Swift: How to check intersection with multiple sets? - swift

Question

I have a master set generated by 5 random numbers from 1 to 52; I would like to compare this master set with 13 other sets, each containing 4 numbers between 1 and 52.
Is there a way to check if there are any 2 sets, each containing 2 numbers from the master set?
import UIKit
var firstCard = 0
var secondCard = 0
var thirdCard = 0
var fourthCard = 0
var fifthCard = 0
func generateRandomNumber(_ from:Int, _ to:Int, _ qut:Int?) -> [Int]
{
var myRandomNumbers = [Int]()
var numberOfNumbers = qut
let lower = UInt32(from)
let higher = UInt32(to+1)
if numberOfNumbers == nil || numberOfNumbers! > (to-from) + 1
{
numberOfNumbers = (to-from) + 1
}
while myRandomNumbers.count != numberOfNumbers
{
let myNumber = arc4random_uniform(higher - lower) + lower
if !myRandomNumbers.contains(Int(myNumber))
{
myRandomNumbers.append(Int(myNumber))
}
}
return myRandomNumbers
}
let myArray = generateRandomNumber(1, 53, 5)
firstCard = myArray[0]
secondCard = myArray[1]
thirdCard = myArray[2]
fourthCard = myArray[3]
fifthCard = myArray[4]
let mainSetA = Set([firstCard, secondCard, thirdCard, fourthCard, fifthCard])
let setB: Set = [1, 2, 3, 4]
let setC: Set = [5, 6, 7, 8]
let setD: Set = [9, 10, 11, 12]
let setE: Set = [13, 14, 15, 16]
let setF: Set = [17, 18, 19, 20]
let setG: Set = [21, 22, 23, 24]
let setH: Set = [25, 26, 27, 28]
let setI: Set = [29, 30, 31, 32]
let setJ: Set = [33, 34, 35, 36]
let setK: Set = [37, 38, 39, 40]
let setL: Set = [41, 42, 43, 44]
let setM: Set = [45, 46, 47, 48]
let setN: Set = [49, 50, 51, 52]
no clue what to do next...

Answer 1

Something like this might help:
let mainSet = Set([1, 2, 3, 4])
Here I have three sets out of four that contain at least two items in the main set:
let inputs: [Set<Int>] = [
Set([9, 8, 7, 1]),
Set([9, 8, 1, 2]),
Set([9, 1, 2, 3]),
Set([9, 0, 3, 4])
]
Filter the input sets array, to find any where the intersection between that set and the main set is at least 2:
let matchingSets = inputs.filter {
$0.intersection(mainSet).count >= 2
}