I copied some code from the web and I had these lines
File image;
...
image.writeAsBytesSync(result);
But I had to change image type to XFile. Is there a way to do the same operation with XFile class?
A simple work-around like this will work:
XFile image;
...
File file = File(image.path);
file.writeAsBytesSync(result);
image = XFile(file.path);
Related
I'm trying to crop an image, I used ImageCropper().
CroppedFile? croppedFile = await ImageCropper().cropImage(sourcePath: file.path);
How to convert this croppedFile into File?
Use the path property of the CroppedFile class to give you the file path as a string. Convert this path to a file type using File(), like so...
yourFile = File(croppedFile!.path);
I want to make the following code work and I do not understand image conversion properly. Would really like someone to point me the right direction to learn this please along with providing a solution to my following problem.
I display the image as a container background image using:
MemoryImage(base64Decode(image)) // My image is in base64 String format here
The above works fine.
Now I have an image path: example-
'/data/user/0/....../cache/scaled_image_picker2751194612758734223.jpg'
How do I go from getting image from this path to base64Encode(image)?
I tried the following up to now and have run out of ideas here:
final Image? image = await Image.file(File(_imagePath));
if (image != null){
setState(() => imageDisplayInContainer = base64Encode(image)); <----Doesn't work
}
Get the file object:
File imageFile = File(_imagePath);
Get the bytes:
List<int> imageBytes = imageFile.readAsBytesSync();
Give the bytes the MemoryImage
MemoryImage(imageBytes);
I'm trying with two different images with same name. But the path was same for two picked images. it was not unique.So that I uploaded in server second image with the same name of first uploaded image. But server had both the image are same and it had first image. So how to handle this case and customize the path?
You can use the path_provider to define the customize directory on your app.
So, copy the file with your customize path and rename the file name.
BTW, do NOT save the absolute path of File on iOS.
The iOS use SandBox to access the file. When you get the file path every time. The file path will be different.
class FileUtils {
final String avatarPath = '/avatar/';
Future<String> getAvatarDirectoryPath() async {
final String appDirPath = await getApplicationSupportDirectory().path;
final Directory avatarDirPath = await Directory(appDirPath + avatarPath).create();
return directory.path;
}
}
// Example
{
final XFile? image = await ImagePicker().pickImage(source: ImageSource.camera);
final File imageFile = File(image.path);
final File newFile = File(await FileUtils().getAvatarDirectoryPath() + 'userAvatar.png');
await imageFile.copy(newFile.path);
}
I am using image picker to pick image from device(App) and after that stored that file in provider class like that.
File? _img;
get img=> _img;
void putbannerimg(File img) {
_img = img;
notifyListeners();
}
I found out that image picker does not compress png images, I tried compressing it with flutter_image_compress
compressFile() async {
final formservice = Provider.of<PostForm>(context, listen: false);
File file = formservice.bannerfile;
final result = await FlutterImageCompress.compressWithFile(
file.absolute.path,
quality: 54,
);
formservice.putbannerimg(File.fromRawPath(result!));
}
I tried this way And other multiple ways but getting different different errors I want to upload this file in firebase storage like this
var task = storageicon.putFile(formservice.iconfile);
please tell me where I am going wrong, without compress file all things are working fine
Edit: I found out that path should be a string how can I parse local code file in that
If you are using the "flutter_image_compress" package
You may have to use the compress function for files stored on the phone like this:
Future<File> testCompressAndGetFile(File file, String targetPath) async {
var result = await FlutterImageCompress.compressAndGetFile(
file.absolute.path, targetPath,
quality: 88,
rotate: 180,
);
print(file.lengthSync());
print(result.lengthSync());
return result;
}
"compressAndGetFile()" returns a file while "compressWithFile()" returns a Uint8List.
If i understand your last question right, you want to use an image built into your application by default.
For this, you have to open your "pubsepc.yaml", go to the "flutter:" mark and add "assets:" like so:
flutter:
assets:
- path
"path", in my example, describes a top level folder containing assets like pictures.
You can freely describe its name.
I'm trying to do some pre-processing in my image before using Firebase MLkit. Previously, I was simply loading my image and then passing it directly like this.
File file = await FilePicker.getFile(type: FileType.IMAGE);
final FirebaseVisionImage visionImage = FirebaseVisionImage.fromFile(file);
VisionText visionText = await textRecognizer.processImage(visionImage);
But now, I wanted to do some processing on the image. I did this using Flutter's Image package like this.
import 'package:image/image.dart' as Img;
File file = await FilePicker.getFile(type: FileType.IMAGE);
Img.Image image = Img.decodeImage(file.readAsBytesSync());
var img = Img.invert(image);
Now, how do I pass this new object to FirebaseVisionImage. I see that there is this function:
FirebaseVisionImage.fromBytes(bytes, metadata)
I'm guessing I can get bytes from the above image object using img.getBytes() but I'm confused how to set the metadata.
EDIT:
I see that one can write the image to a temporary file doing
img.writeAsBytesSync(decoded.ToList());
and then use that image again using FirebaseVisionImage.fromFile() but I would really prefer not to do that.