PowerShell extract each zip file to own folder - powershell

Question

I would like to unzip some files each into their own folder with the same name as the zip file. I have been doing clunky things like this, but as this is PowerShell, there is usually a much smarter way to achieve things.
Are there some kind of one-or-two-liner ways that I can operate on each zip file in a folder and extract it into a subfolder of the same name as the zip (but without the extension)?
foreach ($i in $zipfiles) {
$src = $i.FullName
$name = $i.Name
$ext = $i.Extension
$name_noext = ($name -split $ext)[0]
$out = Split-Path $src
$dst = Join-Path $out $name_noext
$info += "`n`n$name`n==========`n"
if (!(Test-Path $dst)) {
New-Item -Type Directory $dst -EA Silent | Out-Null
Expand-Archive -LiteralPath $src -DestinationPath $dst -EA Silent | Out-Null
}
}

Answer 1

You could do with a few less variables. When the $zipfiles collection contains FileInfo objects as it appears, most variables can be replaced by using the properties the objects already have.
Also, try to avoid concatenating to a variable with += because that is both time and memory consuming.
Just capture the result of whatever you output in the loop in a variable.
Something like this:
# capture the stuff you want here as array
$info = foreach ($zip in $zipfiles) {
# output whatever you need to be collected in $info
$zip.Name
# construct the folderpath for the unzipped files
$dst = Join-Path -Path $zip.DirectoryName -ChildPath $zip.BaseName
if (!(Test-Path $dst -PathType Container)) {
$null = New-Item -ItemType Directory $dst -ErrorAction SilentlyContinue
$null = Expand-Archive -LiteralPath $zip.FullName -DestinationPath $dst -ErrorAction SilentlyContinue
}
}
# now you can create a multiline string from the $info array
$result = $info -join "`r`n==========`r`n"