I am trying to figure out why I am unable to return a longitude field by order descending.
When I use the following leaves some records out of order? It isnt picking up the max value.
select cast(LONGITUDE as decimal(12,8)) from long
order by LONGITUDE desc
Output:
enter image description here
Thanks
Not sure why, but I'd try
Order By 1 desc
So ordered them by the casted value not the uncasted one.
Related
Maybe I'm overlooking something, but none of the answers I found solve my problem. I'm trying to get the sum and average from a column, but everything I see is getting sum and average from a row.
Here is the query I'm using:
SELECT product_name,unit_cost,units,total,SUM(total),AVG(total)
FROM products
GROUP BY product_name,unit_cost,total
And this is what I get:
It returns the exact same amounts. What I need is to add all values in the unit_cost column and return the SUM and AVG of all its values. What am I missing? What did I not understand? Thank you for taking the time to answer!
AVG and SUM as window functions and no grouping will do the job.
select product_name,unit_cost,units,total,
SUM(total) over all_rows as sum_of_all_rows,
AVG(total) over all_rows as avg_of_all_rows
from products
window all_rows as ();
The groups in your query contain just one row if total is a distinct value. This seems to be the case with your example. You can check this with a count aggregate (value = 1).
Removing total and probably unit_cost) from your select and group by clause should help.
I have the following sample from a table with students results with date for a school entry exam
First student passed exam - This is the most common record found for most students
Second student failed 1st time entry and passed second time based on the date
3rd student had a failed input entry and was corrected based on the Version
I need the results to like like the picture above, so we take into regard using the latest date and highest version!
My basic query thus far is
select studentid
,examdate --(Date)
,result -- (charvar)
from StudentEntryExam
How should I approach this issue?
demo:db<>fiddle
SELECT DISTINCT ON (studentid)
*
FROM mytable
ORDER BY studentid, examdate DESC, version DESC
DISTINCT ON returns the first record of an ordered group. In that case the groups are the studentids. You must find the correct order to set the required record first. So, you need to order by studentid, of course. Then you need the most recent examdate first, which can be achieved with DESC order. If there are two records on the same date, you need to order the highest version first as well using the DESC modifier, too.
I tried to write it using ISNULL but I'm getting error.
Try this:
ZN([Price])!=99
Wrap this in INT() to sum the result.
I want average but its showing null. I want the average of score present in different ids
select avg(score*100)from daily_stats1 where id=10 and id=11
Just get rid of null values using coalesce function:
select avg(coalesce(score, 0)*100)from daily_stats1 where id=10 and id=11
Thanks in advance for any advice you can offer! I'm building a Tableau dashboard to explore housing affordability and school quality in different neighborhoods in my area. A user will select their occupation and see a graph of neighborhoods plotted based on school quality and housing affordability. To explore housing affordability, I'm using county level assessor data with the valuation of every property matched to neighborhoods.
The goal is to display the percentage of homes in an area that are affordable given the median occupational wages for the job a user selected. Right now, I'm trying to use a calculated field with COUNT([Parcels]<[Occupation])/COUNT([Parcels]), but I need to find a way to count the number of properties in each specific neighborhood below the cut off value.
Does anyone know of a way to count elements of a particular group in this way in Tableau?
I'm on a Mac, using Tableau Desktop, and doing the back end analysis work in R. Thank you!
You seem to misunderstand what the function COUNT() does. You are certainly not alone. Count() behaves in Tableau almost identically to how it does with SQL.
Count([some field]) returns the number of data rows where the value for [some field] is not null. It does not not return the number of rows where [some field] evaluates to true, or a positive number, or anything else.
If [some field] always has a non-null value, then Count([some field]) is the same as SUM([Number of Records]). If [some field] is always null, then Count([some field]) is zero. Count() is not like Excel's CountIf function.
If you want to count data rows that meet a condition, you could try COUNT(if [condition] then 1 end) Since the missing ELSE case defaults to null values, that expression will count rows where [condition] is true.
So one way to get the percentage of affordable homes is count(if [affordable] then 1 end) / count(1) assumes each Data row represents a home. Then format your field to display as a percentage. Another option is to learn to use quick table calcs
If you want to display the number of rows in a given visualized table you could also use SIZE()
Source, official docs:
https://help.tableau.com/current/pro/desktop/en-us/functions_functions_tablecalculation.htm#size