Write a script command to find the total cost incurred by Company1 - sh

Given the contents of the file as follow:
Company1 400
Company2 500
Company3 600
Company2 150
Company1 350
Write a script command to find the total cost incurred by Company1.

awk is well suited to this:
awk '$1 == "Company1"{sum += $2} END {print sum}' money.txt
awk processes the input file(s) one line at a time, splitting the fields on whitespace. In this script, the second column of all lines in which the first column exactly matches the string Company1 are added to the variable sum. At the end, the sum is printed.
It is easy to parameterize by doing something like:
#!/bin/sh
company=${1-Company1}
awk 'tolower($1) == tolower(c) {sum += $2}
END {print sum}' c="$company" money.txt

#!/bin/bash
sum=0
check="Company1"
while read -r checkin amount;
do
if [[ "$checkin" == "$check" ]];
then
(( sum+=amount ))
fi
done < <(tr -d '\r' < money.txt)
echo "${sum}"
Thanks to this

Related

Validate if a text file contains identical records at specific line's number?

my command looks like:
for i in *.fasta ; do
parallel -j 10 python script.py $i > $i.out
done
I want to add a test condition to this loop where it only executes the parallel python script if there are no identical lines in the .fasta file
an example .fasta file below:
>ref2
GGTTAGGGCCGCCTGTTGGTGGGCGGGAATCAAGCAGCATTTTGGAATTCCCTACAATCC
CCAAAGTCAAGGAGTAGTAGAATCTATGCGGAAAGAATTAAAGAAAATTATAGGACAGGT
AAGAGATCAGGCTGAACATCTTAAGACAGCAGTACAAATGGC
>mut_1_2964_0
AAAAAAAAACGCCTGTTGGTGGGCGGGAATCAAGCAGGTATTTGGAATTCCCTACAATCC
CCAAAGTCAAGGAGTAGTAGAATCTATGTTGAAAGAATTAAAGAAAATTATAGGACAGGT
AAGAGATCAGGCTGAACATCTTAAGACAGCAGTACAAATGGC
an example .fasta file that I would like excluded because lines 2 and 4 are identical.
>ref2
GGTTAGGGCCGCCTGTTGGTGGGCGGGAATCAAGCAGCATTTTGGAATTCCCTACAATCC
CCAAAGTCAAGGAGTAGTAGAATCTATGCGGAAAGAATTAAAGAAAATTATAGGACAGGT
AAGAGATCAGGCTGAACATCTTAAGACAGCAGTACAAATGGC
>mut_1_2964_0
GGTTAGGGCCGCCTGTTGGTGGGCGGGAATCAAGCAGCATTTTGGAATTCCCTACAATCC
CCAAAGTCAAGGAGTAGTAGAATCTATGCGGAAAGAATTAAAGAAAATTATAGGACAGGT
AAGAGATCAGGCTGAACATCTTAAGACAGCAGTACAAATGGC
The input files always have 4 lines exactly, and lines 2 and 4 are always the lines to be compared.
I've been using sort file.fasta | uniq -c to see if there are identical lines, but I don't know how to incorporate this into my bash loop.
EDIT:
command:
for i in read_00.fasta ; do lines=$(awk 'NR % 4 == 2' $i | sort | uniq -c | awk '$1 > 1'); if [ -z "$lines" ]; then echo $i >> not.identical.txt; fi;
read_00.fasta:
>ref
GGTGCCCACACTAATGATGTAAAACAATTAACAGAGGCAGTGCAAAAAATAACCACAGAAAGCATAGTAATATGGGGAAAGACTCCTAAATTTAAACTGCCCATACAAAAGGAAACATGGGAAACATGGTGGACAGAGTATTGGCAAGCCACCTGGATTCCTGAGTGGGAGTTTGTTAATACCCCTCCCTTAGTGAAATTATGGTACCAGTTAGA
>mut_1_2964_0
GGTGCCCACACTAATGATGTAAAACAATTAACAGAGGCAGTGCAAAAAATAACCACAGAAAGCATAGTAATATGGGGAAAGACTCCTAAATTTAAACTGCCCATACAAAAGGAAACATGGGAAACATGGTGGACAGAGTATTGGCAAGCCACCTGGATTCCTGAGTGGGAGTTTGTTAATACCCCTCCCTTAGTGAAATTATGGTACCAGTTAGA
Verify those specifc lines content with below awk and exit failure when lines were identical or exit success otherwise (instead of exit, you can do whatever you want to print/do for you);
awk 'NR==2{ prev=$0 } NR==4{ if(prev==$0) exit 1; else exit }' "./$yourFile"
or to output fileName instead when 2nd and 4th lines were differ:
awk 'NR==2{ prev=$0 } NR==4{ if(prev!=$0) print FILENAME; exit }' ./*.fasta
Using the exit-status of the first command then you can easily execute your next second command, like:
for file in ./*.fasta; do
awk 'NR==2{ prev=$0 } NR==4{ if(prev==$0) exit 1; else exit }' "$file" &&
{ parallel -j 10 python script.py "$file" > "$file.out"; }
done

while loop provide just one block of result using awk

I am processing my text file using awk. I have written the code below:
#!/bin/bash
l=1
while [ $l -lt 5 ]
do
echo $l
awk -v L=$l '/^BS[0-5]|^FG[2-7]/ && length<10 {i++}i==L {print}'
l=$(expr $l + 1)
done <input.txt
But, once i run the code I just get first awk output.
Would you please let me know how can I fix this code?
The while loop is taking its input from the file input.txt. awk is inheriting its input from the while loop, and it reads all of the input on the first iteration of the loop. In the 2nd iteration, awk gets no data. If you want to read from that file on each iteration, pass input.txt as an argument to awk.
Better yet, skip the while loop and do the whole thing in awk:
awk '/^BS[0-5]|^FG[2-7]/ && length<10 && i++ < 5' input.txt
You do not read the lines of our file. Do:
while read line && [ $l -lt 5 ]
do
...

How to print some free text in addition to SED extract

Well-known SED command to extract a first line and print to another file
sed -n '1 p' /p/raw.txt | cat >> /p/001.txt ;
gives an output in /p/001.txt like
John Doe
But how to modify this command above to add some free text and have, for example, the output like
Name: John Doe
Thanks for any hint to try.
You can do that in a single command (and no sub-shells):
sed 's/^/Name: /;q' /p/raw.txt >> /p/001.txt
This prefixes "Name: " in front of the first line, prints it, then quits so you don't process additional lines. Add a line number before the q to print all lines up to (and including) that number. The output is appended to /p/001.txt just like your original code.
If you want a range of lines:
sed -n '3,9{s/^/Name: /;p}9q' /p/raw.txt >> /p/001.txt
This reads from lines 3-9, performs the substitution, prints, then quits after line 9.
If you want specific lines, I recommend awk:
awk 'NR==3 || NR==9 { print "Name: " $0 } NR>=9 { exit }' /p/raw.txt >> /p/001.txt
This has two clauses. One says the number of record (line number) is either 3 or 9, in which case we print the prefix and the line. The other tells us to stop reading the file after the 9th record.
Here are two more commands to show how awk can act on just the first line(s) or a given range:
awk '{ print "Name: " $0 } NR >= 1 { exit }' /p/raw.txt >> /p/001.txt
awk '3 <= NR { print "Name: " $0 } NR >= 9 { exit }' /p/raw.txt >> /p/001.txt
It appears you're continuously building one file from the other. Consider:
tail -Fn0 /p/raw.txt |sed 's/^/Name: /' >> /p/001.txt
This will run continuously, adding only new entries (added after the command is run) to /p/001.txt
Perhaps you have lots of duplicates to resolve?
awk 'NR != FNR { $0 = "Name: " $0 } !s[$0]++' \
/p/001.txt /p/raw.txt > /tmp/001.txt && mv /tmp/001.txt /p/001.txt
This folds together the previously saved names with any new names, printing names only once (!s[$0]++ is true when s[$0] is zero (its default state), but after the evaluation, it increments to one, making it false on the second occurrence. When a bare clause has no action, the line is printed.) Because we're reading the output file, we need a temporary output. Upon its successful completion, we then move it atop the target output file.
printf "Name : %s\n" "$(sed -n '1p;q' /p/raw.txt)" >/p/001.txt
should do it. If sed is not a requirement do
echo -e "Name : $(sed -n '1p;q' /p/raw.txt)" >/p/001.txt
Note
The q option with the sed quits it without processing any more commands or input.
The -e option tells echo to interpret escape sequences. This is a peculiarity of bash shell.

Make some replacements on a bunch of files depending the number of columns per line

I'm having a problem dealing with some files. I need to perform a column count for every line in a file and depending the number of columns i need to add severals ',' in in the end of each line. All lines should have 36 columns separated by ','
This line solves my problem, but how do I run it in a folder with several files in a automated way?
awk ' BEGIN { FS = "," } ;
{if (NF == 32) { print $0",,,," } else if (NF==31) { print $0",,,,," }
}' <SOURCE_FILE> > <DESTINATION_FILE>
Thank you for all your support
R&P
The answer depends on your OS, which you haven't told us. On UNIX and assuming you want to modify each original file, it'd be:
for file in *
do
awk '...' "$file" > tmp$$ && mv tmp$$ "$file"
done
Also, in general to get all records in a file to have the same number of fields you can do this without needing to specify what that number of fields is (though you can if appropriate):
$ cat tst.awk
BEGIN { FS=OFS=","; ARGV[ARGC++] = ARGV[ARGC-1] }
NR==FNR { nf = (NF > nf ? NF : nf); next }
{
tail = sprintf("%*s",nf-NF,"")
gsub(/ /,OFS,tail)
print $0 tail
}
$
$ cat file
a,b,c
a,b
a,b,c,d,e
$
$ awk -f tst.awk file
a,b,c,,
a,b,,,
a,b,c,d,e
$
$ awk -v nf=10 -f tst.awk file
a,b,c,,,,,,,
a,b,,,,,,,,
a,b,c,d,e,,,,,
It's a short one-liner with Perl:
perl -i.bak -F, -alpe '$_ .= "," x (36-#F)' *
if this is only a single folder without subfolders, use:
for oldfile in /path/to/files/*
do
newfile="${oldfile}.new"
awk '...' "${oldfile}" > "${newfile}"
done
if you also want to include subdirectories recursively, it's probably easiest to put the awk+redirection into a small shell-script, like this:
#!/bin/bash
oldfile=$1
newfile="${oldfile}.new"
awk '...' "${oldfile}" > "${newfile}"
and then run this script (let's calls it runawk.sh) via find:
find /path/to/files/ -type f -not -name "*.new" -exec runawk.sh \{\} \;

How can I extract a predetermined range of lines from a text file on Unix?

I have a ~23000 line SQL dump containing several databases worth of data. I need to extract a certain section of this file (i.e. the data for a single database) and place it in a new file. I know both the start and end line numbers of the data that I want.
Does anyone know a Unix command (or series of commands) to extract all lines from a file between say line 16224 and 16482 and then redirect them into a new file?
sed -n '16224,16482p;16483q' filename > newfile
From the sed manual:
p -
Print out the pattern space (to the standard output). This command is usually only used in conjunction with the -n command-line option.
n -
If auto-print is not disabled, print the pattern space, then, regardless, replace the pattern space with the next line of input. If
there is no more input then sed exits without processing any more
commands.
q -
Exit sed without processing any more commands or input.
Note that the current pattern space is printed if auto-print is not disabled with the -n option.
and
Addresses in a sed script can be in any of the following forms:
number
Specifying a line number will match only that line in the input.
An address range can be specified by specifying two addresses
separated by a comma (,). An address range matches lines starting from
where the first address matches, and continues until the second
address matches (inclusively).
sed -n '16224,16482 p' orig-data-file > new-file
Where 16224,16482 are the start line number and end line number, inclusive. This is 1-indexed. -n suppresses echoing the input as output, which you clearly don't want; the numbers indicate the range of lines to make the following command operate on; the command p prints out the relevant lines.
Quite simple using head/tail:
head -16482 in.sql | tail -258 > out.sql
using sed:
sed -n '16224,16482p' in.sql > out.sql
using awk:
awk 'NR>=16224&&NR<=16482' in.sql > out.sql
You could use 'vi' and then the following command:
:16224,16482w!/tmp/some-file
Alternatively:
cat file | head -n 16482 | tail -n 258
EDIT:- Just to add explanation, you use head -n 16482 to display first 16482 lines then use tail -n 258 to get last 258 lines out of the first output.
There is another approach with awk:
awk 'NR==16224, NR==16482' file
If the file is huge, it can be good to exit after reading the last desired line. This way, it won't read the following lines unnecessarily:
awk 'NR==16224, NR==16482-1; NR==16482 {print; exit}' file
awk 'NR==16224, NR==16482; NR==16482 {exit}' file
perl -ne 'print if 16224..16482' file.txt > new_file.txt
People trying to wrap their heads around computing an interval for the head | tail combo are overthinking it.
Here's how you get the "16224 -- 16482" range without computing anything:
cat file | head -n +16482 | tail -n +16224
Explanation:
The + instructs the head/tail command to "go up to / start from" (respectively) the specified line number as counted from the beginning of the file.
Similarly, a - instructs them to "go up to / start from" (respectively) the specified line number as counted from the end of the file
The solution shown above simply uses head first, to 'keep everything up to the top number', and then tail second, to 'keep everything from the bottom number upwards', thus defining our range of interest (with no need to compute an interval).
Standing on the shoulders of boxxar, I like this:
sed -n '<first line>,$p;<last line>q' input
e.g.
sed -n '16224,$p;16482q' input
The $ means "last line", so the first command makes sed print all lines starting with line 16224 and the second command makes sed quit after printing line 16428. (Adding 1 for the q-range in boxxar's solution does not seem to be necessary.)
I like this variant because I don't need to specify the ending line number twice. And I measured that using $ does not have detrimental effects on performance.
# print section of file based on line numbers
sed -n '16224 ,16482p' # method 1
sed '16224,16482!d' # method 2
cat dump.txt | head -16224 | tail -258
should do the trick. The downside of this approach is that you need to do the arithmetic to determine the argument for tail and to account for whether you want the 'between' to include the ending line or not.
sed -n '16224,16482p' < dump.sql
Quick and dirty:
head -16428 < file.in | tail -259 > file.out
Probably not the best way to do it but it should work.
BTW: 259 = 16482-16224+1.
I wrote a Haskell program called splitter that does exactly this: have a read through my release blog post.
You can use the program as follows:
$ cat somefile | splitter 16224-16482
And that is all that there is to it. You will need Haskell to install it. Just:
$ cabal install splitter
And you are done. I hope that you find this program useful.
Even we can do this to check at command line:
cat filename|sed 'n1,n2!d' > abc.txt
For Example:
cat foo.pl|sed '100,200!d' > abc.txt
Using ruby:
ruby -ne 'puts "#{$.}: #{$_}" if $. >= 32613500 && $. <= 32614500' < GND.rdf > GND.extract.rdf
I wanted to do the same thing from a script using a variable and achieved it by putting quotes around the $variable to separate the variable name from the p:
sed -n "$first","$count"p imagelist.txt >"$imageblock"
I wanted to split a list into separate folders and found the initial question and answer a useful step. (split command not an option on the old os I have to port code to).
Just benchmarking 3 solutions given above, that works to me:
awk
sed
"head+tail"
Credits on the 3 solutions goes to:
#boxxar
#avandeursen
#wds
#manveru
#sibaz
#SOFe
#fedorqui 'SO stop harming'
#Robin A. Meade
I'm using a huge file I find in my server:
# wc fo2debug.1.log
10421186 19448208 38795491134 fo2debug.1.log
38 Gb in 10.4 million lines.
And yes, I have a logrotate problem. : ))
Make your bets!
Getting 256 lines from the beginning of the file.
# time sed -n '1001,1256p;1256q' fo2debug.1.log | wc -l
256
real 0m0,003s
user 0m0,000s
sys 0m0,004s
# time head -1256 fo2debug.1.log | tail -n +1001 | wc -l
256
real 0m0,003s
user 0m0,006s
sys 0m0,000s
# time awk 'NR==1001, NR==1256; NR==1256 {exit}' fo2debug.1.log | wc -l
256
real 0m0,002s
user 0m0,004s
sys 0m0,000s
Awk won. Technical tie in second place between sed and "head+tail".
Getting 256 lines at the end of the first third of the file.
# time sed -n '3473001,3473256p;3473256q' fo2debug.1.log | wc -l
256
real 0m0,265s
user 0m0,242s
sys 0m0,024s
# time head -3473256 fo2debug.1.log | tail -n +3473001 | wc -l
256
real 0m0,308s
user 0m0,313s
sys 0m0,145s
# time awk 'NR==3473001, NR==3473256; NR==3473256 {exit}' fo2debug.1.log | wc -l
256
real 0m0,393s
user 0m0,326s
sys 0m0,068s
Sed won. Followed by "head+tail" and, finally, awk.
Getting 256 lines at the end of the second third of the file.
# time sed -n '6947001,6947256p;6947256q' fo2debug.1.log | wc -l
A256
real 0m0,525s
user 0m0,462s
sys 0m0,064s
# time head -6947256 fo2debug.1.log | tail -n +6947001 | wc -l
256
real 0m0,615s
user 0m0,488s
sys 0m0,423s
# time awk 'NR==6947001, NR==6947256; NR==6947256 {exit}' fo2debug.1.log | wc -l
256
real 0m0,779s
user 0m0,650s
sys 0m0,130s
Same results.
Sed won. Followed by "head+tail" and, finally, awk.
Getting 256 lines near the end of the file.
# time sed -n '10420001,10420256p;10420256q' fo2debug.1.log | wc -l
256
real 1m50,017s
user 0m12,735s
sys 0m22,926s
# time head -10420256 fo2debug.1.log | tail -n +10420001 | wc -l
256
real 1m48,269s
user 0m42,404s
sys 0m51,015s
# time awk 'NR==10420001, NR==10420256; NR==10420256 {exit}' fo2debug.1.log | wc -l
256
real 1m49,106s
user 0m12,322s
sys 0m18,576s
And suddenly, a twist!
"Head+tail" won. Followed by awk and, finally, sed.
(some hours later...)
Sorry guys!
My analysis above ends up being an example of a basic flaw in doing an analysis.
The flaw is not knowing in depth the resources used for the analysis.
In this case, I used a log file to analyze the performance of a search for a certain number of lines within it.
Using 3 different techniques, searches were made at different points in the file, comparing the performance of the techniques at each point and checking whether the results varied depending on the point in the file where the search was made.
My mistake was to assume that there was a certain homogeneity of content in the log file.
The reality is that long lines appear more frequently at the end of the file.
Thus, the apparent conclusion that longer searches (closer to the end of the file) are better with a given technique, may be biased. In fact, this technique may be better when dealing with longer lines. What remains to be confirmed.
I was about to post the head/tail trick, but actually I'd probably just fire up emacs. ;-)
esc-x goto-line ret 16224
mark (ctrl-space)
esc-x goto-line ret 16482
esc-w
open the new output file, ctl-y
save
Let's me see what's happening.
I would use:
awk 'FNR >= 16224 && FNR <= 16482' my_file > extracted.txt
FNR contains the record (line) number of the line being read from the file.
Using ed:
ed -s infile <<<'16224,16482p'
-s suppresses diagnostic output; the actual commands are in a here-string. Specifically, 16224,16482p runs the p (print) command on the desired line address range.
I wrote a small bash script that you can run from your command line, so long as you update your PATH to include its directory (or you can place it in a directory that is already contained in the PATH).
Usage: $ pinch filename start-line end-line
#!/bin/bash
# Display line number ranges of a file to the terminal.
# Usage: $ pinch filename start-line end-line
# By Evan J. Coon
FILENAME=$1
START=$2
END=$3
ERROR="[PINCH ERROR]"
# Check that the number of arguments is 3
if [ $# -lt 3 ]; then
echo "$ERROR Need three arguments: Filename Start-line End-line"
exit 1
fi
# Check that the file exists.
if [ ! -f "$FILENAME" ]; then
echo -e "$ERROR File does not exist. \n\t$FILENAME"
exit 1
fi
# Check that start-line is not greater than end-line
if [ "$START" -gt "$END" ]; then
echo -e "$ERROR Start line is greater than End line."
exit 1
fi
# Check that start-line is positive.
if [ "$START" -lt 0 ]; then
echo -e "$ERROR Start line is less than 0."
exit 1
fi
# Check that end-line is positive.
if [ "$END" -lt 0 ]; then
echo -e "$ERROR End line is less than 0."
exit 1
fi
NUMOFLINES=$(wc -l < "$FILENAME")
# Check that end-line is not greater than the number of lines in the file.
if [ "$END" -gt "$NUMOFLINES" ]; then
echo -e "$ERROR End line is greater than number of lines in file."
exit 1
fi
# The distance from the end of the file to end-line
ENDDIFF=$(( NUMOFLINES - END ))
# For larger files, this will run more quickly. If the distance from the
# end of the file to the end-line is less than the distance from the
# start of the file to the start-line, then start pinching from the
# bottom as opposed to the top.
if [ "$START" -lt "$ENDDIFF" ]; then
< "$FILENAME" head -n $END | tail -n +$START
else
< "$FILENAME" tail -n +$START | head -n $(( END-START+1 ))
fi
# Success
exit 0
This might work for you (GNU sed):
sed -ne '16224,16482w newfile' -e '16482q' file
or taking advantage of bash:
sed -n $'16224,16482w newfile\n16482q' file
Since we are talking about extracting lines of text from a text file, I will give an special case where you want to extract all lines that match a certain pattern.
myfile content:
=====================
line1 not needed
line2 also discarded
[Data]
first data line
second data line
=====================
sed -n '/Data/,$p' myfile
Will print the [Data] line and the remaining. If you want the text from line1 to the pattern, you type: sed -n '1,/Data/p' myfile. Furthermore, if you know two pattern (better be unique in your text), both the beginning and end line of the range can be specified with matches.
sed -n '/BEGIN_MARK/,/END_MARK/p' myfile
I've compiled some of the highest rated solutions for sed, perl, head+tail, plus my own code for awk, and focusing on performance via the pipe, while using LC_ALL=C to ensure all candidates at their fastest possible, allocating 2-second sleep gap in between.
The gaps are somewhat noticeable :
abs time awk/app speed ratio
----------------------------------
0.0672 sec : 1.00x mawk-2
0.0839 sec : 1.25x gnu-sed
0.1289 sec : 1.92x perl
0.2151 sec : 3.20x gnu-head+tail
Haven't had chance to test python or BSD variants of those utilities.
(fg && fg && fg && fg) 2>/dev/null;
echo;
( time ( pvE0 < "${m3t}"
| LC_ALL=C mawk2 '
BEGIN {
_=10420001-(\
__=10420256)^(FS="^$")
} _<NR {
print
if(__==NR) { exit }
}' ) | pvE9) | tee >(xxh128sum >&2) | LC_ALL=C gwc -lcm | lgp3 ;
sleep 2;
(fg && fg && fg && fg) 2>/dev/null
echo;
( time ( pvE0 < "${m3t}"
| LC_ALL=C gsed -n '10420001,10420256p;10420256q'
) | pvE9 ) | tee >(xxh128sum >&2) | LC_ALL=C gwc -lcm | lgp3 ;
sleep 2; (fg && fg && fg && fg) 2>/dev/null
echo
( time ( pvE0 < "${m3t}"
| LC_ALL=C perl -ne 'print if 10420001..10420256'
) | pvE9 ) | tee >(xxh128sum >&2) | LC_ALL=C gwc -lcm | lgp3 ;
sleep 2; (fg && fg && fg && fg) 2>/dev/null
echo
( time ( pvE0 < "${m3t}"
| LC_ALL=C ghead -n +10420256
| LC_ALL=C gtail -n +10420001
) | pvE9 ) | tee >(xxh128sum >&2) | LC_ALL=C gwc -lcm | lgp3 ;
in0: 1.51GiB 0:00:00 [2.31GiB/s] [2.31GiB/s] [============> ] 81%
out9: 42.5KiB 0:00:00 [64.9KiB/s] [64.9KiB/s] [ <=> ]
( pvE 0.1 in0 < "${m3t}" | LC_ALL=C mawk2 ; )
0.43s user 0.36s system 117% cpu 0.672 total
256 43487 43487
54313365c2e66a48dc1dc33595716cc8 stdin
out9: 42.5KiB 0:00:00 [51.7KiB/s] [51.7KiB/s] [ <=> ]
in0: 1.51GiB 0:00:00 [1.84GiB/s] [1.84GiB/s] [==========> ] 81%
( pvE 0.1 in0 < "${m3t}" |LC_ALL=C gsed -n '10420001,10420256p;10420256q'; )
0.68s user 0.34s system 121% cpu 0.839 total
256 43487 43487
54313365c2e66a48dc1dc33595716cc8 stdin
in0: 1.85GiB 0:00:01 [1.46GiB/s] [1.46GiB/s] [=============>] 100%
out9: 42.5KiB 0:00:01 [33.5KiB/s] [33.5KiB/s] [ <=> ]
( pvE 0.1 in0 < "${m3t}" | LC_ALL=C perl -ne 'print if 10420001..10420256'; )
1.10s user 0.44s system 119% cpu 1.289 total
256 43487 43487
54313365c2e66a48dc1dc33595716cc8 stdin
in0: 1.51GiB 0:00:02 [ 728MiB/s] [ 728MiB/s] [=============> ] 81%
out9: 42.5KiB 0:00:02 [19.9KiB/s] [19.9KiB/s] [ <=> ]
( pvE 0.1 in0 < "${m3t}"
| LC_ALL=C ghead -n +10420256
| LC_ALL=C gtail -n ; )
1.98s user 1.40s system 157% cpu 2.151 total
256 43487 43487
54313365c2e66a48dc1dc33595716cc8 stdin
The -n in the accept answers work. Here's another way in case you're inclined.
cat $filename | sed "${linenum}p;d";
This does the following:
pipe in the contents of a file (or feed in the text however you want).
sed selects the given line, prints it
d is required to delete lines, otherwise sed will assume all lines will eventually be printed. i.e., without the d, you will get all lines printed by the selected line printed twice because you have the ${linenum}p part asking for it to be printed. I'm pretty sure the -n is basically doing the same thing as the d here.
I was looking for an answer to this but I had to end up writing my own code which worked. None of the answers above were satisfactory.
Consider you have very large file and have certain line numbers that you want to print out but the numbers are not in order. You can do the following:
My relatively large file
for letter in {a..k} ; do echo $letter; done | cat -n > myfile.txt
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i
10 j
11 k
Specific line numbers I want:
shuf -i 1-11 -n 4 > line_numbers_I_want.txt
10
11
4
9
To print these line numbers, do the following.
awk '{system("head myfile.txt -n " $0 " | tail -n 1")}' line_numbers_I_want.txt
What the above does is to head the n line then take the last line using tail
If you want your line numbers in order, sort ( is -n numeric sort) first then get the lines.
cat line_numbers_I_want.txt | sort -n | awk '{system("head myfile.txt -n " $0 " | tail -n 1")}'
4 d
9 i
10 j
11 k
Maybe, you would be so kind to give this humble script a chance ;-)
#!/usr/bin/bash
# Usage:
# body n m|-m
from=$1
to=$2
if [ $to -gt 0 ]; then
# count $from the begin of the file $to selected line
awk "NR >= $from && NR <= $to {print}"
else
# count $from the begin of the file skipping tailing $to lines
awk '
BEGIN {lines=0; from='$from'; to='$to'}
{++lines}
NR >= $from {line[lines]=$0}
END {for (i = from; i < lines + to + 1; i++) {
print line[i]
}
}'
fi
Outputs:
$ seq 20 | ./body.sh 5 15
5
6
7
8
9
10
11
12
13
14
15
$ seq 20 | ./body.sh 5 -5
5
6
7
8
9
10
11
12
13
14
15
You could use sed command in your case and is pretty fast.
As mentioned lets assume the range is: between 16224 and 16482 lines
#get the lines from 16224 to 16482 and prints the values into filename.txt file
sed -n '16224 ,16482p' file.txt > filename.txt
#Additional Info to showcase other possible scenarios:
#get the 16224 th line and writes the value to filename.txt
sed -n '16224p' file.txt > filename.txt
#get the 16224 and 16300 line values only and write to filename.txt.
sed -n '16224p;16300p;' file.txt > filename.txt