elem -> idx))
) { firstIdx =>
State(
seenElements = this.seenElements.removed(key = elem),
duplicates = Result(elem, firstIdx, secondIdx = idx) :: this.duplicates
)
}
}
private object State {
def initial[A]: State[A] =
State(
seenElements = Map.empty,
duplicates = List.empty
)
}
def apply[A](data: List[A]): List[Result[A]] =
data.iterator.zipWithIndex.foldLeft(State.initial[A]) {
case (acc, (elem, idx)) =>
acc.next(elem, idx)
}.duplicates // You may add a reverse here if order is important.
}
Which can be used like this:
val numList = List(1,2,3,4,5,1,2)
val result = catchDuplicates(numList)
// result: List[Result] = List(Result(2,1,6), Result(1,0,5))
You can see the code running here.
I think returning tuple is not a good option instead you should try Map like -
object FindIndexOfDupElement extends App {
val numList = List(1, 2, 3, 4, 5, 1, 2)
#tailrec
def findIndex(elems: List[Int], res: Map[Int, List[Int]] = Map.empty, index: Int = 0): Map[Int, List[Int]] = {
elems match {
case head :: rest =>
if (res.get(head).isEmpty) {
findIndex(rest, res ++ Map(head -> (index :: Nil)), index + 1)
} else {
val updatedMap: Map[Int, List[Int]] = res.map {
case (key, indexes) if key == head => (key, (indexes :+ index))
case (key, indexes) => (key, indexes)
}
findIndex(rest, updatedMap, index + 1)
}
case _ => res
}
}
println(findIndex(numList).filter(x => x._2.size > 1))
}
you can clearly see the number(key) and respective index in the map -
HashMap(1 -> List(0, 5), 2 -> List(1, 6))
I have the following issue
Given this list in input , I want to concateneate integers for each line having the same title,
val listIn= List("TitleB,Int,11,0",
"TitleB,Int,1,0",
"TitleB,Int,1,0",
"TitleB,Int,3,0",
"TitleA,STR,3,0",
"TitleC,STR,4,5")
I wrote the following function
def sumB(list: List[String]): List[String] = {
val itemPattern = raw"(.*)(\d+),(\d+)\s*".r
list.foldLeft(ListMap.empty[String, (Int,Int)].withDefaultValue((0,0))) {
case (line, stri) =>
val itemPattern(k,i,j) = stri
val (a, b) = line(k)
line.updated(k, (i.toInt + a, j.toInt + b))
}.toList.map { case (k, (i, j)) => s"$k$i,$j" }
}
Expected output would be:
List("TitleB,Int,16,0",
"TitleA,STR,3,0",
"TitleC,STR,4,5")
Since you are looking to preserve the order of the titles as they appear in the input data, I would suggest you to use LinkedHashMap with foldLeft as below
val finalResult = listIn.foldLeft(new mutable.LinkedHashMap[String, (String, String, Int, Int)]){ (x, y) => {
val splitted = y.split(",")
if(x.keySet.contains(Try(splitted(0)).getOrElse(""))){
val oldTuple = x(Try(splitted(0)).getOrElse(""))
x.update(Try(splitted(0)).getOrElse(""), (Try(splitted(0)).getOrElse(""), Try(splitted(1)).getOrElse(""), oldTuple._3+Try(splitted(2).toInt).getOrElse(0), oldTuple._4+Try(splitted(3).toInt).getOrElse(0)))
x
}
else {
x.put(Try(splitted(0)).getOrElse(""), (Try(splitted(0)).getOrElse(""), Try(splitted(1)).getOrElse(""), Try(splitted(2).toInt).getOrElse(0), Try(splitted(3).toInt).getOrElse(0)))
x
}
}}.mapValues(iter => iter._1+","+iter._2+","+iter._3+","+iter._4).values.toList
finalResult should be your desired output
List("TitleB,Int,16,0", "TitleA,STR,3,0", "TitleC,STR,4,5")
I had a simple task to find combination which occurs most often when we drop 4 cubic dices an remove one with least points.
So, the question is: are there any Scala core classes to generate streams of cartesian products in Scala? When not - how to implement it in the most simple and effective way?
Here is the code and comparison with naive implementation in Scala:
object D extends App {
def dropLowest(a: List[Int]) = {
a diff List(a.min)
}
def cartesian(to: Int, times: Int): Stream[List[Int]] = {
def stream(x: List[Int]): Stream[List[Int]] = {
if (hasNext(x)) x #:: stream(next(x)) else Stream(x)
}
def hasNext(x: List[Int]) = x.exists(n => n < to)
def next(x: List[Int]) = {
def add(current: List[Int]): List[Int] = {
if (current.head == to) 1 :: add(current.tail) else current.head + 1 :: current.tail // here is a possible bug when we get maximal value, don't reuse this method
}
add(x.reverse).reverse
}
stream(Range(0, times).map(t => 1).toList)
}
def getResult(list: Stream[List[Int]]) = {
list.map(t => dropLowest(t).sum).groupBy(t => t).map(t => (t._1, t._2.size)).toMap
}
val list1 = cartesian(6, 4)
val list = for (i <- Range(1, 7); j <- Range(1,7); k <- Range(1, 7); l <- Range(1, 7)) yield List(i, j, k, l)
println(getResult(list1))
println(getResult(list.toStream) equals getResult(list1))
}
Thanks in advance
I think you can simplify your code by using flatMap :
val stream = (1 to 6).toStream
def cartesian(times: Int): Stream[Seq[Int]] = {
if (times == 0) {
Stream(Seq())
} else {
stream.flatMap { i => cartesian(times - 1).map(i +: _) }
}
}
Maybe a little bit more efficient (memory-wise) would be using Iterators instead:
val pool = (1 to 6)
def cartesian(times: Int): Iterator[Seq[Int]] = {
if (times == 0) {
Iterator(Seq())
} else {
pool.iterator.flatMap { i => cartesian(times - 1).map(i +: _) }
}
}
or even more concise by replacing the recursive calls by a fold :
def cartesian[A](list: Seq[Seq[A]]): Iterator[Seq[A]] =
list.foldLeft(Iterator(Seq[A]())) {
case (acc, l) => acc.flatMap(i => l.map(_ +: i))
}
and then:
cartesian(Seq.fill(4)(1 to 6)).map(dropLowest).toSeq.groupBy(i => i.sorted).mapValues(_.size).toSeq.sortBy(_._2).foreach(println)
(Note that you cannot use groupBy on Iterators, so Streams or even Lists are the way to go whatever to be; above code still valid since toSeq on an Iterator actually returns a lazy Stream).
If you are considering stats on the sums of dice instead of combinations, you can update the dropLowest fonction :
def dropLowest(l: Seq[Int]) = l.sum - l.min
I have multiple Option's. I want to check if they hold a value. If an Option is None, I want to reply to user about this. Else proceed.
This is what I have done:
val name:Option[String]
val email:Option[String]
val pass:Option[String]
val i = List(name,email,pass).find(x => x match{
case None => true
case _ => false
})
i match{
case Some(x) => Ok("Bad Request")
case None => {
//move forward
}
}
Above I can replace find with contains, but this is a very dirty way. How can I make it elegant and monadic?
Edit: I would also like to know what element was None.
Another way is as a for-comprehension:
val outcome = for {
nm <- name
em <- email
pwd <- pass
result = doSomething(nm, em, pwd) // where def doSomething(name: String, email: String, password: String): ResultType = ???
} yield (result)
This will generate outcome as a Some(result), which you can interrogate in various ways (all the methods available to the collections classes: map, filter, foreach, etc.). Eg:
outcome.map(Ok(result)).orElse(Ok("Bad Request"))
val ok = Seq(name, email, pass).forall(_.isDefined)
If you want to reuse the code, you can do
def allFieldValueProvided(fields: Option[_]*): Boolean = fields.forall(_.isDefined)
If you want to know all the missing values then you can find all missing values and if there is none, then you are good to go.
def findMissingValues(v: (String, Option[_])*) = v.collect {
case (name, None) => name
}
val missingValues = findMissingValues(("name1", option1), ("name2", option2), ...)
if(missingValues.isEmpty) {
Ok(...)
} else {
BadRequest("Missing values for " + missingValues.mkString(", ")))
}
val response = for {
n <- name
e <- email
p <- pass
} yield {
/* do something with n, e, p */
}
response getOrElse { /* bad request /* }
Or, with Scalaz:
val response = (name |#| email |#| pass) { (n, e, p) =>
/* do something with n, e, p */
}
response getOrElse { /* bad request /* }
if ((name :: email :: pass :: Nil) forall(!_.isEmpty)) {
} else {
// bad request
}
I think the most straightforward way would be this:
(name,email,pass) match {
case ((Some(name), Some(email), Some(pass)) => // proceed
case _ => // Bad request
}
A version with stone knives and bear skins:
import util._
object Test extends App {
val zero: Either[List[Int], Tuple3[String,String,String]] = Right((null,null,null))
def verify(fields: List[Option[String]]) = {
(zero /: fields.zipWithIndex) { (acc, v) => v match {
case (Some(s), i) => acc match {
case Left(_) => acc
case Right(t) =>
val u = i match {
case 0 => t copy (_1 = s)
case 1 => t copy (_2 = s)
case 2 => t copy (_3 = s)
}
Right(u)
}
case (None, i) =>
val fails = acc match {
case Left(f) => f
case Right(_) => Nil
}
Left(i :: fails)
}
}
}
def consume(name: String, email: String, pass: String) = Console println s"$name/$email/$pass"
def fail(is: List[Int]) = is map List("name","email","pass") foreach (Console println "Missing: " + _)
val name:Option[String] = Some("Bob")
val email:Option[String]= None
val pass:Option[String] = Some("boB")
val res = verify(List(name,email,pass))
res.fold(fail, (consume _).tupled)
val res2 = verify(List(name, Some("bob#bob.org"),pass))
res2.fold(fail, (consume _).tupled)
}
The same thing, using reflection to generalize the tuple copy.
The downside is that you must tell it what tuple to expect back. In this form, reflection is like one of those Stone Age advances that were so magical they trended on twitter for ten thousand years.
def verify[A <: Product](fields: List[Option[String]]) = {
import scala.reflect.runtime._
import universe._
val MaxTupleArity = 22
def tuple = {
require (fields.length <= MaxTupleArity)
val n = fields.length
val tupleN = typeOf[Tuple2[_,_]].typeSymbol.owner.typeSignature member TypeName(s"Tuple$n")
val init = tupleN.typeSignature member nme.CONSTRUCTOR
val ctor = currentMirror reflectClass tupleN.asClass reflectConstructor init.asMethod
val vs = Seq.fill(n)(null.asInstanceOf[String])
ctor(vs: _*).asInstanceOf[Product]
}
def zero: Either[List[Int], Product] = Right(tuple)
def nextProduct(p: Product, i: Int, s: String) = {
val im = currentMirror reflect p
val ts = im.symbol.typeSignature
val copy = (ts member TermName("copy")).asMethod
val args = copy.paramss.flatten map { x =>
val name = TermName(s"_$i")
if (x.name == name) s
else (im reflectMethod (ts member x.name).asMethod)()
}
(im reflectMethod copy)(args: _*).asInstanceOf[Product]
}
(zero /: fields.zipWithIndex) { (acc, v) => v match {
case (Some(s), i) => acc match {
case Left(_) => acc
case Right(t) => Right(nextProduct(t, i + 1, s))
}
case (None, i) =>
val fails = acc match {
case Left(f) => f
case Right(_) => Nil
}
Left(i :: fails)
}
}.asInstanceOf[Either[List[Int], A]]
}
def consume(name: String, email: String, pass: String) = Console println s"$name/$email/$pass"
def fail(is: List[Int]) = is map List("name","email","pass") foreach (Console println "Missing: " + _)
val name:Option[String] = Some("Bob")
val email:Option[String]= None
val pass:Option[String] = Some("boB")
type T3 = Tuple3[String,String,String]
val res = verify[T3](List(name,email,pass))
res.fold(fail, (consume _).tupled)
val res2 = verify[T3](List(name, Some("bob#bob.org"),pass))
res2.fold(fail, (consume _).tupled)
I know this doesn't scale well, but would this suffice?
(name, email, pass) match {
case (None, _, _) => "name"
case (_, None, _) => "email"
case (_, _, None) => "pass"
case _ => "Nothing to see here"
}
I think this might be a common operation. So maybe it's inside the API but I can't find it. Also I'm interested in an efficient functional/simple solution if not.
Given a sequence of tuples ("a" -> 1, "b" ->2, "c" -> 3) I want to turn it into a map. That's easy using TraversableOnce.toMap. But I want to fail this construction if the resulting map "would contain a contradiction", i.e. different values assigned to the same key. Like in the sequence ("a" -> 1, "a" -> 2). But duplicates shall be allowed.
Currently I have this (very imperative) code:
def buildMap[A,B](in: TraversableOnce[(A,B)]): Option[Map[A,B]] = {
val map = new HashMap[A,B]
val it = in.toIterator
var fail = false
while(it.hasNext){
val next = it.next()
val old = map.put(next._1, next._2)
fail = old.isDefined && old.get != next._2
}
if(fail) None else Some(map.toMap)
}
Side Question
Is the final toMap really necessary? I get a type error when omitting it, but I think it should work. The implementation of toMap constructs a new map which I want to avoid.
As always when working with Seq[A] the optimal solution performance-wise depends on the concrete collection type.
A general but not very efficient solution would be to fold over an Option[Map[A,B]]:
def optMap[A,B](in: Iterable[(A,B)]): Option[Map[A,B]] =
in.iterator.foldLeft(Option(Map[A,B]())) {
case (Some(m),e # (k,v)) if m.getOrElse(k, v) == v => Some(m + e)
case _ => None
}
If you restrict yourself to using List[A,B]s an optimized version would be:
#tailrec
def rmap[A,B](in: List[(A,B)], out: Map[A,B] = Map[A,B]()): Option[Map[A,B]] = in match {
case (e # (k,v)) :: tail if out.getOrElse(k,v) == v =>
rmap(tail, out + e)
case Nil =>
Some(out)
case _ => None
}
Additionally a less idiomatic version using mutable maps could be implemented like this:
def mmap[A,B](in: Iterable[(A,B)]): Option[Map[A,B]] = {
val dest = collection.mutable.Map[A,B]()
for (e # (k,v) <- in) {
if (dest.getOrElse(k, v) != v) return None
dest += e
}
Some(dest.toMap)
}
Here is a fail-slowly solution (if creating the entire map and then discarding it is okay):
def uniqueMap[A,B](s: Seq[(A,B)]) = {
val m = s.toMap
if (m.size == s.length) Some(s) else None
}
Here is a mutable fail-fast solution (bail out as soon as the error is detected):
def uniqueMap[A,B](s: Seq[(A,B)]) = {
val h = new collection.mutable.HashMap[A,B]
val i = s.iterator.takeWhile(x => !(h contains x._1)).foreach(h += _)
if (h.size == s.length) Some(h) else None
}
And here's an immutable fail-fast solution:
def uniqueMap[A,B](s: Seq[(A,B)]) = {
def mapUniquely(i: Iterator[(A,B)], m: Map[A,B]): Option[Map[A,B]] = {
if (i.hasNext) {
val j = i.next
if (m contains j._1) None
else mapUniquely(i, m + j)
}
else Some(m)
}
mapUniquely(s.iterator, Map[A,B]())
}
Edit: and here's a solution using put for speed (hopefully):
def uniqueMap[A,B](s: Seq[(A,B)]) = {
val h = new collection.mutable.HashMap[A,B]
val okay = s.iterator.forall(x => {
val y = (h put (x._1,x._2))
y.isEmpty || y.get == x._2
})
if (okay) Some(h) else None
}
Edit: now tested, and it's ~2x as fast on input that works (returns true) than Moritz' or my straightforward solution.
Scala 2.9 is near, so why not to take advantage of the combinations method (inspired by Moritz's answer):
def optMap[A,B](in: List[(A,B)]) = {
if (in.combinations(2).exists {
case List((a,b),(c,d)) => a == c && b != d
case _ => false
}) None else Some(in.toMap)
}
scala> val in = List(1->1,2->3,3->4,4->5,2->3)
in: List[(Int, Int)] = List((1,1), (2,3), (3,4), (4,5), (2,3))
scala> optMap(in)
res29: Option[scala.collection.immutable.Map[Int,Int]] = Some(Map(1 -> 1, 2 -> 3, 3 -> 4, 4 -> 5))
scala> val in = List(1->1,2->3,3->4,4->5,2->3,1->2)
in: List[(Int, Int)] = List((1,1), (2,3), (3,4), (4,5), (2,3), (1,2))
scala> optMap(in)
res30: Option[scala.collection.immutable.Map[Int,Int]] = None
You can also use gourpBy as follows:
val pList = List(1 -> "a", 1 -> "b", 2 -> "c", 3 -> "d")
def optMap[A,B](in: Iterable[(A,B)]): Option[Map[A,B]] = {
Option(in.groupBy(_._1).map{case(_, list) => if(list.size > 1) return None else list.head})
}
println(optMap(pList))
It's efficiency is competitive to the above solutions.
In fact if you examine the gourpBy implementation you will see that it is very similar to some of the solutions suggested.