does anyone know if there is a formula for Google Sheet to check if a specific month (eg, Nov) is present between two dates?
In the Example above, what formula should I write in cell C2 in order to return a TRUE?
Thanks!
try:
=IF((MONTH(C1&1)>=MONTH(A2))*(MONTH(C1&1)<=MONTH(B2)); TRUE)
Try this:
=isbetween( month(1 & C1), month(A2), month(B2), false, false )
To use inclusive boundaries, use true instead of false.
Related
I text based .csv file with a semicolon separated data set which contains date values that look like this
22.07.2020
22.07.2020
17.07.2020
09.07.2020
30.06.2020
When I go to Format>number> I see the Google sheets has automatic set.
In this state I cannot use and formulas with this data.
I go to Format>number> and set this to date but formulas still do not see the actual date value and continue to display an error
Can someone share how I can quickly activate the values of this array so formulas will work against them?
I would be super thankful
Where the date are in column A, starting in cell A1, this formula will convert to DATE as a number, after which you apply formatting to Short Date style.
=ARRAYFORMULA(IF(A1:A="",,DATE(RIGHT(A1:A,4),MID(A1:A,4,2),LEFT(A1:A,2))))
Hopefully(!) the dates stay as text, otherwise Google Sheets would sometimes detect MM/dd/yyyy instead of dd/MM/yyyy, and you won't be able to distinguish between July 9th and September 7th in your example.
Solution #1
If your locale is for instance FR, you can then apply
=arrayformula(if(A1:A="";;value(A1:A)))
solution#2
you can try/adapt
function importCsvFromIdv1() {
var id = 'the id of the csv file';
var csv = DriveApp.getFileById(id).getBlob().getDataAsString();
var csvData = Utilities.parseCsv(csv);
csvData.forEach(function(row){
date = row[0]
row[0] = date.substring(6,10)+'-'+date.substring(3,5)+'-'+date.substring(0,2)
})
var f = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
f.getRange(1, 1, csvData.length, csvData[0].length).setValues(csvData);
}
First thanks to those that suggested a fix. I am not really a programmer and get cold sweats when I see suggesting of running scripts to solve simple problems. Sorry guys.
So the (non programmer) solution with the dates was to do a find/replace (CTRL + H) and replace all the (.)dots with (/)slashes, then to make sure the column is formatted as a date, then Google finally understands it as a date.
With the accounting values as well, I had to do the same find/replace to remove all the ' between thousands, then google woke up and understood them as numbers.
I am significantly underwhelmed by this from Google. They are getting too fat and lazy. They need some competition.
I am using Tableau Server version 10.4.3
I have a dimension rTime which has string value. the entries in rTime is of like this
May 10, 2019 8:59:56.303 PM UTC
I want to check whether the rTime is today or not. I cannot use DateParse since my server doesn't have this functionality.
I created a calculated field CheckrTime with below content :
STR(LEFT(SPLIT([rTime],':',1),LEN(SPLIT([rTime],':',1))-2))
When I am dragging CheckrTime into workspace area, the output is coming in below format which is what I wanted :
May 10, 2019
When I am checking ISDATE("May 10, 2019") (a normal string), it is outputting TRUE as expected but when I am checking ISDATE(CheckrTime) it is outputting FALSE . Why?
The reason I am checking above thing is I am looking to use DATEDIFF function of tableau in this way:
DATEDIFF('day', DATE(CheckrTime), TODAY()) == 0
NOTE
If someone is wondering ,I have taken care of the level of granularity.
If you have a better solution then the one I am following, please do tell me.
This is working for me. I would expect May 10 <> May 16 (today) and therefore return false. However, when I change your example to today's date it does in fact come back as true.
You could also try this formula for the date LEFT([rTime],FINDNTH([rTime],' ',3)). It is slightly less complicated but will give you the same answer.
Calculated field (date type) depends the locale used which defines date format. Are you able to use Date function?
In Tableau website there is a example using english locale
For string 06May2017
DATE (LEFT([Original Date], 2) + "/" + MID([Original Date],3,3) + "/" + RIGHT([Original Date],4))
Above mentioned highligts / character between digits which is depending on locale
I have been working on what seemed to a simple date comparison to hide an object until the proper date arrives.
I have trying different variations and each seem NOT to work. I am trying to suppress an object in Crystal Reports until, let's say, August 1 2018. After the specified date, have it display.
CurrentDate >= #8/1/2018#
ToText(CurrentDate) >= "8/1/2018"
The reasoning I have to change labels soon and rather manually go back in later (I have a ton of labels) figured I'd do what seemed a simple date comparison and switch.
Thanks,
Gary
Figured it out;
if (CurrentDate) >= #8/1/2018# AND (#TrueFalse Field) = false then false
if (CurrentDate) >= #8/1/2018# AND (#TrueFalse Field) = true then true
else true
Worked like a charm.
Thanks,
Gary
I have a DateTime property.
I want to check if a date is equal to the date in my property and it has to be done purely in the url query parameters available in OData v4.
This doesn't work :(
GET ~/odata/foo$filter=date(myProperty) eq date(1980-01-01)
Yes I can use greater then or equal but that's is already working as intended. It's equal and not equal that's the problem.
From ABNF rules, Date value is a value with format:
dateValue = year "-" month "-" day
So, I think you shouldn't add date prefix. That's:
GET ~/odata/foo$filter=date(myProperty) eq 1980-01-01
Here's some test cases provided by ODataTeam:
https://github.com/OData/WebApi/blob/master/OData/test/E2ETest/WebStack.QA.Test.OData/DateAndTimeOfDay/DateAndTimeOfDayTest.cs#L169-L171
and
https://github.com/OData/WebApi/blob/master/OData/test/E2ETest/WebStack.QA.Test.OData/DateAndTimeOfDay/DateAndTimeOfDayTest.cs#L208-L212
Besides, there's a simple tutorial you can refer to:
http://odata.github.io/WebApi/#04-04-date-and-timeofday-support
Thanks. Hope it can help.
I've get value "SDFE12:56" from database, but in my report, i only want to show 12:56 under the colume Time. Is there a way to do that? I've already tried by Ctime()function. but it seems not working
thanks
try val function
val(SDFE12:56)
if you want check link
In the same lay as your other question
Mid ("SDFE12:56",4 ,5 )
or because it is at then end you can do
Mid ("SDFE12:56",4)