I want to find entries in my MongoDB collection that match some filters.
Each entry in my mongo collection looks like this data:
{
type: "admin"
senderId: "6131e7c597f50700160703fe"
read_by: [
{
Object_id: 614dbbf83ad51412f16c0757
readerId: "60b968dc5150a20015d6fcae"
}
]
},
{
type: "admin"
senderId: "6131e7c597f50700160703fe"
read_by: [
{}
]
}
What I want to achieve properly, is to filter on the collection and get only the entries that match 'admin' as type and that don't have the current user's ID in the read_by array (that is an array of objects)
I wrote this (and tried some other combinations with errors :) )
but it is not working, I get 0 entries on the end, but I expect to get one of the two as the second have it's read_by array empty.
Thank you very much!
I validated my solution using cloud.mongodb.com interface and the simplest following filter seems to do the job:
{ "read_by.readerId": {$ne:"60b968dc5150a20015d6fcae"}}
Only the record with empty array is being returned.
$nin operator works fine as well but if there is only single value for comparision then $ne should be enough.
{ "read_by.readerId": {$nin: ["60b968dc5150a20015d6fcae"]}}
Related
I'm trying to update an array that sits inside another array in a document. The schema is like this:
const projectSchema = new mongoose.Schema({
stakeholders: [{
stakeholderTitle: {
type: String,
},
...
subgroup: [{
subgroupTitle: {
type: String
},
subgroupPercent: {
type: Number,
}
}]
}],
and I'm trying to update the 'subgroup' array. I have got the query to work on its parent (the stakeholder array) with the positional $ operator, using the answer to this question I asked previously. So my query looks like this.....
await db.findOneAndUpdate({ find by the id }, { "stakeholders.$.stakeholderTitle": req.body.stakeholderTitle, ... "stakeholders.$.subgroup": req.body.subgroup })
However, this query doesn't work for the 'stakeholders subgroup' array, and makes it null. Looking through the mongo docs for the positional operator it states that 'The positional $ operator cannot be used for queries which traverse more than one array, such as queries that traverse arrays nested within other arrays, because the replacement for the $ placeholder is a single value', which I guess might be my problem.
So how can I do this with a findOneAndUpdate query?
From what I see is you have to specify the object you want to update inside the subgroup array. Try this - (i.e I'm updating the subgroupTitle of the subgroup array);
await db.findOneAndUpdate(
{
_id: userId,
"stakeholders.stakeholderTitle": req.body.stakeholderTitle,
"stakeholders.stakeholderTitle.subgroup.subgroupTitle": req.body.subgroupTitle
},
{$set: {
"stakeholders.stakeholderTitle.subgroup.$.subgroupPercent": somePercentValue,
}
},
);
Also note, it's only the array that you find that you can update. It might not be exactly what you want, but its a step closer
I need help with filtering reactively minimongo collection with 3+ parameters. Firs, I have loaded minimongo from server's mongo collection with publish/subscribe. Now, I want to filter that collection and let user see only objects from collection that are same like filters. First of all I have search query filter that checks if input string is same as some filed in collection:
Job.find({ $or: [ { Name: regex }, { Description: regex }, ]});
This part is doing his job well. And now second filter: I have field in object that is true if that particular job is remote friendly and false if it is not, I wanted to if user enables that filter he only see just remote friendly job positions, and if he disables that, he can see all jobs available ( + search query of course):
if (remoteQuery === true ) {
return Job.find({ $or: [ { Name: regex }, { Description: regex }, ] , Remote: true});
}
This is working, but it is bad way for doing this. And now biggest problem comes with last filter: I have one more field that is storing "job" (collection object) type. Type can be 1, 2 , 3 or 4. So how could I say to minimongo e.g. "Show only jobs that have "Front-end" inside (search query), that are remote friendly, and have third filter 2 and 3 inside"
Job.find({ $or: [ { Name: "Front-end"}, { Description: "Front-end"}, ] , Remote: true, positionType: [2,3],});
Something like this? Thanks!
Sounds like you are looking for the MongoDB query $in operator:
The $in operator selects the documents where the value of a field equals any value in the specified array.
Therefore your 3rd query could look like:
Job.find({
positionType: {
$in: [2, 3] // Matches documents where `positionType` is either 2 or 3
},
// Other conditions…
});
the documents looks like :
{
name: 'abc',
types: [
{name:'Large',stock:true},
{name:'XLarge',stock:false},
{name:'XXLarge',stock:true}
]
}
I'm trying to figure out the query to return all documents which are out of stock.
Something like : .find({types:{{$nin:{stock:true}}})
Can I somehow do that?
You can query using positional operator like this:
db.collection.find({'types.stock':{$ne:true}})
$nin operator is used for finding elements not in a particular array. $ne (not equal to) is a much better operation in your case.
I need to update multiple records in mongodb.
From frontend logic , i got the array of id's as below.
ids: [ [ '530ac94c9ff87b5215a0d6e6', '530ac89a7345edc214618b25' ] ]
I have an array of ids as above , i need to update the folder field for all the records in that array.
I tried passing the id's to mongodb query as below , but still that doesn't work.
Post.native(function(err, collection) {
collection.update({
_id : {
"$in" : ids
}
}, { folder : 'X'}, {
multi : true
}, function(err, result) {
console.log(result);
});
});
Please help.
There seem to be two possible problems.
1) your ids array is not an array of ids, it's an array which has a single element which is itself an array, which has two elements. An array of ids would be `[ 'idvalue1', 'idvalue2']
2) your id values inside of arrays are strings - is that how you are storing your "_id" values? If they are ObjectId() type then they are not a string but a type ObjectId("stringhere") which is not the same type and won't be equal to "stringhere".
There is no reason to use the native method in this case. Just do:
Post.update({id : ids}, {folder : 'X'}).exec(console.log);
Waterline automatically does an "in" query when you set a criteria property to an array, and Sails-Mongo automatically translates "id" to "_id" and handles ObjectId translation for you.
Those strings look like the string representation of mongod ObjectIds, so probably what you want to do is turn them into ObjectIds before querying. Assuming you've corrected your problem with the extra level of nesting in the array, that is:
ids = ['530ac94c9ff87b5215a0d6e6', '530ac89a7345edc214618b25']
Then you want to do something like this:
oids = []
for (var i in ids)
oids.push(ObjectId(ids[i]))
db.c.find({_id: {$in: oids}})
Does that fix your problem?
I have documents like this:
db.planet.insert({
name: 'Earth',
stuff: {
'grass': 'green',
'sky': 'blue',
'sea': 'blue'
}
})
db.planet.insert({
name: 'Mars',
stuff: {
'dust': 'red',
'sky': 'yellow'
}
})
I want to find all planets that have at least some blue stuff (only earth in this case). How can I do that?
Catch: I tried solving this by using an array (instead of object) for stuff (stuff: [ { k: 'grass', v: 'green'},... ]) but I also need to be able to update (upsert to be exact) value of some stuff. For instance I must be able to do this:
db.planet.update({ name: 'Mars' }, {
'$set': {
'stuff.canals': 'brown',
'stuff.dust': 'reddish'
}
})
So, how can I find the planets with something blue on them? :)
Use the $or operator. The $or operator value should be an array, with the array containing conditions of which at least one must be true.
In your case, given the field names you have mentioned:
db.planet.find($or:[
{"stuff.sky":"blue"},
{"stuff.grass":"blue"},
{"stuff.sea":"blue"},
{"stuff.dust":"blue"},
{"stuff.canals":"blue")
])
See http://docs.mongodb.org/manual/reference/operator/or/
As there are a quite a number of different fields you want to query, you may want to keep an array of all these field names somewhere so you can generate the $or array programmatically.
I don't think there's a way to make the query without knowing the field names in advance. See mongodb query without field name .