Query userId for having one condition and NOT having other - mongodb

Question

Can you please help me with this?
I have these documents:
{
userId: 123,
event: 'A',
properties: {
status: 'Sent'
}
}
{
userId: 123,
event: 'B',
properties: {
status: 'Opened'
}
}
{
userId: 123,
event: 'C',
properties: {
status: 'Clicked'
}
}
I need a query to match all userId == 'A', that also registered for event 'B', but has not done event 'C' with properties.status == "Clicked".
Here's what I did so far:
db.collection.aggregate([
{ $match: { "event": "A"} },
{
$lookup: {
from: "collection",
let: { "userId": "$userId" },
pipeline: [{
$match: {
$expr: { $eq: ["$userId", "$$userId"] }
}
}],
as: "events"
}
}
This gives me this unified output:
{
userId: 123,
event: "A",
properties: {
status: 'Sent'
},
events: [
{ event: 'A' /* and all the other fields from original document */ },
{ event: 'B' /* and all the other fields from original document */ },
{
event: 'C',
properties: {
status: 'Clicked'
}
},
]
I tried to do this next, but it didn't work:
{
$match: {
$expr: {
$not: {
$and: [
{ $eq: ["$events.event", "C"] },
{ $eq: ["$events.properties.status', 'Clicked'] }
]
}
}
}
}
My expectation is that this query does not brings me userId: 123 in this case, but it's on the results.
Can someone please help me with that?
Tks!

Answer 1

I ended up doing this by adding these steps after the lookup. Not sure if it's the best solution, but I couldn't achieve this in any other way I've tried.
{ $unwind: "$events"},
{
$project: {
"userId": 1, "events": "$events",
"exclude": {
$cond: { if: {
$and: [
{ $eq: ["$events.event", "C"] },
{ $eq: ['$events.properties.status', 'Clicked'] }
]
}, then: 1, else: 0 }
}
}
},
{
$group: {
_id: "$userId",
exclude: { $sum: "$exclude" }
}
},
{
$match: { "exclude": 0 }
}