Ok, so I have this command that turns off my touchscreen. It works when I execute it in a root shell.
So this works:
sudo su
/usr/bin/echo $(ls /sys/bus/hid/drivers/hid-multitouch | awk NR==1'{print $1}') > /sys/bus/hid/drivers/hid-multitouch/unbind
And then my touchscreen stops working, which is the result that I wanted.
Now I want to make a touchscreen.service file to execute this on every boot. So in the service file I include:
ExecStart=/usr/bin/echo $(ls /sys/bus/hid/drivers/hid-multitouch | awk NR==1'{print $1}') > /sys/bus/hid/drivers/hid-multitouch/unbind
However it isn't working > nor throwing any errors that I've been able to catch.
I do know from earlier fidlings with .service files that I might actually need to use /usr/bin/sh -c, so I have also tried:
ExecStart=/usr/bin/sh -c "/usr/bin/echo $(ls /sys/bus/hid/drivers/hid-multitouch | awk NR==1'{print $1}') > /sys/bus/hid/drivers/hid-multitouch/unbind"
Yet this also doesn't work.. maybe because of the awk NR==1'{print $1}'part? I have also tried replacing it with awk NR==1'\''{print $1}'\''but again it fails to work.
Does anyone have any ideas on how to get the command that is working in my root cli environment to also work as a systemd service?
To start with,
The syntax of the awk command is just wrong. The quotes are incorrectly placed. The part NR == 1 is part of the awk command to indicate the first line record in the file, i.e.
awk NR==1'{print $1}'
# ^^^^^^^ should be within quotes
awk 'NR == 1 { print $1 }'
Your sequence of echo, ls and the command substitution $(..) doesn't look right. You are effectively echo-ing the literal string /sys/bus/hid/drivers/hid-multitouch (if ls finds the file at that path) over to the pipe and awk just writes that to the /sys/bus/hid/drivers/hid-multitouch/unbind file which might not be your desired action. You just needed to do run the command on the file directly as
awk 'NR == 1 { print $1 }' /sys/bus/hid/drivers/hid-multitouch > /sys/bus/hid/drivers/hid-multitouch/unbind
Now that, that the awk command is fixed, you have two options to run the above command as part of systemd, either put your command in a script or run the command directly. For putting it in a script refer to the Unix.SE answer Where do I put scripts executed by systemd units?. As for running the command directly in ExecStart. Aside from using /bin/sh also use the path /bin/awk
So putting it together and using /bin/ over /usr/bin, you can do below. This command uses ".." over awk script and needs escape of $1
ExecStart=/bin/sh -c '/bin/awk "NR == 1 { print \$1 }" /sys/bus/hid/drivers/hid-multitouch > /sys/bus/hid/drivers/hid-multitouch/unbind'
Related
I would like to execute this make command to first replace the first line of all csv files inside the directory and then replace the # for commas through the other lines.
The second command is working fine and does what it is supposed to do, but the first one only replaces the line on the first file.
Could anyone give me a help on that?
csv:
$(DOCKER_RUN) npm run csv-generator
make format-csv
format-csv:
#sed -i '' '1 s/^.*$$/"bar","repository"/g' $(CURDIR)/foo/npm/*.csv
#sed -i '' 's/\(.*\)#/\1","/g' $(CURDIR)/foo/npm/*.csv
The reason that the first sed command "fails" is that sed doesn't reset the line counter between input files (on your system, and neither on my Mac OS X machine, see comments):
$ cat test1
a
b
g
$ cat test2
aa
bb
cc
$ sed -n '=' test1 test2 # the '=' sed command outputs line numbers
1
2
3
4
5
6
This is why the first sed command isn't doing what you want it to do, it only affects the first file's first line.
The solution is to loop over the files and call sed for each of them (untested in Makefile):
#for f in $(CURDIR)/foo/npm/*.csv; do \
sed -i '' '1 s/^.*$$/"bar","repository"/g' $f; \
done
Using find and xargs will also work, just make sure that find isn't picking up files further down in the folders.
EDIT: In light of the comments on this answer, I would recommend avoiding the use of sed -i on multiple files altogether, and convert both statements into for-loops (in this case, they may be collapsed into one loop with two statements):
#for f in $(CURDIR)/foo/npm/*.csv; do \
sed -i '' '1 s/^.*$$/"bar","repository"/g' $f; \
sed -i '' 's/\(.*\)#/\1","/g' $f; \
done
In my experience, using for-loops in Makefiles seems to be far more common compared to using find and xargs. This is probably due to incompatibility between find and xargs versions between Unices. It also makes the Makefile a lot easier to read if one uses explicit loops.
I managed to solve with:
#find $(CURDIR)/foo/npm -name "*.csv" -type f | xargs -L 1 sed -i '' '1 s/^.*$$/"bar"/g'
I'm using here document of sh to run some commands. now I want to parse the output of those commands using awk. However, everytime I execute it, I get the output of the command append with something like this "% No such child process"
This is how my script looks like.
#!/bin/sh
com = "sudo -u username /path/of/file -l"
$com <<EOF | awk '{print $0}'
Commands.
.
.
.
EOF
How am I going to use heredoc and pipeline without appending that unwanted string?
Thanks
Your variable assignment is wrong in a couple of ways. First, you aren't actually assigning a variable; you're trying to run a command named com whose arguments are = and a string "sudo ...". Spaces must not be used on either side of the =:
com="sudo ..."
Second, command lines should not be stored in a variable; the shell's parser can only make that work they way you intend for very simple commands. Type the command out in full, or use a shell function.
com () {
sudo -u username /path/to/file -l
}
com <<EOF | awk '{print $0}'
...
EOF
There's no problem, check :
$ cat <<EOF | awk '{print $1}'
a b c
1 2 3
EOF
a
1
I have a CSV. I want to edit the 35th field of the CSV and write the change back to the 35th field. This is what I am doing on bash:
awk -F "," '{print $35}' test.csv | sed -i 's/^0/+91/g'
so, I am pulling the 35th entry using awk and then replacing the "0" in the starting position in the string with "+91". This one works perfet and I get desired output on the console.
Now I want this new entry to get written in the file. I am thinking of sed's "in -place" replacement feature but this fetuare needs and input file. In above command, I cannot provide input file because my primary command is awk and sed is taking the input from awk.
Thanks.
You should choose one of the two tools. As for sed, it can be done as follows:
sed -ri 's/^(([^,]*,){34})0([^,]*)/\1+91\3/' test.csv
Not sure about awk, but #shellter's comment might help with that.
The in-place feature of sed is misnamed, as it does not edit the file in place. Instead, it creates a new file with the same name. eg:
$ echo foo > foo
$ ln -f foo bar
$ ls -i foo bar # These are the same file
797325 bar 797325 foo
$ echo new-text > foo # Changes bar
$ cat bar
new-text
$ printf '/new/s//newer\nw\nq\n' | ed foo # Edit foo "in-place"; changes bar
9
newer-text
11
$ cat bar
newer-text
$ ls -i foo bar # Still the same file
797325 bar 797325 foo
$ sed -i s/new/newer/ foo # Does not edit in-place; creates a new file
$ ls -i foo bar
797325 bar 792722 foo
Since sed is not actually editing the file in place, but writing a new file and then renaming it to the old file, you might as well do the same.
awk ... test.csv | sed ... > test.csv.1 && mv test.csv.1 test.csv
There is the misperception that using sed -i somehow avoids the creation of the temporary file. It does not. It just hides the fact from you. Sometimes abstraction is a good thing, but other times it is unnecessary obfuscation. In the case of sed -i, it is the latter. The shell is really good at file manipulation. Use it as intended. If you do need to edit a file in place, don't use the streaming version of ed; just use ed
So, it turned out there are numerous ways to do it. I got it working with sed as below:
sed -i 's/0\([0-9]\{10\}\)/\+91\1/g' test.csv
But this is little tricky as it will edit any entry which matches the criteria. however in my case, It is working fine.
Similar implementation of above logic in perl:
perl -p -i -e 's/\b0(\d{10})\b/\+91$1/g;' test.csv
Again, same caveat as mentioned above.
More precise way of doing it as shown by Lev Levitsky because it will operate specifically on the 35th field
sed -ri 's/^(([^,]*,){34})0([^,]*)/\1+91\3/g' test.csv
For more complex situations, I will have to consider using any of the csv modules of perl.
Thanks everyone for your time and input. I surely know more about sed/awk after reading your replies.
This might work for you:
sed -i 's/[^,]*/+91/35' test.csv
EDIT:
To replace the leading zero in the 35th field:
sed 'h;s/[^,]*/\n&/35;/\n0/!{x;b};s//+91/' test.csv
or more simply:
|sed 's/^\(\([^,]*,\)\{34\}\)0/\1+91/' test.csv
If you have moreutils installed, you can simply use the sponge tool:
awk -F "," '{print $35}' test.csv | sed -i 's/^0/+91/g' | sponge test.csv
sponge soaks up the input, closes the input pipe (stdin) and, only then, opens and writes to the test.csv file.
As of 2015, moreutils is available in package repositories of several major Linux distributions, such as Arch Linux, Debian and Ubuntu.
Another perl solution to edit the 35th field in-place:
perl -i -F, -lane '$F[34] =~ s/^0/+91/; print join ",",#F' test.csv
These command-line options are used:
-i edit the file in-place
-n loop around every line of the input file
-l removes newlines before processing, and adds them back in afterwards
-a autosplit mode – split input lines into the #F array. Defaults to splitting on whitespace.
-e execute the perl code
-F autosplit modifier, in this case splits on ,
#F is the array of words in each line, indexed starting with 0
$F[34] is the 35 element of the array
s/^0/+91/ does the substitution
I have this line
samtools view -h file | awk '$3=="chr$a" || /^#/' | samtools view -S - -b -o output
the dash between the -S and the -b is supposed to indicate to the program that it is from STDIN. I can run it from a perl script on the command line but as soon as I try to move it into a shell script it just creates the file without outputting any data. Any ideas would be greatly appreciated.
In a shell script the $a inside single quotes will not be expanded:
for a in {1..22} do
samtools view -h AD3.sorted.bam | awk '$3=="chr$a" || /^#/' | samtools view -S - -b -o chr$a.bam
done
If you haven't already, have a look at the samtools FAQ. This has examples for doing similar things to what you want to do with your pipeline.
Its been a while since I used samtools, but I would've written your command like this:
samtools view -h file | awk '$3=="chr$a" || /^#/' | samtools view -S -b - > output.bam
Also you mentioned you had moved the command to a shell script. Is the shell script doing anything else? If it still doesn't work, I would post that for us to look at.
I have the following sed command. I need to execute the below command in single line
cat File | sed -n '
/NetworkName/ {
N
/\n.*ims3/ p
}' | sed -n 1p | awk -F"=" '{print $2}'
I need to execute the above command in single line. can anyone please help.
Assume that the contents of the File is
System.DomainName=shayam
System.Addresses=Fr6
System.Trusted=Yes
System.Infrastructure=No
System.NetworkName=AS
System.DomainName=ims5.com
System.DomainName=Ram
System.Addresses=Fr9
System.Trusted=Yes
System.Infrastructure=No
System.NetworkName=Peer
System.DomainName=ims7.com
System.DomainName=mani
System.Addresses=Hello
System.Trusted=Yes
System.Infrastructure=No
System.NetworkName=Peer
System.DomainName=ims3.com
And after executing the command you will get only peer as the output. Can anyone please help me out?
You can use a single nawk command. And you can lost the useless cat
nawk -F"=" '/NetworkName/{n=$2;getline;if($2~/ims3/){print n} }' file
You can use sed as well as proposed by others, but i prefer less regex and less clutter.
The above save the value of the network name to "n". Then, get the next line and check the 2nd field against "ims3". If matched, then print the value of "n".
Put that code in a separate .sh file, and run it as your single-line command.
cat File | sed -n '/NetworkName/ { N; /\n.*ims3/ p }' | sed -n 1p | awk -F"=" '{print $2}'
Assuming that you want the network name for the domain ims3, this command line works without sed:
grep -B 1 ims3 File | head -n 1 | awk -F"=" '{print $2}'
So, you want the network name where the domain name on the following line includes 'ims3', and not the one where the following line includes 'ims7' (even though the network names in the example are the same).
sed -n '/NetworkName/{N;/ims3/{s/.*NetworkName=\(.*\)\n.*/\1/p;};}' File
This avoids abuse of felines, too (not to mention reducing the number of commands executed).
Tested on MacOS X 10.6.4, but there's no reason to think it won't work elsewhere too.
However, empirical evidence shows that Solaris sed is different from MacOS sed. It can all be done in one sed command, but it needs three lines:
sed -n '/NetworkName/{N
/ims3/{s/.*NetworkName=\(.*\)\n.*/\1/p;}
}' File
Tested on Solaris 10.
You just need to put -e pretty much everywhere you'd break the command at a newline or have a semicolon. You don't need the extra call to sed or awk or cat.
sed -n -e '/NetworkName/ {' -e 'N' -e '/\n.*ims3/ s/[^\n]*=\(.*\).*/\1/P' -e '}' File