I want to add text after exactly 20 characters inklusiv blanks. Does someone have a short solution with add-content or can post a link where i can read about a way to do so.
My file looks somthing like this:
/path1/path1/path1 /path2/path2/path2 /path3/path3/path3
than an application will read this pahts (not my application and i can not edit it in any way) the application will read these paths and it will read them on their position so if the second path starts 10 characters later it wont recognize it, so i can not simply replace the path or edit it easy sinc the path has not always the same lenght. Why the application reads it that way dont ask me.
So i need to add a string at start than the next string at exactly character 20 and than the next at charcter 40.
You could use the regex -replace operator to inject a new substring after 20 characters:
PS ~> $inject = "Hello Manuel! ..."
PS ~> $string = "Injected text goes: and then there's more"
PS ~> $string -replace '(?<=^.{20})',$inject
Injected text goes: Hello Manuel! ...and then there's more
The regex pattern (?<=^.{20}) describes a position in the string where exactly 20 characters occur between the start of the string and the current position, and the -replace operator then replaces the empty string at said position with the value in $inject
This did it for me
$data.PadRight(20," ") | Out-File -FilePath F:\test\path.txt -NoNewline -Append
Related
I have looked at this question, and it's close to what I need to do, but the text I need to replace is inconsistent.
I need to replace "`r`n with ", but only the first of the 2 adjacent lines
example: (the full file is 50k lines and up to 500 chars wide)
ID,Name,LinkedRecords
54429,Abe,
54247,Jonathan,"
63460|63461"
54249,Teresa,
54418,Cody,
58046,Joseph,
58243,David,
,Barry,"
74330"
C8876,Simon,
X_10934,David,
should become
ID,Name,LinkedRecords
54429,Abe,
54247,Jonathan,"63460|63461"
54249,Teresa,
54418,Cody,
58046,Joseph,
58243,David,
,Barry,"74330"
C8876,Simon,
X_10934,David,
I can see this will probably be useful, but I'm having a hard time getting the command to work as desired
If the `r`n characters are literal, then you can do the following:
[System.IO.File]::ReadAllText('c:\path\file.txt') -replace '(?<=,")`r`n\r?\n' |
Set-Content c:\path\file.txt
If `r`n are actual carriage return and line feed chars, then you can do the following:
[System.IO.File]::ReadAllText('c:\path\file.txt') -replace '(?<=,")\r\n' |
Set-Content c:\path\file.txt
Note if memory becomes an issue, a different approach may be needed.
If I run the below code, $SRN can be written as output or added to another variable, but trying to include either another variable or regular text causes it to be overwritten from the beginning of the line. I'm assuming it's something to do with how I'm assigning $autocode and $SRN initially but can't tell what it's trying to do.
# Load the property set to allow us to get to the email body.
$item.load($psPropertySet) # Load the data.
$bod = ($item.Body.Text -creplace '(?m)^\s*\r?\n','') -split "\n" # Get the body text, remove blank lines, split on line breaks to create an array (otherwise it is a single string).
$autocode = $bod[4].split('-')[2] # Get line 4 (should be Title), split on dash, look for 3rd element, this should contain our automation code.
$SRN = $bod[1] -replace 'ID: ','' # Get line 2 (should be ID), find and replace the preceding text.
# Skip processing if autocode does not match our list of handled ones.
if ($autocode -cin $autocodes)
{
write-host "$SRN $autocode"
write-host "$autocode $SRN"
write-host "$SRN test"
$var = "$SRN $autocode"
$var
}
The code results in this, you can see if $SRN isn't at the start of the line it is fine. Unsure where the extra spaces come from either:
KRNE8385
KRNE SR1788385
test8385
KRNE8385
I would expect to see this:
SR1788385 KRNE
KRNE SR1788385
SR1788385 test
SR1788385 KRNE
LotPings pointed me down the right path, both variables still had either "0D" or "\r" in them. My regex replace was only getting rid of them on blank lines, and I split the array on "\n" only. Changing line 3 in the original code to the below appears to have resolved the issue. First time seeing Format-Hex, but it appears to be excellent for troubleshooting such issues.
$bod = ($item.Body.Text -creplace '(?m)^\s*\r?\n','') -split "\r\n"
I am using PowerShell and I need replace a line in a .txt file.
The .txt file always has different number at the end of the line.
For example:
...............................txt (first)....................................
appversion= 10.10.1
............................txt (a second time)................................
appversion= 10.10.2
...............................txt (third)...................................
appversion= 10.10.5
I need to replace appversion + number behind it (the number is always different). I have set the required value in variable.
How do I do this?
Part of this issue you are getting, which I see from your comments, is that you are trying to replace text in a file and saved it back to the same file while you are still reading it.
I will try to show a similar solution while addressing this. Again we are going to use -replaces functionality as an array operator.
$NewVersion = "Awesome"
$filecontent = Get-Content C:\temp\file.txt
$filecontent -replace '(^appversion=.*\.).*',"`$1$NewVersion" | Set-Content C:\temp\file.txt
This regex will match lines starting with "appversion=" and everything up until the last period. Since we are storing the text in memory we can write it back to the same file. Change $NewVersion to a number ... unless that is your versioning structure.
Not sure about what numbers you are keeping
About which part of the numbers, if any, you are trying to preserve. If you intend to change the whole number then you can just .*\. to a space. That way you ignore everything after the equal sign.
Yes, you can with regex.
Let call $myString and $verNumber the variables with text and version number
$myString = "appversion= 10.10.1";
$verNumber = 7;
You can use -replace operator to get the version part and replace only last subversion number this way
$mystring -replace 'appversion= (\d+).(\d+).(\d+)', "appversion= `$1.`$2.$verNumber";
I have a file containing a few thousand lines of text. I need to extract some data from it,
but the data I need is always 57 characters from the left, and 37 characters from the end.
The bit I need (in the middle) is of varying length.
e.g. 20141126_this_piece_of_text_needs_to_be_removed<b>this_needs_to_be_kept</b>this_also_needs_to_be_removed
So far I have got:
SELECT-STRING -path path_to_logfile.log -pattern "20141126.*<b>" |
FOREACH{$_.Line} |
FOREACH{
$_.substring(57)
}
This gets rid of the text at the start of the line, but I can't see how to get rid of the text from the end.
I tried:
$_.subString(0,-37)
$_.subString(-37)
but these didn't work
Is there a way to get rid of the last x characters?
to remove the last x chars in a text, use:
$text -replace ".{x}$"
ie
PS>$text= "this is a number 1234"
PS>$text -replace ".{5}$" #drop last 5 chars
this is a number
If I understand you correctly, you need this:
$_.substring(57,$_.length-57-37)
Though this doesn't seem to work precisely with the example you gave but it will give you the varying middle section i.e. starting at 57 chars from the start and ending 37 chars from the end
This is how to remove the last 37 characters from your string:
$_.subString(0,$_.length-37)
but arco´s answer is the preferred solution to your overall problem
I have a binary file that I need to process, but it contains no line breaks in it.
The data is arranged, within the file, into 104 character blocks and then divided into its various fields by character count alone (no delimiting characters).
I'd like to firstly process the file, so that there is a line break (`n) every 104 characters, but after much web searching and a lot of disappointment, I've found nothing useful yet. (Unless I ditch PowerShell and use awk.)
Is there a Split option that understands character counts?
Not only would it allow me to create the file with nice easy to read lines of 104 chars, but it would also allow me to then split these lines into their component fields.
Can anyone help please, without *nix options?
Cheers :)
$s = get-content YourFileName | Out-String
$a = $s.ToCharArray()
$a[0..103] # will return an array of first 104 chars
You can get your string back the following way, the replace removes space char( which is what array element separators turn into)
$ns = ([string]$a[0..103]).replace(" ","")
Using the V4 Where method with Split option:
$text = 'abcdefghi'
While ($text)
{
$x,$text = ([char[]]$text).where({$_},'Split',3)
$x -join ''
}
abc
def
ghi