Flutter how to subtract time from other time - flutter

I have 2 times which I need to do subtract and I am almost close but there is one big issue
I have 2 times in string-like 10:00AM and 10:00PM
And my code is this
var df = DateFormat("hh:mm");
var durationStart = DateFormat('HH:mm').format(df.parse(10:00AM));
var durationEnd = DateFormat('HH:mm').format(df.parse(10:00PM));
print('durationStart ${durationStart}');
print('durationEnd ${durationEnd}');
var Startparts = durationStart.split(':');
var startDurationSet = Duration(hours: int.parse(Startparts[0].trim()), minutes: int.parse(Startparts[1].trim()));
var Endparts = durationEnd.split(':');
var endDurationSet = Duration(hours: int.parse(Endparts[0].trim()), minutes: int.parse(Endparts[1].trim()));
print('startDurationSet ${startDurationSet}');
var result = Duration(hours: int.parse(Endparts[0].trim()) - int.parse(Startparts[0].trim()) , minutes: int.parse(Startparts[1].trim()) - int.parse(Endparts[1].trim()));
print('result ${result.toString().replaceAll('-', '')}');
So I have 2 times one is startTime and one is End time. I simply need a difference between hours. for example, I have 10:00Am and 01:00PM i need 3hours but it's showing 9hours. But what I am receiving is if I have 10:00AM and 10:00pm it's showing 0 hours but its needs to show 12. Same

It is easy if you can get your start and end date in DateTime properly
Hint, I use "hh:mma" since that is your original format => "10:00AM"
If I use "HH:mm" like you do, i'll always get the same time since it doesn't parse the AM/PM after the 10:00
// Get your time in term of date time
DateTime startDate = DateFormat("hh:mma").parse("10:00AM");
DateTime endDate = DateFormat("hh:mma").parse("10:00PM");
// Get the Duration using the diferrence method
Duration dif = endDate.difference(startDate);
// Print the result in any format you want
print(dif.toString(); // 12:00:00.000000
print(dif.inHours); // 12

Are you looking for something like this?
TimeOfDay _calcTimeOfDay(int hour, int minute) {
if (minute > 60) {
minute = (minute % 60);
hour += 1;
}
return TimeOfDay(hour: hour, minute: minute);
}
The problem is if you have hour=24 and minute=75 then the hour would be 25, which is not a valid hour.
Not sure I fully understand the question, maybe if you can provide more info.

What you need to add on your DateFormat is the code for am/pm marker: a. Using either format hh:mma or h:ma should work.
You can then use DateTime.difference() to calculate the time variance from durationStart and durationEnd. Here's a sample that you can run on DartPad.
import 'package:intl/intl.dart';
void main() {
/// Set the format that of the Date/Time that like to parse
/// h - 12h in am/pm
/// m - minute in hour
/// a - am/pm marker
/// See more format here: https://pub.dev/documentation/intl/latest/intl/DateFormat-class.html
var dateFormat = DateFormat('h:ma');
DateTime durationStart = dateFormat.parse('10:00AM');
DateTime durationEnd = dateFormat.parse('10:00PM');
print('durationStart: $durationStart');
print('durationEnd: $durationEnd');
/// Fetch the difference using DateTime.difference()
/// https://api.flutter.dev/flutter/dart-core/DateTime/difference.html
print('difference: ${durationEnd.difference(durationStart).inHours}');
}

Use package
intl: ^0.17.0
import 'package:intl/intl.dart';
var dateFormat = DateFormat('h:ma');
DateTime durationStart = dateFormat.parse('10:00AM');
DateTime durationEnd = dateFormat.parse('1:00PM');
print('durationStart: $durationStart');
print('durationEnd: $durationEnd');
var differenceInHours = durationEnd.difference(durationStart).inHours;
print('difference: $differenceInHours hours');

I have created one class for you:
import 'package:intl/intl.dart';
class DateUtils {
static String getTimeDifference(String startTime, String endTime){
/// Set the format that of the Date/Time that like to parse
/// h - 12h in am/pm
/// m - minute in hour
/// a - am/pm marker
/// See more format here: https://pub.dev/documentation/intl/latest/intl/DateFormat-class.html
var dateFormat = DateFormat('h:ma');
DateTime durationStart = dateFormat.parse(startTime);
DateTime durationEnd = dateFormat.parse(endTime);
return '${durationEnd.difference(durationStart).inHours} hours';
}
}
How you can use:
void main() {
print("10:00PM, 10:30PM => " + DateUtils.getTimeDifference("10:00PM", "10:30PM"));
print("12:00AM, 04:00AM => " + DateUtils.getTimeDifference("12:00AM", "04:00AM"));
print("01:00AM, 03:00AM => " + DateUtils.getTimeDifference("01:00AM", "03:00AM"));
print("12:00AM, 06:00PM => " + DateUtils.getTimeDifference("12:00AM", "06:00PM"));
print("04:00PM, 03:00PM => " + DateUtils.getTimeDifference("04:00PM", "03:00PM"));
}
Output:
10:00PM, 10:30PM => 0 hours
12:00AM, 04:00AM => 4 hours
01:00AM, 03:00AM => 2 hours
12:00AM, 06:00PM => 18 hours
04:00PM, 03:00PM => -1 hours
Hope it will be helpful.

Related

Dart Flutter adding weeks to a DateTime

Guys. I want to write a simple code to add X weeks to a chosen Date but I just can't figure out how. I always get a ton of errors. The function should basically return the chosen date plus "addedweeks" in the format "dd-MM-yyyy". Below is my last attempt. Thanks in advance!
import 'dart:math' as math;
String? addXWeeks(
DateTime? datum,
int? addedweeks,
) {
// add 2 weeks
DateTime date = datum.toLocal;
date = DateTime(date.year, date.month, date.day + (addedweeks*7));
}
this is very easy. DateTime has a method called add. You only need to add 7 days, because duration has not the propertie "weeks".
Here is a samle:
void main() {
// Current date
DateTime date = DateTime.now();
// Weeks you want to add
int weeksToAdd = 10;
print("Before: $date");
// Multiply 7 (days a week) with your week and set int to and int
date = date.add(Duration(days: (7 * weeksToAdd).toInt()));
print("After: $date");
// Format date
print("Format date: ${date.day}.${date.month}.${date.year}");
}
The output:
Before: 2022-10-06 13:23:16.342888
After: 2022-12-15 12:23:16.342888
Format date: 15.12.2022

How can we identify time section in datetime flutter

I will receive DateTime in UTC format from API and I need to convert the DateTime to local time zone based on the condition.
We have toLocal() method to change the time based on the device time zone.
condition: 23-4-2021 // no need to change it to toLocal()
23-4-2021 00:00:00 // no need to change it to toLocal()
23-4-2021 10:30:34 // need to change it to toLocal()
If we have time in the DateTime then only we have to change it in local time.
DateTime utcToDateTimeLocal(DateTime value) {
return value.toLocal();
}
Thanks!
Something like this maybe ?
DateTime utcToDateTimeLocal(DateTime value) {
if (value.hour!=0 || value.minute!=0 || value.second!=0){
return value.toLocal();
}
return value;
}
Here is quick solution that work for me.
You can get time (or any format) by DateFormat class
In your case
dateTime = '23-4-2021 10:30:34'
final format = DateFormat('HH:mm a');
final clockString = format.format(dateTime);
you will get // 10:30 AM
DateTime utcToDateTimeLocal(DateTime value) {
var dateFormat =
DateFormat("dd-mm-yyyy hh:mm a"); // you can change the format here
var utcDate =
dateFormat.format(DateTime.parse(value.toString())); // pass the UTC time here
var localDate = dateFormat.parse(utcDate, true).toLocal().toString();
return DateTime.parse(localDate);
}

How to convert date and time only at time?

I get by API such data about time and date 2021-09-05T18:16:47.790601+02:00 how can I get only hours from here?
From the API you're getting a formatted date and want to get only the hour.
First, it would be better to you get from the API the UNIX date (if available) which has a timestamp format like this: https://www.unixtimestamp.com
Your first question would be more either:
How getting from a fromatted date a Timestamp to obtain the hour
or
How parsing the string to get the hour.
Here the formatted method:
DateTime which should help you: https://api.flutter.dev/flutter/dart-core/DateTime-class.html
Here an example:
final DateTime myDate = DateTime.parse('2021-09-05 18:16:47');
final int hour = myDate.hour;
final int minute = myDate.minute;
final int second = myDate.second;
print('hour: $hour');
print('minute: $minute');
print('second: $second');
Result:
hour: 18
minute: 16
second: 47
Here the parsing method:
Substring which should help you: enter link description here
RegExp which should help you: enter link description here
Here an example:
const String myDate = '2021-09-05T18:16:47.790601+02:00';
final String hour = myDate.substring(11, 13);
final String minute = myDate.substring(14, 16);
final String second = myDate.substring(17, 19);
final String date = RegExp(r"[0-9]{2}:[0-9]{2}:[0-9]{2}").stringMatch(myDate).toString();
final List<String> splitDate = date.split(':');
print('hour: $hour');
print('minute: $minute');
print('second: $second');
print('date: $date');
print('split date: $splitDate');
Result:
hour: 18
minute: 16
second: 47
date: 18:16:47
split date: [18, 16, 47]
For ISO8601 String you can convert with DateTime
DateTime dt = DateTime.parse('2020-01-02 03:04:05');
then you can access what you want with dt

JasperSoft Studio - How is the best way to to print a period of time (minutes) as hh:mm? [duplicate]

I need to convert minutes to hours and minutes in java. For example 260 minutes should be 4:20. can anyone help me how to do convert it.
If your time is in a variable called t
int hours = t / 60; //since both are ints, you get an int
int minutes = t % 60;
System.out.printf("%d:%02d", hours, minutes);
It couldn't get easier
Addendum from 2021:
Please notice that this answer is about the literal meaning of the question: how to convert an amount of minute to hours + minutes. It has nothing to do with time, time zones, AM/PM...
If you need better control about this kind of stuff, i.e. you're dealing with moments in time and not just an amount of minutes and hours, see Basil Bourque's answer below.
tl;dr
Duration.ofMinutes( 260L )
.toString()
PT4H20M
… or …
LocalTime.MIN.plus(
Duration.ofMinutes( 260L )
).toString()
04:20
Duration
The java.time classes include a pair of classes to represent spans of time. The Duration class is for hours-minutes-seconds, and Period is for years-months-days.
Duration d = Duration.ofMinutes( 260L );
Duration parts
Access each part of the Duration by calling to…Part. These methods were added in Java 9 and later.
long days = d.toDaysPart() ;
int hours = d.toHoursPart() ;
int minutes = d.toMinutesPart() ;
int seconds = d.toSecondsPart() ;
int nanos = d.toNanosPart() ;
You can then assemble your own string from those parts.
ISO 8601
The ISO 8601 standard defines textual formats for date-time values. For spans of time unattached to the timeline, the standard format is PnYnMnDTnHnMnS. The P marks the beginning, and the T separates the years-month-days from the hours-minutes-seconds. So an hour and a half is PT1H30M.
The java.time classes use ISO 8601 formats by default for parsing and generating strings. The Duration and Period classes use this particular standard format. So simply call toString.
String output = d.toString();
PT4H20M
For alternate formatting, build your own String in Java 9 and later (not in Java 8) with the Duration::to…Part methods. Or see this Answer for using regex to manipulate the ISO 8601 formatted string.
LocalTime
I strongly suggest using the standard ISO 8601 format instead of the extremely ambiguous and confusing clock format of 04:20. But if you insist, you can get this effect by hacking with the LocalTime class. This works if your duration is not over 24 hours.
LocalTime hackUseOfClockAsDuration = LocalTime.MIN.plus( d );
String output = hackUseOfClockAsDuration.toString();
04:20
About java.time
The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.
The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.
To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.
Where to obtain the java.time classes?
Java SE 8 and SE 9 and later
Built-in.
Part of the standard Java API with a bundled implementation.
Java 9 adds some minor features and fixes.
Java SE 6 and SE 7
Much of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport.
Android
The ThreeTenABP project adapts ThreeTen-Backport (mentioned above) for Android specifically.
See How to use ThreeTenABP….
The ThreeTen-Extra project extends java.time with additional classes. This project is a proving ground for possible future additions to java.time. You may find some useful classes here such as Interval, YearWeek, YearQuarter, and more.
Use java.text.SimpleDateFormat to convert minute into hours and minute
SimpleDateFormat sdf = new SimpleDateFormat("mm");
try {
Date dt = sdf.parse("90");
sdf = new SimpleDateFormat("HH:mm");
System.out.println(sdf.format(dt));
} catch (ParseException e) {
e.printStackTrace();
}
You can also use the TimeUnit class. You could define private static final String FORMAT = "%02d:%02d:%02d";
can have a method like:
public static String parseTime(long milliseconds) {
return String.format(FORMAT,
TimeUnit.MILLISECONDS.toHours(milliseconds),
TimeUnit.MILLISECONDS.toMinutes(milliseconds) - TimeUnit.HOURS.toMinutes(
TimeUnit.MILLISECONDS.toHours(milliseconds)),
TimeUnit.MILLISECONDS.toSeconds(milliseconds) - TimeUnit.MINUTES.toSeconds(
TimeUnit.MILLISECONDS.toMinutes(milliseconds)));
}
I use this function for my projects:
public static String minuteToTime(int minute) {
int hour = minute / 60;
minute %= 60;
String p = "AM";
if (hour >= 12) {
hour %= 12;
p = "PM";
}
if (hour == 0) {
hour = 12;
}
return (hour < 10 ? "0" + hour : hour) + ":" + (minute < 10 ? "0" + minute : minute) + " " + p;
}
It can be done like this
int totalMinutesInt = Integer.valueOf(totalMinutes.toString());
int hours = totalMinutesInt / 60;
int hoursToDisplay = hours;
if (hours > 12) {
hoursToDisplay = hoursToDisplay - 12;
}
int minutesToDisplay = totalMinutesInt - (hours * 60);
String minToDisplay = null;
if(minutesToDisplay == 0 ) minToDisplay = "00";
else if( minutesToDisplay < 10 ) minToDisplay = "0" + minutesToDisplay ;
else minToDisplay = "" + minutesToDisplay ;
String displayValue = hoursToDisplay + ":" + minToDisplay;
if (hours < 12)
displayValue = displayValue + " AM";
else
displayValue = displayValue + " PM";
return displayValue;
} catch (Exception e) {
LOGGER.error("Error while converting currency.");
}
return totalMinutes.toString();
(In Kotlin) If you are going to put the answer into a TextView or something you can instead use a string resource:
<string name="time">%02d:%02d</string>
And then you can use this String resource to then set the text at run time using:
private fun setTime(time: Int) {
val hour = time / 60
val min = time % 60
main_time.text = getString(R.string.time, hour, min)
}
Given input in seconds you can transform to format hh:mm:ss like this :
int hours;
int minutes;
int seconds;
int formatHelper;
int input;
//formatHelper maximum value is 24 hours represented in seconds
formatHelper = input % (24*60*60);
//for example let's say format helper is 7500 seconds
hours = formatHelper/60*60;
minutes = formatHelper/60%60;
seconds = formatHelper%60;
//now operations above will give you result = 2hours : 5 minutes : 0 seconds;
I have used formatHelper since the input can be more then 86 400 seconds, which is 24 hours.
If you want total time of your input represented by hh:mm:ss, you can just avoid formatHelper.
I hope it helps.
Here is my function for convert a second,millisecond to day,hour,minute,second
public static String millisecondToFullTime(long millisecond) {
return timeUnitToFullTime(millisecond, TimeUnit.MILLISECONDS);
}
public static String secondToFullTime(long second) {
return timeUnitToFullTime(second, TimeUnit.SECONDS);
}
public static String timeUnitToFullTime(long time, TimeUnit timeUnit) {
long day = timeUnit.toDays(time);
long hour = timeUnit.toHours(time) % 24;
long minute = timeUnit.toMinutes(time) % 60;
long second = timeUnit.toSeconds(time) % 60;
if (day > 0) {
return String.format("%dday %02d:%02d:%02d", day, hour, minute, second);
} else if (hour > 0) {
return String.format("%d:%02d:%02d", hour, minute, second);
} else if (minute > 0) {
return String.format("%d:%02d", minute, second);
} else {
return String.format("%02d", second);
}
}
Testing
public static void main(String[] args) {
System.out.println("60 => " + secondToFullTime(60));
System.out.println("101 => " + secondToFullTime(101));
System.out.println("601 => " + secondToFullTime(601));
System.out.println("7601 => " + secondToFullTime(7601));
System.out.println("36001 => " + secondToFullTime(36001));
System.out.println("86401 => " + secondToFullTime(86401));
}
Output
60 => 1:00
101 => 1:41
601 => 10:01
7601 => 2:06:41
36001 => 10:00:01
86401 => 1day 00:00:01
Hope it help
Minutes mod 60 will gives hours with minutes remaining.
http://www.cafeaulait.org/course/week2/15.html
int mHours = t / 60; //since both are ints, you get an int
int mMinutes = t % 60;
System.out.printf("%d:%02d", "" +mHours, "" +mMinutes);
Solution on kotlin Documentation
import kotlin.time.Duration
import kotlin.time.DurationUnit
import kotlin.time.toDuration
val min = 150.toDuration(DurationUnit.MINUTES)
val time = min.toComponents { days, hours, minutes, seconds, nanoseconds ->
"$days $hours $minutes $seconds $nanoseconds"
}
We get 0 days 2 hours 30 minutes 0 seconds 0 nanoseconds
We can also use
DurationUnit.DAYS
DurationUnit.HOURS
DurationUnit.SECONDS
DurationUnit.MILLISECONDS
DurationUnit.MICROSECONDS
DurationUnit.NANOSECONDS
long d1Ms=asa.getTime();
long d2Ms=asa2.getTime();
long minute = Math.abs((d1Ms-d2Ms)/60000);
int Hours = (int)minute/60;
int Minutes = (int)minute%60;
stUr.setText(Hours+":"+Minutes);
Try this code:
import java.util.Scanner;
public class BasicElement {
public static void main(String[] args){
Scanner input = new Scanner(System.in);
int hours;
System.out.print("Enter the hours to convert:");
hours =input.nextInt();
int d=hours/24;
int m=hours%24;
System.out.println(d+"days"+" "+m+"hours");
}
}
import java.util.Scanner;
public class Time{
public static void main(String[]args){
int totMins=0;
int hours=0;
int mins=0;
Scanner sc= new Scanner(System.in);
System.out.println("Enter the time in mins: ");
totMins= sc.nextInt();
hours=(int)(totMins/60);
mins =(int)(totMins%60);
System.out.printf("%d:%d",hours,mins);
}
}

How to extract day, month, and year from date returned by QML Calender?

The Calendar clicked signal returns a date as follows:
2015-11-13T00:00:00
However, I would like to have a date formatted like this:
Fri Nov 13 2015
This is what I tried:
onSelectedDateChanged:
{
calender.visible = false;
selectedDate = selectedDate.toLocaleTimeString(Qt.LocalDate, Locale.ShortFormat);
textOfSelectedDate.text = Date.fromLocaleTimeString(Qt.LocalDate, selectedDate, Locale.ShortFormat)}
}
textOfSelectedDate is the id of the text box where this date will be displayed.
How can I extract day, month, and year in a desired format from Date returned by Calender?
QML's date type extends Javascript's Date. Thus you can do:
onSelectedDateChanged: {
const day = selectedDate.getDate();
const month = selectedDate.getMonth() + 1; //assuming you want 1..12, getMonth()'s return value is zero-based!
const year = selectedDate.getFullYear();
...
}
First of all, date is similar to JS date type. So you can use all its functions, like getDate() etc. See it here
Also, you can use Qt.formatDate() object to format the result. In your case it can be as follows:
onClicked: {
console.log(Qt.formatDate(date,"ddd MMM d yyyy"))
}