The Data.map implement in NSData [duplicate] - swift

I am implementing push notifications. I'd like to save my APNS Token as a String.
- (void)application:(UIApplication *)application
didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)newDeviceToken
{
NSString *tokenString = [NSString stringWithUTF8String:[newDeviceToken bytes]]; //[[NSString alloc]initWithData:newDeviceToken encoding:NSUTF8StringEncoding];
NSLog(#"%#", tokenString);
NSLog(#"%#", newDeviceToken);
}
The first line of code prints null. the second prints the token. How can I get my newDeviceToken as an NSString?

If anyone is looking for a way to do this in Swift:
Swift 3 introduces the Data type, with value semantics. To convert the deviceToken to a String, you can do as follows:
func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
let token = deviceToken.map { String(format: "%02.2hhx", $0) }.joined()
print(token)
}
Old answer using NSData:
func application(application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: NSData) {
let tokenChars = UnsafePointer<CChar>(deviceToken.bytes)
var tokenString = ""
for i in 0..<deviceToken.length {
tokenString += String(format: "%02.2hhx", arguments: [tokenChars[i]])
}
print("tokenString: \(tokenString)")
}

Someone Helped me with this.I am just passing along
- (void)application:(UIApplication *)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)devToken {
const unsigned *tokenBytes = [deviceToken bytes];
NSString *hexToken = [NSString stringWithFormat:#"%08x%08x%08x%08x%08x%08x%08x%08x",
ntohl(tokenBytes[0]), ntohl(tokenBytes[1]), ntohl(tokenBytes[2]),
ntohl(tokenBytes[3]), ntohl(tokenBytes[4]), ntohl(tokenBytes[5]),
ntohl(tokenBytes[6]), ntohl(tokenBytes[7])];
[[MyModel sharedModel] setApnsToken:hexToken];
}

You could use this
- (NSString *)stringWithDeviceToken:(NSData *)deviceToken {
const char *data = [deviceToken bytes];
NSMutableString *token = [NSMutableString string];
for (NSUInteger i = 0; i < [deviceToken length]; i++) {
[token appendFormat:#"%02.2hhX", data[i]];
}
return [token copy];
}

For those who want in Swift 3 and most easier method
func extractTokenFromData(deviceToken:Data) -> String {
let token = deviceToken.reduce("", {$0 + String(format: "%02X", $1)})
return token.uppercased();
}

Note - This will not work when compiling with the iOS 13 or later SDK
use this :
NSString * deviceTokenString = [[[[deviceToken description]
stringByReplacingOccurrencesOfString: #"<" withString: #""]
stringByReplacingOccurrencesOfString: #">" withString: #""]
stringByReplacingOccurrencesOfString: #" " withString: #""];
NSLog(#"The generated device token string is : %#",deviceTokenString);

Explanation of %02.2hhx in the high vote answer:
%: Introduces the x conversion specifier.
02: The minimum width of the converted value is 2. If the converted value has fewer bytes than the field width, it shall be padded with 0 on the left.
.2: Gives the minimum number of digits to appear for the x conversion specifier.
hh: Specifies that the x conversion specifier applies to a signed char or unsigned char argument (the argument will have been promoted according to the integer promotions, but its value shall be converted to signed char or unsigned char before printing).
x: The unsigned argument shall be converted to unsigned hexadecimal format in the style "dddd"; the letters "abcdef" are used. The precision specifies the minimum number of digits to appear; if the value being converted can be represented in fewer digits, it shall be expanded with leading zeros. The default precision is 1. The result of converting zero with an explicit precision of zero shall be no characters.
For more details, see the IEEE printf specification.
Based on the above explanation, I think it is better to change %02.2hhx to %02x or %.2x.
For Swift 5, the following methods are all feasible:
deviceToken.map({String(format: "%02x", $0)}).joined()
deviceToken.map({String(format: "%.2x", $0)}).joined()
deviceToken.reduce("", {$0 + String(format: "%02x", $1)})
deviceToken.reduce("", {$0 + String(format: "%.2x", $1)})
The test is as follows:
let deviceToken = (0..<32).reduce(Data(), {$0 + [$1]})
print(deviceToken.reduce("", {$0 + String(format: "%.2x", $1)}))
// Print content:
// 000102030405060708090a0b0c0d0e0f101112131415161718191a1b1c1d1e1f

In iOS 13 the description will be in different format. Kindly use below code to fetch the device token.
- (NSString *)fetchDeviceToken:(NSData *)deviceToken {
NSUInteger len = deviceToken.length;
if (len == 0) {
return nil;
}
const unsigned char *buffer = deviceToken.bytes;
NSMutableString *hexString = [NSMutableString stringWithCapacity:(len * 2)];
for (int i = 0; i < len; ++i) {
[hexString appendFormat:#"%02x", buffer[i]];
}
return [hexString copy];
}

It's my solution and It works well in my app:
NSString* newToken = [[[NSString stringWithFormat:#"%#",deviceToken]
stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"<>"]] stringByReplacingOccurrencesOfString:#" " withString:#""];
convert NSData to NSString with stringWithFormat
trim the "<>"
remove the spaces

I think converting deviceToken to hex byte string has no sense. Why? You will send it to your backend, where it will be transformed back to bytes to be pushed to APNS. So, use NSData's method base64EncodedStringWithOptions, push it to server, and then use reverse base64decoded data :) That is so much easier :)
NSString *tokenString = [tokenData base64EncodedStringWithOptions:NSDataBase64EncodingEndLineWithLineFeed];

In iOS 13 description will break so use this
let deviceTokenString = deviceToken.map { String(format: "%02x", $0) }.joined()
For clarity, let’s break this down and explain each part:
The map method operates on each element of a sequence. Because Data is a sequence of bytes in Swift, the passed closure is evaluated for each byte in deviceToken.
The String(format:) initializer evaluates each byte in the data (represented by the anonymous parameter $0) using the %02x format specifier, to produce a zero-padded, 2-digit hexadecimal representation of the byte / 8-bit integer.
After collecting each byte representation created by the map method, joined() concatenates each element into a single string.
P.S don't use description gives different string in iOS 12 and iOS 13 and not safe as per future scope. Developers shouldn’t have relied on a specific format for an object’s description.
// iOS 12
(deviceToken as NSData).description // "<965b251c 6cb1926d e3cb366f dfb16ddd e6b9086a 8a3cac9e 5f857679 376eab7C>"
// iOS 13
(deviceToken as NSData).description // "{length = 32, bytes = 0x965b251c 6cb1926d e3cb366f dfb16ddd ... 5f857679 376eab7c }"
For more information read This.

2020
token as text...
let tat = deviceToken.map{ data in String(format: "%02.2hhx", data) }.joined()
or if you prefer
let tat2 = deviceToken.map { String(format: "%02.2hhx", $0) }.joined()
(result is the same)

This is a little bit shorter solution:
NSData *token = // ...
const uint64_t *tokenBytes = token.bytes;
NSString *hex = [NSString stringWithFormat:#"%016llx%016llx%016llx%016llx",
ntohll(tokenBytes[0]), ntohll(tokenBytes[1]),
ntohll(tokenBytes[2]), ntohll(tokenBytes[3])];

Functional Swift version
One liner:
let hexString = UnsafeBufferPointer<UInt8>(start: UnsafePointer(data.bytes),
count: data.length).map { String(format: "%02x", $0) }.joinWithSeparator("")
Here's in a reusable and self documenting extension form:
extension NSData {
func base16EncodedString(uppercase uppercase: Bool = false) -> String {
let buffer = UnsafeBufferPointer<UInt8>(start: UnsafePointer(self.bytes),
count: self.length)
let hexFormat = uppercase ? "X" : "x"
let formatString = "%02\(hexFormat)"
let bytesAsHexStrings = buffer.map {
String(format: formatString, $0)
}
return bytesAsHexStrings.joinWithSeparator("")
}
}
Alternatively, use reduce("", combine: +) instead of joinWithSeparator("") to be seen as a functional master by your peers.
Edit: I changed String($0, radix: 16) to String(format: "%02x", $0), because one digit numbers needed to having a padding zero
(I don't know yet how to mark a question as a duplicate of this other one, so I just posted my answer again)

Throwing my answer on the pile. Avoid using string parsing; It's not guaranteed by the docs that NSData.description will always work that way.
Swift 3 Implementation:
extension Data {
func hexString() -> String {
var bytesPointer: UnsafeBufferPointer<UInt8> = UnsafeBufferPointer(start: nil, count: 0)
self.withUnsafeBytes { (bytes) in
bytesPointer = UnsafeBufferPointer<UInt8>(start: UnsafePointer(bytes), count:self.count)
}
let hexBytes = bytesPointer.map { return String(format: "%02hhx", $0) }
return hexBytes.joined()
}
}

This will work for you,
NSUInteger dataLength = deviceToken.length;
const unsigned char *dataBuffer = (const unsigned char *)deviceToken.bytes;
NSMutableString *deviceTokenString = [NSMutableString stringWithCapacity:(dataLength * 2)];
for (int i = 0; i < dataLength; ++i) {
[deviceTokenString appendFormat:#"%02x", dataBuffer[i]];
}
NSLog(#"The generated device token string is : %#",deviceTokenString);

I've tried to test two different methods with format "%02.2hhx" and "%02x"
var i :Int = 0
var j: Int = 0
let e: Int = Int(1e4)
let time = NSDate.timeIntervalSinceReferenceDate
while i < e {
_ = deviceToken.map { String(format: "%02x", $0) }.joined()
i += 1
}
let time2 = NSDate.timeIntervalSinceReferenceDate
let delta = time2-time
print(delta)
let time3 = NSDate.timeIntervalSinceReferenceDate
while j < e {
_ = deviceToken.reduce("", {$0 + String(format: "%02x", $1)})
j += 1
}
let time4 = NSDate.timeIntervalSinceReferenceDate
let delta2 = time4-time3
print(delta2)
and the result is that the fastest is "%02x" at average 2.0 vs 2.6 for the reduced version:
deviceToken.reduce("", {$0 + String(format: "%02x", $1)})

Here's how you do it in Xamarin.iOS
public override void RegisteredForRemoteNotifications(UIApplication application, NSData deviceToken)
{
var tokenStringBase64 = deviceToken.GetBase64EncodedString(NSDataBase64EncodingOptions.None);
//now you can store it for later use in local storage
}

Using updateAccumulatingResult is more efficient than the various other approaches found here, so here's the Swiftiest way to stringify your Data bytes:
func application(_ application: UIApplication,
didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
let token = deviceToken.reduce(into: "") { $0 += String(format: "%.2x", $1) }
print(token)
}

For Swift :
var characterSet: NSCharacterSet = NSCharacterSet( charactersInString: "<>" )
var deviceTokenString: String = ( deviceToken.description as NSString )
.stringByTrimmingCharactersInSet( characterSet )
.stringByReplacingOccurrencesOfString( " ", withString: "" ) as String
println( deviceTokenString )

NSString *tokenString = [[newDeviceToken description] stringByReplacingOccurrencesOfString:#"[<> ]" withString:#"" options:NSRegularExpressionSearch range:NSMakeRange(0, [[newDeviceToken description] length])];

Swift:
let tokenString = deviceToken.description.stringByReplacingOccurrencesOfString("[ <>]", withString: "", options: .RegularExpressionSearch, range: nil)

What about one line solution?
Objective C
NSString *token = [[data.description componentsSeparatedByCharactersInSet:[[NSCharacterSet alphanumericCharacterSet]invertedSet]]componentsJoinedByString:#""];
Swift
let token = data.description.components(separatedBy: CharacterSet.alphanumerics.inverted).joined()

-(NSString *)deviceTokenWithData:(NSData *)data
{
NSString *deviceToken = [[data description] stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"<>"]];
deviceToken = [deviceToken stringByReplacingOccurrencesOfString:#" " withString:#""];
return deviceToken;
}

Swift
// make sure that we have token for the devie on the App
func application(application: UIApplication
, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: NSData) {
var tokenStr = deviceToken.description
tokenStr = tokenStr.stringByReplacingOccurrencesOfString("<", withString: "", options: [], range: nil)
tokenStr = tokenStr.stringByReplacingOccurrencesOfString(">", withString: "", options: [], range: nil)
tokenStr = tokenStr.stringByReplacingOccurrencesOfString(" ", withString: "", options: [], range: nil)
print("my token is: \(tokenStr)")
}

Use excellent category!
// .h file
#interface NSData (DeviceToken)
- (NSString *)stringDeviceToken;
#end
// .m file
#import "NSData+DeviceToken.h"
#implementation NSData (DeviceToken)
- (NSString *)stringDeviceToken {
const unsigned *deviceTokenBytes = [deviceToken bytes];
NSString *deviceToken = [NSString stringWithFormat:#"%08x%08x%08x%08x%08x%08x%08x%08x",
ntohl(deviceTokenBytes[0]), ntohl(deviceTokenBytes[1]), ntohl(deviceTokenBytes[2]),
ntohl(deviceTokenBytes[3]), ntohl(deviceTokenBytes[4]), ntohl(deviceTokenBytes[5]),
ntohl(deviceTokenBytes[6]), ntohl(deviceTokenBytes[7])];
return deviceToken;
}
#end
// AppDelegate.m
#import "NSData+DeviceToken.h"
- (void)application:(UIApplication *)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken
{
NSString *token = deviceToken.stringDeviceToken;
}
Works fine!

Swift 3:
If any one is looking for a way to get device token in Swift 3. Use the below modified snippet.
let characterSet: CharacterSet = CharacterSet( charactersIn: "<>" )
let deviceTokenString: String = (deviceToken.description as NSString)
.trimmingCharacters(in: characterSet as CharacterSet)
.replacingOccurrences(of: " ", with: "")
.uppercased()
print(deviceTokenString)

var token: String = ""
for i in 0..<deviceToken.count {
token += String(format: "%02.2hhx", deviceToken[i] as CVarArg)
}
print(token)

The solution #kulss posted here, while lacking in elegance but having the virtue of simplicity no longer works in iOS 13, since description will work differently for NSData. You can still use debugDescription though.
NSString * deviceTokenString = [[[[deviceToken debugDescription]
stringByReplacingOccurrencesOfString: #"<" withString: #""]
stringByReplacingOccurrencesOfString: #">" withString: #""]
stringByReplacingOccurrencesOfString: #" " withString: #""];

Try this one unless the data is null-terminated.
NSString* newStr = [[NSString alloc] initWithData:newDeviceToken
encoding:NSUTF8StringEncoding];

NSString *tokenstring = [[NSString alloc] initWithData:token encoding:NSUTF8StringEncoding];

Related

Convert NSRange in Objective-C to Swift

How do I convert this to Swift:
NSString *searchString = [NSString stringWithFormat:#"%#", #"Apple_HFS "];
NSRange range = [tempString rangeOfString:searchString];
NSUInteger *idx = range.location + range.length;
Thanks
If you use String, you can just reference endIndex:
let searchString: String = "Apple_HFS "
if let range: Range<String.Index> = tempString.rangeOfString(searchString) {
let index = range.endIndex
let stringAfter = tempString.substringFromIndex(index)
// do something with `stringAfter`
} else {
// not found
}
I included the types so you could see what's going on, but generally I'd just write:
let searchString = "Apple_HFS "
if let range = tempString.rangeOfString(searchString) {
let stringAfter = tempString.substringFromIndex(range.endIndex)
// do something with `stringAfter`
} else {
// not found
}
Is that what you're looking for ?
var str : NSString = "A string that include the searched string Apple_HFS inside"
let searchString : NSString = "Apple_HFS "
let range : NSRange = str.rangeOfString(searchString) // (42, 10)
let idx : Int = range.location + range.length // 52
Demonstration : http://swiftstub.com/831969865/
Simple solution without using ANY objc methods or types:
Suppose you have:
let nsrange = NSRange(location: 3, length: 5)
let string = "My string"
And now you need to convert NSRange to Range:
let range = Range(start: advance(string.startIndex, nsrange.location), end: advance(string.startIndex, nsrange.location + nsrange.length))

About AttributeString - making multiple occurrences bold

I am trying to make multiple occurrences in a attributed string bold using something like the following
[attrStr setFont:[UIFont ...] range:[attrStr.string rangeOfString:#"hello world"]];
As you know, 'rangeOfString' always return the FIRST occurrence of the match... I am still quite new to iOS, just wondering what's the best way to set all occurrences to bold... Is there any function provided in NSString or something?
Thanks in advance!
You should first try to get all ranges in the string and then set the attribute for every range. There are some great code examples right here on stackoverflow: https://stackoverflow.com/a/4653266/381870
Edit:
Here's an example for you
- (NSArray *)rangesOfString:(NSString *)searchString inString:(NSString *)str {
NSMutableArray *results = [NSMutableArray array];
NSRange searchRange = NSMakeRange(0, [str length]);
NSRange range;
while ((range = [str rangeOfString:searchString options:0 range:searchRange]).location != NSNotFound) {
[results addObject:[NSValue valueWithRange:range]];
searchRange = NSMakeRange(NSMaxRange(range), [str length] - NSMaxRange(range));
}
return results;
}
Usage:
NSArray *results = [self rangesOfString:#"foo" inString:#"foo bar foo"];
NSLog(#"%#", results);
gives you
(
"NSRange: {0, 3}",
"NSRange: {8, 3}"
)
Converting Tim's answer to Swift 4:
extension NSString {
open func ranges(of searchString: String) -> [NSRange] {
var ranges = [NSRange]()
var searchRange = NSRange(location: 0, length: self.length)
var range: NSRange = self.range(of: searchString)
while range.location != NSNotFound {
ranges.append(range)
searchRange = NSRange(location: NSMaxRange(range), length: self.length - NSMaxRange(range))
range = self.range(of: searchString, options: [], range: searchRange)
}
return ranges
}
}
Also did it to Swift's String primitive:
extension String {
func ranges(of substring: String, options: CompareOptions = [], locale: Locale? = nil) -> [Range<Index>] {
var ranges: [Range<Index>] = []
while let range = self.range(of: substring, options: options, range: (ranges.last?.upperBound ?? self.startIndex)..<self.endIndex, locale: locale) {
ranges.append(range)
}
return ranges
}
}
You will like have to use NSScanner to scan through the text and replace it.You can find an example for NSScanner here.

Replace only the first instance of a substring in an NSString

So if you have an NSString that goes:
#"My blue car is bigger than my blue shoes or my blue bicycle";
I would like a method that replaces only the first instance of blue with green, to produce:
#"My green car is bigger than my blue shoes or my blue bicycle";
How does one do this?
Assuming the following inputs:
NSString *myString = #"My blue car is bigger then my blue shoes or my blue bicycle";
NSString *original = #"blue";
NSString *replacement = #"green";
The algorithm is quite simple:
NSRange rOriginal = [myString rangeOfString:original];
if (NSNotFound != rOriginal.location) {
myString = [myString stringByReplacingCharactersInRange:rOriginal withString:replacement];
}
SWIFT 3 and 4 UPDATE:
extension String
{
func stringByReplacingFirstOccurrenceOfString(
target: String, withString replaceString: String) -> String
{
if let range = self.range(of: target) {
return self.replacingCharacters(in: range, with: replaceString)
}
return self
}
}
A more Swift'y version of the implementations posted here. This one matches the syntax replacingOccurrences(of:with:) in Swift 5.1
extension String {
func replacingFirstOccurrence(of target: String, with replacement: String) -> String {
guard let range = self.range(of: target) else { return self }
return self.replacingCharacters(in: range, with: replacement)
}
}
An example of usage:
let string = "I like bacon, please give me some more bacon!"
let newString = string.replacingFirstOccurrence(of: "bacon", with: "meat")
Swift 4 version:
func replacingFirstOccurrence(of string: String, with replacement: String) -> String {
guard let range = self.range(of: string) else { return self }
return replacingCharacters(in: range, with: replacement)
}
In Swift is useful extends String in this way:
public extension String {
func stringByReplacingFirstOccurrenceOfString(target: String, withString replaceString: String) -> String {
if let range = self.rangeOfString(target) {
return self.stringByReplacingCharactersInRange(range, withString: replaceString)
}
return self
}
}
In this way you can call wherever:
let s = "The red red cat".stringByReplacingFirstOccurrenceOfString("red", withString: "fat")
print(s) // "The fat red cat"
NSString *initialString = #"My blue car is bigger then my blue shoes or my blue bicycle";
NSRange range = [initialString rangeOfString:#"blue"];
NSString *replacedString = [initialString stringByReplacingCharactersInRange:range withString:#"green"];
NSLog(#"replacedString: %#", replacedString);
First locate the substring, and then make the replacement. Example :
NSString *aString = #"foo bar foo";
NSRange firstFooRange = [aString rangeOfString:#"foo"];
NSString *anotherString = [aString stringByReplacingOccurrencesOfString:#"foo"
withString:#"bar"
options:0
range:firstFooRange];
NSString documentation.
-(NSString*) replaceFirstOccuarnceFromString: (NSString*)input withOriginal:(NSString*) original AndReplacment:(NSString*)replacement
{
NSRange rOriginal = [input rangeOfString: original];
if (NSNotFound != rOriginal.location) {
input = [input
stringByReplacingCharactersInRange: rOriginal
withString: replacement];
}
return input;
}

How to validate a website name in UItextfield in objective c? [duplicate]

In an iPhone app I am developing, there is a setting in which you can enter a URL, because of form & function this URL needs to be validated online as well as offline.
So far I haven't been able to find any method to validate the url, so the question is;
How do I validate an URL input on the iPhone (Objective-C) online as well as offline?
Why not instead simply rely on Foundation.framework?
That does the job and does not require RegexKit :
NSURL *candidateURL = [NSURL URLWithString:candidate];
// WARNING > "test" is an URL according to RFCs, being just a path
// so you still should check scheme and all other NSURL attributes you need
if (candidateURL && candidateURL.scheme && candidateURL.host) {
// candidate is a well-formed url with:
// - a scheme (like http://)
// - a host (like stackoverflow.com)
}
According to Apple documentation :
URLWithString: Creates and returns an NSURL object initialized with a
provided string.
+ (id)URLWithString:(NSString *)URLString
Parameters
URLString : The string with which to initialize the NSURL object. Must conform to RFC 2396. This method parses URLString according to RFCs 1738 and 1808.
Return Value
An NSURL object initialized with URLString. If the string was malformed, returns nil.
Thanks to this post, you can avoid using RegexKit.
Here is my solution (works for iphone development with iOS > 3.0) :
- (BOOL) validateUrl: (NSString *) candidate {
NSString *urlRegEx =
#"(http|https)://((\\w)*|([0-9]*)|([-|_])*)+([\\.|/]((\\w)*|([0-9]*)|([-|_])*))+";
NSPredicate *urlTest = [NSPredicate predicateWithFormat:#"SELF MATCHES %#", urlRegEx];
return [urlTest evaluateWithObject:candidate];
}
If you want to check in Swift my solution given below:
func isValidUrl(url: String) -> Bool {
let urlRegEx = "^(https?://)?(www\\.)?([-a-z0-9]{1,63}\\.)*?[a-z0-9][-a-z0-9]{0,61}[a-z0-9]\\.[a-z]{2,6}(/[-\\w#\\+\\.~#\\?&/=%]*)?$"
let urlTest = NSPredicate(format:"SELF MATCHES %#", urlRegEx)
let result = urlTest.evaluate(with: url)
return result
}
Instead of writing your own regular expressions, rely on Apple's. I have been using a category on NSString that uses NSDataDetector to test for the presence of a link within a string. If the range of the link found by NSDataDetector equals the length of the entire string, then it is a valid URL.
- (BOOL)isValidURL {
NSUInteger length = [self length];
// Empty strings should return NO
if (length > 0) {
NSError *error = nil;
NSDataDetector *dataDetector = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeLink error:&error];
if (dataDetector && !error) {
NSRange range = NSMakeRange(0, length);
NSRange notFoundRange = (NSRange){NSNotFound, 0};
NSRange linkRange = [dataDetector rangeOfFirstMatchInString:self options:0 range:range];
if (!NSEqualRanges(notFoundRange, linkRange) && NSEqualRanges(range, linkRange)) {
return YES;
}
}
else {
NSLog(#"Could not create link data detector: %# %#", [error localizedDescription], [error userInfo]);
}
}
return NO;
}
My solution with Swift:
func validateUrl (stringURL : NSString) -> Bool {
var urlRegEx = "((https|http)://)((\\w|-)+)(([.]|[/])((\\w|-)+))+"
let predicate = NSPredicate(format:"SELF MATCHES %#", argumentArray:[urlRegEx])
var urlTest = NSPredicate.predicateWithSubstitutionVariables(predicate)
return predicate.evaluateWithObject(stringURL)
}
For Test:
var boolean1 = validateUrl("http.s://www.gmail.com")
var boolean2 = validateUrl("https:.//gmailcom")
var boolean3 = validateUrl("https://gmail.me.")
var boolean4 = validateUrl("https://www.gmail.me.com.com.com.com")
var boolean6 = validateUrl("http:/./ww-w.wowone.com")
var boolean7 = validateUrl("http://.www.wowone")
var boolean8 = validateUrl("http://www.wow-one.com")
var boolean9 = validateUrl("http://www.wow_one.com")
var boolean10 = validateUrl("http://.")
var boolean11 = validateUrl("http://")
var boolean12 = validateUrl("http://k")
Results:
false
false
false
true
false
false
true
true
false
false
false
use this-
NSString *urlRegEx = #"http(s)?://([\\w-]+\\.)+[\\w-]+(/[\\w- ./?%&=]*)?";
I solved the problem using RegexKit, and build a quick regex to validate a URL;
NSString *regexString = #"(http|https)://((\\w)*|([0-9]*)|([-|_])*)+([\\.|/]((\\w)*|([0-9]*)|([-|_])*))+";
NSString *subjectString = brandLink.text;
NSString *matchedString = [subjectString stringByMatching:regexString];
Then I check if the matchedString is equal to the subjectString and if that is the case the url is valid :)
Correct me if my regex is wrong ;)
I've found the easiest way to do this is like so:
- (BOOL)validateUrl: (NSURL *)candidate
{
NSURLRequest *req = [NSURLRequest requestWithURL:candidate];
return [NSURLConnection canHandleRequest:req];
}
Oddly enough, I didn't really find a solution here that was very simple, yet still did an okay job for handling http / https links.
Keep in mind, THIS IS NOT a perfect solution, but it worked for the cases below. In summary, the regex tests whether the URL starts with http:// or https://, then checks for at least 1 character, then checks for a dot, and then again checks for at least 1 character. No spaces allowed.
+ (BOOL)validateLink:(NSString *)link
{
NSString *regex = #"(?i)(http|https)(:\\/\\/)([^ .]+)(\\.)([^ \n]+)";
NSPredicate *predicate = [NSPredicate predicateWithFormat:#"SELF MATCHES %#", regex];
return [predicate evaluateWithObject:link];
}
Tested VALID against these URLs:
#"HTTP://FOO.COM",
#"HTTPS://FOO.COM",
#"http://foo.com/blah_blah",
#"http://foo.com/blah_blah/",
#"http://foo.com/blah_blah_(wikipedia)",
#"http://foo.com/blah_blah_(wikipedia)_(again)",
#"http://www.example.com/wpstyle/?p=364",
#"https://www.example.com/foo/?bar=baz&inga=42&quux",
#"http://✪df.ws/123",
#"http://userid:password#example.com:8080",
#"http://userid:password#example.com:8080/",
#"http://userid#example.com",
#"http://userid#example.com/",
#"http://userid#example.com:8080",
#"http://userid#example.com:8080/",
#"http://userid:password#example.com",
#"http://userid:password#example.com/",
#"http://142.42.1.1/",
#"http://142.42.1.1:8080/",
#"http://➡.ws/䨹",
#"http://⌘.ws",
#"http://⌘.ws/",
#"http://foo.com/blah_(wikipedia)#cite-",
#"http://foo.com/blah_(wikipedia)_blah#cite-",
#"http://foo.com/unicode_(✪)_in_parens",
#"http://foo.com/(something)?after=parens",
#"http://☺.damowmow.com/",
#"http://code.google.com/events/#&product=browser",
#"http://j.mp",
#"http://foo.bar/?q=Test%20URL-encoded%20stuff",
#"http://مثال.إختبار",
#"http://例子.测试",
#"http://उदाहरण.परीक्षा",
#"http://-.~_!$&'()*+,;=:%40:80%2f::::::#example.com",
#"http://1337.net",
#"http://a.b-c.de",
#"http://223.255.255.254"
Tested INVALID against these URLs:
#"",
#"foo",
#"ftp://foo.com",
#"ftp://foo.com",
#"http://..",
#"http://..",
#"http://../",
#"//",
#"///",
#"http://##/",
#"http://.www.foo.bar./",
#"rdar://1234",
#"http://foo.bar?q=Spaces should be encoded",
#"http:// shouldfail.com",
#":// should fail"
Source of URLs:
https://mathiasbynens.be/demo/url-regex
You can use this if you do not want http or https or www
NSString *urlRegEx = #"^(http(s)?://)?((www)?\.)?[\w]+\.[\w]+";
example
- (void) testUrl:(NSString *)urlString{
NSLog(#"%#: %#", ([self isValidUrl:urlString] ? #"VALID" : #"INVALID"), urlString);
}
- (void)doTestUrls{
[self testUrl:#"google"];
[self testUrl:#"google.de"];
[self testUrl:#"www.google.de"];
[self testUrl:#"http://www.google.de"];
[self testUrl:#"http://google.de"];
}
Output:
INVALID: google
VALID: google.de
VALID: www.google.de
VALID: http://www.google.de
VALID: http://google.de
Lefakir's solution has one issue.
His regex can't match with "http://instagram.com/p/4Mz3dTJ-ra/".
Url component has combined numerical and literal character. His regex fail such urls.
Here is my improvement.
"(http|https)://((\\w)*|([0-9]*)|([-|_])*)+([\\.|/]((\\w)*|([0-9]*)|([-|_])*)+)+(/)?(\\?.*)?"
Below code will let you find the valid URLs
NSPredicate *websitePredicate = [NSPredicate predicateWithFormat:#"SELF MATCHES %#",#"^(((((h|H)(t|T){2}(p|P)s?)|((f|F)(t|T)(p|P)))://(w{3}.)?)|(w{3}.))[A-Za-z0-9]+(.[A-Za-z0-9-:;\?#_]+)+"];
if ([websitePredicate evaluateWithObject:##MY_STRING##])
{
printf"Valid"
}
for such URLS
http://123.com
https://123.com
http://www.123.com
https://www.123.com
ftp://123.com
ftp://www.123.com
www.something.com
The approved answer is incorrect.
I have an URL with an "-" in it, and the validation fails.
Tweeked Vaibhav's answer to support G+ links:
NSString *urlRegEx = #"http(s)?://([\\w-]+\\.)+[\\w-]+(/[\\w-\\+ ./?%&=]*)?";
Some URL's without / at the end are not detected as the correct one in the solutions above. So this might be helpful.
extension String {
func isValidURL() -> Bool{
let length:Int = self.characters.count
var err:NSError?
var dataDetector:NSDataDetector? = NSDataDetector()
do{
dataDetector = try NSDataDetector(types: NSTextCheckingType.Link.rawValue)
}catch{
err = error as NSError
}
if dataDetector != nil{
let range = NSMakeRange(0, length)
let notFoundRange = NSRange(location: NSNotFound, length: 0)
let linkRange = dataDetector?.rangeOfFirstMatchInString(self, options: NSMatchingOptions.init(rawValue: 0), range: range)
if !NSEqualRanges(notFoundRange, linkRange!) && NSEqualRanges(range, linkRange!){
return true
}
}else{
print("Could not create link data detector: \(err?.localizedDescription): \(err?.userInfo)")
}
return false
}
}
URL Validation in Swift
Details
Xcode 8.2.1, Swift 3
Code
enum URLSchemes: String
import Foundation
enum URLSchemes: String {
case http = "http://", https = "https://", ftp = "ftp://", unknown = "unknown://"
static func detectScheme(urlString: String) -> URLSchemes {
if URLSchemes.isSchemeCorrect(urlString: urlString, scheme: .http) {
return .http
}
if URLSchemes.isSchemeCorrect(urlString: urlString, scheme: .https) {
return .https
}
if URLSchemes.isSchemeCorrect(urlString: urlString, scheme: .ftp) {
return .ftp
}
return .unknown
}
static func getAllSchemes(separetedBy separator: String) -> String {
return "\(URLSchemes.http.rawValue)\(separator)\(URLSchemes.https.rawValue)\(separator)\(URLSchemes.ftp.rawValue)"
}
private static func isSchemeCorrect(urlString: String, scheme: URLSchemes) -> Bool {
if urlString.replacingOccurrences(of: scheme.rawValue, with: "") == urlString {
return false
}
return true
}
}
extension String
import Foundation
extension String {
var isUrl: Bool {
// for http://regexr.com checking
// (?:(?:https?|ftp):\/\/)(?:xn--)?(?:\S+(?::\S*)?#)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[#-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/[^\s]*)?
let schemes = URLSchemes.getAllSchemes(separetedBy: "|").replacingOccurrences(of: "://", with: "")
let regex = "(?:(?:\(schemes)):\\/\\/)(?:xn--)?(?:\\S+(?::\\S*)?#)?(?:(?!10(?:\\.\\d{1,3}){3})(?!127(?:\\.\\d{1,3}){3})(?!169\\.254(?:\\.\\d{1,3}){2})(?!192\\.168(?:\\.\\d{1,3}){2})(?!172\\.(?:1[6-9]|2\\d|3[0-1])(?:\\.\\d{1,3}){2})(?:[1-9]\\d?|1\\d\\d|2[01]\\d|22[0-3])(?:\\.(?:1?\\d{1,2}|2[0-4]\\d|25[0-5])){2}(?:\\.(?:[1-9]\\d?|1\\d\\d|2[0-4]\\d|25[0-4]))|(?:(?:[a-z\\u00a1-\\uffff0-9]+-?)*[a-z\\u00a1-\\uffff0-9]+)(?:\\.(?:[a-z\\u00a1-\\uffff0-9]+-?)*[a-z\\u00a1-\\uffff0-9]+)*(?:\\.(?:[#-z\\u00a1-\\uffff]{2,})))(?::\\d{2,5})?(?:\\/[^\\s]*)?"
let regularExpression = try! NSRegularExpression(pattern: regex, options: [])
let range = NSRange(location: 0, length: self.characters.count)
let matches = regularExpression.matches(in: self, options: [], range: range)
for match in matches {
if range.location == match.range.location && range.length == match.range.length {
return true
}
}
return false
}
var toURL: URL? {
let urlChecker: (String)->(URL?) = { url_string in
if url_string.isUrl, let url = URL(string: url_string) {
return url
}
return nil
}
if !contains(".") {
return nil
}
if let url = urlChecker(self) {
return url
}
let scheme = URLSchemes.detectScheme(urlString: self)
if scheme == .unknown {
let newEncodedString = URLSchemes.http.rawValue + self
if let url = urlChecker(newEncodedString) {
return url
}
}
return nil
}
}
Usage
func tests() {
chekUrl(urlString:"http://example.com")
chekUrl(urlString:"https://example.com")
chekUrl(urlString:"http://example.com/dir/file.php?var=moo")
chekUrl(urlString:"http://xn--h1aehhjhg.xn--d1acj3b")
chekUrl(urlString:"http://www.example.com/wpstyle/?p=364")
chekUrl(urlString:"http://-.~_!$&'()*+,;=:%40:80%2f::::::#example.com")
chekUrl(urlString:"http://example.com")
chekUrl(urlString:"http://xn--d1acpjx3f.xn--p1ai")
chekUrl(urlString:"http://xn--74h.damowmow.com/")
chekUrl(urlString:"ftp://example.com:129/myfiles")
chekUrl(urlString:"ftp://user:pass#site.com:21/file/dir")
chekUrl(urlString:"ftp://ftp.example.com:2828/asdah%20asdah.gif")
chekUrl(urlString:"http://142.42.1.1:8080/")
chekUrl(urlString:"http://142.42.1.1/")
chekUrl(urlString:"http://userid:password#example.com:8080")
chekUrl(urlString:"http://userid#example.com")
chekUrl(urlString:"http://userid#example.com:8080")
chekUrl(urlString:"http://foo.com/blah_(wikipedia)#cite-1")
chekUrl(urlString:"http://foo.com/(something)?after=parens")
print("\n----------------------------------------------\n")
chekUrl(urlString:".")
chekUrl(urlString:" ")
chekUrl(urlString:"")
chekUrl(urlString:"-/:;()₽&#.,?!'{}[];'<>+_)(*#^%$")
chekUrl(urlString:"localhost")
chekUrl(urlString:"yandex.")
chekUrl(urlString:"коряга")
chekUrl(urlString:"http:///a")
chekUrl(urlString:"ftps://foo.bar/")
chekUrl(urlString:"rdar://1234")
chekUrl(urlString:"h://test")
chekUrl(urlString:":// should fail")
chekUrl(urlString:"http://-error-.invalid/")
chekUrl(urlString:"http://.www.example.com/")
}
func chekUrl(urlString: String) {
var result = ""
if urlString.isUrl {
result += "url: "
} else {
result += "not url: "
}
result += "\"\(urlString)\""
print(result)
}
Result
Objective C
- (BOOL)validateUrlString:(NSString*)urlString
{
if (!urlString)
{
return NO;
}
NSDataDetector *linkDetector = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeLink error:nil];
NSRange urlStringRange = NSMakeRange(0, [urlString length]);
NSMatchingOptions matchingOptions = 0;
if (1 != [linkDetector numberOfMatchesInString:urlString options:matchingOptions range:urlStringRange])
{
return NO;
}
NSTextCheckingResult *checkingResult = [linkDetector firstMatchInString:urlString options:matchingOptions range:urlStringRange];
return checkingResult.resultType == NSTextCheckingTypeLink && NSEqualRanges(checkingResult.range, urlStringRange);
}
Hope this helps!
did you mean to check if what the user entered is a URL? It can be as simple as a regular expression, for example checking if the string contain www. (this is the way that yahoo messenger checks if the user status is a link or not)
Hope that help
Selfishly, I would suggest using a KSURLFormatter instance to both validate input, and convert it to something NSURL can handle.
I have created inherited class of UITextField which can handle all kind of validation using regex string. In this you just need to give them all the regex string in sequence and their message that you want to show when validation get failed. You can check my blog for more info, it will really help you
http://dhawaldawar.wordpress.com/2014/06/11/uitextfield-validation-ios/
Extending #Anthony's answer to swift, I wrote a category on String which returns an optional NSURL. The return value is nil if the String can not be validated to be a URL.
import Foundation
// A private global detector variable which can be reused.
private let detector = try! NSDataDetector(types: NSTextCheckingType.Link.rawValue)
extension String {
func URL() -> NSURL? {
let textRange = NSMakeRange(0, self.characters.count)
guard let URLResult = detector.firstMatchInString(self, options: [], range: textRange) else {
return nil
}
// This checks that the whole string is the detected URL. In case
// you don't have such a requirement, you can remove this code
// and return the URL from URLResult.
guard NSEqualRanges(URLResult.range, textRange) else {
return nil
}
return NSURL(string: self)
}
}
func checkValidUrl(_ strUrl: String) -> Bool {
let urlRegEx: String = "(http|https)://((\\w)*|([0-9]*)|([-|_])*)+([\\.|/]((\\w)*|([0-9]*)|([-|_])*))+"
let urlTest = NSPredicate(format: "SELF MATCHES %#", urlRegEx)
return urlTest.evaluate(with: strUrl)
}
My solution in Swift 5:
extension String {
func isValidUrl() -> Bool {
do {
let detector = try NSDataDetector(types: NSTextCheckingResult.CheckingType.link.rawValue)
// check if the string has link inside
return detector.numberOfMatches(in: self, options: [], range: .init( location: 0, length: utf16.count)) > 0
} catch {
print("Error during NSDatadetector initialization \(error)" )
}
return false
}
}

Iphone device token - NSData or NSString

I am receiving iPhone device token in the form of NSData object.
When I tested my notifications script function, I have only copied that object from log and the notifications went fine. However when I try now to automatically do it, I am sending the device token as ASCII encoded string in the form of variable
self.deviceToken = [[NSString alloc] initWithData:webDeviceToken encoding:NSASCIIStringEncoding];
The string that I am getting has some funky characters and looks similar to this "å-0¾fZÿ÷ʺÎUQüRáqEªfÔk«"
When server side script sends the notification to that token, I am not receiving anything.
Do I need to decode something and how?
Regardz
Ok, I found a solution. If anyone has the same problem, forget about ASCII encoding, just make the string with the following lines:
NSString *deviceToken = [[webDeviceToken description] stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"<>"]];
deviceToken = [deviceToken stringByReplacingOccurrencesOfString:#" " withString:#""];
If anyone is looking for a way to do this in Swift:
func application(application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: NSData) {
let tokenChars = UnsafePointer<CChar>(deviceToken.bytes)
var tokenString = ""
for i in 0..<deviceToken.length {
tokenString += String(format: "%02.2hhx", arguments: [tokenChars[i]])
}
print("tokenString: \(tokenString)")
}
Edit: For Swift 3
Swift 3 introduces the Data type, with value semantics. To convert the deviceToken to a String, you can do as follows:
func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
var token: String = ""
for i in 0..<deviceToken.count {
token += String(format: "%02.2hhx", deviceToken[i] as CVarArg)
}
print(token)
}
I found this solution better as iOS can change the usage of description in future versions, so using description property on data can be unreliable in future.
We can directly use this by creating hex Token from the data token bytes.
- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)devToken {
const unsigned *tokenBytes = [deviceToken bytes];
NSString *hexToken = [NSString stringWithFormat:#"%08x%08x%08x%08x%08x%08x%08x%08x",
ntohl(tokenBytes[0]), ntohl(tokenBytes[1]), ntohl(tokenBytes[2]),
ntohl(tokenBytes[3]), ntohl(tokenBytes[4]), ntohl(tokenBytes[5]),
ntohl(tokenBytes[6]), ntohl(tokenBytes[7])];
[[MyModel sharedModel] setApnsToken:hexToken];
}
We can also store the device token in our NSUserdefaults and use it later to send it out to our server.
I don't think it's a good solution, as you have to reconstruct the string before sending the notifications to Apple servers. Use Base64 encoding for transmitting the strings or something similar.
Another way of converting device token into hexa decimal string
NSUInteger capacity = [deviceToken length] * 2;
NSMutableString *stringBuffer = [NSMutableString stringWithCapacity:capacity];
const unsigned char *dataBuffer = [deviceToken bytes];
NSInteger i;
for (i=0; i<[deviceToken length]; ++i) {
[stringBuffer appendFormat:#"%02X", (NSUInteger)dataBuffer[i]];
}
NSLog(#"token string buffer is %#",stringBuffer);
For Swift 3 :
var tokenString: String = ""
for i in 0..<deviceToken.count {
tokenString += String(format: "%02.2hhx", deviceToken[i] as CVarArg)
}
print(tokenString)
Other Method
Create Data extension for getting hexstring
extension Data {
var hexString: String {
return map { String(format: "%02.2hhx", arguments: [$0]) }.joined()
}
}
And call this extension in
func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
let tokenString = deviceToken.hexString()
print("token: \(tokenString)")
}