Group Subdocuments Array by key in MongoDB - mongodb

Is it possible to use MongoDB's aggregation framework to group channels using folder key and without joining documents?
[{key: 1, channels: {A: [], B: [], etc}}, {key: 2, channels: {A: [], B: [], etc}}]
I am trying to do using $unwind and then $group by folder name but it seems impossible.
Mongo Playground
Documents:
[
{
key: 1,
channels: [
{
"id": 1,
"name": "XXX",
"folder": "C"
},
{
"id": 2,
"name": "XXX",
"folder": "A"
},
{
"id": 3,
"name": "XXX",
"folder": "B"
},
{
"id": 4,
"name": "XXX",
"folder": "A"
},
{
"id": 5,
"name": "XXX",
"folder": "B"
},
{
"id": 6,
"name": "XXX",
"folder": "C"
}
]
},
{
key: 2,
channels: [
{
"id": 1,
"name": "XXX",
"folder": "D"
},
{
"id": 2,
"name": "XXX",
"folder": "B"
},
{
"id": 3,
"name": "XXX",
"folder": "A"
},
{
"id": 4,
"name": "XXX",
"folder": "C"
},
{
"id": 5,
"name": "XXX",
"folder": "A"
},
{
"id": 6,
"name": "XXX",
"folder": "D"
}
]
}
]
Expected Result:
[
{
key: 1,
channels: {
A: [{
"id": 2,
"name": "XXX"
},{
"id": 4,
"name": "XXX"
}],
B: [{
"id": 3,
"name": "XXX"
}, {
"id": 5,
"name": "XXX"
}],
C: [{
"id": 1,
"name": "XXX"
},{
"id": 6,
"name": "XXX"
}]
}
},
{
"key": 2,
"channels": ...
}
]
Thank you very much in advance.

$group by key and folder, construct channels array by providing required fields
$group by only key and construct the channels array in key-vlaue format
$arrayToObject convert above constructed channels to object
db.collection.aggregate([
{ $match: { key: { $in: [1, 2] } } },
{ $unwind: "$channels" },
{
$group: {
_id: {
id: "$key",
folder: "$channels.folder"
},
channels: {
$push: {
id: "$channels.id",
name: "$channels.name"
}
}
}
},
{
$group: {
_id: "$_id.id",
channels: {
$push: {
k: "$_id.folder",
v: "$channels"
}
}
}
},
{ $project: { channels: { $arrayToObject: "$channels" } } }
])
Playground

You just have to add one more $group stage followed by project stage which will alter the data as per requirement.
db.collection.aggregate([
{
$match: {
key: {
$in: [
1,
2
]
}
}
},
{
$unwind: "$channels"
},
{
$group: {
_id: {
key: "$key",
folder: "$channels.folder"
},
value: {
$push: "$channels",
},
"foldersRef": {
$push: "$channels.folder"
},
}
},
{
$group: {
_id: "$_id.key",
"channels": {
"$push": "$value"
},
},
},
{
"$project": {
"channels": {
"$map": {
"input": "$channels",
"as": "channel",
"in": {
"$arrayToObject": [
[
{
"v": {
"$map": {
"input": "$$channel",
"as": "subChannel",
"in": {
"id": "$$subChannel.id",
"name": "$$subChannel.name",
}
}
},
"k": {
"$arrayElemAt": [
"$$channel.folder",
0
]
},
}
]
],
},
}
},
},
},
])
Mongo Playground Sample Execution

What you have done is more appreciated. You might need two grop to easly preform the aggregations
$unwind to deconstruct the array
$group to group by key and foldername and second group to group by key only, but make the grp as key value pair which helps for $arrayToObject
$replaceRoot to make it to root with other fields _id ($mergeobjects)
$project for projection
Here is the code
db.collection.aggregate([
{ $unwind: "$channels" },
{
"$group": {
"_id": { key: "$key", fname: "$channels.folder" },
"channels": { "$push": "$channels" }
}
},
{
"$group": {
"_id": "$_id.key",
"grp": { "$push": { k: "$_id.fname", v: "$channels" } }
}
},
{ "$addFields": { "grp": { "$arrayToObject": "$grp" } } },
{
"$replaceRoot": {
"newRoot": { "$mergeObjects": [ "$grp", "$$ROOT" ] }
}
},
{
"$project": { grp: 0 }
}
])
Working Mongo playground

Related

MongoDB match filters with grouping and get total count

My sample data:
{
"_id": "random_id_1",
"priority": "P1",
"owners": ["user-1", "user-2"],
},
{
"_id": "random_id_2",
"priority": "P1",
"owners": ["user-1", "user-2"],
},
{
"_id": "random_id_3",
"priority": "P2",
"owners": ["user-1", "user-2"],
},
I want to run an aggregation pipeline on the data involving match filters and grouping, also I want to limit the number of groups returned as well as the number of items in each group.
Essentially, if limit=2, limit_per_group=1, group_by=owner, priority=P1, I want the following results:
[
{
"data": [
{
"group_key": "user-1",
"total_items_in_group": 2,
"limited_items": [
{
"_id": "random_id_1",
"priority": "P1",
"owners": ["user-1", "user-2"],
},
],
},
{
"group_key": "user-2",
"total_items_in_group": 2,
"limited_items": [
{
"_id": "random_id_1",
"priority": "P1",
"owners": ["user-1", "user-2"],
},
],
},
]
},
{
"metadata": {
"total_items_matched": 2,
"total_groups": 2
}
},
]
Need some help on how to write an aggregation pipeline to get the required result.
My current query is as follows:
{
"$match": {
"priority": "P1"
}
},
{
"$facet": {
"data": [
{
$addFields: {
"group_by_owners": "$owners"
}
},
{
$unwind: "$group_by_owners"
},
{
$group: {
"_id": "$group_by_owners",
"total_items_in_group": {
$sum: 1
},
"items": {
$push: "$$ROOT"
}
}
},
{
$sort: {
"total": -1
}
},
{
$unset: "items.group_by_owners"
},
{
$project: {
"_id": 1,
"total_items_in_group": 1,
"limited_items": {
$slice: [
"$items",
1
]
}
}
},
{
"$limit": 2
}
],
"metadata": [
{
$count: "total_items_matched"
}
]
}
}
Mongo playground link
I am unable to calculate the total number of groups.
add new stage of $addfields at the end of pipeline
db.collection.aggregate([
{
"$match": {
"priority": "P1"
}
},
{
"$facet": {
"data": [
{
$addFields: {
"group_by_owners": "$owners"
}
},
{
$unwind: "$group_by_owners"
},
{
$group: {
"_id": "$group_by_owners",
"total_items_in_group": {
$sum: 1
},
"items": {
$push: "$$ROOT"
}
}
},
{
$sort: {
"total": -1
}
},
{
$unset: "items.group_by_owners"
},
{
$project: {
"_id": 0,
"group_key": "$_id",
"total_items_in_group": 1,
"limited_items": {
$slice: [
"$items",
1
]
}
}
},
{
"$limit": 2
}
],
"metadata": [
{
$count: "total_items_matched",
}
]
}
},
{
"$addFields": {
"metadata.total_groups": {
"$size": "$data"
}
}
}
])
https://mongoplayground.net/p/y5a0jvr6fxI

Adding Group counters and Items counter in MongoDB?

I have this Json :
[
{
"key": "guitar",
"name": "john"
},
{
"key": "guitar",
"name": "paul"
},
{
"key": "guitar",
"name": "george"
},
{
"key": "drums",
"name": "ringo"
}
]
Let's group by key and add items to each group :
db.collection.aggregate([
{
$sort: {
name: -1
}
},
{
$group: {
_id: "$key",
"projects": {
"$push": "$$ROOT"
},
count: {
$sum: 1
}
}
},
{
$sort: {
"_id": 1
}
}
])
Result:
[
{
"_id": "drums",
"count": 1,
"projects": [
{
"_id": ObjectId("5a934e000102030405000003"),
"key": "drums",
"name": "ringo"
}
]
},
{
"_id": "guitar",
"count": 3,
"projects": [
{
"_id": ObjectId("5a934e000102030405000001"),
"key": "guitar",
"name": "paul"
},
{
"_id": ObjectId("5a934e000102030405000000"),
"key": "guitar",
"name": "john"
},
{
"_id": ObjectId("5a934e000102030405000002"),
"key": "guitar",
"name": "george"
}
]
}
]
Question:
How can I add counter such as this :
[
{
"_id": "drums",
"Counter":0, // <--------------------------------
"count": 1,
"projects": [
{
"_id": ObjectId("5a934e000102030405000003"),
"key": "drums",
"name": "ringo",
"InnerCounter":0 // <--------------------------------
}
]
},
{
"_id": "guitar",
"Counter":1, // <--------------------------------
"count": 3,
"projects": [
{
"_id": ObjectId("5a934e000102030405000001"),
"key": "guitar",
"name": "paul",
"InnerCounter":0 // <--------------------------------
},
{
"_id": ObjectId("5a934e000102030405000000"),
"key": "guitar",
"name": "john",
"InnerCounter":1 // <--------------------------------
},
{
"_id": ObjectId("5a934e000102030405000002"),
"key": "guitar",
"name": "george",
"InnerCounter":2 // <--------------------------------
}
]
}
]
Live Demo
I don't think is there any other option to do this, You can try using $unwind to create index field in array using includeArrayIndex property,
db.collection.aggregate([
{ $sort: { name: -1 } },
{
$group: {
_id: "$key",
projects: { $push: "$$ROOT" }
}
},
// $unwind "projects" array and store index in field "projects.InnerCounter"
{
$unwind: {
path: "$projects",
includeArrayIndex: "projects.InnerCounter"
}
},
// again group by _id and reconstruct "projects" array
{
$group: {
_id: "$_id",
projects: { $push: "$projects" },
count: { $sum: 1 }
}
},
// sort by "_id"
{ $sort: { "_id": 1 } },
// group by $$ROOT and construct root array
{
$group: {
_id: null,
root: { $push: "$$ROOT" }
}
},
// deconstruct root array and add field "Counter" ofr index counter
{
$unwind: {
path: "$root",
includeArrayIndex: "root.Counter"
}
},
// replace to root
{ $replaceRoot: { newRoot: "$root" } }
])
Playground
Another option for projects array without $unwind,
Playground

How to create nested array inside $group in MongoDB?

After some of the aggregation pipeline stages, my MongoDB Document has the following format:
{
"key": "A",
"status": "To Do",
"val": 4
},
{
"key": "A",
"status": "Done",
"val": 1
},
{
"key": "A",
"status": "To Do",
"val": 3
},
{
"key": "A",
"status": "Done",
"val": 2
},
{
"key": "B",
"status": "Done",
"val": 5
},
{
"key": "B",
"status": "Done",
"val": 6
}
Expected output:
Group by key
Group by status
Push val
{
"key": "A",
"status_val": [
{
"status": "To Do",
"val": [
3,
4
]
},
{
"status": "Done",
"val": [
1,
2
]
}
]
},
{
"key": "B",
"status_val": "Done",
"val": [
5,
6
]
}
Here is what I tried:
db.collection.aggregate([
{
$group: {
_id: {
key:"$key",
status:"$status"
},
v: {
$push: "$val"
}
}
},
{
$group: {
_id: "$_id.key",
status_val: {
$addToSet: {
status: "$_id.status",
val: "$_id.v"
}
}
}},
{
$project: { _id: 0,key:"$_id",status_val:1 }
}
]).pretty()
But I get the wrong output:
[
{
"key": "B",
"status_val": [
{
"status": "Done"
}
]
},
{
"key": "A",
"status_val": [
{
"status": "Done"
},
{
"status": "To Do"
}
]
}
]
How to get nested array inside $group?
You're correctly running $group twice but this line needs to be changed:
val: "$_id.v"
v is not a part of _id, your data after first $group looks like this:
{
"_id": { "key": "B, "status": "Done" },
"v": [ 5, 6 ]
}
try:
db.collection.aggregate([
{
$group: {
_id: { key: "$key", status: "$status" },
val: { $push: "$val" }
}
},
{
$group: {
_id: "$_id.key",
status_val: {
$push: {
status: "$_id.status",
val: "$val"
}
}
}
},
{
$project: {
_id: 0,
key: "$_id",
status_val: 1
}
}
])
Mongo Playground

MongoDb aggregation with arrays inside an array possible

I am struggling to find some examples of using the mongo aggregation framework to process documents which has an array of items where each item also has an array of other obejects (array containing an array)
In the example document below what I would really like is an example that sums the itemValue in the results array of all cases in the document and accross the collection where the result.decision was 'accepted'and group by the document locationCode
However, even an example that found all documents where the result.decision was 'accepted' to show or that summmed the itemValue for the same would help
Many thanks
{
"_id": "333212",
"data": {
"locationCode": "UK-555-5566",
"mode": "retail",
"caseHandler": "A N Other",
"cases": [{
"caseId": "CSE525666",
"items": [{
"id": "333212-CSE525666-1",
"type": "hardware",
"subType": "print cartridge",
"targetDate": "2020-06-15",
"itemDetail": {
"description": "acme print cartridge",
"quantity": 2,
"weight": "1.5"
},
"result": {
"decision": "rejected",
"decisionDate": "2019-02-02"
},
"isPriority": true
},
{
"id": "333212-CSE525666-2",
"type": "Stationery",
"subType": "other",
"targetDate": "2020-06-15",
"itemDetail": {
"description": "staples box",
"quantity": 3,
"weight": "1.66"
},
"result": {
"decision": "accepted",
"decisionDate": "2020-03-03",
"itemValue": "23.01"
},
"isPriority": true
}
]
},
{
"caseId": "CSE885655",
"items": [{
"id": "333212-CSE885655-1",
"type": "marine goods",
"subType": "fish food",
"targetDate": "2020-06-04",
"itemDetail": {
"description": "fish bait",
"quantity": 5,
"weight": "0.65"
},
"result": {
"decision": "accepted",
"decisionDate": "2020-03-02"
},
"isPriority": false
},
{
"id": "333212-CSE885655-4",
"type": "tobacco products",
"subType": "cigarettes",
"deadlineDate": "2020-06-15",
"itemDetail": {
"description": "rolling tobbaco",
"quantity": 42,
"weight": "2.25"
},
"result": {
"decision": "accepted",
"decisionDate": "2020-02-02",
"itemValue": "48.15"
},
"isPriority": true
}
]
}
]
},
"state": "open"
}
You're probably looking for $unwind. It takes an array within a document and creates a separate document for each array member.
{ foos: [1, 2] } -> { foos: 1 }, { foos: 2}
With that you can create a flat document structure and match & group as normal.
db.collection.aggregate([
{
$unwind: "$data.cases"
},
{
$unwind: "$data.cases.items"
},
{
$match: {
"data.cases.items.result.decision": "accepted"
}
},
{
$group: {
_id: "$data.locationCode",
value: {
$sum: {
$toDecimal: "$data.cases.items.result.itemValue"
}
}
}
},
{
$project: {
_id: 0,
locationCode: "$_id",
value: "$value"
}
}
])
https://mongoplayground.net/p/Xr2WfFyPZS3
Alternative solution...
We group by data.locationCode and sum all items with this condition:
cases[*].items[*].result.decision" == "accepted"
db.collection.aggregate([
{
$group: {
_id: "$data.locationCode",
itemValue: {
$sum: {
$reduce: {
input: "$data.cases",
initialValue: 0,
in: {
$sum: {
$concatArrays: [
[ "$$value" ],
{
$map: {
input: {
$filter: {
input: "$$this.items",
as: "f",
cond: {
$eq: [ "$$f.result.decision", "accepted" ]
}
}
},
as: "item",
in: {
$toDouble: {
$ifNull: [ "$$item.result.itemValue", 0 ]
}
}
}
}
]
}
}
}
}
}
}
}
])
MongoPlayground

MongoDB multiple counts, single document, arrays

I have been searching on stackoverflow and cannot find exactly what I am looking for and hope someone can help. I want to submit a single query, get multiple counts back, for a single document, based on array of that document.
My data:
db.myCollection.InsertOne({
"_id": "1",
"age": 30,
"items": [
{
"id": "1",
"isSuccessful": true,
"name": null
},{
"id": "2",
"isSuccessful": true,
"name": null
},{
"id": "3",
"isSuccessful": true,
"name": "Bob"
},{
"id": "4",
"isSuccessful": null,
"name": "Todd"
}
]
});
db.myCollection.InsertOne({
"_id": "2",
"age": 22,
"items": [
{
"id": "6",
"isSuccessful": true,
"name": "Jeff"
}
]
});
What I need back is the document and the counts associated to the items array for said document. In this example where the document _id = "1":
{
"_id": "1",
"age": 30,
{
"totalIsSuccessful" : 2,
"totalNotIsSuccessful": 1,
"totalSuccessfulNull": 1,
"totalNameNull": 2
}
}
I have found that I can get this in 4 queries using something like this below, but I would really like it to be one query.
db.test1.aggregate([
{ $match : { _id : "1" } },
{ "$project": {
"total": {
"$size": {
"$filter": {
"input": "$items",
"cond": { "$eq": [ "$$this.isSuccessful", true ] }
}
}
}
}}
])
Thanks in advance.
I am assuming your expected result is invalid since you have an object literal in the middle of another object and also you have totalIsSuccessful for id:1 as 2 where it seems they should be 3. With that said ...
you can get similar output via $unwind and then grouping with $sum and $cond:
db.collection.aggregate([
{ $match: { _id: "1" } },
{ $unwind: "$items" },
{ $group: {
_id: "_id",
age: { $first: "$age" },
totalIsSuccessful: { $sum: { $cond: [{ "$eq": [ "$items.isSuccessful", true ] }, 1, 0 ] } },
totalNotIsSuccessful: { $sum: { $cond: [{ "$ne": [ "$items.isSuccessful", true ] }, 1, 0 ] } },
totalSuccessfulNull: { $sum: { $cond: [{ "$eq": [ "$items.isSuccessful", null ] }, 1, 0 ] } },
totalNameNull: { $sum: { $cond: [ { "$eq": [ "$items.name", null ]}, 1, 0] } } }
}
])
The output would be this:
[
{
"_id": "_id",
"age": 30,
"totalIsSuccessful": 3,
"totalNameNull": 2,
"totalNotIsSuccessful": 1,
"totalSuccessfulNull": 1
}
]
You can see it working here