Changing amount of resource sets in Seize-block programmatically - anylogic

So the problem is:
How can I change the amount in "Resource Sets" programmatically? I'am planning on changing this value back and forth from 1 and 2 given some conditions during the simulation run.
Amount I want to change is marked in yellow below.

Emile answer is right, but if you insist in using what you are using, you can click on the equal sign and make it a function:
and in the function (which i made take a random number between 1 and 2, but you can do what you want), you use the following (the function returns a type ResourcePool[][])
ResourcePool[][] rp = new ResourcePool[1][num];
for(int i=0;i<num;i++){
rp[0][i]=resourcePool;
}
return rp;

In your case, it seems you are using one resource alternative only.
Why don't you choose units of the same pool, then the number of units to be seized becomes dynamic.

Related

Anylogic: Dynamically change source rate using variable/slider

I am trying to dynamically change the source Arrival rate using a variable "arrivalRate" linked to a slider (see image).
However, during the simulation the initial rate remains the same, even when I change the arrivalRate. I know that the arrivalRate variable is changing successfully (it is an int) - but this has no effect on the source rate during the simulation.
Anyone have an idea what the issue is - or how to fix it?
Whenever you see the = sign before a field, it means it's not dynamic, it is only evaluated at the start of the model or at the element creation and will not change throughout the simulation run unless you force it. In other words, the variable arrivalRate is checked only once to assign the source's arrival rate and that's it.
Now if you want to change it dynamically, in the slider's Action field, write the following:
source.set_rate( arrivalRate );

Get value of Web Audio node or param after automation

I would like to access a Web Audio Node's calculated output or param value at the current time (after any connected node's contributions have been added) in the main thread.
Currently all I can access is the value set using the AudioParam methods or the setter of AudioParam.value, but the contributions from any other nodes that I connect are not applied when using the AudioParam.value getter. Is this 1) intentional and 2) are there any workarounds to get the actual value in the main thread that a AudioWorkletProcessor would receive (which would sum the values from each input and add that to the value)?
You could use a ConstantSourceNode with appropriate automations of the offset AudioParam. Then connect some signal to the offset and finally look at the output of the node to see the computed value. You still need to use an AnalyserNode, ScriptProcessorNode, or AudioWorkletNode to get at the output values.
This isn't a perfect solution.

Setting up openai gym

I've been given a task to set up an openai toy gym which can only be solved by an agent with memory. I've been given an example with two doors, and at time t = 0 I'm shown either 1 or -1. At t = 1 I can move to correct door and open it.
Does anyone know how I would go about starting out? I want to show that a2c or ppo can solve this using an lstm policy. How do I go about setting up environment, etc?
To create a new environment in gym format, it should have the 5 functions mentioned in the gym.core file.
https://github.com/openai/gym/blob/e689f93a425d97489e590bba0a7d4518de0dcc03/gym/core.py#L11-L35
To lay this down in steps-
Define observation space and action space for your environment, preferably using gym.spaces module.
Write down the step function which performs agent's action and returns a 4 tuple containing - next set of observations from the environment , reward ,
done - a boolean indicating whether the episode is over , and some extra info if you want.
Write a reset function for the environment to reinitialise the episode to a random start state and return a 4 tuple similar to step.
These functions are enough to be able to run an RL agent on your environment.
You can skip the render, seed and close functions if you want.
For the task you have defined,you can model the observation and action space using Discrete(2). 0 for first door and 1 for second door.
Reset would return in it's observation which door has the reward.
Then agent would choose either of the door - 0 or 1.
Then perform a environment step by calling step(action), which will return agent's reward and done flag as true - signifying that the episode is over.
Frankly, the problem you describe seems too simple to accomplish for any reinforcement learning algorithm, but I assume you have provided that as an example.
Remembering for longer horizons is usually harder.
You can read their documentation and toy environments to understand how to create one.

Anylogic: How to conditionally close/open a valve

I am very new at Anylogic. I have a simple model, using the Fluid dynamics library: two tanks and a valve between them. The valve have to open at a rate, say X, only when the amount in the first tank, say tank_1, were twice of the amount of the second tank, say tank_2
Could you please help me with that?
Regards
You probably have more conditions on what to use with the valve depending on different things. But it's a bad idea to make something occur when then tank_1 is exactly 2 times larger than tank_2... Instead, create a boolean variable that tells you if the current situation is that tank_1 is over or below 2*tank_2. Let's call it "belowTank2". I will assume tank_1 is below 2*tank_2 in the beginning of the simulation. so belowTank2 is true.
Then you create an event that runs cyclically every second or even more often if you want and you use the following code:
if(belowTank2){
if(tank_1.amount()>2*tank_2.amount()){
valve.set_openRate(0.1);
belowTank2=false;
}
}else{
if(tank_1.amount()<2*tank_2.amount()){
valve.set_openRate(0.3);
belowTank2=true;
}
}
So this means that whenever tank_1 surpases 2*tank_2, it will trigger the rate change on the valve. And it will trigger again a change when it's below 2*tank_2

SB37 JCL error to small a size?

The following space allocation is giving me an sB37 JCL error. The cobol size of the output file is 100 bytes and the lrecl size is 100 bytes. What do you think is causing this error? I have tried increase the size to 500,100 and still get the same error.
Code:
//OUTPUT1 DD DSN=A.B.C,DISP=(NEW,CATLG,DELETE),
// DCB=(LRECL=100,BLKSIZE=,RECFM=FBM),
// SPACE=(CYL,(10,5),RLSE)
Try to increase not only the space, but the volume as well.
Include VOL=(,,,#) in your DD. # is the numbers of values you want to allocate
Ex: SPACE=(CYL,(10,5),RLSE),VOL=(,,,3) - includes 3 volumes.
Additionally, you can increase the size, but try to stay within reasonable limits :)
The documentation for B37 says the application programmer should respond as indicated for message IEC030I. The documentation for IEC030I says, in part...
Probable user error. For all cases, allocate as many units as volumes
required.
...as noted in another answer. However, be advised that the documentation for the VOL parameter of the DD statement says...
If you omit the volume count or if you specify 1 through 5, the system
allows up to five volumes; if you specify 6 through 20, the system
allows 20 volumes; if you specify a count greater than 20, the system
allows 5 plus a multiple of 15 volumes. You can override the maximum
volume count in data class by using the volume-count subparameter. The
maximum volume count for an SMS-managed mountable tape data set or a
Non-managed tape data set is 255.
...so for DASD allocations you are best served specifying a volume count greater than 5 (at least).
//OUTPUT1 DD DSN=A.B.C,DISP=(NEW,CATLG,DELETE),
// DCB=(LRECL=100,BLKSIZE=,RECFM=FBM),
// SPACE=(CYL,(10,5),RLSE)
Try this instead. Notice that the secondary will take advantage of a large dataset whereas without that parameter the largest secondary that makes any sense is < 300. Oh, and if indeed it is from a COBOL program make sure that the FD says "BLOCK 0"!!!!! If it isn't "BLOCK 0" then you might not even need to change your JCL because it wasn't fixed block machine. It was merely fixed and unblocked so the space would almost never be enough. And finally you may wish to revisit why you have the M in the RECFM to begin with. Notice also that I took out the LRECL, the BLKSIZE and the RECFM. That is because the FD in the COBOL program is all you need and putting it in the JCL is not only redundant but dangerous because any change will have to be now done in multiple places.
//OUTPUT1 DD DSN=A.B.C,DISP=(NEW,CATLG,DELETE),
// DSNTYPE=LARGE,UNIT=(SYSALLDA,59),
// SPACE=(CYL,(10,1000),RLSE)
There is a limit of 65,535 tracks per one volume. So if you will specify a SPACE that exceeds that limit - system will simply ignore it.
You can increase this limit to 16,777,215 tracks by adding DSNTYPE=LARGE paramter.
Or you can specify that your dataset is a multi volume by adding VOL=(,,,3)
You can also use DATACLAS=xxxx paramter here, however first of all you need to find it. Easy way is to contact your local Storage Team and ask for one. Or If you are familiar with ISPF navigation, you can enter ISMF;4 command to open a panel
use bellow paramters before hitting enter.
CDS Name . . . . . . 'ACTIVE'
Data Class Name . . *
It should produce a list of all available data classes. Find the one that suits you ( has enougth amount of volume count, does not limit primary and secondary space