The argument type 'String?' can't be assigned to the parameter type 'String' because 'String?' is nullable and 'String' isn't in Text widget - flutter

Question

I am trying to display the name and email of the person when he logs in to the profile screen using Getx
Column(
children: [
Text(
controller.userModel!.name,
style: TextStyle(
fontSize: 20,
fontWeight: FontWeight.w600,
color: Kprimarycolor,
),
),
Text(
controller.userModel!.email,
style: TextStyle(
fontSize: 20,
fontWeight: FontWeight.w600,
color: Kprimarycolor,
),
),
],
),
],
but this error keep showing Error in vs code
and Error in terminal
the related code to name and email is
class UserModel {
late String? userId, email, name, pic;
UserModel({
required this.userId,
required this.email,
required this.name,
required this.pic,
});
UserModel.fromJson(Map<dynamic, dynamic> map) {
userId = map['userId'];
email = map['email'];
name = map['name'];
pic = map['pic'];
}
toJson() {
return {
'userId': userId,
'email': email,
'name': name,
'pic': pic,
};
}
}
I tried to add .toString() and as String but the error keeps showing after debugging

Answer 1

Column(
children: [
Text(
controller.userModel!.name!,
style: TextStyle(
fontSize: 20,
fontWeight: FontWeight.w600,
color: Kprimarycolor,
),
),
Text(
controller.userModel!.email!,
style: TextStyle(
fontSize: 20,
fontWeight: FontWeight.w600,
color: Kprimarycolor,
),
),
],
),
],
I added '!' character, it should work.

Answer 2

In your model, late String? userId, email, name, pic; and #Salih Can answer will be work.
Here, String? means string can accept null value. But Text widget don't accept null value. You need to use bang operator ! to handle it and by adding ! means this value is not null anymore. A better practice would be checking if it is null or not, then assign on Text. It can be
Text(myVal==null? "defalut value": myVal)
Text(myVal??"default Value")
if(myval!=null) Text(myVal) and it will render only if string is not null.