Aggregate method for each document resulting from find method in mongodb - mongodb

Question

I want to execute this aggregate query:
db.collection('mycoll').aggregate([
{
$search: {
index: 'default',
text: {
query: 'night',
path: {
wildcard: '*',
},
},
},
},
])
})
for each document resulting from my find method:
here is my find method:
app.get('/', (req, res) => {
db.collection('subs').find(
{ name: { $regex: 'dexter', $options: '$i' } },
{ projection: { _id: 0, content: 0 } }
)
.toArray((err, result) => {
if (err) {
throw new err();
}
res.json({
length: result.length,
body: { result },
});
});
});
I know I probably have to use forEach and create a function, but I couldn't find out what to put in this function, I assume ## Heading ##it should be something like that:
.find(
{ name: { $regex: 'dexter', $options: '$i' } },
{ projection: { _id: 0, content: 0 } }
).forEach(()=>{})
.toArray((err, result) => {
if (err) {
throw new err();
}
res.json({
length: result.length,
body: { result },
});
});
});

Answer 1

You can achieve this in several different ways, here is the simplest code sample I could produce:
app.get('/', async (req, res) => {
const result = await db.collection('subs').find(
{name: {$regex: 'dexter', $options: '$i'}},
{projection: {_id: 0, content: 0}}
).toArray();
const finalResults = await Promise.all(result.map(async (each) => {
each.textSearchResults = await db.collection('mycoll').aggregate([
{
$search: {
index: 'default',
text: { // decide what your query is based on each document
query: each.name,
path: {
wildcard: '*',
},
},
},
},
])
return each
}))
res.json({
length: result.length,
body: {result},
});
});