I am looking to create the table below, trying to figure out the if statement with dates and buckets and need assistance. note the dates I have do not include days, just mm/yy.
Make a date field by string concatenation to add in a day value.
date('01/'+[your_mm/yyyy_field])
Then create a date bucket field with the newly created [date] calc and comparing to today's date.
if datediff('month',[date],TODAY()) > 1 then 'In past'
elseif datediff('month',[date],TODAY()) = 1 then 'Last Month'
elseif datediff('month',[date],TODAY()) = 0 then 'Current Month'
elseif datediff('month',[date],TODAY()) = -1 then 'Next Month'
else 'Future'
end
Related
We're currently rebuilding basic emailed reports built using T-SQL to be paginated reports published on Power BI.
We're muddling through by creating the tables we need with the appropriate filters in Power BI Desktop to reconcile the numbers, then taking the DAX code from them using the Performance Analyser.
The one I'm working at the minute has a simple bit of SQL code to get data for a previous calendar month. I have no idea how or if it's possible for this to exist in DAX?
-- Validation to get previous month
IF (MONTH(GETDATE()) - 1) > 0
SET #MONTH = MONTH(GETDATE()) - 1
ELSE
SET #MONTH = '12'
-- Validation to get year of previous month
IF (#MONTH < 12)
SET #YEAR = YEAR(GETDATE())
ELSE
SET #YEAR = YEAR(GETDATE()) - 1
-- Set start date and finish date for extract
SET #PERIOD = #YEAR + RIGHT('00' + #MONTH, 2)
It needs to become a hidden SSRS parameter or just inline code to be used with this DAX variable:
VAR __DS0FilterTable =
TREATAS({"202212"}, 'Org View_VaultexCalendar'[Calendar Month No])
So the "202212" would become #period or the equivalent if doable without a parameter.
SSRS Parameter:
=IIF(
Month(Today()) > 1,
Year(Today()) & RIGHT("00" & Month(Today()) - 1, 2),
Year(Today())-1 & "12"
)
DAX expression:
IF (
MONTH ( TODAY () ) > 1,
YEAR ( TODAY () ) & FORMAT ( MONTH ( TODAY () ) - 1, "00" ),
YEAR ( TODAY () ) - 1 & "12"
)
In both cases we look at today's month and check if it's after January. If it is, take the current year and concatenate it with the current month less one and padded with a leading zero when needed. In the other case we know that the month is January so take the current year less one and concatenate it with "12"
This seems like it should be fairly simple and straight forward but I haven't yet found the right combination. I have a column called last_assess_yr that is an integer. I am trying to find all rows from my_table where '01-01' + 'year' < current_date and give them a value in a new column. I have the following:
SELECT last_assess_yr,
CASE
WHEN format('01-01-%s'::text, last_assess_yr)::timestamp without time
zone < current_date
THEN YES
ELSE NO
END AS assess_value
FROM my__table
but, the results are not correct
You don't actually need to convert the integer into a timestamp, you could just compare the extracted year to the integer.
select
case when last_assess_yr < extract('year' from current_date)::int
then 'YES' else 'NO'
end
However for reference the following will work:
select
case when format('01-01-%s'::text, 2017)::timestamp < current_date
then 'YES' else 'NO'
end
i.e. you do not need to remove time (of day) when you convert a string of '01-01-2017' to a timestamp.
and: I assume YES and NO also need to be treated as literals: 'YES' and 'NO'
In case someone else is looking, this worked for me:
WHEN last_assess_yr > 0 AND format('%s-05-05'::text, w.last_assess_yr)::timestamp <
current_date THEN 'yes'
ELSE 'no'
END
i need to calculate difference between two date excluding sunday. I have table with dates and i need to calculate number of dates of repeated days from last date.
if i have dates like that
27-05-2017
29-05-2017
30-05-2017
I use this code in script
date(max(Date)) as dateMax,
date(min(Date)) as dateMin
And i get min date = 27-05-2017 and max date = 30-05-2017 then i use in expressions
=floor(((dateMax - dateMin)+1)/7)*6 + mod((dateMax - dateMin)+1,7)
+ if(Weekday(dateMin) + mod((dateMax - dateMin)+1,7) < 7, 0, -1)
And get result 3 days. Thats OK, but the problem is if I have next dates:
10-05-2017
11-05-2017
27-05-2017
29-05-2017
30-05-2017
When use previously code I get min date = 10-05-2017 and max date = 30-05-2017 and result 18, but this is not OK.
I need to count only dates from
27-05-2017
29-05-2017
30-05-2017
I need to get max date and go throw loop repeated dates and if have brake to see is that date sunday if yes then step that date and continue to count repeated dates and if i again have break and if not sunday than close loop and remember number of days.
In my case instead of 18 days i need to get 3 days.
Any idea?
I'd recommend you creating a master calendar in the script where you can apply weights or any other rule to your days. Then in your table or app you can just loop through the dates or perform operations and sum their weights (0: if sunday, 1: if not). Let's see an example:
// In this case I'll do a master calendar of the present year
LET vMinDate = Num(MakeDate(year(today()),1,1));
LET vMaxDate = Num(MakeDate(year(today()),12,31));
Calendar_tmp:
LOAD
$(vMinDate) + Iterno() - 1 as Num,
Date($(vMinDate) + Iterno() - 1) as Date_tmp
AUTOGENERATE 1 WHILE $(vMinDate) + Iterno() - 1 <= $(vMaxDate);
Master_Calendar:
LOAD
Date_tmp AS Date,
Week(Date_tmp) as Week,
Year(Date_tmp) as Year,
Capitalize(Month(Date_tmp)) as Month,
Day(Date_tmp) as Day,
WeekDay(Date_tmp) as WeekDay,
if(WeekDay = '7',0,1) as DayWeight //HERE IS WHERE YOU COULD DEFINE A VARIABLE TO DIRECTLY COUNT THE DAY IF IT IS NOT SUNDAY
'T' & ceil(num(Month(Date_tmp))/3) as Quarter,
'T' & ceil(num(Month(Date_tmp))/3) & '-' & right(year(Date_tmp),2) as QuarterYear,
date(monthStart(Date_tmp),'MMMM-YYYY') as MonthYear,
date(monthstart(Date_tmp),'MMM-YY') as MonthYear2
RESIDENT Calendar_tmp
ORDER BY Date_tmp ASC;
DROP Table Calendar_tmp;
Let's say that I have a range of SQL tables that are named name_YYYY_WW where YYYY = year and WW = week number. If I call upon a function that guides a user defined date to the right table.
If the date entered is "20110101":
SELECT EXTRACT (WEEK FROM DATE '20110101') returns 52 and
SELECT EXTRACT (YEAR FROM DATE '20110101') returns 2011.
While is nothing wrong with these results I want "20110101" to either point to table name_2010_52 or name_2011_01, not name_2011_52 as it does now when I concanate the results to form the query for the table.
Any elegant solutions to this problem?
The function to_char() will allow you to format a date or timestamp to output correct the iso week and iso year.
SELECT to_char('2011-01-01'::date, 'IYYY_IW') as iso_year_week;
will produce:
iso_year_week
---------------
2010_52
(1 row)
You could use a CASE:
WITH sub(field) AS (
SELECT CAST('20110101' AS date) -- just to test
)
SELECT
CASE
WHEN EXTRACT (WEEK FROM field ) > 1 AND EXTRACT (MONTH FROM field) = 1 AND EXTRACT (DAY FROM field) < 3 THEN 1
ELSE
EXTRACT (WEEK FROM field)
END
FROM
sub;
I get to dust off my VBScript hat and write some classic ASP to query a SQL Server 2000 database.
Here's the scenario:
I have two datetime fields called fieldA and fieldB.
fieldB will never have a year value that's greater than the year of fieldA
It is possible the that two fields will have the same year.
What I want is all records where fieldA >= fieldB, independent of the year. Just pretend that each field is just a month & day.
How can I get this? My knowledge of T-SQL date/time functions is spotty at best.
You may want to use the built in time functions such as DAY and MONTH. e.g.
SELECT * from table where
MONTH(fieldA) > MONTH(fieldB) OR(
MONTH(fieldA) = MONTH(fieldB) AND DAY(fieldA) >= DAY(fieldB))
Selecting all rows where either the fieldA's month is greater or the months are the same and fieldA's day is greater.
select *
from t
where datepart(month,t.fieldA) >= datepart(month,t.fieldB)
or (datepart(month,t.fieldA) = datepart(month,t.fieldB)
and datepart(day,t.fieldA) >= datepart(day,t.fieldB))
If you care about hours, minutes, seconds, you'll need to extend this to cover the cases, although it may be faster to cast to a suitable string, remove the year and compare.
select *
from t
where substring(convert(varchar,t.fieldA,21),5,20)
>= substring(convert(varchar,t.fieldB,21),5,20)
SELECT *
FROM SOME_TABLE
WHERE MONTH(fieldA) > MONTH(fieldB)
OR ( MONTH(fieldA) = MONTH(fieldB) AND DAY(fieldA) >= DAY(fieldB) )
I would approach this from a Julian date perspective, convert each field into the Julian date (number of days after the first of year), then compare those values.
This may or may not produce desired results with respect to leap years.
If you were worried about hours, minutes, seconds, etc., you could adjust the DateDiff functions to calculate the number of hours (or minutes or seconds) since the beginning of the year.
SELECT *
FROM SOME_Table
WHERE DateDiff(d, '1/01/' + Cast(DatePart(yy, fieldA) AS VarChar(5)), fieldA) >=
DateDiff(d, '1/01/' + Cast(DatePart(yy, fieldB) AS VarChar(5)), fieldB)
Temp table for testing
Create table #t (calDate date)
Declare #curDate date = '2010-01-01'
while #curDate < '2021-01-01'
begin
insert into #t values (#curDate)
Set #curDate = dateadd(dd,1,#curDate)
end
Example of any date greater than or equal to today
Declare #testDate date = getdate()
SELECT *
FROM #t
WHERE datediff(dd,dateadd(yy,1900 - year(#testDate),#testDate),dateadd(yy,1900 - year(calDate),calDate)) >= 0
One more example with any day less than today
Declare #testDate date = getdate()
SELECT *
FROM #t
WHERE datediff(dd,dateadd(yy,1900 - year(#testDate),#testDate),dateadd(yy,1900 - year(calDate),calDate)) < 0