I have an Int, this Int relates to number of minutes. I convert this Int to hours, minutes and seconds using following code and all works great until the timer is below 0.
let hours = Int(timeRemaining) / 3600
let minutes = Int(timeRemaining) / 60 % 60
let seconds = Int(timeRemaining) % 60
timeLeftLabel.text = String(format:"%02i:%02i:%02i", hours, minutes, seconds)
The output from the above code looks something like this and it counts down perfectly:
02:56:07
However, as soon as the time reaches 0 the format starts looking like this:
-2:-56:-7 (this is obviously after minus 2 hours, it doesn't immediately jump to minus 2 hours, I'm just trying to highlight the point)
As you can see, there are numerous issues here, firstly the minus symbol, I simply want there to be one minus symbol at the start. Then the 0's are missing from hours and seconds, it should simply read:
-02:56:07
The only way I can think to try and resolve this is to use: replacingOccurrences(of) but was wondering if there was a better option?
Any advice much appreciated.
A much better solution is to use a DateComponentsFormatter
let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.hour, .minute, .second]
formatter.zeroFormattingBehavior = .pad
Example
let timeRemaining: TimeInterval = 2 * 60 * 60 + 56 * 60 + 7
let negative = -1 * timeRemaining
print(formatter.string(from: timeRemaining)!)
print(formatter.string(from: negative)!)
02:56:07
-02:56:07
Since you just want a single negative sign in front of the whole string, start with the absolute value of your interval and do your arithmetic, and then prepend the minus sign if the original was negative.
(But I agree that it is better to use a formatter and no arithmetic.)
Related
I want to convert seconds to days, hours and minutes
Currently, it works just for hours and minutes but not for days. Can you please support me tell me what I did wrong:
<cfscript>
seconds = '87400';
midnight = CreateTime(0,0,0);
time = DateAdd("s", seconds, variables.midnight);
date= xxxxxxxxxxxxxxxxxxxxx???
</cfscript>
<cfoutput>
#DateFormat(variables.date, 'd')# not working
#TimeFormat(variables.time, 'HH:mm')#
</cfoutput>
For the value 87400 the expected result is
1 Days, 0 hours, 16 minutes
If I take 94152 seconds it will be:
1 days, 3 hours, 22 minutes
The only issue i have is to get the correct days ... hours and minutes are diplayed but not the correct days
thank you for all the support
A simple way to calculate the intervals is by taking advantage of the modulus operator:
totalSeconds = 94152;
days = int(totalSeconds / 86400);
hours = totalSeconds / 3600 % 24;
minutes = totalSeconds / 60 % 60;
seconds = totalSeconds % 60;
For 94152 seconds, the results would be:
Interval
Value
DAYS
1
HOURS
2
MINUTES
9
SECONDS
12
TOTALSECONDS
94152
demo trycf.com
I understand from your question that you don't need to get a certain date and time along a timeline, but convert a total amount of seconds in days, hours and minutes. To do that you don't necessary need to use cfml time and date functions like CreateTime() or DateAdd(). You just may need these in order to get a reference point of time or date along a timeline, which doesn't seem to be the case, otherwise you would know the value of your starting date variable. Thus, you can solve this with plain rule of three. There may be simpler methods, so I'm posting an alternative only.
We know that:
60 seconds is equivalent to 1 minute
60 minutes is equivalent to 1 hour
24 hours is equivalent to 1 day
Thus, your calcualtion within cfml could be like so:
<cfscript>
//Constants for calculation
secondsPerDay= 60*60*24;
secondsPerHour= 60*60;
secondsPerMinute= 60;
//Seconds to convert
secondsTotal=87400;
// temp variable
secondsRemain= secondsTotal;
days= int( secondsRemain / secondsPerDay);
secondsRemain= secondsRemain - days * secondsPerDay;
hours= int( secondsRemain / secondsPerHour);
secondsRemain= secondsRemain - hours * secondsPerHour;
minutes= int( secondsRemain / secondsPerMinute);
secondsRemain= secondsRemain - minutes * secondsPerMinute;
writeoutput( "#secondsTotal# seconds are: #days# days, #hours# hours, #minutes# minutes and #secondsRemain# seconds." );
</cfscript>
That outputs:
87400 seconds are: 1 days, 0 hours, 16 minutes and 40 seconds.
Hello I am trying to make a count down. I want to convert an integer from second to date and show in a label with this below formats. Lets say that 2.500.000 it prints out to label 29 days 22 hour
29 days 22 hour remained
15 hour 30 minutes remained
15 minutes remained
It sounds like you want a DateComponentsFormatter . That lets you generate strings that describe amounts of time rather than dates.
You could use the function func string(from ti: TimeInterval) -> String? which takes a time interval and converts it to a string describing an amount of time.
The following code, loosely based on the example code in Apple's documentation on DateComponentsFormatter:
let formatter = DateComponentsFormatter()
formatter.unitsStyle = .full
formatter.includesApproximationPhrase = true
formatter.includesTimeRemainingPhrase = true
formatter.allowedUnits = [.day, .hour, .minute, .second]
print(formatter.string(from: 123456.7) ?? "nil")
Generates the string About 1 day, 10 hours, 17 minutes, 36 seconds remaining (At least with a US English locale.)
I have some text fields in an array. HH:MM:SS. I'm having two issues, one is when one of the fields is left blank, the app crashes and I want it to just read as "0" if blank. Second, I use below to convert HH:MM:SS to Minutes. I do 0:18:30 and the math below to decimal comes out to 18.5
Now how would I convert this back to HH:MM:SS? array[0] is hours, array[1] is minutes, array[2] is seconds.
stepOne = (Float(array[0])! * 60) + Float(array[1])! + (Float(array[2])! / 60)
What you need is to calculate the number of seconds instead of number of minutes. Using the reduce method just multiply the first element by 3600 and then divide the multiplier by 60 after each iteration. Next you can use DateComponentsFormatter to display the resulting seconds time interval using .positional units style to the user:
let array = [0,18,30]
var n = 3600
let seconds = array.reduce(0) {
defer { n /= 60 }
return $0 + $1 * n
}
let dcf = DateComponentsFormatter()
dcf.allowedUnits = [.hour, .minute, .second]
dcf.unitsStyle = .positional
dcf.zeroFormattingBehavior = .pad
let string = dcf.string(from: TimeInterval(seconds)) // "00:18:30"
I have 2 TimeIntervals, which just represent date-agnostic times of day (e.g. 8:00 AM and 5:00 PM). So 0 represents exactly midnight, in this case, and 29,040 represents 8:04 AM. I want to check if the phone's time of day is between the two TimeIntervals.
I found a few similar Stack Overflow questions, but none of them really dealt with TimeIntervals. It seems like just using start <= Date().timeIntervalSinceReferenceDate <= end or something wouldn't work, because it would return a huge value.
What's the best way to handle this type of situation in Swift 3?
Edit: To clarify, I don't need to worry about things like daylight savings. As an example, assume that the user only wants certain things in the app to happen between the hours of X and Y, where X and Y are given to me as TimeInterval values since midnight. So it should be sufficient to check if the phone's TimeInterval since midnight on a typical day is between X and Y before completing the action.
Date().timeIntervalSinceReferenceDate returns the number of seconds since Jan 1, 2000 so no doubt it's a huge number.
It's inadvisable to store time as seconds since midnight due to this naggy little thing called Daylight Saving Time. Every year, different countries do it on different days and on different hours. For example, even though Britain and France change their clock on the same day (March 26, 2017), one makes the shift from 1AM to 2AM, the other goes from 2AM to 3AM. That's very easy to make for a mess!
Use DateComponents instead:
let calendar = Calendar.current
let startTimeComponent = DateComponents(calendar: calendar, hour: 8)
let endTimeComponent = DateComponents(calendar: calendar, hour: 17, minute: 30)
let now = Date()
let startOfToday = calendar.startOfDay(for: now)
let startTime = calendar.date(byAdding: startTimeComponent, to: startOfToday)!
let endTime = calendar.date(byAdding: endTimeComponent, to: startOfToday)!
if startTime <= now && now <= endTime {
print("between 8 AM and 5:30 PM")
} else {
print("not between 8 AM and 5:30 PM")
}
I ended up using DateComponents to calculate a TimeInterval.
let components = Calendar.current.dateComponents(
[.hour, .minute, .second], from: Date())
guard let seconds = components.second,
let minutes = components.minute,
let hours = components.hour else
{
return false
}
let currentTime = Double(seconds + minutes * 60 + hours * 60 * 60)
return startTime <= currentTime && currentTime <= endTime
Example:
Time = 09:41:46
Duration = 0:00:17 (IE 17 seconds)
Start Time = Time - Duration
Clearly I can't just break this up into hours minutes and seconds and do a basic minus operation given the 60 minute hour and 60 second minute etc.
Can't seem to get my head around how to calculate this and hoping someone has come across this before :).
You can use the DateAdd function.
For example, this will subtract 17 seconds from the specified date/time.
DateAdd("s", -17, "1/1/2013 09:41:46")
Try this
Time = 09:41:46
Duration = 0:00:17
Start_Time = FormatDateTime(Time - Duration, 3)
wscript.echo hour(Start_Time)
wscript.echo minute(Start_Time)
wscript.echo second(Start_Time)
References:
https://www.w3schools.com/asp/asp_ref_vbscript_functions.asp#date