How to count embedded array object elements in mongoDB - mongodb

{
"orderNo": "123",
"bags": [{
"type": "small",
"products": [{
"id": "1",
"name": "ABC",
"returnable": true
}, {
"id": "2",
"name": "XYZ"
}
]
},{
"type": "big",
"products": [{
"id": "3",
"name": "PQR",
"returnable": true
}, {
"id": "4",
"name": "UVW"
}
]
}
]
}
I have orders collection where documents are in this format. I want to get a total count of products which has the returnable flag. e.g: for the above order the count should be 2. I am very new to MongoDB wanted to know how to write a query to find this out, I have tried few things but did not help:
this is what I tried but not worked:
db.orders.aggregate([
{ "$unwind": "$bags" },
{ "$unwind": "$bags.products" },
{ "$unwind": "$bags.products.returnable" },
{ "$group": {
"_id": "$bags.products.returnable",
"count": { "$sum": 1 }
}}
])

For inner array you can use $filter to check returnable flag and $size to get number of such items. For the outer one you can take advantage of $reduce to sum the values from inner arrays:
db.collection.aggregate([
{
$project: {
totalReturnable: {
$reduce: {
input: "$bags",
initialValue: 0,
in: {
$add: [
"$$value",
{
$size: {
$filter: {
input: "$$this.products",
as: "prod",
cond: {
$eq: [ "$$prod.returnable", true ]
}
}
}
]
}
}
}
}
}
}
])
Mongo Playground

Related

MongoDB: Assign document objects to field in '$project' stage

I have a user collection:
[
{"_id": 1,"name": "John", "age": 25, "valid_user": true}
{"_id": 2, "name": "Bob", "age": 40, "valid_user": false}
{"_id": 3, "name": "Jacob","age": 27,"valid_user": null}
{"_id": 4, "name": "Amelia","age": 29,"valid_user": true}
]
I run a '$facet' stage on this collection. Checkout this MongoPlayground.
I want to talk about the first output from the facet stage. The following is the response currently:
{
"user_by_valid_status": [
{
"_id": false,
"count": 1
},
{
"_id": true,
"count": 2
},
{
"_id": null,
"count": 1
}
]
}
However, I want to restructure the output in this way:
"analytics": {
"invalid_user": {
"_id": false
"count": 1
},
"valid_user": {
"_id": true
"count": 2
},
"user_with_unknown_status": {
"_id": null
"count": 1
}
}
The problem with using a '$project' stage along with 'arrayElemAt' is that the order may not be definite for me to associate an index with an attribute like 'valid_users' or others. Also, it gets further complicated because unlike the sample documents that I have shared, my collection may not always contain all the three categories of users.
Is there some way I can do this?
You can use $switch conditional operator,
$project to show value part in v with _id and count field as object, k to put $switch condition
db.collection.aggregate([
{
"$facet": {
"user_by_valid_status": [
{
"$group": {
"_id": "$valid_user",
"count": { "$sum": 1 }
}
},
{
$project: {
_id: 0,
v: { _id: "$_id", count: "$count" },
k: {
$switch: {
branches: [
{ case: { $eq: ["$_id", null] }, then: "user_with_unknown_status" },
{ case: { $eq: ["$_id", false] }, then: "invalid_user" },
{ case: { $eq: ["$_id", true] }, then: "valid_user" }
]
}
}
}
}
],
"users_above_30": [{ "$match": { "age": { "$gt": 30 } } }]
}
},
$project stage in root, convert user_by_valid_status array to object using $arrayToObject
{
$project: {
analytics: { $arrayToObject: "$user_by_valid_status" },
users_above_30: 1
}
}
])
Playground

How to get count by order in mongodb aggregate?

I have two collections name listings and moods.
listings sample:
{
"_id": ObjectId("5349b4ddd2781d08c09890f3"),
"name": "Hotel Radisson Blu",
"moods": [
ObjectId("507f1f77bcf86cd799439010"),
ObjectId("507f1f77bcf86cd799439011")
]
}
moods sample:
{
"_id": ObjectId("507f1f77bcf86cd799439011"),
"name": "Sports"
},
{
"_id": ObjectId("507f1f77bcf86cd799439010"),
"name": "Spanish Food"
},
{
"_id": ObjectId("507f1f77bcf86cd799439009"),
"name": "Action"
}
I need this record.
{
"_id": ObjectId("507f1f77bcf86cd799439011"),
"name": "Sports",
"count": 1
},
{
"_id": ObjectId("507f1f77bcf86cd799439010"),
"name": "Spanish Food",
"count": 1
},
{
"_id": ObjectId("507f1f77bcf86cd799439009"),
"name": "Action",
"count": 0
}
I need this type of record. I have no idea about aggregate.
You can do it using aggregate(),
$lookup to join collection listings
$match pipeline to check moods _id in listings field moods array
db.moods.aggregate([
{
"$lookup": {
"from": "listings",
"as": "count",
let: { id: "$_id" },
pipeline: [
{
"$match": {
"$expr": { "$in": ["$$id", "$moods"] }
}
}
]
}
},
$addFields to add count on the base of $size of array count that we got from above lookup
{
$addFields: {
count: { $size: "$count" }
}
}
])
Playground
did this work:
db.collection.aggrate().count()
Try to combine the functions, it might work.

Sort records by array field values in MongoDb

I have a collection which has documents like;
{
"name": "Subject1",
"attributes": [{
"_id": "security_level1",
"level": {
"value": "100",
"valueKey": "ABC"
}
}, {
"_id": "security_score1",
"level": {
"value": "1000",
"valueKey": "CDE"
}
}
]
},
{
"name": "Subject2",
"attributes": [{
"_id": "security_level1",
"level": {
"value": "99",
"valueKey": "XYZ"
}
}, {
"_id": "security_score1",
"level": {
"value": "2000",
"valueKey": "EDF"
}
}
]
},
......
Each document will have so many attributes generated dynamically, can be different in size.
Is it possible to sort records based on level.value of security_level1? (security_level1 is _id field value)
As per above example, the second document ("name": "Subject2") should come first as the value ('level.value') of _id:security_level1 is 99, which is less than of Subject1's security_level1 value (100) - (Ascending order)
Use $filter and $arrayElemAt to get security_level1 item. Then you can use $toInt to convert that value to an integer so that $sort can be applied:
db.collection.aggregate([
{
$addFields: {
level: {
$let: {
vars: {
level_1: { $arrayElemAt: [ { $filter: { input: "$attributes", cond: { $eq: [ "$$this._id", "security_level1" ] } } } ,0] }
},
in: {
$toInt: "$$level_1.level.value"
}
}
}
}
},
{
$sort: {
level: 1
}
}
])
Mongo Playground

MongoDb aggregation with arrays inside an array possible

I am struggling to find some examples of using the mongo aggregation framework to process documents which has an array of items where each item also has an array of other obejects (array containing an array)
In the example document below what I would really like is an example that sums the itemValue in the results array of all cases in the document and accross the collection where the result.decision was 'accepted'and group by the document locationCode
However, even an example that found all documents where the result.decision was 'accepted' to show or that summmed the itemValue for the same would help
Many thanks
{
"_id": "333212",
"data": {
"locationCode": "UK-555-5566",
"mode": "retail",
"caseHandler": "A N Other",
"cases": [{
"caseId": "CSE525666",
"items": [{
"id": "333212-CSE525666-1",
"type": "hardware",
"subType": "print cartridge",
"targetDate": "2020-06-15",
"itemDetail": {
"description": "acme print cartridge",
"quantity": 2,
"weight": "1.5"
},
"result": {
"decision": "rejected",
"decisionDate": "2019-02-02"
},
"isPriority": true
},
{
"id": "333212-CSE525666-2",
"type": "Stationery",
"subType": "other",
"targetDate": "2020-06-15",
"itemDetail": {
"description": "staples box",
"quantity": 3,
"weight": "1.66"
},
"result": {
"decision": "accepted",
"decisionDate": "2020-03-03",
"itemValue": "23.01"
},
"isPriority": true
}
]
},
{
"caseId": "CSE885655",
"items": [{
"id": "333212-CSE885655-1",
"type": "marine goods",
"subType": "fish food",
"targetDate": "2020-06-04",
"itemDetail": {
"description": "fish bait",
"quantity": 5,
"weight": "0.65"
},
"result": {
"decision": "accepted",
"decisionDate": "2020-03-02"
},
"isPriority": false
},
{
"id": "333212-CSE885655-4",
"type": "tobacco products",
"subType": "cigarettes",
"deadlineDate": "2020-06-15",
"itemDetail": {
"description": "rolling tobbaco",
"quantity": 42,
"weight": "2.25"
},
"result": {
"decision": "accepted",
"decisionDate": "2020-02-02",
"itemValue": "48.15"
},
"isPriority": true
}
]
}
]
},
"state": "open"
}
You're probably looking for $unwind. It takes an array within a document and creates a separate document for each array member.
{ foos: [1, 2] } -> { foos: 1 }, { foos: 2}
With that you can create a flat document structure and match & group as normal.
db.collection.aggregate([
{
$unwind: "$data.cases"
},
{
$unwind: "$data.cases.items"
},
{
$match: {
"data.cases.items.result.decision": "accepted"
}
},
{
$group: {
_id: "$data.locationCode",
value: {
$sum: {
$toDecimal: "$data.cases.items.result.itemValue"
}
}
}
},
{
$project: {
_id: 0,
locationCode: "$_id",
value: "$value"
}
}
])
https://mongoplayground.net/p/Xr2WfFyPZS3
Alternative solution...
We group by data.locationCode and sum all items with this condition:
cases[*].items[*].result.decision" == "accepted"
db.collection.aggregate([
{
$group: {
_id: "$data.locationCode",
itemValue: {
$sum: {
$reduce: {
input: "$data.cases",
initialValue: 0,
in: {
$sum: {
$concatArrays: [
[ "$$value" ],
{
$map: {
input: {
$filter: {
input: "$$this.items",
as: "f",
cond: {
$eq: [ "$$f.result.decision", "accepted" ]
}
}
},
as: "item",
in: {
$toDouble: {
$ifNull: [ "$$item.result.itemValue", 0 ]
}
}
}
}
]
}
}
}
}
}
}
}
])
MongoPlayground

MongoDB multiple counts, single document, arrays

I have been searching on stackoverflow and cannot find exactly what I am looking for and hope someone can help. I want to submit a single query, get multiple counts back, for a single document, based on array of that document.
My data:
db.myCollection.InsertOne({
"_id": "1",
"age": 30,
"items": [
{
"id": "1",
"isSuccessful": true,
"name": null
},{
"id": "2",
"isSuccessful": true,
"name": null
},{
"id": "3",
"isSuccessful": true,
"name": "Bob"
},{
"id": "4",
"isSuccessful": null,
"name": "Todd"
}
]
});
db.myCollection.InsertOne({
"_id": "2",
"age": 22,
"items": [
{
"id": "6",
"isSuccessful": true,
"name": "Jeff"
}
]
});
What I need back is the document and the counts associated to the items array for said document. In this example where the document _id = "1":
{
"_id": "1",
"age": 30,
{
"totalIsSuccessful" : 2,
"totalNotIsSuccessful": 1,
"totalSuccessfulNull": 1,
"totalNameNull": 2
}
}
I have found that I can get this in 4 queries using something like this below, but I would really like it to be one query.
db.test1.aggregate([
{ $match : { _id : "1" } },
{ "$project": {
"total": {
"$size": {
"$filter": {
"input": "$items",
"cond": { "$eq": [ "$$this.isSuccessful", true ] }
}
}
}
}}
])
Thanks in advance.
I am assuming your expected result is invalid since you have an object literal in the middle of another object and also you have totalIsSuccessful for id:1 as 2 where it seems they should be 3. With that said ...
you can get similar output via $unwind and then grouping with $sum and $cond:
db.collection.aggregate([
{ $match: { _id: "1" } },
{ $unwind: "$items" },
{ $group: {
_id: "_id",
age: { $first: "$age" },
totalIsSuccessful: { $sum: { $cond: [{ "$eq": [ "$items.isSuccessful", true ] }, 1, 0 ] } },
totalNotIsSuccessful: { $sum: { $cond: [{ "$ne": [ "$items.isSuccessful", true ] }, 1, 0 ] } },
totalSuccessfulNull: { $sum: { $cond: [{ "$eq": [ "$items.isSuccessful", null ] }, 1, 0 ] } },
totalNameNull: { $sum: { $cond: [ { "$eq": [ "$items.name", null ]}, 1, 0] } } }
}
])
The output would be this:
[
{
"_id": "_id",
"age": 30,
"totalIsSuccessful": 3,
"totalNameNull": 2,
"totalNotIsSuccessful": 1,
"totalSuccessfulNull": 1
}
]
You can see it working here