find value of difference DISTINCT a column in PostgreSQL - postgresql

I have a table, I run count(capture_time) on a column the result is 616606. Also, I run count (DISTINCT capture_time) on the same column the result is 580580.
Now, I want to see the value of the 36026 rows.(616606 - 580580 = 36026)
Which query I can use?

You can use a GROUP BY to group all identical capture_time values. Then you filter on those capture_time values which exist more than one time by using HAVING. Something like this:
select * from tablename where capture_time in(select capture_time from tablename group by capture_time having count(*) > 1)

Related

how to select multiple column from the table using group by( based on one column) , having and count in hive query

Requirement :
Using group by A and get records having count > 1
eg:
SELECT count(sk), id, sk
FROM table x
GROUP BY id
HAVING COUNT(sk) > 1
But I am not able to select sk in select statement. Is there any other way to do this. how to use partition on this input and output set attached here?
Something like this, you can do.
select * from (
SELECT count(sk)over(partition by id) as cnt, id, sk
FROM table x) a
where a.cnt >1

how to values transfer to another column with two query

I have a query. this query is calculated percentage for every product. I created a virtual column on this query this columns name is 'yüzde'. After that, i want to transfer yüzde columns to another column in another table with update query if product ids are same.
I think I need to write a stored procedure. How can I do that?
SELECT [ProductVariantId] ,
count([ProductVariantId]) as bedensayısı,
count([ProductVariantId]) * 100.0 / (SELECT Top 1 Count(*) as Total
FROM [Live_ADL].[dbo].[_INV_ProductCombinationAttributes]
Where Size LIKE '%[^0-9]%' and [StockQuantity]>0
Group by [ProductVariantId]
order by Total Desc) as yüzde
FROM [Live_ADL].[dbo].[_INV_ProductCombinationAttributes]
Where Size LIKE '%[^0-9]%' and [StockQuantity]>0
group by [ProductVariantId]
order by yüzde desc
you don't really need a SP, you can do it in-line, using CTE for instance, something along these lines:
; with tabyuzde as
(
SELECT [ProductVariantId] ,
count([ProductVariantId]) as bedensayısı,
count([ProductVariantId]) * 100.0 / (SELECT Top 1 Count(*) as Total
FROM [Live_ADL].[dbo].[_INV_ProductCombinationAttributes]
Where Size LIKE '%[^0-9]%' and [StockQuantity]>0
Group by [ProductVariantId]
order by Total Desc) as yüzde
FROM [Live_ADL].[dbo].[_INV_ProductCombinationAttributes]
Where Size LIKE '%[^0-9]%' and [StockQuantity]>0
group by [ProductVariantId]
)
update x
set othertablevalue=yüzde
from
othertable x
join tabyuzde t on x.ProductVariantId=t.ProductVariantId

Simple SELECT, but adding JOIN returns too many rows

The query below returns 9,817 records. Now, I want to SELECT one more field from another table. See the 2 lines that are commented out, where I've simply selected this additional field and added a JOIN statement to bind this new columns. With these lines added, the query now returns 649,200 records and I can't figure out why! I guess something is wrong with my WHERE criteria in conjunction with the JOIN statement. Please help, thanks.
SELECT DISTINCT dbo.IMPORT_DOCUMENTS.ITEMID, BEGDOC, BATCHID
--, dbo.CATEGORY_COLLECTION_CATEGORY_RESULTS.CATEGORY_ID
FROM IMPORT_DOCUMENTS
--JOIN dbo.CATEGORY_COLLECTION_CATEGORY_RESULTS ON
dbo.CATEGORY_COLLECTION_CATEGORY_RESULTS.ITEMID = dbo.IMPORT_DOCUMENTS.ITEMID
WHERE (BATCHID LIKE 'IC0%' OR BATCHID LIKE 'LP0%')
AND dbo.IMPORT_DOCUMENTS.ITEMID IN
(SELECT dbo.CATEGORY_COLLECTION_CATEGORY_RESULTS.ITEMID FROM
CATEGORY_COLLECTION_CATEGORY_RESULTS
WHERE SCORE >= .7 AND SCORE <= .75 AND CATEGORY_ID IN(
SELECT CATEGORY_ID FROM CATEGORY_COLLECTION_CATS WHERE COLLECTION_ID IN (11,16))
AND Sample_Id > 0)
AND dbo.IMPORT_DOCUMENTS.ITEMID NOT IN
(SELECT ASSIGNMENT_FOLDER_DOCUMENTS.Item_Id FROM ASSIGNMENT_FOLDER_DOCUMENTS)
One possible reason is because one of your tables contains data at lower level, lower than your join key. For example, there may be multiple records per item id. The same item id is repeated X number of times. I would fix the query like the below. Without data knowledge, Try running the below modified query.... If output is not what you're looking for, convert it into SELECT Within a Select...
Hope this helps....
Try this SQL: SELECT DISTINCT a.ITEMID, a.BEGDOC, a.BATCHID, b.CATEGORY_ID FROM IMPORT_DOCUMENTS a JOIN (SELECT DISTINCT ITEMID FROM CATEGORY_COLLECTION_CATEGORY_RESULTS WHERE SCORE >= .7 AND SCORE <= .75 AND CATEGORY_ID IN (SELECT DISTINCT CATEGORY_ID FROM CATEGORY_COLLECTION_CATS WHERE COLLECTION_ID IN (11,16)) AND Sample_Id > 0) B ON a.ITEMID =b.ITEMID WHERE a.(a.BATCHID LIKE 'IC0%' OR a.BATCHID LIKE 'LP0%') AND a.ITEMID NOT IN (SELECT DIDTINCT Item_Id FROM ASSIGNMENT_FOLDER_DOCUMENTS)

In Firebird, how to aggregate the first N rows?

I would like to do something like this:
CNT=2;
//[edit]
select avg(price) from (
select first :CNT p.Price
from Price p
order by p.Date desc
);
This does not work, Firebird does not allow :cnt as a parameter to FIRST. I need to average the first CNT newest prices. The number 2 changes so it can not be hard-coded.
This can be broken out into a FOR SELECT loop and break when a count is reached. Is that the best way though? Can this be done in a single SQL statement?
Creating the SQL as a string and running it is not the best fit either. It is important that the database compile my SQL statement.
You don't have to use CTE, you can do it directly:
select avg(price) from (
select first :cnt p.Price
from Price p
order by p.Date desc
);
You can use a CTE (Common Table Expression) (see http://www.firebirdsql.org/refdocs/langrefupd21-select.html#langrefupd21-select-cte) to select data before calculate average.
See example below:
with query1 as (
select first 2 p.Price
from Price p
order by p.Date desc
)
select avg(price) from query1

Postgres: select the sum of values and then sum this again

I tried a lot but can´t find the right way.
If I select values in Postgres and sum them it looks like this:
SELECT name,sum(size) as total
FROM mytable group by name order by name;
How can I alter this so it also sum all values in total? I think I need a subselect but how?
Try this:
SELECT sum(a.total)
FROM (SELECT sum(size) as total
FROM mytable group by name) a
UPDATE
I'm sorry, I don't read that you want it all in the same query. For this reason the answer of greg it's better. However, other possibility if you have a postgresql version >= 9:
WITH mytableWith (name, sum) as
(SELECT name, sum(size)
FROM mytable
GROUP BY name)
SELECT 'grand total' AS name,
sum(sum) AS sum
FROM mytableWith
UNION ALL
SELECT name, sum
FROM mytableWith
I would use the ROLLUP function on POSTRGESQL:
SELECT name,sum(size) as total
FROM mytable
group by ROLLUP(name )
order by name;
This will give you a grand total of any value that you aggregate and can also be used for aggregating multiple columns.
Hope it helps!
If you want all results with the same SELECT, you could do something like
SELECT
'grand total' AS name,
sum(size) AS sum
FROM
mytable
UNION ALL
SELECT
name,
sum(size) AS sum
FROM
mytable
GROUP BY
name;
Hope it helps…
Well this should help you:
select sum(innerselect.innertotal) as outertotal from
(select sum(size) as innertotal from mytable group by name) as innerselect