Upload dynamic CSV file via Gatling - scala

Question

I recently took some interest in learning some load testing tools and Gatling seemed a very good choice. The only drawback related to other tools is the lack of documentation/examples for the upload of files with dynamic values.
For example, to upload a static CSV file I can use:
val scn: ScenarioBuilder = scenario("My First Test")
.exec(http("Upload CSV")
.post("/csv-upload")
.formUpload("file", "file.csv")
.check(status.is(202))
)
But if I want to add a feeder to add values to that CSV I would like to have something like:
val scn: ScenarioBuilder = scenario("My First Test")
.feed(customFeeder)
.exec(http("Upload CSV")
.post("/csv-upload")
.formUpload("file", ElFileBody("file.csv"))
.check(status.is(202))
)
I already tried multiple methods to upload body parts and for example, if I do something of the sort:
val scn: ScenarioBuilder = scenario("My First Test")
.feed(customFeeder)
.exec(http("Upload CSV")
.post("/csv-upload")
.bodyPart(ElFileBodyPart("file", "file.csv"))
.check(status.is(202))
)
I get an error on the server-side:
MissingServletRequestPartException: Required request part 'file' is not present
I was able to proxy the request that Gatling does and the generated curl request is:
curl --location --request POST 'http://localhost:8080/api/v1/resource/csv' \
--header 'accept: application/json' \
--header 'content-length: 310' \
--header 'content-type: multipart/form-data; boundary=UhyANQVVCm0hahnV9JvGEA8tPLU1Kc2Z5Fj' \
--header 'host: localhost:8080' \
--header 'x-tenantid: t1' \
--data-raw '--UhyANQVVCm0hahnV9JvGEA8tPLU1Kc2Z5Fj
Content-Disposition: form-data; name="file"
Content-Type: multipart/form-data; charset=UTF-8
Name,Phone,Address
PersonName,123456,ThatStreet
--UhyANQVVCm0hahnV9JvGEA8tPLU1Kc2Z5Fj--
'
Which constructs the request correctly, but the error on the server side remains.
Is there any way that this can be achievable?

Answer 1

The only drawback related to other tools is the upload of files with dynamic values.
No idea where this comes from.
.formUpload("name", "path") is merely a handy shortcut for bodyPart(RawFileBodyPart("name", "path")).
Please read the official documentation regarding multipart support.