By default Ag Grid Quick Filter function return rows that contains search string. For example if I type "30 June" in the searchbox, quick filter will also return rows that contains "30 cars were sold by 2 June" text. How can I override default behavior to receive only rows that exactly match my search string?
What I did was the following:
In the search itself, I removed the spaces from the search criteria:
this.gridApi.setQuickFilter(event.toLowerCase().replace(" ", ""));
In each column that I wanted an exact match, I added this code in the column definition:
getQuickFilterText: (params) => { return params.value && params.value.toLowerCase().replace(" ", "");}
(That is the override method for search. See here for more details: https://www.ag-grid.com/angular-data-grid/filter-quick/)
It seems to be working for me.
To achieve the exact match results column wise, You have to do these two things :
Remove cacheQuickFilter property from your default column definition object in gridOptions as caching convert all the columns data into a string separated by backward slash. That's the reason it will not be able to search column by column.
Add getQuickFilterText function in each column definition and add a condition for a exact match else return an empty string.
getQuickFilterText: params => {
return (params.value === <quick filter value>) ? params.value : ''
}
Now the tricky part here is how to access quick filter value inside getQuickFilterText function. You can achieve this in two ways :
Assign an id to quick filter search element and then access it's value using document.getElementById('quick-filter').value
Store the quick filter search value on change and put into a store state or service and then access that inside getQuickFilterText function.
Related
I am listing users in a CustomScrollView/SliversList,ListTiles. I have a String field in my firestore and only want to return ListTile of a user, where his String field contains specific words (more than 2). For example, the users fields contain: "Apples, Ice, Bananas, Soup, Peaches, e.g...." and i want to list all users which have apples and bananas inside the field. how can i achieve this?
The only way to do it at the moment (with the way you have it set up) is actually pulling the value and doing a string "contains" or splitting the string into an array and check whether the value is within that array, otherwise I'd advise to refactor that field and make it into an array, that way you can perform a native arrayContainsAny against your field.
For you it will look like this (with your current implementation):
// ... after pulling all users' documents
// let's say your field is called 'foodField':
var criteria = 'Banana';
var fieldContent = doc.data()['foodField'];
// you can either do this:
if (fieldContent.toLowerCase().contains(criteria.toLowerCase())) {
// ...
}
// or you can tokenize it depending on your purposes...
var foodTokens = fieldContent.split(',').map((f) => f.toLowerCase());
if (foodTokens.contains(criteria.toLowerCase()) {
// ...
}
If your Firestore field was an array type, then you could've just done that, while querying:
FirebaseFirestore.instance.collection('users').where('foodField', arrayContainsAny: ['Banana', 'Apples'])
Which then would give you only the users whose foodField contain that value.
As you can see from previous questions on querying where text contains a substring, Firestore does not currently support such text searches. The typical solutions are to either perform part of your filtering in your application code as Roman answered, or to integrate a third-party full-text search solution.
In your specific case though, your string seems to be a list of words, so I'd recommend considering to change your data model to an array of the individual values in there:
"foodFields": ["Apples", "Ice", "Banana", "Soup", "Peaches"]
You can then use array field operators in the query.
While there is no array-contains-all operator, using array-contains you can at least filter on one value in the database, and with array-contains-any you can do on OR like condition.
Another data model would be to store the individual values in a map field with value true for each of them:
"foodFields": {
"Apples": true,
"Ice": true,
"Banana": true,
"Soup": true,
"Peaches": true
}
With such a structure you can perform an AND like query with:
collectionRef
.where('foodFields.Apples', isEqualTo: true)
.where('foodFields.Bananas', isEqualTo: true)
I have in my index a list of object, each of them has an objectID value.
On some search, i want to filter OUT a certain number of them, using there objectID.
For the moment it works with one value as a string, i would like to know how to do for multiple value.
filters = 'NOT objectID:' + objectIDToFilter;
This work for one object, what can i do to apply this for an array of ObjectID. because :
filters = 'NOT objectID:' + arrayObjectID;
does not work.
I was thinking of generating a huge string with an arrayId.map with all my 'NOT objectID:1 AND NOT objectID: 2 ...' but i wanted to know if there is a cleaner way to do it.
I unfortunately misunderstood the line in algolia doc :
Array Attributes: Any attribute set up as an array will match the filter as soon as one of the values in the array match.
This apparently refers to the value itself in Algolia and not the filter
So i did not found a solution on algolia doc, i went for the long string, hope there is no limits on how much filter we can add on a query (found nothing about that).
Here is what i did if someone need it :
let filters = `NOT objectID:${userID}`;
blockedByUsers.map((blockedByUser) => {
filters = filters + ` AND NOT objectID:${blockedByUser}`;
});
If you need to add multiple but don't have a starting point like i do, you can't start the query with an AND , a solution i found to bypass that:
let filters = `NOT objectID:${blockedByUsers[0]}`;
blockedByUsers.map((blockedByUser, i) => {
if (i > 0) filters = filters + ` AND NOT objectID:${blockedByUser}`;
});
There is probably a cleaner solution, but this work. If you have found other solution for that problems i'll be happy to see :)
Is there a search all filter when trying to search through the db? I have multiple select boxes that I would like to get the value of and then according to the values, it searches for the data. I found that I would need to have an if statement for each select box to check if it is the default value(String) or a selected value(Integer).
items.find({
"person.age": obj.age, //is 'All'
"person.gender": obj.gender // is 'male'
},{
limit: this.state.limit
}).fetch()
In my example above, one is the default (all) and the other is the selected value. When I try to search, it would return nothing because of the 'all'. I am looking for a symbol or something to replace the 'all'.
#masteram is right - you want to avoid the keys that contain All - there is no * in mongodb. You can simplify your logic at the same time.
The following will copy only the keys of obj that are not equal to All then run the search on those keys:
const person = {};
Object.keys(obj).forEach((k) => {
if (obj[k] !== 'All') person[k] = obj[k];
});
items.find(person, { limit: this.state.limit }).fetch()
I need to search for users by name, their first name and last names are stored in separate columns in a postgresql database. The columns need to be concatenated for search to work properly. Typing the full first and last name of a user should match a result.
What could I pass as a query to the find method of a Feathers service that would allow me to do this?
As in the answer linked you can pass the where clause to the Feathers service by modifying params.query in a before hook:
app.service('users').before({
find(hook) {
const where = Sequelize.where(Sequelize.fn("concat",
Sequelize.col("firstname"),
Sequelize.col("lastname")), {
like: '%John Do%'
}
);
hook.params.query.where = where;
}
})
I'm new to Couchbase and am struggling to get a composite index to do what I want it to. The use-case is this:
I have a set of "Enumerations" being stored as documents
Each has a "last_updated" field which -- as you may have guessed -- stores the last time that the field was updated
I want to be able to show only those enumerations which have been updated since some given date but still sort the list by the name of the enumeration
I've created a Couchbase View like this:
function (doc, meta) {
var time_array;
if (doc.doc_type === "enum") {
if (doc.last_updated) {
time_array = doc.last_updated.split(/[- :]/);
} else {
time_array = [0,0,0,0,0,0];
}
for(var i=0; i<time_array.length; i++) { time_array[i] = parseInt(time_array[i], 10); }
time_array.unshift(meta.id);
emit(time_array, null);
}
}
I have one record that doesn't have the last_updated field set and therefore has it's time fields are all set to zero. I thought as a first test I could filter out that result and I put in the following:
startkey = ["a",2012,0,0,0,0,0]
endkey = ["Z",2014,0,0,0,0,0]
While the list is sorted by the 'id' it isn't filtering anything! Can anyone tell me what I'm doing wrong? Is there a better composite view to achieve these results?
In couchbase when you query view by startkey - endkey you're unable to filter results by 2 or more properties. Couchbase has only one index, so it will filter your results only by first param. So your query will be identical to query with:
startkey = ["a"]
endkey = ["Z"]
Here is a link to complete answer by Filipe Manana why it can't be filtered by those dates.
Here is a quote from it:
For composite keys (arrays), elements are compared from left to right and comparison finishes as soon as a element is different from the corresponding element in the other key (same as what happens when comparing strings à la memcmp() or strcmp()).
So if you want to have a view that filters by date, date array should go first in composite key.