mongo $filter and multiple condition in sub-sub array - mongodb

Question

I have this portion of collections:
[{
"_id": ObjectId("604f3ae3194f2135b0ade569"),
"parameters": [
{
"_id": ObjectId("602b7455f4b4bf5b41662ec1"),
"name": "Purpose",
"options": [
{
"id": ObjectId("602b764ff4b4bf5b41662ec2"),
"name": "debug",
"sel": true
},
{
"id": ObjectId("602b767df4b4bf5b41662ec3"),
"name": "performance",
"sel": false
},
{
"id": ObjectId("602b764ff4b4bf5b41662ec4"),
"name": "security",
"sel": true
},
{
"id": ObjectId("602b767df4b4bf5b41662ec5"),
"name": "Not Applicable",
"sel": false
}
],
"type": "multiple"
}]
}]
And this query:
db.testCollection.aggregate([
{ $unwind: "$parameters" },
{
$match: {
"parameters._id": ObjectId("602b7455f4b4bf5b41662ec1"),
}
},
{
$addFields: {
match: {
$filter: {
input: "$parameters.options",
as: "option",
cond: {
$and: [
{ $eq: ["$$option.id", ObjectId('602b764ff4b4bf5b41662ec2')] },
{ $eq: ["$$option.sel", true] }
]
}
}
}
}
}
])
The result is a new array match with, in this case,
"match": [
{
"id": ObjectId("602b764ff4b4bf5b41662ec2"),
"name": "debug",
"sel": true
}
]
How I can match, for collections, match for example
"id": ObjectId("602b764ff4b4bf5b41662ec2") and
"id": ObjectId("602b764ff4b4bf5b41662ec4")
and have a result array with or two results or empty?

Answer 1

I am not sure it is possible in single condition inside $filter, but you can try with $let,
$let to declare a variable called filtered and store your filtered result
$in to check condition if filtered element size is 2 then return filtered result otherwise blank array
You have to put the number that you are matching number of ids in filter in $eq condition
{
$addFields: {
match: {
$let: {
vars: {
filtered: {
$filter: {
input: "$parameters.options",
as: "option",
cond: {
$and: [
{
$in: [
"$$option.id",
[ObjectId("602b764ff4b4bf5b41662ec2"), ObjectId("602b767df4b4bf5b41662ec3")]
]
},
{ $eq: ["$$option.sel", true] }
]
}
}
}
},
in: {
$cond: [
{ $eq: [{ $size: "$$filtered" }, 2] },
"$$filtered",
[]
]
}
}
}
}
}
Playground