I have a LocalDateTime object and I would like to format this, to have printouts like:
Tue 23. Nov. Therefore, I used a DateTimeFormatter like:
val formatter: DateTimeFormatter = DateTimeFormatter.ofPattern("e dd. LLL")
But unfortunately I get Tue 23. 11 The month is a number and no letters!?
The correct format pattern string is E dd. MMM. Excuse my Java syntax.
private static final DateTimeFormatter DATE_FORMATTER
= DateTimeFormatter.ofPattern("E dd. MMM", Locale.ENGLISH);
Also remember to specify desired locale for your formatter.
Trying it out:
LocalDate date = LocalDate.of(2021, Month.NOVEMBER, 23);
String formatted = date.format(DATE_FORMATTER);
System.out.println(formatted);
Output is the desired:
Tue 23. Nov
Spelling out how my format pattern is different:
I am using upper case E for the abbreviation of the day of week. Lower case e should give you the number of the day of week like 2 for Tuesday. eee should work for the abbreviation too.
I am using MMM for the abbreviation of the month. LLL is for the standalone form. Some languages use a different form of the month depending on whether the day of month is present or not. A language may for example use the nominative for the month alone and the genetive with a day number, a bit the differene between November and of November. Since you have the day included, you should not use pattern letter L here. Funnily for some languages that have not got a stand-alone form (like English), Java gives you the number instead when you specify LLL.
Edit: you asked:
How would that look for "November" fully written out? "MMM" works for
"Dec."
The documentation that you linked to in another comment gives the answer:
Text: The text style is determined based on the number of pattern letters used. Less than 4 pattern letters will use the short form.
Exactly 4 pattern letters will use the full form. …
So use MMMM instead of MMM:
private static final DateTimeFormatter DATE_FORMATTER
= DateTimeFormatter.ofPattern("E dd. MMMM", Locale.ENGLISH);
Tue 23. November
Documentation link: DateTimeFormatter
Related
I am using intl pakage's DateFormat class to format dates with a format like this:
_standardDateFormat = DateFormat('MMM dd, yyyy');
This produces strings like Feb 01, 2023.
How can I have the date without the prefix of 0 when it's a single-digit date? I would like to show Feb 1, 2023. I have tried d, dd, c but they all render with the prefixed 0.
If it's a double-digit date, I would of course like to show both digits: Mar 13, 2023.
Update: the single d format is indeed working, but I needed to restart flutter build to see the effect (not sure why).
need some suggestions on below requirement.
Each response help a lot thanks in advance....
I have a date of type String with timestamp ex: Jan 8 2019 4:44 AM
My requirement is if the date is single digit I want date to be 1 space and digit
(ex: 8) and if the date is 2 digits which is dates from 10 to 31 I want date with no space(ex:10) and also same for hour in timestamp.
to summarize: if the date is 1 to 9 and hour in timestamp is 1 to 9 looking for below string
Jan 8 2019 4:44 AM
if the date is 10 to 31 and hour in timestamp is 10 to 12 looking for below string
Jan 18 2019 12:44 AM
right now I am creating a date in following way:
val sdf = new SimpleDateFormat("MMM d yyyy h:mm a")
but the above format satisfies only one condition which is dates from 1 to 9.
my application is spark with scala so looking for some spark scala code or java.
I appreciate your help...
Thanks..
java.time
Use p as a pad modifier in the format pattern string. In Java syntax (sorry):
DateTimeFormatter formatter = DateTimeFormatter.ofPattern(
"MMM ppd ppppu pph:mm a", Locale.ENGLISH);
System.out.println(LocalDateTime.of(2019, Month.JANUARY, 8, 4, 44)
.format(formatter));
System.out.println(LocalDateTime.of(2019, Month.JANUARY, 18, 0, 44)
.format(formatter));
Jan 8 2019 4:44 AM
Jan 18 2019 12:44 AM
And do yourself the favour: Forget everything about the SimpleDateFormat class. It is notoriously troublesome and fortunately long outdated. Use java.time, the modern Java date and time API.
Link: Oracle tutorial: Date Time explaining how to use java.time.
To quote the DateTimeFormatter class documentation:
Pad modifier: Modifies the pattern that immediately follows to be padded with spaces. The pad width is determined by the number of pattern letters. This is the same as calling DateTimeFormatterBuilder.padNext(int).
For example, 'ppH' outputs the hour-of-day padded on the left with spaces to a width of 2.
I'm trying to insert date field in MS Word that will display tomorrow's date we one opens the document.
I can insert Today's date {DATE \# "dd/MM/yyyy"}, can we insert tomorrow's date using modified formula?
Thanks
Without VBA, the calculation is possible, but not straightforward, because the Word field language has very limited support for date-related operations.
Originally I thought Word would auto-update the DATE when you open or close/re-open the document, but further experiments suggest that even the second suggestion in here will not do that.
In the specific case described (add 1 day), you should be able to use the following field coding:
{QUOTE {SET xxx { DATE }}{SET yyy {xxx \#YYYY}}{SET mmm {xxx \#M}}{SET xxx1 {={xxx \#YYYYMMDD}+1 \#0000'-'00'-'00}}{=13-{xxx1 \#M} \#"'{xxx1}';'{=mmm-11 \#'{=yyy+1}-01-01';'{yyy}-{=mmm+1 \#00'-01'}'"}'"} \#DD/MM/YYYY}
All the {} must be the special field code brace pairs that you can insert on Windows Word using ctrl-F9, and (typically) on Mac Word using cmd-F9 or fn-cmd-F9, depending on your keyboard setup. You can change the format at the end ("\#DD/MM/YYYY" ) as required.
However, that set of field codes probably will not be updated automatically by Word when you open the document, so the user would need to select the field codes and press F9.
I originally thought Word would update the date on open and/or close/re-open using the following coding, but I now believe I was wrong. The one thing it does achieve on recent versions of Windows Word is to present the Date field in a "bubble" with an option to update the field:
{DATE \#"'{QUOTE {SET xxx { DATE }}{SET yyy {xxx \#YYYY}}{SET mmm {xxx \#M}}{SET xxx1 {={xxx \#YYYYMMDD}+1 \#0000'-'00'-'00}}{=13-{xxx1 \#M} \#"'{xxx1}';'{=mmm-11 \#'{=yyy+1}-01-01';'{yyy}-{=mmm+1 \#00'-01'}'"}'"} \#DD/MM/YYYY}'"}
Here is some pseudocode for the algorithm:
Set xxx to the date.
Set yyy to the 4-digit year
Set mmm to the month
Set xxx1 to the date but with the day number incremented by 1. e.g., for 2016-12-31, that would be a string, "2106-12-32"
This is the tricky bit:
Try to extract the month from that date using { xxx1 \#M }. If the date is valid, { xxx1 \#M } will return a valid month number, i.e. in the range 1 to 12. If the date is not valid, { xxx1 \#M } will return xxx1, e.g. "2106-12-32", which the { = } field will treat as a calculation, i.e. "year-(a maximum of 12+32=44)", so it is always going to return a number larger than 12.
If xxx1 is a valid date then
result=xxx1
Else 'xxx1 is not a valid date so...
If mmm (the original month) is 12 then
result = "(yyy+1)-01-01"
Else
result = "yyy-(mmm+1)-01"
End If
End If
Apply the date format you want to "result".
NB, this also relies on the assumption that Word always correctly recognises the month and day when you specify a date in the format "YYYY-MM-DD", regardless of the locale, in other words that "2016-04-01" is always recognised as 01 April 2016, never as 04 January 2016. If anyone can provide a counter-example, then the assumption is wrong, the field coding will need to change, and will probably need to be locale-dependent.
I'm trying to use joda-time to parse a date string of the form YYYY-MM-DD. I have test code like this:
DateTimeFormatter dateDecoder = DateTimeFormat.forPattern("YYYY-MM-DD");
DateTime dateTime = dateDecoder.parseDateTime("2005-07-30");
System.out.println(dateTime);
Which outputs:
2005-01-30T00:00:00.000Z
As you can see, the DateTime object produced is 30 Jan 2005, instead of 30 July 2005.
Appreciate any help. I just assumed this would work because it's one of the date formats listed here.
The confusion is with what the ISO format actually is. YYYY-MM-DD is not the ISO format, the actual resulting date is.
So 2005-07-30 is in ISO-8601 format, and the spec uses YYYY-MM-DD to describe the format. There is no connection between the use of YYYY-MM-DD as a pattern in the spec and any piece of code. The only constraint the spec places is that the result consists of a 4 digit year folowed by a dash followed by a 2 digit month followed by a dash followed by a two digit day-of-month.
As such, the spec could have used $year4-$month2-$day2, which would equally well define the output format.
You will need to search and replace any input pattern to convert "Y" to "y" and "D" to "d".
I've also added some enhanced documentation of formatting.
You're answer is in the docs: http://www.joda.org/joda-time/apidocs/org/joda/time/format/DateTimeFormat.html
The string format should be something like: "yyyy-MM-dd".
The date format described in the w3 document and JodaTime's DateTimeFormat are different.
More specifically, in DateTimeFormat, the pattern DD is for Day in year, so the value for DD of 30 is the 30th day in the year, ie. January 30th. As the formatter is reading your date String, it sets the month to 07. When it reads the day of year, it will overwrite that with 01 for January.
You need to use the pattern strings expected by DateTimeFormat, not the ones expected by the w3 dat and time formats. In this case, that would be
DateTimeFormatter dateDecoder = DateTimeFormat.forPattern("yyyy-MM-dd");
date.parse() method of groovy detects date DD and year yyyy correctly but is unable to detect the month as mmm.. As in
println new Date().parse("DD-MMM-yyyy", '22-MAR-2011')
yields output as
Sat Jan 22 00:00:00 GMT+05:30 2011
Why is the month march as MAR picked up as Jan? What can I do to make it detect the month in mmm format?
The problem is actualy that you are using DD - that means day in year
Correct way:
println new Date().parse("dd-MMM-yyyy", '22-MAR-2011')
Quick tip when formatting dates try using the reverse and see what comes out:
println new Date().format("dd-MMM-yyyy")
Groovy uses SimpleDateFormat under the hood but that's not that important since most date libraries use the same format conventions.