Trying to export from a multivalued attribute "Proxyaddresses" from multiple OUs to csv. i am getting "Microsoft.ActiveDirectory.Management.ADPropertyValueCollection"
Here is my code,
Thanks
"ou=no gpo,ou=Staff, ou=offices,dc=ddddd,dc=ca",
"ou=Staff win10,dc=ddddd,dc=ca" | ForEach-Object {
Get-ADUser -Filter * -SearchBase $_ -Properties *
}| select name, #{Name=’proxyAddresses’;Expression={[string]::join(“;”, ($_.proxyAddresses))}} | Export-Csv c:\temp\all_proxyaddresses.csv -NoTypeInformation
Try this:
$a= "ou=no gpo,ou=Staff, ou=offices,dc=ddddd,dc=ca", "ou=Staff win10,dc=ddddd,dc=ca"
$a| ForEach-Object { Get-ADUser -Filter * -SearchBase $_ -Properties *}| select name, #{Name=’proxyAddresses’;Expression={$_.proxyAddresses -join ';'}} | Export-Csv c:\temp\all_proxyaddresses.csv -NoTypeInformation
Related
I want to get canonical name for each groups as well. how can I do that ?
Here is my script :
Get-ADUser -Filter {Enabled -eq $true} -Properties * | Select displayname ,#{Name="MemberOf";Expression={($_.MemberOf | %{(Get-ADGroup $_).sAMAccountName}) -Join ";"}} | Export-Csv -Path "c:\temp\users.csv" -NoTypeInformation -Encoding UTF8
My output :
"displayname","MemberOf"
"User01","Group01;Group02;Group03"
My desired output:
"displayname","MemberOf"
"User01","Group01;Contoso.com/OU1/OU2;Group02;Contoso.com/OU21/OU52;Group03;Contoso.com/OU1/OU21/OU22"
I agree with Mathias but this is how you can do it using the code you already have. Definitely recommend you to only call the properties that you need to query.
Get-ADUser -Filter {Enabled -eq $true} -Properties Displayname,MemberOf |
Select-Object Displayname,
#{
Name="MemberOf"
Expression={
# ($_.MemberOf | ForEach-Object{
# (Get-ADGroup $_ -Properties CanonicalName).CanonicalName
# }) -Join ";"
# You can pipe $_.MemberOf to Get-ADGroup, since it's an array of
# distinguishedNames it should work fine
($_.MemberOf | Get-ADGroup -Properties CanonicalName).CanonicalName -Join ";"
}
} | Export-Csv -Path "c:\temp\users.csv" -NoTypeInformation -Encoding UTF8
An alternative to that code, using a more classical approach:
$users = Get-ADUser -Filter {Enabled -eq $true} -Properties DisplayName
$result = foreach($user in $users)
{
$params = #{
LDAPFilter = "(member=$($user.DistinguishedName))"
Properties = "CanonicalName"
}
$membership = (Get-ADGroup #params).CanonicalName -join ";"
[pscustomobject]#{
DisplayName = $user.DisplayName
MemberOf = $membership
}
}
$result | Export-Csv -Path "c:\temp\users.csv" -NoTypeInformation -Encoding UTF8
First of all, you shouldn't be using Properties * when you only need two properties.
Then, the -Filter should be a string, not a scriptblock.
With just a small adaptation to your code, this should work:
Get-ADUser -Filter "Enabled -eq 'True'" -Properties DisplayName, MemberOf |
Select-Object DisplayName,
#{Name = "MemberOf"; Expression = {
($_.MemberOf | ForEach-Object {
($_ | Get-ADGroup -Properties CanonicalName).CanonicalName -Join ";" })
}
} |
Export-Csv -Path "c:\temp\users.csv" -NoTypeInformation -Encoding UTF8
Looking at your latest comment, I believe you want the group NAME joined with the canonicalname of the group as well.
You can do this like so:
Get-ADUser -Filter "Enabled -eq 'True'" -Properties DisplayName, MemberOf |
Select-Object DisplayName,
#{Name = "MemberOf"; Expression = {
$_.MemberOf | ForEach-Object {
$group = $_ | Get-ADGroup -Properties CanonicalName
'{0};{1}' -f $group.Name, ($group.CanonicalName -join ';')
}
}
} |
Export-Csv -Path "c:\temp\users.csv" -NoTypeInformation -Encoding UTF8
I have a list of users in a CSV, but I need to collect the SamAccount attribute from each user by name in the ad.
CSV model
Script
Get-ADObject -Filter 'ObjectClass -eq "user" -and userAccountControl -eq "512"' -Properties * | Select-Object SamAccountName,CN,DisplayName, | Export-CSV -Path C:\Temp\UserAccounts.csv -Encoding UTF8 -NoTypeInformation
I'm a little lost I don't know how to do a foreach using name
I am trying but without success.
Trying to get samaccountname based on Name on csv file.
Import-Csv -Path C:\Temp\userteste.csv | foreach-Object {Get-ADUser -Filter {Name -like $_.name} -Properties Name | Select-Object samAccountName}
and export to csv file.
Why use Get-ADObject and not Get-ADUser for this? The latter gives you more of the desired properties you need in the CSV.
As aside, it is wasteful to do -Properties * if all you want is a small set of user attributes.
Something like this should work:
Get-ADUser -Filter "Enabled -eq $true" -Properties DisplayName, CN |
Select-Object SamAccountName, CN, DisplayName |
Export-Csv -Path C:\Temp\UserAccounts.csv -Encoding UTF8 -NoTypeInformation
As per your comment you need to get some extra attributes of the users listed in the CSV, you can do this:
Import-Csv -Path C:\Temp\userteste.csv | ForEach-Object {
Get-ADUser -Filter "Name -like '$($_.Name)'" -Properties DisplayName, CN |
Select-Object SamAccountName, CN, DisplayName
} | Export-Csv -Path C:\Temp\UserAccounts.csv -Encoding UTF8 -NoTypeInformation
Hope that helps
I have a list with AD groups in a CSV file: Input_ADGroup.csv
Column A looks like this:
CN
ADgroup1
ADgroup2
I already have some code which list all the users of the groups in the output.csv file, however I am missing the ADgroup name. So it is unclear which users are member of which group.
$Manager = #{Name = "Manager"; Expression = {%{(Get-ADUser $_.Manager -Properties DisplayName).DisplayName}}}
$Manager_Location = #{Name = "Manager_Location"; Expression = {%{(Get-ADUser $_.Manager -Properties Office).Office}}}
$Fields = #(
'SamAccountName'
'CN'
'DisplayName'
'Office'
'mail'
'Department'
$Manager
$Manager_Location
)
Import-Csv -Path H:\Test\Input_ADGroup.csv |
ForEach-Object {
Get-ADGroup -Filter "CN -eq '$($_.CN)'" -Properties * -ErrorAction SilentlyContinue |
Get-ADGroupMember | Get-ADUser -properties * | Select $Fields
} | Export-Csv -Path H:\Test\Output_ADGroup.csv -NoTypeInformation
H:\Test\Output_ADGroup.csv
So is it possible to get a column which shows the "source-ADgroup"... or another format which breaks the list with the ADGroup name or something?
IMO my other suggested solution is more efficient applyig the same CN from the input:
$Data = ForEach($CN in (Import-Csv -Path H:\Test\Input_ADGroup.csv).CN) {
Get-ADGroup -Filter "CN -eq '$CN'" -Properties CN -ErrorAction SilentlyContinue |
Get-ADGroupMember | Get-ADUser -Properties * | Select-Object ($Fields+#{n="Group";e={$CN}})
}
$Data
$Data | Export-Csv -Path H:\Test\Output_ADGroup.csv -NoTypeInformation
As you already have AD group name in $_, you can add one more calculated property to your Select-Object by changing this:
Get-ADGroup -Filter "CN -eq '$($_.CN)'" -Properties * -ErrorAction SilentlyContinue |
Get-ADGroupMember | Get-ADUser -properties * | Select $Fields
to this (saving first group name to variable to not mix up with $_ used later in pipeline):
$GroupName = $_.CN
Get-ADGroup -Filter "CN -eq '$($_.CN)'" -Properties * -ErrorAction SilentlyContinue |
Get-ADGroupMember | Get-ADUser -properties * | Select ($Fields+#{n="Group";e={$GroupName}})
Credits to #LotPings and #Maikel for pointing out the issue with incorrect $_ usage in comments
NOTE: remember about brackets, otherwise you'd receive an error like:
Select-Object : A positional parameter cannot be found that accepts argument n="Group";e={$GroupName}
#Lotpings #robdy - Thanks for your input, I got it working so many thanks. See code below
Import-Csv -Path H:\Test\Input_ADGroup.csv |
ForEach-Object {
Get-ADGroup -Filter "CN -eq '$($_.CN)'" -Properties CN -PipelineVariable name -ErrorAction SilentlyContinue |
Get-ADGroupMember | Get-ADUser -properties * | Select ($Fields+#{n="Group";e={$name}})
} | Export-Csv -Path H:\Test\Output_ADGroup.csv -NoTypeInformation
H:\Test\Output_ADGroup.csv
One last note: The AD group gets displayed as CN=Groupname,OU=...OU=… etc
I couldn't get it to show just "Groupname" but this really is not an issue.
I have this Powershell command:
Get-ADComputer -filter { Name -like 'srv*' } | Select -Expand dnshostname | Export-CSV -path ad_export.csv
In the CSV it only writes the length of the Strings. I read that I have to pipe an object to Export-CSV so it writes the Servernames and not only the length. How do I do that?
Based on the requirement , you can use :
Get-ADComputer -Filter 'ObjectClass -eq "Computer"' | Select -Expand DNSHostName | Export-CSV -path ad_export.csv
# Getting just the hostname
Get-ADComputer -Filter * | Select -Expand Name | Export-CSV -path ad_export.csv
# Getting a specific computer
Get-ADComputer -Filter { Name -eq 'server2012' } -Propert LastLogonTimestamp | Select DistinguishedName, LastLogonTimestamp | Format-Table -AutoSize | Export-CSV -path ad_export.csv
Note: You can use the "where" clause also if required.
Hope This suffice your need
I am trying to export all groups and the members assigned (if any) for a given OU. How do I include groups with no members?
Get-ADGroup -Properties * -Filter * -SearchBase "OU=BI-Security,OU=BH-Security Groups,DC=bh,DC=intra" | Foreach {
$Group = $_
Get-ADGroupMember -Id $Group | `
select #{Expression={$Group.Name};Label="Group Name"},Name | `
Export-CSV C:\Scripts\BIGroups.CSV -NoTypeInformation -append
}
Thanks in advance.
Call Get-ADGroupMember inside a calculated property with Select-Object:
$groups = Get-ADGroup -Filter * -SearchBase 'OU=BI-Security,OU=BH-Security Groups,DC=bh,DC=intra'
$groups |Select-Object #{Expression={$_.Name};Label='Group Name'},#{Expression={#(Get-ADGroupMember -Identity $_|Select -Expand Name) -join ';'};Label='Name'} | Export-CSV C:\Scripts\BIGroups.CSV -NoTypeInformation -append