I have to handle a message coming from application on form filling. if it comes have to close the alert window using (X)button.
problem is I'm not able to close it. directly close (.click()) works fine.
but on condition when i say if alert is present then only close it scenario is not working. Any help is appreciated
try {
var Alert1 = element(by.xpath("//h2[text()='Job Role']/parent::div/following-sibling::div//span"));
Alert1.isPresent().then(async function(res) {
if (res) {
Alert1.click();
}
})
} catch (err) {
console.log(err)
}
})
it('async test case', async () => {
var Alert1 = element(by.xpath("//h2[text()='Job Role']/parent::div/following-sibling::div//span"));
if (await Alert1.isPresent()) {
await Alert1.click();
}
})
simple, readable and robust if you avoid .then
Related
For some reason, the function .save() isn't saving my documents on MongoDB. All seem right and the first two registers work and update successfully, but my third register 'specialBanner' doesn't work.
When I console log service it doesn't show as part of the special object, although when I console special.specialBanner it is there.
Has anyone experienced something like this before?
Thanks for your help :)
const updateSpecial = async (req, res, next) => {
const { title, description, specialBanner } = req.body;
let special;
try {
special = await Special.findById(specialId);
} catch (err) {
const error = new HttpError(
"Something went wrong, could not update special.",
500
);
return next(error);
}
if (title) {
special.title = title;
}
if (description) {
special.description = description;
}
if (specialBanner) {
special.specialBanner = specialBanner;
}
try {
//Here if I check 'special I get all the right inputs, but the 'specialBanner'.
special = await special.save();
} catch (err) {
const error = new HttpError(
"Something went wrong, could not update special.",
500
);
return next(error);
}
res.status(200).json({ special: special.toObject({ getters: true }) });
};
I assume you are using mongoose and, Special is a collection.
Replace the line
special = await Special.findById(specialId)
with
special = await Special.findById(specialId).exec()
Hi I finished the project recently and noticed that in a lists collection creates duplicates the first time saving an item in MongoDb. The first item created is always a duplicate. Please see screenshot attached. Is there any particular reasonenter image description here why this is case?
somthing like this should work:
app.get('/:customListName', async (req, res) => {
try {
let foundList = await List.findOne({ name: req.params.customListName });
if (!foundList) {
const foundList = new List({
name: req.params.customListName,
item: defualtItems
});
await foundList.save();
res.redirect(`/${req.params.customListName}`);
} else {
res.render('list', {
listTitle: foundList.name,
newListItems: foundList.items
});
}
} catch (error) {
res.status(500).json({ error: error.message });
}
});
I recommend you to read more about async await when writing and saving to database, and about the usage of try-catch blocks when handling errors.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/try...catch
I am working in my Ionic 4 app and I want to stop the functions when the page will leave.
This is my tab4.page.ts:
async getUserDetail(){
this.dataexists = false;
this.userActiveChallanges = [];
let me=this;
const loading = await this.loadingController.create({
message: '',
// duration: 2200,
translucent: true,
spinner: 'crescent',
showBackdrop: false,
cssClass: 'my-loading-class'
});
await loading.present();
this.userActiveChallanges=[];
this.storage.get('USERPROFILE').then(userObj => {
// console.log('User Profile :',userObj);
me.userprofile = userObj;
me.sendFitDatafunction(userObj);
me.myapi.apiCall('userActiveChallenges/'+userObj.id,'GET','').subscribe((data) => {
// console.log(data);
me.response=data;
loading.dismiss();
if(me.response.status === 'success'){
if(me.response && me.response.data && me.response.data.length>0){
this.userActiveChallanges=me.response.data;
this.flip(this.userActiveChallanges[0].challenge_id);
}
this.dataexists = true;
} else{
this.userActiveChallanges = '';
this.dataexists = true;
}
}, error => { loading.dismiss(); console.log(error); });
});
}
ionViewWillLeave() {
}
I want to stop this function when the page will leave because when I am not getting any response nor any error from the api the loader keeps running and when I move to the other page, it is showing there.
So, I want to stop the function when the page will leave.
Any help is much appreciated.
instead of local const loading, declare it as a property of your ts class (tab4).
now change your code and assign loader to it:
replace: const loading
with:
this.loading
Now inside ionViewWillLeave call:
ionViewWillLeave() {
if (this.loading) { this.loading.dismiss() }
}
Well, I don't know the function to stop your function, but to make something when you leave a page, you make it in IonViewDidLeave()
I have a mobile app where the user needs to re-login after some time for security reasons. The thing is that the content that was open in the background needs to stay there, and open after the login. So, even if it was a modal.
What is the best way to do this.
Pushing the login view when a modal is open doesn't help, since the view is put behind the modal.
Thanks in advance!
on the current page
public openLogin() {
let loginModal = this.modalController.create(LoginPage, { modal: true });
loginModal.present();
loginModal.onDidDismiss(data => {
if (data) {
this.profileData = data;
} else {
}
});
};
on loginPage
this.userService.login(username, password)
.subscribe(
data => {
console.log(data);
if (data.success) {
var user = data.result;
this.userService.setSession(user);
if (this.itsModal) {
this.closeModal(data)
}
else {
this.gotoHome();
}
} else {
// error handling
}
},
error => {
console.log(error);
}
);
public closeModal(data: any = null) {
this.viewController.dismiss(data);
}
Ok, I've got the following in one of my controllers:
User.find({email: 'email#example.com'}).then(function (user) {
user[0].field = 'new_value';
user[0].field_2 = 'new_value';
console.log(user[0], 'before saving');
user[0].save();
console.log(user[0], 'after saving');
});
If I console user[0] at this stage I can see the updated fields. However the changes were not saved to the db. If I do the following:
User.find({email: 'email#example.com'}).then(function (user) {
user[0].field = 'new_value';
user[0].field_2 = 'new_value';
user[0].save();
User.find(user[0].id).then(function (updateduser) {
console.log(updateduser[0])
});
});
The updateduser does not have the updated fields... Why is that? How can should I proceed in this case?
Actually
user[0].save();
will return a promise like you have done for User.find().then();
user[0].save() is an asynchronous call so the next call to find the user will run even though the user[0] is not updated in the database.
so place the second find command inside the then of save() function and you will get the updated user.
user[0].save().then(function(err){
User.find(user[0].id).then(function (updateduser) {
console.log(updateduser[0])
});
}))
Why you not use updated() method?
User.find({ email: 'email#example.com' })
.then(function(user) {
if (!user) return res.notFound();
User.update({ eamil: 'eamil#example.com' }, {
field: 'new_value',
field_2: 'new_value'
})
.then(function(updated_user) {
console.log(updated_user);
return res.ok();
})
.catch(function(err) {
sails.log.error(err);
return res.serverError();
});
})
.catch(function(err) {
sails.log.error(err);
return res.serverError();
});
First of all, you want to update only one user data because you are using user[0](I think).
So it is easy to use findOne().
Simple code
User
.findOne({email: 'email#example.com'})
.exec(function(err,user){
if(err || !user) {
//handle here
}
else {
user.key1 = 'new_value';
user.key2 = 'new_value';
user.save(function(err){
if(err){
//handle error
}
console.log('updatedUser',user)
})
}
})
Thank you.