Syntax to remove the single coutes in temp table column in db2 - db2

EX:
table employee column below
EmpID
'10001'
expected result:
EmpID
10001

Try this:
select
empid
, translate (empid, '', '''') as empid_new
from (values '''1001''') employee (empid)
The result is:
EMPID
EMPID_NEW
'1001'
1001

Related

Postgresql: Concatenate 2 columns data into 1 column

I am migrating the data from one DB to another (both postgresql). I want to concatenate the value of firstname and lastname columns from the source DB to name column of the destination DB. When I try to run the query, I am getting an error: psycopg2.ProgrammingError: more than one row returned by a subquery used as an expression Checking other threads here in SO, I found this concatenate. I added LIMIT 1 to the code but it gives me the first and last name of the existing name in the table.
My code:
cur_t.execute("""
SELECT firstname, lastname
FROM authors;
""")
for row in cur_t:
cur_p.execute("""
INSERT INTO lib_author (
created, modified, last_name,
first_name, country,
school_id, name)
VALUES (current_timestamp, current_timestamp, %s, %s, %s,
(SELECT id FROM ed_school WHERE name='My Test School'),
(SELECT CONCAT(first_name, ',', last_name) AS name FROM lib_author LIMIT 1)
)
""", (row['lastname'], row['firstname'], ''))
How can I call the firstname and lastname column from the source DB?

Microsoft TSQL change text row to column

I want to change the 20 rows with one column to 1 row with 20 columns to insert it later in a second database
Name
----------
- Frank
- Dora
- ...
- Michael
to
Name1 | Name2 | ... | Name20
Frank | Dora | ... | Michael
I tried
SELECT *
FROM (SELECT TOP 20 firstname AS NAME
FROM database) AS d
PIVOT (Min(NAME)
FOR NAME IN (name1,
name2,
name3,
name4,
name5,
name6,
name7,
name8,
name9,
name10,
name11,
name12,
name13,
name14,
name15,
name16,
name18,
name19,
name20) ) AS f
But all names are NULL. DEMO
You were close... But your inner select must carry the new column name. Try it like this:
DECLARE #tbl TABLE(Name VARCHAR(100));
INSERT INTO #tbl VALUES('Frank'),('Dora'),('Michael');
SELECT p.*
FROM
(
SELECT 'Name' + CAST(ROW_NUMBER() OVER(ORDER BY Name) AS VARCHAR(150)) AS ColumnName
,Name
From #tbl
) AS tbl
PIVOT
(
MIN(Name) FOR ColumnName IN(Name1,Name2,Name3)
) AS p

Quotation mark incorrect when using crosstab() in PostgreSQL

I have a table t1 as below:
create table t1 (
person_id int,
item_name varchar(30),
item_value varchar(100)
);
There are five records in this table:
person_id | item_name | item_value
1 'NAME' 'john'
1 'GENDER' 'M'
1 'DOB' '1970/02/01'
1 'M_PHONE' '1234567890'
1 'ADDRESS' 'Some Addresses unknown'
Now I want to use crosstab function to extract NAME, GENDER data, so I write a SQL as:
select * from crosstab(
'select person_id, item_name, item_value from t1
where person_id=1 and item_name in ('NAME', 'GENDER') ')
as virtual_table (person_id int, NAME varchar, GENDER varchar)
My problem is, as you see the SQL in crosstab() contains condition of item_name, which will cause the quotation marks to be incorrect.
How do I solve the problem?
To avoid any confusion about how to escape single quotes and generally simplify the syntax, use dollar-quoting for the query string:
SELECT *
FROM crosstab(
$$
SELECT person_id, item_name, item_value
FROM t1
WHERE person_id = 1
AND item_name IN ('NAME', 'GENDER')
$$
) AS virtual_table (person_id int, name varchar, gender varchar);
See:
Insert text with single quotes in PostgreSQL
And you should add ORDER BY to your query string. I quote the manual for the tablefunc module:
In practice the SQL query should always specify ORDER BY 1,2 to ensure
that the input rows are properly ordered, that is, values with the
same row_name are brought together and correctly ordered within the
row. Notice that crosstab itself does not pay any attention to the
second column of the query result; it's just there to be ordered by,
to control the order in which the third-column values appear across the page.
See:
PostgreSQL Crosstab Query
Double your single quotes to escape them:
select * from crosstab(
'select person_id, item_name, item_value from t1
where person_id=1 and item_name in (''NAME'', ''GENDER'') ')
as virtual_table (person_id int, NAME varchar, GENDER varchar)

one column split to more column sql server 2008?

Table name: Table1
id name
1 1-aaa-14 milan road
2 23-abcde-lsd road
3 2-mnbvcx-welcoome street
I want the result like this:
Id name name1 name2
1 1 aaa 14 milan road
2 23 abcde lsd road
3 2 mnbvcx welcoome street
This function ought to give you what you need.
--Drop Function Dbo.Part
Create Function Dbo.Part
(#Value Varchar(8000)
,#Part Int
,#Sep Char(1)='-'
)Returns Varchar(8000)
As Begin
Declare #Start Int
Declare #Finish Int
Set #Start=1
Set #Finish=CharIndex(#Sep,#Value,#Start)
While (#Part>1 And #Finish>0)Begin
Set #Start=#Finish+1
Set #Finish=CharIndex(#Sep,#Value,#Start)
Set #Part=#Part-1
End
If #Part>1 Set #Start=Len(#Value)+1 -- Not found
If #Finish=0 Set #Finish=Len(#Value)+1 -- Last token on line
Return SubString(#Value,#Start,#Finish-#Start)
End
Usage:
Select ID
,Dbo.Part(Name,1,Default)As Name
,Dbo.Part(Name,2,Default)As Name1
,Dbo.Part(Name,3,Default)As Name2
From Dbo.Table1
It's rather compute-intensive, so if Table1 is very long you ought to write the results to another table, which you could refresh from time to time (perhaps once a day, at night).
Better yet, you could create a trigger, which automatically updates Table2 whenever a change is made to Table1. Assuming that column ID is primary key:
Create Table Dbo.Table2(
ID Int Constraint PK_Table2 Primary Key,
Name Varchar(8000),
Name1 Varchar(8000),
Name2 Varchar(8000))
Create Trigger Trigger_Table1 on Dbo.Table1 After Insert,Update,Delete
As Begin
If (Select Count(*)From Deleted)>0
Delete From Dbo.Table2 Where ID=(Select ID From Deleted)
If (Select Count(*)From Inserted)>0
Insert Dbo.Table2(ID, Name, Name1, Name2)
Select ID
,Dbo.Part(Name,1,Default)
,Dbo.Part(Name,2,Default)
,Dbo.Part(Name,3,Default)
From Inserted
End
Now, do your data manipulation (Insert, Update, Delete) on Table1, but do your Select statements on Table2 instead.
The below solution uses a recursive CTE for splitting the strings, and PIVOT for displaying the parts in their own columns.
WITH Table1 (id, name) AS (
SELECT 1, '1-aaa-14 milan road' UNION ALL
SELECT 2, '23-abcde-lsd road' UNION ALL
SELECT 3, '2-mnbvcx-welcoome street'
),
cutpositions AS (
SELECT
id, name,
rownum = 1,
startpos = 1,
nextdash = CHARINDEX('-', name + '-')
FROM Table1
UNION ALL
SELECT
id, name,
rownum + 1,
nextdash + 1,
CHARINDEX('-', name + '-', nextdash + 1)
FROM cutpositions c
WHERE nextdash < LEN(name)
)
SELECT
id,
[1] AS name,
[2] AS name1,
[3] AS name2
/* add more columns here */
FROM (
SELECT
id, rownum,
part = SUBSTRING(name, startpos, nextdash - startpos)
FROM cutpositions
) s
PIVOT ( MAX(part) FOR rownum IN ([1], [2], [3] /* extend the list here */) ) x
Without additional modifications this query can split names consisting of up to 100 parts (that's the default maximum recursion depth, which can be changed), but can only display no more than 3 of them. You can easily extend it to however many parts you want it to display, just follow the instructions in the comments.
select T.id,
substring(T.Name, 1, D1.Pos-1) as Name,
substring(T.Name, D1.Pos+1, D2.Pos-D1.Pos-1) as Name1,
substring(T.Name, D2.Pos+1, len(T.name)) as Name2
from Table1 as T
cross apply (select charindex('-', T.Name, 1)) as D1(Pos)
cross apply (select charindex('-', T.Name, D1.Pos+1)) as D2(Pos)
Testing performance of suggested solutions
Setup:
create table Table1
(
id int identity primary key,
Name varchar(50)
)
go
insert into Table1
select '1-aaa-14 milan road' union all
select '23-abcde-lsd road' union all
select '2-mnbvcx-welcoome street'
go 10000
Result:
if you always will have 2 dashes, you can do the following by using PARSENAME
--testing table
CREATE TABLE #test(id INT, NAME VARCHAR(1000))
INSERT #test VALUES(1, '1-aaa-14 milan road')
INSERT #test VALUES(2, '23-abcde-lsd road')
INSERT #test VALUES(3, '2-mnbvcx-welcoome street')
SELECT id,PARSENAME(name,3) AS name,
PARSENAME(name,2) AS name1,
PARSENAME(name,1)AS name2
FROM (
SELECT id,REPLACE(NAME,'-','.') NAME
FROM #test)x
if you have dots in the name column you have to first replace them and then replace them back to dots in the end
example, by using a tilde to substitute the dot
INSERT #test VALUES(3, '5-mnbvcx-welcoome street.')
SELECT id,REPLACE(PARSENAME(name,3),'~','.') AS name,
REPLACE(PARSENAME(name,2),'~','.') AS name1,
REPLACE(PARSENAME(name,1),'~','.') AS name2
FROM (
SELECT id,REPLACE(REPLACE(NAME,'.','~'),'-','.') NAME
FROM #test)x

Finding duplicate rows but skip the last result?

I am trying to find duplicate rows in my DB, like this:
SELECT email, COUNT(emailid) AS NumOccurrences
FROM users
GROUP BY emailid HAVING ( COUNT(emailid) > 1 )
This returns the emailid and the number of matches found. Now what I want do is compare the ID column to another table I have and set a column there with the count.
The other table has a column named duplicates, which should contain the amount of duplicates from the select. So let's say we have 3 rows with the same emailid. The duplicates column has a "3" in all 3 rows. What I want is a "2" in the first 2 and nothing or 0 in the last of the 3 matching ID rows.
Is this possible?
Update:
I managed to have a temporary table now, which looks like this:
mailid | rowcount | AmountOfDups
643921 | 1 | 3
643921 | 2 | 3
643921 | 3 | 3
Now, how could I decide that only the first 2 should be updated (by mailid) in the other table? The other table has mailid as well.
SELECT ...
ROW_NUMBER() OVER (PARTITION BY email ORDER BY emailid DESC) AS RN
FROM ...
...is a great starting point for such a problem. Never underestimate the power of ROW_NUMBER()!
Using Sql Server 2005+ you could try something like (full example)
DECLARE #Table TABLE(
ID INT IDENTITY(1,1),
Email VARCHAR(20)
)
INSERT INTO #Table (Email) SELECT 'a'
INSERT INTO #Table (Email) SELECT 'b'
INSERT INTO #Table (Email) SELECT 'c'
INSERT INTO #Table (Email) SELECT 'a'
INSERT INTO #Table (Email) SELECT 'b'
INSERT INTO #Table (Email) SELECT 'a'
; WITH Duplicates AS (
SELECT Email,
COUNT(ID) TotalDuplicates
FROM #Table
GROUP BY Email
HAVING COUNT(ID) > 1
)
, Counts AS (
SELECT t.ID,
ROW_NUMBER() OVER(PARTITION BY t.Email ORDER BY t.ID) EmailID,
d.TotalDuplicates
FROM #Table t INNER JOIN
Duplicates d ON t.Email = d.Email
)
SELECT ID,
CASE
WHEN EmailID = TotalDuplicates
THEN 0
ELSE TotalDuplicates - 1
END Dups
FROM Counts